Triangle FGH is formed by connecting the midpoints of the side of triangle CDE The lengths of the sides of triangle FGH are shown. Find the perimeter of triangle CDE. Figures not necessarily drawn to scale.

Answer:

=4x³-4x²+4x-3

Step-by-step explanation:

(f+g)(x)=4x³+2x²-6x²+4x-6+3

=4x³-4x²+4x-3

Answer:

the sequence begins as {4, 7, ... }

Step-by-step explanation:

a(n) = 3n + 1

The first term is a(1) = 3(1) + 1 = 4, and

the second term is a(s) = 3(2) + 1 = 7

So the sequence begins as {4, 7, ... }

Step-by-step explanation:

the picture is not representing the real angle sizes. so, don't let yourself get confused by that.

the right neighbor angle of 90° at E is also 90°.

it has to be, because it is the supplementary angle to the left 90° (that means together they are 180°).

remember, all angles around a single point on one side of a line have to sum up to 180° (because the line can be seen as the diameter of a circle, with the point being the center of the circle, and so one side of the line is representing a half-circle and therefore 180°).

for the same reason angle 1 (the lower neighbor of the 90° angle at A) is also 90°.

for the same reason the lower neighbor angle of the 60° angle at E is 180 - 60 = 120°.

for the same reason the angle ABC is 180 - 40 = 140°.

for the angle BCD we need to remember :

the sum of interior angles of a polygon with n sides is

(n − 2) × 180°.

in our case ABCDE has 5 sides, so the sum of all interior angles is

(5 - 2) × 180 = 3×180 = 540°

we know 4 of the interior angles already, so

angle BCD = 540 - 90 - 90 - 120 - 140 = 100°

x is now the supplementary angle to the angle BCD.

so,

x = 180 - 100 = 80°

Answer:

alternate exterior angles

Step-by-step explanation:

<3 i hope this helps! sorry if it doesnt :)

[tex]~~~~~~~\log_{10} N = 3.8609\\\\\\\implies N = 10^{3.8609} ~~~~~~~~~;[\log_b c =d \implies b^d = c]\\\\\\\implies N \approx 7259[/tex]

Answer:

Step-by-step explanation:

[tex]\sf \left(2x+\cfrac{1}{2}\right)+\left(8x-2\cfrac{1}{2}\right)[/tex]

We'll need to convert the mixed number 2 1/2 to improper fraction.

[tex]\sf \left(2x+\cfrac{1}{2}\right)+\left(8x-\cfrac{5}{2}\right)[/tex]

Simplify...

[tex]\sf 2x+\cfrac{1}{2}+8x-\cfrac{5}{2}[/tex]

Add similar elements.

[tex]\sf 10x+\cfrac{1}{2}-\cfrac{5}{2}[/tex]

[tex]\sf 10x+\cfrac{-4}{2}[/tex]

Divide numbers..

[tex]\sf 10x-2[/tex]

_______________________

Answer:

x=3

13x-5=1+11x

(ADD 5 TO BOTH SIDES)

13x-5+5=1+11x+5

SIMPLIFY

13x=11x+6

SUBTRACT 11x FROM BOTH SIDES

13x-11x=11x+6-11x

SIMPLIFY

2x=6

DIVIDE BOTH SIDES BY 2

2x/2 = 6/2

SIMPLIFY TO GET FINAL ANSWER

x=3

Answer:

3.5 gallons of punch

Step-by-step explanation:

There are 4 quarts in 1 gallon.

Set up equation to convert 14 quarts to gallons: 14÷4 = 3.5.

Elijah made 3.5 gallons of punch.

The 1- diameter, 2-inscribed angle, 3-chord, 4-minor arc, 5-central angle, 6-radius, and 7-centre.

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

The radius is the double the diameter.

The longest chord in the circle is diameter.

The angle formed at the centre is known as centeral angle.

Thus, the 1- diameter, 2-inscribed angle, 3-chord, 4-minor arc, 5-central angle, 6-radius, and 7-centre.

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The value of x in all case is

1. The value of x is 2

2. The value of x is 1

3.The value of x is 57

4.The value of x is 93

If the sum of two angles is 180 degrees then they are said to be b angles, which form a linear angle together. Whereas if the sum of two angles is 90 degrees, then they are said to be complementary angles, and they form a right angle together.

1. As the given angle is 90 degree i.e., complementary angle.

So,

54+10x+16=90

20=10x

x=2

2. 65x-12=43x+10  (Vertically opposite angle)

 22x= 22

x=1

3. 72= x+15  (Vertically opposite angle)

x= 57

4.x+244+23=360  (Complete angle)

 x=93

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Answer:

Step-by-step explanation:

The given equations are:

1) 2y = -x + 9

⇒ x = 9-2y

2) 3x - 6y = -15

⇒3x = 6y - 15

x = 2y - 5

Equating the values of x, we get:

9 - 2y = 2y - 5

9 + 5 = 4y

14 = 4y

y = 3.5

Using this value of y in equation 1 we get:

x = 9 - 2(3.5) = 2

So, the solution set is (2, 3.5)

5ax+6ax=7ax+8

5ax+6ax-7ax=8

4ax=8

x= 8/4a

x=2a

Let S be the given sum, so

[tex]S = 8 + 8 \left(\dfrac14\right) + 8 \left(\dfrac14\right)^2 + \cdots + 8 \left(\dfrac14\right)^9[/tex]

[tex]\displaystyle S = 8 \left(1 + \dfrac14 + \frac1{4^2} + \cdots + \frac1{4^9}\right)[/tex]

Multiply both sides by 1/4.

[tex]\displaystyle \frac S4 = 8 \left(\frac14 + \frac1{4^2} + \frac1{4^3} + \cdots + \frac1{4^{10}}\right)[/tex]

Subtract this from S to eliminate all the but the first term in S and the last term in S/4 :

[tex]\displaystyle S - \frac S4 = 8 \left(1 - \frac1{4^{10}}\right)[/tex]

Solve for S :

[tex]\displaystyle \frac{3S}4 = 8 \left(1 - \frac1{4^{10}}\right)[/tex]

[tex]\displaystyle S = \frac{32}3 \left(1 - \frac1{4^{10}}\right) = \boxed{\frac{349,525}{32,768}}[/tex]

Answer:

AC = BC = 5

AB = 5√2

∠A = ∠B = 45

∠A = 90

Step-by-step explanation:

AC = 5 ( Reason : 5 squares are present in between A and C )

Similarly,

BC = 5

By Pythagoras theorem,

(AB)² = (AC)² + (BC)²

        = 5² + 5²

        = 2 * 5²

(AB)² = 2 * 5²

AB = 5√2

Since, sides AC and BC are equal,

∠A = ∠B = 45

Since, AC is perpendicular to BC,

∠A = 90

The quadrants is tan⁻¹x restricted is A. Quadrants I and IV

To answer the question, we need to know what tan⁻¹x is.

tan⁻¹x is the inverse trigonometric function of tanx, which is the value of the angle for tanx.

To find the quadrants in which tan⁻¹x is restricted, we know that tanx lies in the range

-∞ ≤ tanx ≤ +∞ for -90° ≤ x ≤ 90°.

tan⁻¹x lies between quadrant I and IV

So, the quadrants is tan⁻¹x restricted is A. Quadrants I and IV

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Answer:

C. 91.46

Step-by-step explanation:

Use BODMAS!

Answer:

C. 91.46

Step-by-step explanation:

Using Pemdas to solve:

5.9 (9 - 5) + 4^3 + 3.86

First you have to solve in the parenthesis

5.9 (9 - 5) + 4^3 + 3.86

= 4

New equation:

5.9 x 4 + 4^3 + 3.86

Now solve the exponent:

5.9 x 4 + 4^3 + 3.86

= 64

New equation:

5.9 x 4 + 64 + 3.86

Now we have to do multiplication:

5.9 x 4 + 64 + 3.86

= 23.6

New equation:

23.6 + 64 + 3.86

Now all you have to do is add all that together and you have your answer:

23.6 + 64 + 3.86

= 91.46

Hope this helps.

Answer:

25.5

Step-by-step explanation:

I did the same assignment

Answer:

135

Step-by-step explanation:

every njmber is divided by 3

If 135 is divised by 3 it becomes 45

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to fill in the missing number in the following sequence:

[tex]\pmb{(~~~),45,15,5}[/tex]

[tex]\triangle~\fbox{\bf{KEY:}}[/tex]

Since every number here is divided by 3, the common ratio is 3.

To find the missing number, we should multiply 45 times the common ratio, 3:

[tex]\star~\mathrm{\overline{\underline{\overline{\underline{135}}}}}[/tex]

Hope it helps you out! :D

Ask in comments if any queries arise.

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~Just a smiley person helping fellow students :)

The value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We know that:

P + Q are complementary, which means that

P+Q = 90°

Then R is a right angle, i.e. it measures 90°.

sin(90-x) = cos (x)

cos(90-x) = sin (x)

Then sinQ = 4/5  

cos(90-Q) = cosP = 4/5

Now sin²(P) + cos²(P) = 1

sin²(P) = 1 - cos²(P)

sin²(P) = 1 -[4/5]² =9/25

sin(P) = 3/5

cos(Q) = sin(P) = 3/5

cos(P) + cos(Q) = 4/5 + 3/5 = 7/5

Thus, the value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.

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#a

[tex]\\ \rm\Rrightarrow f(-4)[/tex]

[tex]\\ \rm\Rrightarrow 3(-4)+2[/tex]

[tex]\\ \rm\Rrightarrow -12+2[/tex]

[tex]\\ \rm\Rrightarrow -10[/tex]

#b

#1

[tex]\\ \rm\Rrightarrow y=\dfrac{2x-1}{3}[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{2y-1}{3}[/tex]

Find y

[tex]\\ \rm\Rrightarrow y=\dfrac{3x+1}{2}[/tex]

Inverse is

[tex]\\ \rm\Rrightarrow g^{-1}(x)=\dfrac{3x+1}{2}[/tex]

#2

[tex]\\ \rm\Rrightarrow gof(x)[/tex]

[tex]\\ \rm\Rrightarrow g(f(x))[/tex]

[tex]\\ \rm\Rrightarrow g(3x+2)[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{2(3x+2)-1}{3}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6x+4-1}{3}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{6x+3}{3}[/tex]

If we factor out

[tex]\\ \rm\Rrightarrow \dfrac{2x+1}{1}[/tex]

[tex]\\ \rm\Rrightarrow 2x+1[/tex]

#c

[tex]\\ \rm\Rrightarrow f(x)=g(x)[/tex]

[tex]\\ \rm\Rrightarrow 3x+2=\dfrac{2x-1}{3}[/tex]

[tex]\\ \rm\Rrightarrow 3(3x+2)=2x-1[/tex]

[tex]\\ \rm\Rrightarrow 9x+6=2x-1[/tex]

[tex]\\ \rm\Rrightarrow 7x=-7[/tex]

[tex]\\ \rm\Rrightarrow x=-1[/tex]

Answer:

Given functions:

[tex]f(x)=3x+2[/tex]

[tex]g(x)=\left(\dfrac{2x-1}{3}\right)[/tex]

Part (a)

[tex]\begin{aligned}\implies f(-4) & = 3(-4)+2\\& = -12+2\\ & = -10\end{aligned}[/tex]

Part (b)(i)

[tex]\begin{aligned}g(x) & =\left(\dfrac{2x-1}{3}\right)\\\\\textsf{Swap }g(x) \textsf{ for }y : \\\implies y & = \left(\dfrac{2x-1}{3}\right)\\\\\textsf{Make } x \textsf{ the subject}: \\\implies 3y & = 2x-1\\3y+1 & = 2x\\x & = \dfrac{3y+1}{2}\\\\\textsf{Swap }x \textsf{ for }g^{-1}(x) \textsf{ and }y \textsf{ for }x:\\\implies g^{-1}(x) & = \dfrac{3x+1}{2}\end{aligned}[/tex]

Part (b)(ii)

[tex]\begin{aligned}gf(x) & = \dfrac{2[f(x)]-1}{3}\\\\& = \dfrac{2(3x+2)-1}{3}\\\\& = \dfrac{6x+4-1}{3}\\\\& = \dfrac{6x+3}{3}\\\\& = \dfrac{6x}{3}+\dfrac{3}{3}\\\\& = 2x+1\end{aligned}[/tex]

Part (c)

[tex]\begin{aligned}f(x) & = g(x)\\\\\implies 3x+2 & = \dfrac{2x-1}{3}\\\\3(3x+2) & = 2x-1\\\\9x+6 & = 2x-1\\\\7x & = -7\\\\\implies x & = -1\end{aligned}[/tex]

Answer: 330 pupils

Step-by-step explanation:

the number of pupils are in the lower school

= (1- 1/5 - ¼) × 600

= (20/20 - 4/20 - 5/20)×600

= (11/20) ×600

= 330 pupils

Answer:

$8/hour

Step-by-step explanation:

We will start by finding how much money she made before spending it. The amount of money she took home added to how much money she spent will give us this. ([tex]12 + 36 = 48[/tex]). This means she made $48 before spending it.

Now we can solve for her wage. Let [tex]x[/tex] be her hourly wage

(the 6 is the number of hours she worked, this multiplied by her wage should give us 48)

[tex]6x = 48\\x = 8[/tex]

This means that she made $8/hour.

That is the answer

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The graph (A) in the picture represents the solution to the inequality, option (A) is correct.

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

The options are missing.

The graph is in the picture, please refer to the picture.

We have an inequality:

y − 2x ≤ 1

The above inequality represents a straight line with a positive slope.

The right side region of the line is representing the solution to the inequality.

Graph (A) represents the inequality.

Thus, the graph (A) in the picture represents the solution to the inequality, option (A) is correct.

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Answer:

i believe the answer is false !

Step-by-step explanation:

Answer:

the answer is B:42.8

Step-by-step explanation:

because when u do this :24+58+30+42+87+11+ 12+55+91+18 = 428

the total numbers here is 10. so 428÷10 = 42.8

That is how u get ur final answer

u hope have helped you dear

The area of this trapezoid is A = 55

We know that the application formula for calculating the area of a trapezoid is given by:

[tex] \boxed{ \large \sf A = \dfrac{(b + b) \times h}{2} } \\ \\ [/tex]

⚘ Then, the resolution will be:

[tex]{ \large \sf A = \dfrac{(7 + 15) \times 5}{2} } [/tex]

[tex]{ \large \sf A= \dfrac {22 \times 5}{2} } [/tex]

[tex]{ \large \sf A= \dfrac {110}{2} } [/tex]

[tex]\pink{ \boxed{ \purple{ \boxed{ \large \sf A= 55 }}}} \\ \\ [/tex]

Therefore, the area of this trapezoid will be, A = 55

Answer:

B and C

Step-by-step explanation:

vertical angles are angles that are opposite of each other when two lines cross. Vertical angles are congruent = they are equally large.

the angles listed in B and C are mirrored across either an imaginary or a directly visible line. and that makes them vertical angles.

Answer:

1: sin B, cos B, and tan B = 36.87°

2: x = 11.7

Step-by-step explanation:

Question 1: As toy can see they all have the same angle answer just different methods of finding it

Question 2:

adjacent is the closest side to the angle

opposite is the side across from the angle

hypotenuse is always the longest side

x = 11.7025

Hope it helps :)

If you have any questions or anymore help lmk, happy to help with any school work!!

Have a nice day, you’ll make it thru <3

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Answer:

x=5 and y=7

Step-by-step explanation:

Just substitute in y=x+2 into the equation 5x-4y=-3 to get 5x-4(x+2)=-3 which simplifies to x=5. Substitute x into y=x+2 to find y=7