Answer:
Explanation:
Machine learning is a branch of artificial intelligence (AI) and computer science which focuses on the use of data and algorithms to imitate the way that humans learn, gradually improving its accuracy.
Answer:
Machine learning is a type of learning that makes learning easy and faster with the help of electrical devices such as mobile phones,laptops etc
Explanation:
This enable the user to work faster and easily with no stress at all
Java 2D Drawing Application. The application will contain the following elements:
a) an Undo button to undo the last shape drawn.
b) a Clear button to clear all shapes from the drawing.
c) a combo box for selecting the shape to draw, a line, oval, or rectangle.
d) a checkbox which specifies if the shape should be filled or unfilled.
e) a checkbox to specify whether to paint using a gradient.
f) two JButtons that each show a JColorChooser dialog to allow the user to choose the first and second color in the gradient.
g) a text field for entering the Stroke width.
h) a text field for entering the Stroke dash length.
I) a checkbox for specifying whether to draw a dashed or solid line.
j) a JPanel on which the shapes are drawn.
k) a status bar JLabel at the bottom of the frame that displays the current location of the mouse on the draw panel.
If the user selects to draw with a gradient, set the Paint on the shape to be a gradient of the two colors chosen by the user. If the user does not chosen to draw with a gradient, the Paint with a solid color of the 1st Color.
Note: When dragging the mouse to create a new shape, the shape should be drawn as the mouse is dragged.
Answer:
sadness and depression is my answer
Explanation:
In a spreadsheet what does the following symbol mean?
$
Answer:
$ = dollar sign
Explanation:
In a spreadsheet, the $ symbol is the symbol of the dollar. The dollar is the currency of the United States.
What is currency?Currency is a form of payment for goods and services. In a nutshell, it is money in the form of paper and coins that is usually issued by a government and is generally accepted as a form of payment at face value.
Currency exchange rates differ between businesses because each one distorts the interbank rate to maximize profits. We encounter numerous competitors who post interbank rates internet as bait to attract new customers, but once the customers are onboard, they drastically change the rate, typically not in the customers' favor.
Therefore, the $ symbol represents the dollar in a spreadsheet. The US dollar is the country's currency.
To learn more about a dollar, refer to the below link:
https://brainly.com/question/23899116
#SPJ2
What is the problem with paying only your minimum credit card balance each month?
A. It lowers your credit score
B. You have to pay interest
C. The bank will cancel your credit card
D. All of the above
Answer:b
Explanation:
Answer: The answer is B.
Explanation: While yes it is important to make at least the minimum payment, its not ideal to carry a balance from month to month (You'll rack up interest charges). And risk falling into debt. Therefore, the answer is B.
Hope this helps!
Write a function to calculate the distance between two points Distance( x1, y1,x2.2) For example Distance(0.0,3.0, 4.0.0.0) should return 5.0 Use the function in main to loop through reading in pairs of points until the all zeros are entered printing distance with two decimal precision for each pair of points.
For example with input
32 32 54 12
52 56 8 30
44 94 4439 6
5 19 51 91 7.5
89 34 0000
Your output would be:__________.
a. 29.73
b. 51.11
c. 55.00
d. 73.35
e. 92.66
Answer:
The function in Python3 is as follows
def Distance(x1, y1, x2, y2):
dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5
return dist
Explanation:
This defines the function
def Distance(x1, y1, x2, y2):
This calculates distance
dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5
This returns the calculated distance to the main method
return dist
The results of the inputs is:
[tex]32, 32, 54, 12 \to 29.73[/tex]
[tex]52,56,8,30 \to 51.11[/tex]
[tex]44,94,44,39\to 55.00[/tex]
[tex]19,51,91,7.5 \to 84.12[/tex]
[tex]89,34,00,00 \to 95.27[/tex]
A "Pythagorean Triple" is a set of integers which will make the sides of a right triangle when used in the calculation of Pythagoras’ Theorem. For example, "3, 4, 5" is a Pythagorean Triple. Write a short "C" function that takes three decimal integers and determines if they are a "Pythagorean Triple". The function should return a boolean which is true if the three numbers fit the pattern, and false otherwise. DO NOT write a "main()" method in this code! [15 pts.]
Answer:
The function in C is as follows:
bool checkPythagoras(int a, int b, int c ){
bool chk = false;
if(a*a == b*b + c*c || b*b == a*a + c*c || c*c == b*b + a*a){
chk = true;
}
return chk;
}
Explanation:
This defines the function. It receives three integer parameters a, b and c
bool checkPythagoras(int a, int b, int c ){
This initializes the return value to false
bool chk = false;
This checks if the three integers are Pythagorean Triple
if(a*a == b*b + c*c || b*b == a*a + c*c || c*c == b*b + a*a){
If yes, the return value is updated to true
chk = true;
}
This returns true or false
return chk;
}
New cars use embedded computers to make driving safer
Answer:
true.......................
New cars use embedded computers to make driving safer. The given statement is true.
What is RAM?
The word RAM stands for random-access memory and it is known as memory of short term where data is stored and as required by the processor. This is not there to deal with long term data and it is working after the computer turned off.
Generally, there are three types of RAM and these are SRAM, ECC, and DRAM. The SRAM stands for static random memory, and DRAM stands for dynamic access memory.
CPU stands for central processing unit and commonly it is known as brain of the computer, the main function of CPU is to control the function of the computer or system and it gives command to the parts of computer.
Therefore, New cars use embedded computers to make driving safer. The given statement is true.
Learn more about RAM and CPU here:
brainly.com/question/21252547
#SPJ2
Describing How to Insert a Subdatasheet
Use the drop-down menus to complete the steps for inserting a subdatasheet.
1. Open a table in Design view.
2. Click the
v tab, and in the Records group, click
3. In the drop-down menu, select Subdatasheet.
4. In the Insert Subdatasheet dialog box, select the table you want and click
5. If there is no relationship between the tables, you can
one.
Ve
Answer:
1. Home
2. More
4. Ok
5. Create
Explanation:
Answer:
1. insert
2. smartart
3. OK
4. close
Explanation:
The speed density fuel injection system uses the blank sensor as the primary sensor as the primary sensor to determine base pulse width
A. Map
B TP
C Maf
D baro
Answer:
A) Map
Explanation:
All gasoline (petrol) fuel systems need ways or method that will be calculating amount of the air that is entering the engine.This is true as regards mechanical fuel injection, carburetors and electronic fuel injection.Speed density system fall under one of this method. "Speed" in this context means the speed of the engine while "density" means density of the air. The Speed is been measured using the distributor, crankshaft position sensor could be used here. The Density emerge from from measuring of the air pressure which is inside the induction system, using a typical "manifold absolute pressure" (MAP) sensor as well as air temperature sensor. Using pieces of information above, we can calculate
mass flow rate of air entering the engine as well as the correct amount of fuel can be supplied. With this system,
the mass of air can be calculated. One of the drawback if this system is that
Any modification will result to incorrect calculations. Speed-Density can be regarded as method use in estimation of airflow into an engine so that appropriate amount of fuel can be supplied as well as. adequate spark timing. The logic behind Speed-Density is to give prediction of the amount of air ingested by an engine accurately during the induction stroke. Then this information could now be used in calculating how much fuel is required to be provided, This information as well can be used in determining appropriate amount of ignition advance. It should be noted The speed density fuel injection system uses the Map sensor as the primary sensor to determine base pulse width
c Write a program that simulates a magic square using 3 one dimensional parallel arrays of integer type. Each one the arrays corresponds to a row of the magic square. The program asks the user to enter the values of the magic square row by row and informs the user if the grid is a magic square or not. flowchart
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
In numerical methods, one source of error occurs when we use an approximation for a mathematical expression that would otherwise be too costly to compute in terms of run-time or memory resources. One routine example is the approximation of infinite series by a finite series that mostly captures the important behavior of the infinite series.
In this problem you will implement an approximation to the exp(x) as represented by the following infinite series,
exp(x) = Infinity n= 0 xn/xn!
Your approximation will be a truncated finite series with N + 1 terms,
exp(x, N) = Infinityn n = 0 xn/xn!
For the first part of this problem, you are given a random real number x and will investigate how well a finite series expansion for exp(x) approximates the infinite series.
Compute exp(x) using a finite series approximation with N E [0, 9] N (i.e. is an integer).
Save the 10 floating point values from your approximation in a numpy array named exp_approx. exp_approx should be of shape (10,) and should be ordered with increasing N (i.e. the first entry of exp_approx should correspond to exp(x, N) when N = 0 and the last entry when N = 9).
Answer:
The function in Python is as follows:
import math
import numpy as np
def exp(x):
mylist = []
for n in range(10):
num = (x**n)/(math.factorial(n))
mylist.append([num])
exp_approx = np.asarray(mylist)
sum = 0
for num in exp_approx:
sum+=num
return sum
Explanation:
The imports the python math module
import math
The imports the python numpy module
import numpy as np
The function begins here
def exp(x):
This creates an empty list
mylist = []
This iterates from 0 to 9
for n in range(10):
This calculates each term of the series
num = (x**n)/(math.factorial(n))
This appends the term to list, mylist
mylist.append([num])
This appends all elements of mylist to numpy array, exp_approx
exp_approx = np.asarray(mylist)
This initializes the sum of the series to 0
sum = 0
This iterates through exp_approx
for num in exp_approx:
This adds all terms of the series
sum+=num
This returns the calculated sum
return sum
What are 3 data Gathering method that you find effective in creating interactive design for product interface and justify your answer?
Answer:
In other words, you conducted the four fundamental activities that make up the interaction design process – establishing requirements, designing alternatives, prototyping designs, and evaluating prototypes.
Explanation:
PLEASE HELP ME ASAP!!!!
Uhh... What is happening?.. What...
Answer:
the Redstone underneath is activating the piston
Answer:
lever under each piston
What is up with the bots? They are so annoying.
Answer:
very very very annoying
Answer:
yeah
Explanation:
For this assignment your are to implement the Pet Class described in Programming Exercise 1, starting on page 494 in our textbook. Additionally your program will allow users to enter the pet's information until the user enters in the string "quit". Once the user enters quit the program will print out a summary of all the information that has been entered. Your program should not assume any maximum number of pets that can be added. Items in blue designate output. Items in red designate computer input. Example Test Case: Enter name, type and age of your pet: Name: Momo Type: Bird Age: 33 Enter "quit" to stop entering. Anything else to continue. a Enter name, type and age of your pet: Name: Pooh Type: Dog Age: 8 Enter "quit" to stop entering. Anything else to continue. quit SUMMARY: Name: Momo, Type: Bird, Age: 33. Name: Pooh, Type: Dog, Age: 8.
Answer:
ohhhvhhffifyuddfuiicfdguc
The given SQL creates a Movie table and inserts some movies. The SELECT statement selects all movies released before January 1, 2000 Modify the SELECT statement to select the title and release date of PG-13 movies that are released after February 1, 2008. Run your solution and verify the result table shows just the titles and release dates for The Dark Knight and Crazy Rich Asians. 3 6 1 CREATE TABLE Movie ( 2 ID INT AUTO_INCREMENT, Title VARCHAR(100), 4 Rating CHAR(5) CHECK (Rating IN ('G', 'PG', 'PG-13', 'R')), 5 ReleaseDate DATE, PRIMARY KEY (ID) 7); 8 9 INSERT INTO Movie (Title, Rating, ReleaseDate) VALUES 19 ('Casablanca', 'PG', '1943-01-23'), 11 ("Bridget Jones's Diary', 'PG-13', '2001-04-13'), 12 ('The Dark Knight', 'PG-13', '2008-07-18'), 13 ("Hidden Figures', 'PG', '2017-01-06'), 14 ('Toy Story', 'G', '1995-11-22'), 15 ("Rocky', 'PG', '1976-11-21'), 16 ('Crazy Rich Asians', 'PG-13', '2018-08-15'); 17 18 -- Modify the SELECT statement: 19 SELECT * 20 FROM Movie 21 WHERE ReleaseDate < '2000-01-01'; 22
Answer:
The modified SQL code is as follows:
SELECT Title, ReleaseDate FROM movie WHERE Rating = "PG-13" and ReleaseDate > '2008-02-01'
Explanation:
The syntax of an SQL select statement is:
SELECT c1, c2, c...n FROM table WHERE condition-1, AND/OR condition-n
In this query, we are to select only the title and the release date.
So, we have:
SELECT Title, ReleaseDate
The table name is Movie.
So, we have:
SELECT Title, ReleaseDate FROM movie
And the condition for selection is that:
Ratings must be PG-13
And the date must be later than February 1, 2008
This implies that:
Rating = "PG-13"
ReleaseDate > '2008-02-01'
So, the complete query is:
SELECT Title, ReleaseDate FROM movie WHERE Rating = "PG-13" and ReleaseDate > '2008-02-01'
Understanding Join Types
Which join type will only include rows where the joined fields from both tables are equal?
O inner join
O left outer join
Oright inner join
O right outer join
Answer: inner join
Explanation:Edg. 2021
spreadsheet formula for total 91?
Answer:
Go to any blank cell. Enter the number 91.
Select the cell that contains 91. Press Ctrl+C to copy.
Select your range the contains numbers.
Press Ctrl+Alt+V to open the Paste Special dialog.
In the top of the Paste Special dialog, choose Values. In the Operation section, choose Add. Click OK.
Explanation:
Using a text editor, create a file that contains a list of at least 15 six-digit account numbers. Read in each account number and display whether it is valid. An account number is valid only if the last digit is equal to the remainder when the sum of the first five digits is divided by 10. For example, the number 223355 is valid because the sum of the first five digits is 15, the remainder when 15 is divided by 10 is 5, and the last digit is 5. Write only valid account numbers to an output file, each on its own line. Save the application as ValidateCheckDigits.java.
Answer:
Explanation:
The following code is written in Java. It reads every input and checks to see if it is valid. If it is it writes it to the output file.
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
try {
File myObj = new File("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/input.txt");
Scanner myReader = new Scanner(myObj);
FileWriter myWriter = new FileWriter("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/output.txt");
while (myReader.hasNextLine()) {
String data = myReader.nextLine();
int sum = 0;
for (int x = 0; x < 5; x++ ) {
sum += data.charAt(x);
}
int remainder = (sum % 10);
System.out.println(remainder);
System.out.println(data.charAt(5));
if (remainder == Integer.parseInt(String.valueOf(data.charAt(5)))) {
System.out.println("entered");
try {
myWriter.write(data + "\n");
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
sum = 0;
}
myWriter.close();
myReader.close();
} catch (FileNotFoundException e) {
System.out.println("An error occurred.");
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Can you debug the following code using the given test code?public class SavingAccount{ // interest rate for all accounts private static double annualInterestRate = 0; private final double savingsBalance; // balance for currrent account // constructor, creates a new account with the specified balance public void SavingAccount( double savingsBalance ) { savingsBalance = savingsBalance; } // end constructor // get monthly interest public void calculateMonthlyInterest() { savingsBalance += savingsBalance * ( annualInterestRate / 12.0 ); } // end method calculateMonthlyInterest // modify interest rate public static void modifyInterestRate( double newRate ) { annualInterestRate = ( newRate >= 0 && newRate <= 1.0 ) ? newRate : 0.04; } // end method modifyInterestRate // get string representation of SavingAccount public String toString() { return String.format( "$%.2f", savingsBalance ); } // end method toSavingAccountString} // end class SavingAccount Using this test codepublic class SavingAccountTest{ public static void main(String[] args) { SavingAccount s1 = new SavingAccount(400); SavingAccount s2 = new SavingAccount(1000); SavingAccount.modifyInterestRate(0.05); System.out.printf("SavingAccount 1 is: %s\nSavingAccount 2 is: %s\n", s1, s2); s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest(); System.out.printf("\nSavingAccount 1 after the interest is: %s\nSavingAccount 2 after the interest is: %s\n", s1, s2); SavingAccount.modifyInterestRate(.025); s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest(); System.out.printf("\nSavingAccount 1 after the new interest is: %s\nSavingAccount 2 after the new interest is: %s\n", s1, s2); }}
Answer:
Explanation:
The reason the code was not working was due to a couple of errors. First, the SavingAccount class needed to be public so that it can be accessed within the same file. Secondly, the savingsBalance variable was set to final and therefore could not be modified, the final keyword needed to be removed. Lastly, the constructor for the SavingAccount class was incorrect. Constructors do not use the keyword void and instance class variables need to be referenced using the this keyword.
class SavingAccount{
// interest rate for all accounts
private static double annualInterestRate = 0;
private double savingsBalance;
public SavingAccount(double savingsBalance) {
this.savingsBalance = savingsBalance;
}
public void calculateMonthlyInterest() {
savingsBalance += savingsBalance * ( annualInterestRate / 12.0 );
}// end method calculateMonthlyInterest
// modify interest rate
public static void modifyInterestRate( double newRate ) {
annualInterestRate = ( newRate >= 0 && newRate <= 1.0 ) ? newRate : 0.04;
} // end method modifyInterestRate
// get string representation of SavingAccount
public String toString() { return String.format( "$%.2f", savingsBalance );
} // end method toSavingAccountString
}// end class SavingAccount
// Using this test codepublic
//
class SavingAccountTest{
public static void main(String[] args) {
SavingAccount s1 = new SavingAccount(400);
SavingAccount s2 = new SavingAccount(1000);
SavingAccount.modifyInterestRate(0.05);
System.out.printf("SavingAccount 1 is: %s\nSavingAccount 2 is: %s", s1, s2);
s1.calculateMonthlyInterest(); s2.calculateMonthlyInterest();
System.out.printf("\nSavingAccount 1 after the interest is: %s\nSavingAccount 2 after the interest is: %s", s1, s2);
SavingAccount.modifyInterestRate(.025);
s1.calculateMonthlyInterest();
s2.calculateMonthlyInterest();
System.out.printf("\nSavingAccount 1 after the new interest is: %s\nSavingAccount 2 after the new interest is: %s", s1, s2); }}
First one who answers gets brainiest
Answer:
thank for the point anyway
Working with do-while loop
Bring the program dowhile.cpp from the Lab 5 folder.
The code is shown below:
______________________________________________________________________________
// This program displays a hot beverage menu and prompts the user to
// make a selection. A switch statement determines which item the user
// has chosen. A do-while loop repeats until the user selects item E
// from the menu.
// PLACE YOUR NAME HERE
#include
#include
using namespace std;
int main()
{
// Fill in the code to define an integer variable called number,
// a floating point variable called cost,
// and a character variable called beverage
bool validBeverage;
cout << fixed << showpoint << setprecision(2);
do
{
cout << endl << endl;
cout << "Hot Beverage Menu" << endl << endl;
cout << "A: Coffee $1.00" << endl;
cout << "B: Tea $ .75" << endl;
cout << "C: Hot Chocolate $1.25" << endl;
cout << "D: Cappuccino $2.50" << endl <
cout << "Enter the beverage A,B,C, or D you desire" << endl;
cout << "Enter E to exit the program" << endl << endl;
// Fill in the code to read in beverage
switch(beverage)
{
case 'a':
case 'A':
case 'b':
case 'B':
case 'c':
case 'C':
case 'd':
case 'D': validBeverage = true;
break;
default: validBeverage = false;
}
if (validBeverage == true)
{
cout << "How many cups would you like?" << endl;
// Fill in the code to read in number
}
// Fill in the code to begin a switch statement
// that is controlled by beverage
{
case 'a':
case 'A': cost = number * 1.0;
cout << "The total cost is $ " << cost << endl;
break;
// Fill in the code to give the case for tea ( $0.75 a cup)
//Fill in the code to give the case for hot chocolate($1.25 a cup)
// Fill in the code to give the case for cappuccino ($2.50 a cup)
case 'e':
case 'E': cout << " Please come again" << endl;
break;
default:cout << // Fill in the code to write a message
// indicating an invalid selection.
cout << " Try again please" << endl;
}
} // Fill in the code to finish the do-while statement with the
// condition that beverage does not equal (E or e).
// Fill in the appropriate return statement
}
Answer:
it throws an error with the includes.
and some undeclared variables.
Explanation:
please fix that.
Python The Sieve of Eratosthnes Prgram
A prime integer is any integer greater than 1 that is evenly divisible only by itself and 1. The Sieve of Eratosthenes is a method of finding prime numbers. It operates as follows:
Create a list with all elements initialized to 1 (true). List elements with prime indexes will remain 1. All other elements will eventually be set to zero.
Starting with list element 2, every time a list element is found whose value is 1, loop through the remainder of the list and set to zero every element whose index is a multiple of the index for the element with value 1. For list index 2, all elements beyond 2 in the list that are multiples of 2 will be set to zero (indexes 4, 6, 8, 10, etc.); for list index 3, all elements beyond 3 in the list that are multiples of 3 will be set to zero (indexes 6, 9, 12, 15, etc.); and so on.
When this process is complete, the list elements that are still set to 1 indicate that the index is a prime number. These indexes can then be printed. Write a program that uses a list of 1000 elements to determine and print the prime numbers between 2 and 999. Ignore element 0 of the list. The prime numbers must be printed out 10 numbers per line.
Sample Executions:
Prime numbers between 2 and 999 as determined by the Sieve of Eratosthenes.
2 357 11 13 17 19 23 29
31 37 41 43 47 53 59 61 67 71
73 79 83 89 97 101 103 107 109 113
127 131 137 139 149 151 157 163 167 173
179 181 191 193 197 199 211 223 227 229
233 239 241 251 257 263 269 271 277 281
283 293 307 311 313 317 331 337 347 349
353 359 367 373 379 383 389 397 401 409
419 421 431 433 439 443 449 457 461 463
467 479 487 491 499 503 509 521 523 541
547 557 563 569 571 577 587 593 599 601
607 613 617 619 631 641 643 647 653 659
661 673 677 683 691 701 709 719 727 733
739 743 751 757 761 769 773 787 797 809
811 821 823 827 829 839 853 857 859 863
877 881 883 887 907 911 919 929 937 941
947 953 967 971 977 983 991 997
Answer:
try this
Explanation:
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p +=1
c=0
for p in range(2, n):
if prime[p]:
print(p," ",end=" ")
c=c+1
if(c==10):
print("")
c=0
n= 1000
print("prime number between 2 to 999 as determined by seive of eratostenee ")
SieveOfEratosthenes(n)
free pass if you want it.
Answer:
yuh
Explanation:
Answer:
thank youuuu!
Explanation:
have a great day!!
Write the MIPS assembly code to find the area of a given shape. Your program must take a floating-point value and shape (Circle - 1, Triangle - 2, Square - 3) as input and return the circumference/perimeter and area of the shape. Assume the floating-point value units are meters and the triangle is an equilateral triangle. [Note: you can search for the expression to calculate the area and circumference/perimeter of these shapes]
Answer:
Explanation:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number
syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4
la $a0,msg2 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer
syscall # call operating system to perform read operation
move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi
l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4
la $a0,msg3 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg6
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,eq_tr_area
mul.s $f2,$f0,$f0
mul.s $f2,$f2,$f3
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
ELSE:
bne $t0,3,END
li $v0,4
la $a0,msg10
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,four
mul.s $f3,$f3,$f0
li $v0, 2
mov.s $f12,$f3
syscall
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg11
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
mul.s $f2,$f0,$f0
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
END:
li $v0,10
syscall
Code is as follows:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4 la $a0,msg2 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer syscall # call operating system to perform read operation move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2 mov.s $f12,$f0 #move the single precision f2 in f12 syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4 la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4 la $a0,msg3 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall
bne $t0,3,END #if not 3 then end
li $v0,4 # system call code for printing string = 4
la $a0,msg10 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f0 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,four # multilply by 4
mul.s $f3,$f3,$f0 #calculate 4*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f3 in f12
syscall # call operating system to perform print operation
END:
li $v0,10 # system call code for printing exit (end of program)
syscall # call operating system to perform print operation
Learn More:https://brainly.com/question/10169933
We can cluster in one dimension as well as in many dimensions. In this problem, we are going to cluster numbers on the real line. The particular numbers (data points) are 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100, i.e., the squares of 1 through 10. We shall use a k-means algorithm, with two clusters. You can verify easily that no matter which two points we choose as the initial centroids, some prefix of the sequence of squares will go into the cluster of the smaller and the remaining suffix goes into the other cluster. As a result, there are only nine different clusterings that can be achieved, ranging from {1}{4,9,...,100} through {1,4,...,81} {100}. We then go through a reclustering phase, where the centroids of the two clusters are recalculated and all points are reassigned to the nearer of the two new centroids. For each of the nine possible clusterings, calculate how many points are reclassified during the reclustering phase. Identify in the list below the pair of initial centroids that results in exactly one point being reclassified.
a) 36 and 64
b) 36 and 100
c) 4 and 16
d) 4 and 81
The list of the pair of initial centroids that results in exactly one point being reclassified is 36 and 64. The correct option is a.
What is the real line?A real axis, or a line with a set scale so that each real number corresponds to a distinct point on the line, is the most popular definition of "real line." The complex plane is a two-dimensional extension of the real line.
A cluster is a collection or grouping of items in a certain place. Mathematicians define a cluster as data accumulating around a single value, specifically a number. On a table or graph, a cluster can be seen visually where the data points are grouped together.
The numbers are 4, 9, 16, 25, 36, 49, 64, 81, and 100. In the real line, it will be 36 and 64.
Therefore, the correct option is a. 36 and 64.
To learn more about real line, refer to the link:
https://brainly.com/question/19571357
#SPJ2
Use at Least one hundred words to explain what you did the last time your handheld personal computer went slow.
Answer:
Disk defragmentation
clear up storage
restart the computer
Explanation:
PC's going slow is a very common occurence nowadays and what i had to do to usually fix slow computers is to first use disk defragmentation which will automatically sort our files and put them in the right order.Second is to delete any unnessary files,folders,programs that i no longer use or its just sitting there eating dust and finally my last resort is to restart the pc which usually helps fix most of the issues including slow PCs which might be caused by some errors during startup.
Hope this helped
Write a program that reads in a text file, infile.txt, and prints out all the lines in the file to the screen until it encounters a line with fewer than 4 characters. Once it finds a short line (one with fewer than 4 characters), the program stops. Your program must use readline() to read one line at a time. For your testing you should create a file named infile.txt. Only upload your Python program, I will create my own infile.txt using break
Answer:
Explanation:
f=open("infile.txt","r")
flag=True
while(flag):
s=f.readline().strip()
if(len(s)>=4):
print(s)
else:
flag=False
Ill give alot of points if you answer: How do I get a 100 dollar ps4
1) Create a class called Villain. Specifically, a Villain has the following fields: .name (String)
a number of evil plans (int) In addition, a Villain has the following methods: • a constructor that accepts an argument for each of the fields . a copy constructor
an equals method, which checks/returns whether all the fields are the same
a toString method
2) Create a class called Crazy Villain, which inherits from Villain. Specifically, a Crazy Villain has the following additional fields:
a crazy laughter (String)
a crazy idea (String In addition, write code for the following Crazy Villain methods:
a constructor that accepts an argument for each of the fields
a toString method that overrides the Villain toString method, in order to include the additional fields You do not need to instantiate/demo Villain or Crazy Villain objects.
Answer:
Explanation:
The following code is written in Java and creates both of the classes as requested with their variables and methods as needed. The crazyVillain class extends the Villain class and implements and overrides the needed variables and methods. Due to technical reasons, I have added the code as a txt file below.