Answer:
i thank 4 for this players
Question 7(Multiple Choice Worth 1 points)
(01.03 MC)
What is the simplified expression for
4^4•4³
3
4^5
4² is simplified expression for [tex]\frac{4^{4} 4^{3} }{4^{5} }[/tex].
What is Indices?Index (indices) in Maths is the power or exponent which is raised to a number or a variable.
Here, Given expression = [tex]\frac{4^{4} 4^{3} }{4^{5} }[/tex]
[tex]\frac{4^{4} 4^{3} }{4^{5} }[/tex] = [tex]\frac{4^{4+3} }{4^{5} }[/tex]
= 4⁷/4⁵
= 4⁷⁻⁵
= 4²
Thus, 4² is simplified expression for [tex]\frac{4^{4} 4^{3} }{4^{5} }[/tex].
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Find the value of x.
4x = 4
Hint! Remember the Multiplicative
Identity Property.
1.a = a
X = = [?]
Enter the number that belongs in the green box.
Enter
Answer:
x=1
Step-by-step explanation:
4x=4
(Linear equation)
Solved:-
Transpose 4 from LHS to RHS:
[tex] \rm = > x = \tt \cfrac{4}{4} [/tex]
[tex] \rm = > x = \tt1 [/tex]
Does anyone know how to do this
8 3/8 + 3 3/8 + 2 3/8 + 3/8
what is the answer of this ?
The simplification form of the expression 8 3/8 + 3 3/8 + 2 3/8 + 3/8 is 14 whole 1/2 or 14 1/2 after adding all the terms.
What is an arithmetic operation?It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
We have an expression:
[tex]= 8 \dfrac{3}{8} + 3 \dfrac{3}{8} + 2 \dfrac{3}{8} + \dfrac{3}{8}[/tex]
After simplification:
[tex]= \dfrac{67}{8} + \dfrac{27}{8} + \dfrac{19}{8} + \dfrac{3}{8}[/tex]
[tex]= \dfrac{67+27+19+3}{8}[/tex]
= 116/8
= 29/2
[tex]= 14\dfrac{1}{2}[/tex]
Thus, the simplification form of the expression 8 3/8 + 3 3/8 + 2 3/8 + 3/8 is 14 whole 1/2 or 14 1/2 after adding all the terms.
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Answer:
i dont understand your question
Step-by-step explanation:
Solve f (9) for f(x) = -13 + 2x
ƒ(9) = [?]
The value of f(9) for the given function is 5
Evaluating the value of a functionFrom the question, we are to determine the value of f(9)
The given function is
f(x) = -13 + 2x
To determine f(9), we will put x = 9 in the given function
That is,
f(x) = -13 + 2x becomes
f(9) = -13 + 2(9)
f(9) = -13 + 18
f(9) = 5
Hence, the value of f(9) for the given function is 5
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The product of a quarter of 3 more than a number a and two times a number b as an algebraic expression?
Algebraic expression of the product of a quarter of 3 more than a number a and two times a number b is equals to [tex](\frac{3}{4} +a)[/tex]×[tex](2b)[/tex]
What is an algebraic expression?" An algebraic expression is defined as the expression which is represents using variables, number and mathematical operation."
According to the question,
'a' represents a number
'b' represents another number
Algebraic expression as per the given condition we get,
The product of
Quarter of 3 more than a number a = [tex]\frac{3}{4} +a[/tex]
Two times a number b = 2b
Algebraic expression = [tex](\frac{3}{4} +a)[/tex]× [tex](2b)[/tex]
Hence, algebraic expression of the product of a quarter of 3 more than a number a and two times a number b is equals to [tex](\frac{3}{4} +a)[/tex]×[tex](2b)[/tex].
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Simplify the quotient 3-¹ ÷34
Answer:
[tex]\frac{1}{102}[/tex]
Step-by-step explanation:
1) Negative Power Rule: [tex]x}^{-a}=\frac{1}{{x}^{a}}[/tex].
[tex]\frac{1}{3}\div 34[/tex]
2) Use this rule: [tex]a\div \frac{b}{c}=a\times \frac{c}{b}[/tex].
[tex]\frac{1}{3}\times \frac{1}{34}[/tex]
3) Use this rule: [tex]\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}[/tex].
[tex]\frac{1\times 1}{3\times 34}[/tex]
4) Simplify [tex]1\times 1[/tex] to [tex]1[/tex].
[tex]\frac{1}{3\times 34}[/tex]
5) Simplify [tex]3\times 34[/tex] to [tex]102[/tex] .
[tex]\frac{1}{102}[/tex]
Which of the following are solutions to the equation below?
Check all that apply. x^2 + 6x + 9= 20
HELP!!! PLEASE HURRY!!!!
Answer:
B, I solved then used interval notion to convert it.
Answer:
the answer is b
Answer:
the answer is b
I need help with question 20
Integration questions .
[tex]\\\\\ \textbf{a)}\\\\~~~\displaystyle \int (6x- \sin 3x) ~ dx\\\\=6\displaystyle \int x ~ dx - \displaystyle \int \sin 3x ~ dx\\\\=6 \cdot \dfrac{x^2}2 - \dfrac 13 (- \cos 3x) +C~~~~~~~~~~~;\left[\displaystyle \int x^n~ dx = \dfrac{x^{n+1}}{n+1}+C,~~~n \neq -1\right]\\\\ =3x^2 +\dfrac{\cos 3x}3 +C~~~~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \sin (mx) ~dx = -\dfrac 1m ~ (\cos mx)+C \right]\\[/tex]
[tex]\textbf{b)}\\\\~~~~\displaystyle \int(3e^{-2x} +\cos (0.5 x)) dx\\\\=3\displaystyle \int e^{-2x} ~dx+ \displaystyle \int \cos(0.5 x) ~dx\\\\\\=-\dfrac 32 e^{-2x} + \dfrac 1{0.5} \sin (0.5 x) +C~~~~~~~~~~~~~~;\left[\displaystyle \int e^{mx}~dx = \dfrac 1m e^{mx} +C \right]\\\\\\=-\dfrac 32 e^{-2x} + 2 \sin(0.5 x) +C~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \cos(mx)~ dx = \dfrac 1m \sin(mx) +C\right]\\\\\\=-1.5e^{-2x} +2\sin(0.5x) +C[/tex]
2)[tex]\textbf{a)}\\\\y = \displaystyle \int \cos(x+5) ~ dx\\\\\text{Let,}\\\\~~~~~~~u = x+5\\\\\implies \dfrac{du}{dx} = 1+0~~~~~~;[\text{Differentiate both sides.}]\\\\\implies \dfrac{du}{dx} = 1\\\\\implies du = dx\\\\\text{Now,}\\\\y= \displaystyle \int \cos u ~ du\\\\~~~= \sin u +C\\\\~~~=\sin(x+5) + C[/tex]
[tex]\textbf{b)}\\\\y = \displaystyle \int 2(5x-3)^4 dx\\\\\text{Let,}\\~~~~~~~~u = 5x-3\\\\\implies \dfrac{du}{dx} = 5~~~~~~~~~~;[\text{Differentiate both sides}]\\\\\implies dx = \dfrac{du}5\\\\\text{Now,}\\\\y = 2\cdot \dfrac 1 5 \displaystyle \int u^4 ~ du\\\\\\~~=\dfrac 25 \cdot \dfrac{u^{4+1}}{4+1} +C\\\\\\~~=\dfrac 25 \cdot \dfrac{u^5}5+C\\\\\\~~=\dfrac{2u^5}{25}+C\\\\\\~~=\dfrac{2(5x-3)^5}{25}+C[/tex]
3)[tex]\textbf{a)}\\\\y = \displaystyle \int xe^{3x} dx\\\\\text{We know that,}\\\\ \displaystyle \int (uv) ~dx = u \displaystyle \int v ~ dx - \displaystyle \int \left[ \dfrac{du}{dx} \displaystyle \int ~ v ~ dx \right]~ dx\\\\\text{Let}, u =x~ \text{and}~ v=e^{3x} .\\\\y= \displaystyle \int xe^{3x} ~dx\\\\\\~~= x\displaystyle \int e^{3x} ~ dx - \displaystyle \int \left[\dfrac{d}{dx}(x) \displaystyle \int e^{3x}~ dx \right]~ dx\\\\\\[/tex]
[tex]=x\displaystyle \int e^{3x}~ dx - \displaystyle \dfrac 13 \int \left(e^{3x} \right)~ dx\\\\\\=\dfrac{xe^{3x}}3 - \dfrac 13 \cdot \dfrac{ e^{3x}}3+C\\\\\\= \dfrac{xe^{3x}}{3}- \dfrac{e^{3x}}{9}+C\\\\\\=\dfrac{3xe^{3x}}{9}- \dfrac{e^{3x}}9 + C\\\\\\= \dfrac 19e^{3x}(3x-1)+C[/tex]
Match each graph with the function it represents.
A function assigns the values. The graph of the function f(x) and g(x) can be plotted as shown in the below image.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
The graph of the function f(x) and g(x) can be plotted as shown in the below image.
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Question 6(Multiple Choice Worth 1 points)
(02.02 MC)
Given the function f(x) = -5x² + 2x + 9, find f(1) and f(2). Choose the statement that is true concerning these two values.
O The value of f(1) cannot be compared to the value of f(2).
O The value of f(2) is larger than the value of f(1).
O The value of f(2) is smaller than the value of f(1).
O The value of f(1) is the same as the value of f(2). help
Answer:
O The value of f(2) is smaller than the value of f(1).
Step-by-step explanation:
First, let's solve for both. When the problem says f(1) or f(2), this just means that the x value is equal to that. So:
f(1) = -5(1)^2 + 2(1) + 9 = 6
f(2) = -5(2)^2 + 2(2) + 9 = -7
Since f(1) = 6 and f(2) = -7, we know that f(1) is greater than f(2). Therefore, the value of f(2) is smaller than the value of f(1)
One block is needed to make an up-down-up staircase with one step up and one step down.
Four blocks are need to build and up-down-up staircase with 2 steps up and 2 steps down.
Complete parts (a) and (b) below.
***
a. How many blocks are needed to build an up-down-up staircase with 5 steps up and 5 steps down?
25 blocks are needed to build an up-down-up staircase with 5 steps up and 5 steps down.
(Type a whole number.)
b. How many blocks are needed to build an up-down-up staircase with n steps up and n steps down?
blocks are needed to build an up-down-up staircase with n steps up and n steps down.
Answer:
n² blocks are needed to build a staircase with n steps.
Step-by-step explanation:
Solve for (x): (14.5x − 5(x + 2) ≤ 4 + 4(4 − 1/8x)
Answer:x ≤ 3
Step-by-step explanation:
(14.5x − 5(x + 2) ≤ 4 + 4(4 − 1/8x)
14.5x - 5x-10 ≤ 4 + 16 - 1/2x Get rid of the parenthesis
9.5x-10 ≤ 20-1/2x Combine like terms
10x - 10 ≤ 20
10x/10 ≤ 30/10
x ≤ 3
Help me please I been trying to figure out how to do this problem
sin 30 = x/4
sin 30 = 0.5
0.5 = x/4
x = 2
Points ABC forms a right triangle.
A: (-2,4) B: (5,0) C: (2,6)
The sum of the squares of the lengths of the legs of the triangle is?
The square of the length of the hypotenuse of the triangle is?
The sum of squares of the lengths of the triangle is 130 and the square of the length of the hypotenuse is 65
What is a right-angled triangle?This is a triangle with 3 sides and one side is called the hypotenuse which faces one of the angles 90°
Analysis:
distance between two points = [tex]\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }[/tex]
distance AB with coordinates A(-2,4) B(5,0) = [tex]\sqrt{(5 - -2)^{2} + (0 - 4)^{2} }[/tex] = [tex]\sqrt{65}[/tex]
distance AC with coordinates A ( -2,4) C(2,6) = [tex]\sqrt{(2--2)^{2} + (6-4)^{2} }[/tex] = [tex]\sqrt{20}[/tex]
distance BC with coordinates B(5,0) C(2,6) = [tex]\sqrt{(2-5)^{2} + (6-0)^{2} }[/tex] = [tex]\sqrt{45}[/tex]
sum of squares of the lengths = [tex](\sqrt{45} )^{2}[/tex] + [tex](\sqrt{65}) ^{2}[/tex] + [tex](\sqrt{20}) ^{2}[/tex] = 65 + 45 + 20 = 130
the square of the length of the hypotenuse = 65
In conclusion, the sum of the squares of the three length is 130 and the square of the hypotenuse is 65
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Can u help me pls i will be putting some more problems
look the image
Step-by-step explanation:
2x + 28° + 90° = 180° ( The sum of all angle of triangle is 180° )
Now you may add 28° and 90° and subtract it from 180° ...
2x = 62° ..
Now...divide 62 by 2 ...
x = 31°
hence the value of x is 31°....
PLEASE HELP ME I HAVE A F IN MATH
Answer:
pattern 0 i believe would be just the 4 red squares
Step-by-step explanation:
its adding a blue square on the 3 sides and adding enough green squares to cover the middle, or however many blue squares there are on the top and side, multiply them together. like in figure 1 i noticed that 1×1=1 so that's how many green squares there are. Figure 2: 2 blue× 2 blue= 4 green. if that makes sense. Figure 3: 3×3=9 i dont know if that made sense. but that's what i could think of!!
The methods of solving quadratic equations
There are three main ways of solving quadratic equations. The quadratic formula, factoring, and completing the square.
[1] using the quadratic formula
When the equation is in the form of ax² + bx + c = 0.
[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
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[2] factoring
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[3] completing the square
To start out with completing the square, make sure your constant is isolated on one side. The equation will be as ax² + bx = -c
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[tex]tanx^{2} -\frac{1}{3} =0[/tex]
These are expression written as a function of sine, cosine and tangent. The value of x from the given function is 4.29
Trigonometry expression
These are expression written as a function of sine, cosine and tangent.
Given
tanx² - 1/3 = 0
Add 1/3 to both sides
tanx² - 1/3 + 1/3 = 0 + 1/3
tanx² = 1/3
x² = arctan(1/3)
x² = 18.44
x =4.29
Hence the value of x from the given function is 4.29
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Please help I am so confused
The phone company Ringular has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minute used on the phone. If a customer uses 480 minutes, the monthly cost will be $277. If the customer uses 990 minutes, the monthly cost will be $532.
A) Find an equation in the form
y=mx+b, where x is the number of monthly minutes used and
y is the total monthly cost of the Ringular plan.
Answer:
y=
B) Use your equation to find the total monthly cost if 881 minutes are used.
Answer: If 881 minutes are used, the total cost will be
The total cost when 881 minutes is used is $477.50.
What are the equation that model the question?a + 480b = 277 equation 1
a + 990b = 532 equation 2
Where:
a = flat fee b = variable fee What is the flat fee and the variable fee?Subtract equation 1 from equation 2
510b = 255
b = 255 / 510
b = $0.50
In order to determine the flat fee, substitute for b in equation 1
a + 480(0.5) = 277
a + 240 = 277
a = 277 - 240
a = $37
What is the total cost when 881 minutes is used?
Total cost = flat fee + (variable cost x number of minutes spoken)
$37 + (881 x 0.5) = $477.50
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Solve for x to the nearest tenth of centimetre
Answer:
Step-by-step explanation:
6) Suppose you deposit $6000 in a savings account that pays interest at an annual rate of 4% compounded
continuously. How many years will it take for the balance in your savings account to reach $8000? Round
your answer up to the nearest number of years.
Answer:
7 years
Step-by-step explanation:
!!
Mum spent 3/5 of her money and put 1/8 of the remainder in the bank. If she had $750 left, how much did she start with?
Answer:
$2142.86
Step-by-step explanation:
The remaining part of her money, after spending 3/5 of it and depositing 1/8 of it is equal to $750.
===============================================================
Retracing the steps :
⇒ She put 1/8 of the remainder in the bank, which gives $750
⇒ R - R/8 = 750
⇒ 7R/8 = 750
⇒ R = 750/7 × 8
⇒ R = 107.142857 × 8
⇒ R = 857.142856
* Don't worry, we'll simplify at the end of the answer *
=============================================================
Now, this remainder is what was left after spending 3/5 of it.
⇒ T - 3/5T = 857.142856
⇒ 2/5T = 857.142856
⇒ T = 857.142856/2 × 5
⇒ T = 428.571428 × 5
⇒ T = $2142.86 (nearest cent)
a camp charges $40 per student for a full-day camp and the camp only runs if 5 students enroll but the enrollment limit is 16 students. the amount of revenue that the camp collects is a function of the number of students that enrolled defined by this equation: [tex]R(n)=40n[/tex]
please describe the set of all possible outputs of this function
please describe the set of all possible inputs of this function
The set of input of the function are {5, 6, 7, 8, 9,10, 11, 12,13, 14, 15, 16 }
The set of output of the function is a multiple of 40 from 200 to 640
How to find the output and input of a function?The input of the function can be found as follows:
The camp can only run if we have at least 5 students.
The limits of student is 16.
Therefore, the input are {5, 6, 7, 8, 9,10, 11, 12,13, 14, 15, 16 }
The output are the dependent variables or the range. They are gotten when we input the values of the input in the function.
Therefore,
R(n) = 40n
R(5) = 40(5) = 200
R(16) = 40(16) = 640
The output are multiple of 40 from 200 to 640
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the graph of the function f(x)=In x. Match each transformation of function f with a feature of the transformed function. function decreases as x increases x-intercept at y-intercept at
The matching of each transformed function is as follows;
g(x) = 2f(x) → y-intercept at (0,2)
h(x) = f(x) + 2 → asymptote of y=2
j(x) = f(x + 2) → y-intercept at (0,4)
m(x) = function decreases as x increases
How to match transformations?A function is simply defined as a relationship between the inputs and the outputs. Now, we want to map each transformed function.
From the graph of this question as shown in the attached brainly link, the correct matching of each transformation of function f(x) = In x with a feature of the transformed function are as follows;
g(x) = 2f(x) → y-intercept at (0,2)
h(x) = f(x) + 2 → asymptote of y=2
j(x) = f(x + 2) → y-intercept at (0,4)
m(x) = function decreases as x increases
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Write the converse of the statement
below.
If it is 9 a.m., then I am awake.
Answer:
if I am awake then it is 9 am.
Step-by-step explanation:
if p then q the converse is if q then p.
Which of these choices show a pair of equivalent expressions? Check all that apply.
the answer is A.B
I mean the answer is a and b
Mike leaves the house traveling 2 miles per hour. Kim leaves 6 hours later to catch up traveling 8 miles per hour. It will take Kim Blank 1 hours to catch Mike.
any answers ?
Answer:
2 hours
Step-by-step explanation:
Mike has a six hour head start so he is 6 x 2 = 12 miles ahead
their 'closing speed' is 8-2 = 6 m/hr
it will take Kim 12 / 6 = two hours to catch Mike