A climber starts at an elevation of -200 meters and her change in elevation is 300 meters up. What is her final elevation?

Answers

Answer 1

Answer:

100

Step-by-step explanation:

because -100 0 then positive 100      

                     


Related Questions

12
A model maker wants to make a model of a
ship
He will use a scale of 1:50
The ship was 100ft long
1 foot = 0.3 m
How long will the ship be in cm?

Answers

9514 1404 393

Answer:

  60 cm

Step-by-step explanation:

The model ship will be x feet long, where ...

  x/100 = 1/50

  x = 100/50 = 2

In meters, that is ...

  2(0.3 m) = 0.6 m

A meter is 100 cm, so the length in centimeters is ...

  (0.6)(100 cm) = 60 cm

At Davidson's Bike Rentals, it costs $41 to rent a bike for 8 hours. How many hours of bike use does a customer get per dollar?

Answers

Answer:

0.192 hour

Step-by-step explanation:

41$ / 8 = 0.192 hours = 11.703 minutes

Please hurry; Rajiv bought a rare stamp for $125. A function that models the value of Rajiv’s after t years is v(t) = 125 (1.05)t . What is the value of Rajiv’s stamp after 20 years?

a $131.25
b $331.66
c $2,625.00
d $3316.62

Answers

Answer:

C.

Step-by-step explanation:

The answer is C !!! :)

Pls help I’ll mark brainliest

Answers

Answer:

2=72 4=148  6=222  10=370 15=555 16=592

sorry about the second part i didnt see it

Answer:

148, 3 , 740, 1110, 8.

Step-by-step explanation:

Miles: 148 + 740 + 1,110 = 1,998

Gallons: 2 + 4 + 3 + 10 + 15 + 8 = 42

How do I evaluate this using trigonometric substitution?

∫dx/(81x^2+4)^2

Answers

Answer:

[tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

General Formulas and Concepts:

Alg I

Terms/CoefficientsFactorExponential Rule [Dividing]: [tex]\displaystyle \frac{b^m}{b^n} = b^{m - n}[/tex]

Pre-Calc

[Right Triangle Only] Pythagorean Theorem: a² + b² = c²

a is a legb is a legc is hypotenuse

Trigonometric Ratio: [tex]\displaystyle sec(\theta) = \frac{1}{cos(\theta)}[/tex]

Trigonometric Identity: [tex]\displaystyle tan^2\theta + 1 = sec^2\theta[/tex]

TI: [tex]\displaystyle sin(2x) = 2sin(x)cos(x)[/tex]

TI: [tex]\displaystyle cos^2(\theta) = \frac{cos(2x) + 1}{2}[/tex]

Calc

Integration Rule [Reverse Power Rule]:                                                                [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

IP [Addition/Subtraction]:                                                             [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

U-Substitution

U-Trig Substitution: x² + a²x = atanθ

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int {\frac{dx}{(81x^2 + 4)^2}}[/tex]

Step 2: Identify Sub Variables Pt.1

Rewrite integral [factor expression]:

[tex]\displaystyle \int {\frac{dx}{[(9x)^2 + 4]^2}}[/tex]

Identify u-trig sub:

[tex]\displaystyle x = atan\theta\\9x = 2tan\theta \rightarrow x = \frac{2}{9}tan\theta\\dx = \frac{2}{9}sec^2\theta d\theta[/tex]

Later, back-sub θ (integrate w/ respect to x):

[tex]\displaystyle tan\theta = \frac{9x}{2} \rightarrow \theta = arctan(\frac{9x}{2})[/tex]

Step 3: Integrate Pt.1

[Int] Sub u-trig variables:                                                                                 [tex]\displaystyle \int {\frac{\frac{2}{9}sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                           [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4tan^2\theta + 4]^2}} \ d\theta[/tex][Int] Factor:                                                                                                      [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4(tan^2\theta + 1)]^2}} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4sec^2\theta]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{16sec^4\theta} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{72} \int {\frac{sec^2\theta}{sec^4\theta} \ d\theta[/tex][Int] Divide [ER - D]:                                                                                         [tex]\displaystyle \frac{1}{72} \int {\frac{1}{sec^2\theta} \ d\theta[/tex][Int] Rewrite [TR]:                                                                                            [tex]\displaystyle \frac{1}{72} \int {cos^2\theta} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{1}{72} \int {\frac{cos(2\theta) + 1}{2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{144} \int {cos(2\theta) + 1} \ d\theta[/tex][Int] Rewrite [Int Prop - A/S]:                                                                          [tex]\displaystyle \frac{1}{144} [\int {cos(2\theta) \ d\theta + \int {1} \ d\theta][/tex]  

Step 4: Identify Sub Variables Pt.2

Determine u-sub for trig int:

u = 2θ

du = 2dθ

Step 5: Integrate Pt.2

[Ints] Rewrite [Int Prop - MC]:                                                                       [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {2cos(2\theta) \ d\theta + \int {1 \theta ^0} \ d\theta][/tex][Int] U-Sub:                                                                                                     [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {cos(u) \ du + \int {1 \theta ^0} \ d\theta][/tex][Ints] Integrate [Trig/Int Rule - RPR]:                                                             [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(u) + \theta + C][/tex][Expression] Back Sub:                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(2 \theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Rewrite [TI]:                                                                                           [tex]\displaystyle \frac{1}{144} [\frac{1}{2}(2sin(\theta)cos(\theta)) + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [sin(\theta)cos(\theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Back Sub:                                                                                             [tex]\displaystyle \frac{1}{144} [sin(arctan(\frac{9x}{2}))cos(arctan(\frac{9x}{2})) + arctan(\frac{9x}{2}) + C][/tex]

Step 6: Triangle

Find trig values:

[tex]\displaystyle tan\theta = \frac{9x}{2}[/tex]

[tex]\displaystyle \theta = arctan(\frac{9x}{2})[/tex]

tanθ = opposite / adjacent; solve hypotenuse of right triangle, determine trig ratios:

sinθ = opposite / hypotenuse

cosθ = adjacent / hypotenuse

Leg a = 2

Leg b = 9x

Leg c = ?

Sub variables [PT]:                                                                                         [tex]\displaystyle 2^2 + (9x)^2 = c^2[/tex]Evaluate exponents:                                                                                      [tex]\displaystyle 4 + 81x^2 = c^2[/tex][Equality Property] Square root both sides:                                                  [tex]\displaystyle \sqrt{4 + 81x^2} = c[/tex]Rewrite:                                                                                                           [tex]c = \sqrt{81x^2 + 4}[/tex]

Substitute into trig ratios:

[tex]\displaystyle sin\theta = \frac{9x}{\sqrt{81x^2 + 4}}[/tex]

[tex]\displaystyle cos\theta = \frac{2}{\sqrt{81x^2 + 4}}[/tex]

Step 7: Integrate Pt.3

[Exp] Sub variables [TR]:                                                                               [tex]\displaystyle \frac{1}{144} [\frac{9x}{\sqrt{81x^2 + 4}} \cdot \frac{2}{\sqrt{81x^2 + 4}} + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{18x}{81x^2 + 4} + arctan(\frac{9x}{2}) + C][/tex][Exp] Distribute:                                                                                             [tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

How many grams of aluminum hydroxide are produced when 8 moles of aluminum sulfite react in excess sodium hydroxide ?

Answers

Answer:

Number of moles Aluminium sulfide

1 mole of sulfide contains 150 g

Therefore; 16.2/150  

              = 0.108 moles  

The mole ratio of Al2S3 : Al(OH)3 is 1:2

Therefore; moles of Aluminium hydroxide will be;

 = (0.108 × 2)

 = 0.216 moles  

But, 1 mole of  Al(OH)3 contains 77 g

Therefore, the mass of aluminium hydroxide is

  0.216 moles × 77

=  16.632 g

Step-by-step explanation:

please answer
traveling with the current a certain boat went 24 km/h. Against the same current it only went 2 km/h. Find the current and the speed of the boat if there were no current. ​

Answers

Answer:

Current= 13

Speed= 11

Step-by-step explanation:

Let x represent the speed of the boat

Ley y represent the rate of current

x + y= 24......equation 1

x - y= 2...........equation 2

Using elimination method

x + y= 24

+

x - y= 2

2x = 26

x = 26/2

x = 13

Sub 13 for x in equation 1

x + y= 24

13 + y = 24

y = 24-13

y = 11

Hence the current and speed of the boat when there were no current are 11 and 13 respectively

For the geometric sequence, find the sum of the specified number of terms.
The first 8 terms of 4, -12, 36, ...
S8=

Answers

Given:

The geometric sequence is

[tex]4, -12, 36,...[/tex]

To find:

The sum of first 8 terms of the given geometric sequence.

Solution:

We have,

[tex]4, -12, 36,...[/tex]

Here, the first term is 4 and the common ratio is

[tex]r=\dfrac{-12}{4}[/tex]

[tex]r=-3[/tex]

The sum of first n terms of a geometric sequence is

[tex]S_n=\dfrac{a(r^n-1)}{r-1}[/tex]

Where, a is the first term and r is the common ratio.

Putting n=8, a=4 and r=-3, we get

[tex]S_8=\dfrac{4((-3)^8-1)}{-3-1}[/tex]

[tex]S_8=\dfrac{4(6561-1)}{-4}[/tex]

[tex]S_8=-6560[/tex]

Therefore, the sum of first 8 terms is -6560.

fill 1 ⅕ bottles with 3 liters of water. How many liters of water fill 1 bottle?

Answers

Answer: It would be  2 1/2 liters

Step-by-step explanation:

There can be 2 and a half litres of water will be filled in 1 bottle.

What is division?

Division is breaking a number up into an equal number of parts.

Given that,  3 litres of water can fill 1 ⅕ bottles,

Since, there are 3 litres in 6/5 bottles

so, 1 litre = 6/5×3 = 2 ¹/₂

Hence, There can be 2 and a half litres of water will be filled in 1 bottle.

For more references on division, click;

https://brainly.com/question/21416852

#SPJ2

Multiplying by which number is equivalent to a decrease of 8.2%?

Answers

1 - 0.082 = 0.918
Multiply by 0.918

Math please help ASAP

Answers

Answer:

11

Step-by-step explanation:

i don't know

Paisley works on her drawings for 2 hours. She spends 1/6 hour on each drawing. How many drawings does she work on in 2 hours? HELP FAST!!!!

Answers

Answer:

1/12

Step-by-step explanation:

1/6 divided by 2 = 1/12

What is - or how do you find answer to:
12 1/2 - (-4 1/2) =

Answers

Answer:

8

Step-by-step explanation:

12 times 1/2=6

(-4(1/2))= -2

6-(-2)

6+2

=8

PLS HELP!!!! :))) BDHDHSJWJDJD

Answers

Answer:

Your answer is "H"

Step-by-step explanation:

The answer is the answer is H

5 × 3/2, but the answer as a fraction ​

Answers

Answer:

15/2

Step-by-step explanation:

5/1 * 3/2 = 15/2

Answer please.....
Thanks!!!!

Answers

a. x= 11/5
b. x= 6
c. x= -12/2
d. x= 6/5

A 12-pack of soda costs $10.08 and a 6-pack of the same soda cost $5.34. Which is
the better buy?

Answers

Answer:

the twelve pack

Step-by-step explanation:

12 pack = $10.08 if u get the 6 pack for $5.34 and want to buy two pack it equals $10.68 if you want to save change buy the 12 pack

The 6 pack is the better buy because the cost per soda would be about $1.12, vs with the 12 pack the cost per soda would be about $1.19

Please answer ASAP!

Which proportional relationship has the greatest rate of change?

Answers

Answer:

Option (1)  ;   y = 7x

Step-by-step explanation:

(1) reads y = 7x, a line with slope 7, therefore the rate of change in this is 7

(2) says that y increases 12 units every time that x increases 4 Then the rate of change is: (increase in y / increase in x = 12/4 =3

(3) shows a table from which we can see that an increase of y in 8 corresponds to an increase of x in 2:  rate of change = (8 - 0) , (2 - 0) = 4

(4) shos a line with slope (rate of change) given by:  (12 - 0) / (2 - 0) = 12/2 = 6

Therefore, the greatest rate of change is shown by the first expression  

y = 7 x

the area of a certain desert is nine times the area of another desert. if the sum of their areas is 30,000,000 sq miles. find the area of each. ​

Answers

So the sum of both deserts is 30000000 and one is 9 times more than the other, it’s a 1:9 ratio. 9+1 is ten and 30000000/10 is 3,000,000. That’s the area of the smaller desert. You multiply 3 million by 9 and get 27,000,000 sq miles for the larger desert. Hope that makes some sense! :)

X/4-5>-4 what is this please help

Answers

Answer:

4

Step-by-step explanation:

44 yeah yeah what about the other

To make concrete Tyler mixes 55 kilograms of gravel wit 11 kilograms of cement how many kilograms of gravel does Tyler need for each kilogram of cement

Answers

Answer:

5 kilos

Step-by-step explanation:

55:11

5:1 ratio

A white-tailed deer is running from a black bear at 20 miles per hour. It is 1/3 miles in front of the bear. The bear is running at 30 miles per hour. How many minutes will it take the bear to catch the deer? Assume both continue running at a constant pace.

Answers

Answer:

Step-by-step explanation:

d=20t+1/3, b=30t

20t+1/3=30t

10t=1/3

t=1/30 hr

t=(1/30)60=2 min

78.84 is what percent of 292?
Pleasee

Answers

Answer:

230.2128. Im pretty sure

Step-by-step explanation:

Answer:

27%

Step-by-step explanation:

The perimeter of a rectangular e room is 24 feet. Twice the length
decreased by three times the width is 4 feet. What are the dimensions e of
thg room?

Please help me

Answers

Answer:

i am gessing to divide

Step-by-step explanation:

What quadrilateral's diagonals are perpendicular and they bisect each other?

Answers

Answer:

Rhombus

Step-by-step explanation:

The diagonals of Rhombus bisect each other and form 4 right triangles. Since they are right triangles, they measure 90 degrees so the diagonals are perpendicular.

1. -3(-2-4-0)+3-(3-5-7)=

Answers

Answer: The answer is 18

Answer:

[tex] - 3 + 5 + 7 - 18 + 36 \\ - 3 + 12 - 18 + 36 \\ - 21 + 36 \\ = 15 \: \: \: ans.[/tex]

I Need Help Giving Out 10 points! Plz Help

Answers

Answer:

b and d

Step-by-step explanation:

Tyler has $125.00 to spend on books and CDs. He buys one book for $30.00. He wants to spend the rest on CDs that are on sale for $9.00 each. Which of these statements is true?
Group of answer choices

He can't buy any CDs.
He can buy 11 CDs.
He can buy 10 CDs.
He can buy more than 11 CDs.

Answers

Answer:

He can buy 10 cds

Step-by-step explanation:

125-30=95

95 divided by 9 = 10.5555555556

This figure consists of a rectangle and semicircle. What is the perimeter of this figure? Use 3.14 for pi.


Answers

Answer: 36.56

Step-by-step explanation:

A plane travels 1820 meters at a speed of 260 m/sec. How long did it
take to reach its destination? PLEASE HELP!

Answers

Answer:

7 seconds

Step-by-step explanation:

1820/260=7.

Answer:

7m/sec

Step-by-step explanation:

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