1. The area of a rectangular carpet is X² + X - 2. HINT: Area = length X breadth

a). if X is a whole number, use factorization to find the length and the breadth of the carpet in terms of X.

b). if X = 2 m, find the actual dimensions of the carpet.


c). it costs R50 per square metre to make such this carpet. how much will it cost to manufacture 5 carpets?​ ​​

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Answer:

y=-15x+100

Step-by-step explanation:

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}[/tex]

[tex](\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}[/tex]

Answer:

SORRY I DONOT KNOW THE ANSWER

Step-by-step explanation:

i am sorry i do not know the amswer

The area of the rectangle, as shown in the image given is calculated as: 48 square units.

The area of a rectangle = length × width.

Find the length and width of the rectangle:

Area of rectangle ABCD = 8 × 6 = 48 square units.

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The maximum height of the  pumpkin is 3 feet

We have given that,

A catapult hurls a pumpkin from a height of 32 feet at an initial velocity of 96 feet per second.

The function h(t)=-16t^2+96t+32 represents the heights of the pumpkin h(t) in terms of time t.

We have to determine the maximum height.

At the point of maxima f'(x)=0

first, find the maxima

Therefore differentiate the given function with respect to t we get,

[tex]h'(t)=-32t+96[/tex]

h'(t)=0

Then we get,

[tex]0=-32t+96\\-32t=-96\\t=\frac{-96}{-32} \\t=3[/tex]

Therefore the maximum height of the pumpkin is 3 feet.

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Maintain the same constraints on edge capacity, skew symmetry, and flow conservation in the ordinary maximum-flow problem on a flow network of comparable size.

A flow network is a directed graph with each edge having a capacity and each edge receiving a flow, according to graph theory. The amount of flow on an edge must not exceed the edge's capacity.

Let's suppose the network flow is given by;

G = (V, E)

With edge capacity:

c: E → R

And vertex capacity:

d: V → R

Maintain the same constraints on edge capacity, skew symmetry, and flow conservation.

Consider the new stipulation: for each:

v ∈V

So,

[tex]\rm \sum_{u \in v } \{ f(u,v)|f(u,v) > 0 \} \leq d(v)[/tex]

Thus, if maintain the same constraints on edge capacity, skew symmetry, and flow conservation the ordinary maximum-flow problem on a flow network of comparable size.

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Answer:

A.) True

Step-by-step explanation:

A set of outputs and inputs becomes a function when there is only one output per input. In this case, each "x" value only has one "y" value, making it a function.

The following recurring decimal as a rational number are 1/2, 13/100 and 341 / 1000

A rational number is a number that is expressed as the quotient or fraction of two integers, a numerator and a non-zero denominator such as;

3/4. where,

Therefore,

0.5

= 5/10

= 1/2

0.13

= 13/100

0.341

= 341 / 1000

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1. Mean of the data: 8

2. Median: 8

3. IQR = 4

4. Members that use the facility 10 days a month is: 2.

See reasons below.

Mean = sum of all values ÷ number of data values (easily solved using a dot plot

Median = middle value (easily found using a box plot).

Interquartile range (IQR) = Q3 - Q1 (easily found using a box plot).

1. Mean of the data: use the dot plot.

Reasoning: (3 + 3 + 5 + 6 + 6 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 11 + 12 + 14)/15 = 8

2. Median of the data set: Using the box plot, it is the value indicated by the vertical line that divides the box.

Median = 8

3. IQR = Q3 - Q1 = 10 - 6

IQR = 4

4. Members that use the facility 10 days a month, using the dot plot is: 2. 10 has 2 dots.

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The area of the shape is 180 square feet if the length of the diagonals are 20 and 18 ft respectively, option (a) is correct.

It is defined as the four-sided polygon in geometry having four edges and four corners. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

We know the area of the kite = pq/2

Where p and q are the length of the diagonals

p = 10+10 = 20 ft

q = 7+11 = 18 ft

Area = (20×18)/2

Area = 180 square feet

Thus, the area of the shape is 180 square feet if the length of the diagonals are 20 and 18 ft respectively option (a) is correct.

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If ɑ and β are the roots of x² + bx + c = 0, then we can write

x² + bx + c = (x - ɑ) (x - β)

Expanding the right side gives

x² + bx + c = x² - (ɑ + β) x + ɑβ

so that ɑ + β = -b and ɑβ = c.

Recall that for all real numbers m and n,

(m + n)² = m² + 2mn + n²

a) It follows that

(i) ɑ² + β² = (ɑ + β)² - 2ɑβ = (-b)² + c = b² + c

(ii) (ɑ - β)² = ɑ² - 2ɑβ + β² = b² + c - 2c = b² - c

b) I assume you mean to find the quadratic whose roots are ɑ² + β² and (ɑ - β)² (and not (ɑ - 3)²). The simplest quadratic of this form is

(x - (ɑ² + β²)) (x - (ɑ - β)²)

Using the results from part (a), this becomes

(x - (b² + c)) (x - (b² - c))

and expanding, we get

x² - (b² + c + b² - c) x + (b² + c) (b² - c)

= x² - 2b² x + b⁴ - c²

Probability that the mean childhood asthma prevalence for the sample is greater than 2.6% is 0.0357 or 3.57 %.

What is Probability ?

Probability is the measure of likelihood of an event.

For a Normal Distribution ,

the z-score formula is given by

[tex]\rm Z = \dfrac{X - \mu }{\sigma}[/tex]

Here [tex]\rm \mu\\[/tex] is the mean and [tex]\rm \sigma\\[/tex] is the standard deviation .

It is the measure of the deviation of the data from its central tendency.

Each z-score has a probability value.

It is given in the question that

Mean of 2.16% =  [tex]\rm \mu\\[/tex] = 2.16

Standard deviation of 1.36% means that  [tex]\rm \sigma\\[/tex] = 1.36

For Sample of 31 the value of standard deviation is [tex]\rm s = \dfrac{\sigma}{\sqrt{n}}[/tex]

s = 1.36/√31

s = 0.2442

Substituting the values

Z = (2.6 -2.16)/0.2442

Z =1.8

the p value from the graph of z and p , 0.9643

To determine value of probability  more than X is 1 - 0.9643= 0.0357

the

Probability that the mean childhood asthma prevalence for the sample is greater than 2.6% is 0.0357.

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Answer:

-3

Step-by-step explanation:

g(-3) = -2x+3x

-2(-3) +3(-3)

6+-9 = -3

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Answer:

just commenting so you can give the other guy brainliest !

Step-by-step explanation:

The length of the similar tube will be 5041 cm.

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

The radius of the first tube will be calculated as:-

1200 = 2πr ( 13 )

r = 12 / 2π x 113

r = 14.7 cm

Now the length of the second tube will be:-

500 = 2π x 14.7 x L

L = 500 / 2π x 14.7

L = 5.41 cm.

Therefore the length of a similar tube will be 5041 cm.

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Answer:

Step-by-step explanation:

Length=18

Width/Breadth =10

Height=2

The formula for a diagonal face of a cuboid is=√(l²+ b²)

Face diagonal=√(18²+10²)

= 20.59 to 2.d.p

The formula for the body diagonal of a cuboid is=√(l² + b² + h²)

Body diagonal=√(18² + 10² + 2²)

=20.69 to 2.d.p

Answer:

13

Step-by-step explanation:

The way to find the distance between two points on the coordinate plane is to use the distance formula, which is basically a way of applying the Pythagorean Theorem.

The distance formula is [tex]\sqrt{(x_{1}- x_{2} )^2 + (y_{1}- y_{2})^2}[/tex]. Let's say the coordinate (3, -8) is (x1, y1) and the coordinate (8, 4) is (x2, y2). We can plug these values into the formula:

[tex]\sqrt{(3- 8 )^2 + (-8 - 4)^2}\\\sqrt{(-5)^{2} + (-12)^{2}} \\\sqrt{25+144} \\\sqrt{169} \\13[/tex]

So, the distance between the two points is 13.

The banner attached to the archway will be at (1, 5) and (5.25, 3.938).

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

The archway of the main entrance of a university is modeled by the quadratic equation

y = -x² + 6x ....1

The university is hanging a banner at the main entrance at an angle defined by the equation

4y = 21 − x ....2

Then the banner attached to the archway will be

From equations 1 and 2, we have

              4(-x² + 6x) = 21 - x

              -4x² + 24x = 21 - x

        4x² - 25x + 21 = 0

  4x² - 21x - 4x + 21 = 0

x(4x - 21) - 1(4x - 21) = 0

          (4x - 21)(x - 1) = 0

                             x = 5.25, 1

Then the value of y will be

When x = 5.25, then we have

y = -(5.25)² + 6(5.25)

y = 3.938

When x = 1, then we have

y = -(1)² + 6(1)

y = 5

The banner attached to the archway will be at (1, 5) and (5.25, 3.938).

The graph is given below.

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Answer:

  73 cm²

Step-by-step explanation:

Areas and volumes of composite figures are found by dividing the figure into shapes you have formulas for. Sometimes that will be a sum of shapes, and sometimes it will involve the difference of shapes.

__

This shape can be decomposed into two rectangles by extending the horizontal line. (This is the dashed line shown in the attachment.)

The width of the top rectangle will be the sum of the lengths of the labeled horizontal segments:

  4 cm + 5 cm + 3 cm = 12 cm

The height of the top rectangle, and the dimensions of the bottom rectangle (square) are shown in the given figure.

The area of each rectangle is the product of its width and height.

  A = WH

__

  top rectangle area = WH = (12 cm)(4 cm) = 48 cm²

  bottom rectangle area = WH = (5 cm)(5 cm) = 25 cm²

  Area = top rectangle area + bottom rectangle area = (48 cm²) +(25 cm²)

  Area = 73 cm²

The area of this composite shape is 73 cm².

_____

Additional comment

The figure will fit into a rectangle that is 9 cm high by 12 cm wide. From that rectangle, a rectangle 5 cm high and 4 cm wide is removed from the lower left, and a rectangle 5 cm high and 3 cm wide is removed from the lower right. Figuring the area this way, we find it to be ...

  figure area = bounding rectangle area - removed areas

  = (9 cm)(12 cm) -(5 cm)(4 cm) -(5 cm)(3 cm) = 108 cm² -20 cm² -15 cm²

  = 73 cm²

Answer:

x < 5.

Step-by-step explanation:

Creo que esto es correcto. :')

Answer:

C

Step-by-step explanation:

14 + w is the same as w + 14

Answer:

C.  w + 14.

Step-by-step explanation:

The order does not matter when you are adding terms.

this is called the Commutative Property of Addition.

Answer:

help me to find Xian pleaseee:( i miss him so much:(

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Answer:

[tex]\sf 2 x-5y +25=0[/tex]

Explanation:

Equation:

[tex]\dashrightarrow \sf y - y_1 =m(x - x_1)[/tex]

[tex]\dashrightarrow \sf y - 1 = \dfrac{2}{5} (x - (-10))[/tex]

[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +4 + 1[/tex]

[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +5[/tex]

[tex]\dashrightarrow \sf 5y = 2 x +25[/tex]

Answer:

The period is 2π

Explanation:

The period is 2 times pi because 2 is the standalone-term multiplied by pi to get the period.

Answer:

Step-by-step explanation:

angle c

The angle of the triangle with the greatest measure is ∠A

A triangle is a polygon with three sides and three angles.

Analysis:

For the triangle, ABC the angle facing the side with the greatest measure is the angle with the greatest measure. From the given information side BC is the side with the greatest measure and the angle facing it is ∠A.

In conclusion, the angle with the greatest measure is ∠A

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Answer:

Step-by-step explanation:

Answer:

a = 6

Step-by-step explanation:

g(x) = 5x - 2

h(x) = √(x + 3)

g(h(x)) = 5[tex]\sqrt{x+3}[/tex] - 2

g(h(a)) = 5[tex]\sqrt{a+3}[/tex] - 2

5[tex]\sqrt{a+3}[/tex] - 2 = 13

5[tex]\sqrt{a+3}[/tex] = 15

[tex]\sqrt{a+3}[/tex] = 3

( [tex]\sqrt{a+3}[/tex] )² = 3²

a + 3 = 9

a = 6

The missing probability from the line in the diagram attached is 0.5.

The number line is a graduated straight line system showing the value of each real number from (-∞, +∞).

The probability of a number line in the diagram below is halfway (middle) between the impossible event and a certain event.

Thus,

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