What is the side length of the smaller square plate on which 36 CM chopstick can fit along a diagonal without any overhang

Answer:

153.86

Step-by-step explanation:

formula - πr²

= 3.14 * 7²

= 153.86

Answer:

Step-by-step explanation:

you have to use trigonometric functions

cos 30 = adj. /hyp.

cos 30 = 12 / y

y = 12/cos 30 ≅13.86

tan 30 = opp./adj

tan30 = x / 12

x = 12 tan30 ≅6.93

Answer:

both jars contain 12 marbles

for the first jar the probability is 4/12 which is 33%

for the second jar the probability is 6/12 which is 50%

Step-by-step explanation:

Answer:

1/6

Step-by-step explanation:

theres 12 mables in each jar in this situation.

Answer:

A

Step-by-step explanation:

It is A. The problem asks for the interval when the marlin's height is always increasing. Therefore, you want to look at the left half of the parabola, as the line is going into the peak. The right half is declining. The peak is at around 2 (on the x-axis), so you know that the ending interval number has to be 2. The marlin's height begins to go up starting at 0, so the interval is 0 <= x <= 2. Any number past two is a declining height, and the increase starts at 0.

Answer:

C

Step-by-step explanation:

equations for each:

A)  y - x = 25

B)  y = 25x

C)  x = 25y

D)  y = 25 + x

Answer:

Its A for the function that represents the geomertric sequence

Answer:

[tex]1/2y - 21/4 = -35/4[/tex]

[tex]1/2y = 21/4 -35/4[/tex]

[tex]1/2y = - 7/4[/tex]

[tex]y = - \frac{7}{2} [/tex]

Answer:

Amanda > Todd > Derrick

Step-by-step explanation:

Amanda's IQR- 3.5

Derrick's IQR- 2

Todd's IQR- 3

The solution is, ordering the IQR in descending order :

Emma, Sally, Olivia

The interquartile range (IQR) contains the second and third quartiles, or the middle half of your data set. Whereas the range gives you the spread of the whole data set, the interquartile range gives you the range of the middle half of a data set.

here, we have,

Writing out the points obtained from the dot plot, and applying the relevant formula, the Interquartile range of each dot plot is given below ;

Writing out each score on the dot plot to calculate the statistical values :

Emma's Scores:

6 , 7 , 8 , 8 , 9 , 9 , 9 , 10 , 10 , 11 , 11 , 11 , 11 , 11 , 12 , 13 , 13 , 13 , 13 , 14

Q1 = 1/4(n+1)th term

Q1 = (5th + 6th) terms

Q1 = (9 + 9) / 2 = 9

Q3 = 3/4(n+)th term

Q3 = (12 + 13) ÷ 2 = 12.5

IQR = Q3 - Q1

IQR = 12.5 - 9 = 3.5

Sally's Scores:

6 , 6 , 6 , 7 , 7 , 8 , 8 , 8 , 9 , 9 , 10 , 10 , 10 , 10 , 10 , 10 , 11 , 11 , 12 , 12 , 14

Q1 = 1/4(n+1)th term

Q1 = (7 + 8) ÷ 2 = 7.5

Q3 = 3/4(n+1)th term

Q3 = (10 + 11) ÷ 2 = 10.5

IQR = Q3 - Q1

IQR = 10.5 - 7.5 = 3

Olivia's Scores:

6 , 6 , 7 , 7 , 7 , 8 , 8 , 8 , 8 , 9 , 9 , 9 , 9 , 9 , 10 , 10 , 12 , 12 , 13 , 14

Q1 = 1/4(n+1)th term

Q1 = (7 + 8) ÷ 2 = 7.5

Q3 = 1/4(n+1)th term

Q3 = (10 + 10) ÷ 2 = 10

IQR = Q3 - Q1

IQR = 10 - 7.5 = 2.5

Therefore, ordering the IQR in descending order :

Emma, Sally, Olivia

Learn more on IQR :

brainly.com/question/18006476

#SPJ3

complete question:

Drag each tile to the correct box.

Emma, Sally, and Olivia play for the school basketball team. The dot plots show the number of points each of them scored in 20 games.

Find the interquartile range, IQR, for each dot plot. Then, place the basketball players in order from greatest to least IQR.

Answer:

[tex]16[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 8x + c[/tex]

[tex] {x}^{2} + c - 8x[/tex]

To find the c value [tex]c = ( \frac{b}{2})^{2} [/tex] , divide the coefficient of x by 2 and square the result.

[tex]( - 1 \times 4 {)}^{2} [/tex]

[tex]( - 4 {)}^{2} [/tex]

[tex]16[/tex]

Answer:

3

Step-by-step explanation:

Answer:

2 tickets

Step-by-step explanation:

a + c = 5

9a + 4c = 30

let a = 5-c

substitute:

9(5-c) + 4c = 30

45 - 9c + 4c = 30

45 - 5c = 30

-5c = -15

c = 3

a = 2

Answer:

1.73 units

Step-by-step explanation:

The area of a triangle with sides a, b, c and angles A, B, C is given as

Area = 1/2 bc sin A

Given that b=4, c=1, A=120° for a triangle with sides a, b, c and angles A, B, C then the area

= 1/2 * 4 * 1 * sin 120

= 2 sin 120

= 2 * √3/2

= √3

= 1.732

To the nearest hundredth = 1.73

Answer:

B and C

if n=3 then 5ⁿ=5³=5×5×5=125

n³=3³=3×3×3=27

hope it helps :)