Part 1: Come up with and describe two scenarios: one that models a direct variation situation and one that models an inverse variation situation. Do not state explicitly which scenario is which, but provide at least four data pairs for each situation. Your classmates will have to determine which of the scenarios is a direct variation and which is an inverse variation, and the value of k for each.
Answer:
1. I went to a store four days in a row and only bought chocolate bars each day. All chocolate bars were the same and cost the same. On the first day, I bought 2 chocolate bars for $2.38. On the second day I bought 1 chocolate bar for $1.19. On the third day, I bought 10 chocolate bars for $11.90. On the fourth day, I bough 4 chocolate bars for $4.76.
2. A sink is full. It contains 20 gallons of water. The stopper is removed and water starts draining out. One minute after the stopper is removed, the volume of water in the sink is 18 gallons. Two minutes after the stopper is removed, the volume of water in the sink is 16 gallons. Four minutes after the stopper is removed, the volume of water in the sink is 12 gallons. Ten minutes after the stopper is removed, the sink is empty.
In a city park, three walking paths form triangle ABC. The length AB is 800 meters, the length BC is 900 meters, and the length AC is 850 meters. Which angle of this triangle has the greatest measure?
Answer:
Step-by-step explanation:
angle c
The angle of the triangle with the greatest measure is ∠A
What is a triangle?A triangle is a polygon with three sides and three angles.
Analysis:
For the triangle, ABC the angle facing the side with the greatest measure is the angle with the greatest measure. From the given information side BC is the side with the greatest measure and the angle facing it is ∠A.
In conclusion, the angle with the greatest measure is ∠A
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I NEED A.S.A.P PLEASE I WILL GIVE BRAINLIEST
Simplify: 5.9 (9 - 5) + 4^3 + 3.86 A. 63.06 B. 72.83 C. 91.46 D. 98.32
Answer:
C. 91.46
Step-by-step explanation:
Use BODMAS!
Answer:
C. 91.46
Step-by-step explanation:
Using Pemdas to solve:
5.9 (9 - 5) + 4^3 + 3.86
First you have to solve in the parenthesis
5.9 (9 - 5) + 4^3 + 3.86
= 4
New equation:
5.9 x 4 + 4^3 + 3.86
Now solve the exponent:
5.9 x 4 + 4^3 + 3.86
= 64
New equation:
5.9 x 4 + 64 + 3.86
Now we have to do multiplication:
5.9 x 4 + 64 + 3.86
= 23.6
New equation:
23.6 + 64 + 3.86
Now all you have to do is add all that together and you have your answer:
23.6 + 64 + 3.86
= 91.46
Hope this helps.
Compare the equations represented in the table, equation, and graph over
the interval
[-5, 3]. Which function is increasing the fastest?
Answer:
Tabled Function
Step-by-step explanation:
To determine which function is increasing the fastest over the interval [-5, 3], we need to calculate and compare each function's average rate of change over the given interval.
The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:
[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]
Given interval: -5 ≤ x ≤ 3
Therefore, a = -5 and b = 3
Tabled function[tex]f(3)=7[/tex]
[tex]f(-5)=-17[/tex]
[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)}=\dfrac{7-(-17)}{3+5}=3[/tex]
Equation: y = x² - 2[tex]f(3)=(3)^2-2=7[/tex]
[tex]f(-5)=(-5)^2-2=23[/tex]
[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)}=\dfrac{7-23}{3-(-5)}=-2[/tex]
Graphed functionFrom inspection of the graph:
[tex]f(3)\approx8[/tex]
[tex]f(-5) \approx 0[/tex]
[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)} \approx \dfrac{8-0}{3-(-5)}=1[/tex]
Therefore, the Tabled Function has the greatest average rate of change in the interval [-5, 3] and so it is increasing the fastest.
helppppppppppppppppppppppppp
Answer:
reason 1.) This is the original expression
reason 2.) you subtract 4 from both sides
reason 3.) you divide both sides by 2 to get x=5
Solve the system of equations using substitution.
y=x+2,5x-4y=-3
Answer:
x=5 and y=7
Step-by-step explanation:
Just substitute in y=x+2 into the equation 5x-4y=-3 to get 5x-4(x+2)=-3 which simplifies to x=5. Substitute x into y=x+2 to find y=7
Year(x) 1971
Percent(y) 42.4
1978
37.4
1980
37.1
1984
34.1
1989
32.1
1993
28.8
1997
25.7
2000
25.5
Answer:
25.5
Step-by-step explanation:
I did the same assignment
Alex wants to cover his wall
with a circular clock that has a
diameter of 16 in. How much
space will the clock cover on
his wall?
Answer: A = π r2
r=8 and 8 squared is 64 and 64×3.14=200.96 or rounded to the nearest whole number it would be 201
Step-by-step explanation: brainliest please?
What is a factor of X2–9 X +14
The factors of the expression x^2 - 9x + 14 are (x - 7) and (x - 2)
How to factor the expression?The expression is given as:
x^2 - 9x + 14
Expand
x^2 - 2x - 7x + 14
Factorize the expression
x(x - 2) - 7(x - 2)
Factor out x - 2 from the expression
(x - 7)(x - 2)'
Hence, the factorized expression of x^2 - 9x + 14 is (x - 7)(x - 2)'
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If sin Q = 4/5, cos P + cos Q
The value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.
What is trigonometry?Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
We know that:
P + Q are complementary, which means that
P+Q = 90°
Then R is a right angle, i.e. it measures 90°.
sin(90-x) = cos (x)
cos(90-x) = sin (x)
Then sinQ = 4/5
cos(90-Q) = cosP = 4/5
Now sin²(P) + cos²(P) = 1
sin²(P) = 1 - cos²(P)
sin²(P) = 1 -[4/5]² =9/25
sin(P) = 3/5
cos(Q) = sin(P) = 3/5
cos(P) + cos(Q) = 4/5 + 3/5 = 7/5
Thus, the value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.
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If f(x) = |x| + 9 and g(x) = -6, which describes the range of (f+g)(x)
The range exist on all real values. This can be written as (-infty, infty)
Range of a functionThe range is the value of the dependent variable for which it exists. Given the following functions
f(x) = |x| + 9 and;
g(x) = -6
Determine the sum
(f+g)(x) = |x| + 9 + (-6)
(f+g)(x) = |x| + 9 -6
(f+g)(x) = |x| + 3
Determine the range of the function
The range exist on all real values. This can be written as (-infty, infty)
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Simplify the expression.
(x6y-6)
————
(x8y-8)
proving trigonometric identities
2(cosx sinx-sinx cos2x)/sin2x =secx
This is not an identity.
[tex]\dfrac{2(\cos(x)\sin(x) - \sin(x)\cos(2x))}{\sin(2x)} \neq \sec(x)[/tex]
Check x = π/4, for which we have cos(π/4) = sin(π/4) = 1/√2. Together with sin(2•π/4) = sin(π/2) = 1 and cos(2•π/4) = cos(π/2) = 0, the left side becomes 1, while sec(π/4) = 1/cos(π/4) = √2.
Keeping the left side unchanged, the correct identity would be
[tex]\dfrac{2(\cos(x)\sin(x) - \sin(x)\cos(2x))}{\sin(2x)} = -2\cos(x) + 1 + \sec(x)[/tex]
To show this, recall
• sin(2x) = 2 sin(x) cos(x)
• cos(2x) = cos²(x) - sin²(x)
• cos²(x) + sin²(x) = 1
Then we have
[tex]\dfrac{2(\cos(x)\sin(x) - \sin(x)\cos(2x))}{\sin(2x)} = \dfrac{2\cos(x)\sin(x) - 2\sin(x)\cos(2x)}{\sin(2x)} \\\\ = \dfrac{\sin(2x) - 2\sin(x)\cos(2x)}{\sin(2x)} \\\\ = 1 - \dfrac{2\sin(x)\cos(2x)}{\sin(2x)} \\\\ = 1 - \dfrac{2\sin(x)(\cos^2(x) - \sin^2(x))}{2 \sin(x)\cos(x)} \\\\ = 1 - \dfrac{\cos^2(x) - \sin^2(x)}{\cos(x)} \\\\ = 1 - \cos(x) + \dfrac{\sin^2(x)}{\cos(x)} \\\\ = 1 - \cos(x) + \dfrac{1 - \cos^2(x)}{\cos(x)} \\\\ = 1 - \cos(x) + \sec(x) - \cos(x) \\\\ = -2\cos(x) + 1 + \sec(x)[/tex]
Brett draws the shape shown below.
He says the shape can be classified as a quadrilateral, parallelogram, rhombus, and square.
Is Brett correct? Explain.
The given figure is quadrilateral, parallelogram, and a rhombus but not a square. So brett is not correct.
What is a square?A square is a quadrilateral with all the sides equal and all the four sides are perpendicular to each other.
We know that it is a quadrilateral as a quadrilateral is having four sides and the sum of the angles is 180 degrees.
The given figure is a parallelogram as opposite sides of the figure are parallel and equal.
The given figure is a rhombus as all the sides are parallel and equal.
The given figure can not be a square as in the square all the four sides are perpendicular to each other.
Therefore given figure is quadrilateral, parallelogram, and a rhombus but not a square. So brett is not correct.
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Given that 2x³-5x² - 4x+8 = (Ax - 1)(x-B)(x + 1) + C for all values of x, find the
values of A, B and C.
Answer:
A=2, B=3, C=5
Step-by-step explanation:
Two polynomials are equal for all values of the variable if the corresponding coefficients are the same. The way to solve the problem is to multiply the RHS, rewrite it in a more orderly way
[tex](Ax-1)(x-B)(x+1)+C = \\Ax^3+(A-AB-1)x^2+(B-AB-1)x +B+C[/tex]
Now, for the two polynomials to be the same we need to have, at the same time
[tex]x^3: A=2\\x^2: A-AB-1= -5\\x:B-AB-1=-4\\1: B+C=8[/tex]
You might notice that we have more conditions than variables, but you can consider one of the two in the middle as a "check" option.
Now, grabbing the value from the first condition into the second we get B=3. Replacing both value in the third we see that the equality still holds, and replacing into the fourth we get C =5.
The first term in an arithmetic sequence is -3. If the sequence has a common difference of 8, what is the 30th term in the sequence?
Will give brainliest to right answer :))
Answer:
229
Step-by-step explanation:
(my work for the problem is in the photo I attached)
(I also wrote this step-by-step in the photo because I can explain things better as I do them)
This will be a little bit confusing without me writing out the numbers, so mainly this is if you can't read my handwriting
-3 + 8 = 5 ; 5 + 8 = 13
(1st term) (2nd term) (3rd term)
Instead of adding 8 repeatedly (repeated addition), we can use multiplication.
To get the 3rd term in this sequence, we had to add 8 twice, which could also be done by multiplying 8 twice (8 x 2)
13 + 8 = 21
(4th term)
to get the 4th term, we added 8 three times (or, 8 x 3)
So, if we are looking for the 30th term in a sequence, we will have to add 8, 29 times (8 x 29) to our original term.
8 x 29 = 232
-3 + 232 = 229
This means that the 30th term of the sequence will be 229.
what is the answer to −1.4+(−1.2)
Answer:
-2.6
Step-by-step explanation:
-1.4+(-1.2)
-1.4-1.2=-2.6
Hope this helps!
If not, I am sorry.
Can you do it on paper and photos? the answer!
help me
The value of x in all case is
1. The value of x is 2
2. The value of x is 1
3.The value of x is 57
4.The value of x is 93
What is complementary and supplementary angle?If the sum of two angles is 180 degrees then they are said to be b angles, which form a linear angle together. Whereas if the sum of two angles is 90 degrees, then they are said to be complementary angles, and they form a right angle together.
1. As the given angle is 90 degree i.e., complementary angle.
So,
54+10x+16=90
20=10x
x=2
2. 65x-12=43x+10 (Vertically opposite angle)
22x= 22
x=1
3. 72= x+15 (Vertically opposite angle)
x= 57
4.x+244+23=360 (Complete angle)
x=93
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Q). Express each of the following recurring decimal as a rational numbers . 1) 0.5 2) 0.13 3) 0.341
The following recurring decimal as a rational number are 1/2, 13/100 and 341 / 1000
What is rational number?A rational number is a number that is expressed as the quotient or fraction of two integers, a numerator and a non-zero denominator such as;
3/4. where,
Numerator = 3Denominator = 4Therefore,
0.5
= 5/10
= 1/2
0.13
= 13/100
0.341
= 341 / 1000
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f(x) =2x^2+4x-6. g(x)=4x^3-6x^2+3 find (f+g)(x)
Answer:
=4x³-4x²+4x-3
Step-by-step explanation:
(f+g)(x)=4x³+2x²-6x²+4x-6+3
=4x³-4x²+4x-3
If a baseball player hits 10 home runs in the first 45 game, at the same rate how many home runs can he expect to hit during the 162 game season
Using proportions, it is found that he can be expected to hit 36 home runs during the 162 game season.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, the player hits 10 home runs in 45 games, hence the proportion is:
p = 10/45.
Then, in 162 games, the amount is:
HR = 10/45 x 162 = 36.
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find the distance between the two points in simplest radical form.
(3,-8) and (8,4)
Answer:
13
Step-by-step explanation:
The way to find the distance between two points on the coordinate plane is to use the distance formula, which is basically a way of applying the Pythagorean Theorem.
The distance formula is [tex]\sqrt{(x_{1}- x_{2} )^2 + (y_{1}- y_{2})^2}[/tex]. Let's say the coordinate (3, -8) is (x1, y1) and the coordinate (8, 4) is (x2, y2). We can plug these values into the formula:
[tex]\sqrt{(3- 8 )^2 + (-8 - 4)^2}\\\sqrt{(-5)^{2} + (-12)^{2}} \\\sqrt{25+144} \\\sqrt{169} \\13[/tex]
So, the distance between the two points is 13.
4X+8<28
ayudenme por favor
Answer:
x < 5.
Step-by-step explanation:
Creo que esto es correcto. :')
Which pair of angles shares ray A and F as a common side?
The pair of angles that share a ray as a common side in the given diagram is: ∠FAB and ∠FAD.
What are Adjacent Angles?Adjacent angles are angles that lie adjacent or next to each other sharing a common vertex and have the same ray as a common side.
In the diagram attached below, ∠FAB and ∠FAD share a common vertex, A, and a ray FA as a common side.
Therefore, the pair of angles is: ∠FAB and ∠FAD.
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If the coordinate of A is (0, -2) and the coordinate of B is (10, -6), the then midpoint of \overline{AB} AB is: Part A The X portion of the midpoint is __________________. Part B The Y portion of the midpoint is _________________.
Step-by-step explanation:
it is very simple :
the midpoint coordinates are created as the midpoint of the x coordinates, and the midpoint of the y coordinates.
the x coordinate of the midpoint is
(0 + 10)/2 = 10/2 = 5
the y coordinate of the midpoint is
(-2 + -6)/2 = -8/2 = -4
To which quadrants is tan^-1 x restricted?
A. Quadrants I and IV
B. Quadrants III and IV
C. Quadrants II and III
The quadrants is tan⁻¹x restricted is A. Quadrants I and IV
To answer the question, we need to know what tan⁻¹x is.
What is tan⁻¹x?tan⁻¹x is the inverse trigonometric function of tanx, which is the value of the angle for tanx.
Quadrant in which tan⁻¹x is restrictedTo find the quadrants in which tan⁻¹x is restricted, we know that tanx lies in the range
-∞ ≤ tanx ≤ +∞ for -90° ≤ x ≤ 90°.
Since the inverse function of tanx is x.tan⁻¹x lies between -90° and 90°. That is -90° ≤ tan⁻¹x ≤ 90°.Since 90° lies in first quadrant and -90° lies in the fourth quadranttan⁻¹x lies between quadrant I and IV
So, the quadrants is tan⁻¹x restricted is A. Quadrants I and IV
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simplify (x^3+2x-3)-(x^2-2x+4)
Answer:
x³ - ((x+1)(x+1))
Step-by-step explanation:
x³ + 2x -3 - x² - 2x + 4
x³ - x² + 1
x³ - ((x+1)(x+1))
Answer:
x^3−x^2+4x−7
Step-by-step explanation:
Hope this helps! Have a great day!!
Question in the Picture
Step-by-step explanation:
the picture is not representing the real angle sizes. so, don't let yourself get confused by that.
the right neighbor angle of 90° at E is also 90°.
it has to be, because it is the supplementary angle to the left 90° (that means together they are 180°).
remember, all angles around a single point on one side of a line have to sum up to 180° (because the line can be seen as the diameter of a circle, with the point being the center of the circle, and so one side of the line is representing a half-circle and therefore 180°).
for the same reason angle 1 (the lower neighbor of the 90° angle at A) is also 90°.
for the same reason the lower neighbor angle of the 60° angle at E is 180 - 60 = 120°.
for the same reason the angle ABC is 180 - 40 = 140°.
for the angle BCD we need to remember :
the sum of interior angles of a polygon with n sides is
(n − 2) × 180°.
in our case ABCDE has 5 sides, so the sum of all interior angles is
(5 - 2) × 180 = 3×180 = 540°
we know 4 of the interior angles already, so
angle BCD = 540 - 90 - 90 - 120 - 140 = 100°
x is now the supplementary angle to the angle BCD.
so,
x = 180 - 100 = 80°
[tex] \frac{2}{3} n (4p + \sqrt{36} - 2 {n}^{2} [/tex])
n= -3
p=5
need urgent help
Answer:
-16.
Step-by-step explanation:
2/3 * (-3) * (4*5 + 6 - 2(-3)^2)
= -2(20 + 6 - 18)
= -2 * 8
= -16.
A farmer has 6 pumpkins that are the same size. the mass of each pumpkin is 3 kilograms. what is the total mass of the farmer's pumpkins?
Answer: 18 kilograms
Step-by-step explanation:
If each pumpkin weighs 3 kilograms and the farmer has 6 pumpkins the equation would be 6x3=18 in order to find the mass of the farmer's pumpkins.