many organic chemicals are poorly soluble in water due to a lack of electrical charge. T/F

Answers

Answer 1

False. The poor solubility of many organic chemicals in water is primarily due to their non-polar nature rather than a lack of electrical charge.

Water is a polar molecule with a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom. This polarity allows water molecules to form hydrogen bonds and interact with other polar molecules. However, many organic compounds, such as hydrocarbons, have non-polar covalent bonds and lack significant electrical charge separation.

Since like dissolves like, these non-polar organic compounds are poorly soluble in water. Instead, they tend to aggregate and separate from water, forming distinct phases. Non-polar solvents, such as organic solvents, are more suitable for dissolving organic compounds due to their similar non-polar nature. Thus, the poor solubility of organic chemicals in water is primarily attributed to their non-polar character rather than a lack of electrical charge.

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Related Questions

add electron dots and charges as necessary to show the reaction of calcium and oxygen

Answers

The reaction between calcium and oxygen can be represented by the formation of calcium oxide (CaO), where calcium loses two electrons and oxygen gains two electrons to achieve stability.

Calcium has an atomic number of 20 and its electron configuration is 2, 8, 8, 2. Oxygen has an atomic number of 8 and its electron configuration is 2, 6. To achieve a stable electron configuration, calcium tends to lose two electrons, resulting in a 2+ charge (Ca2+). Oxygen tends to gain two electrons, resulting in a 2- charge (O2-). In the reaction between calcium and oxygen, each calcium atom will lose two electrons to form Ca2+ ions, and each oxygen atom will gain two electrons to form O2- ions. The resulting ions will combine to form calcium oxide (CaO), with the charges balancing out. The electron-dot structure can be represented as Ca(2+) + O(2-) → CaO.

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dentify the true statement.
Choose one:
A. Most of the minerals in granite weather to clay except quartz.
B. Quartz weathers more quickly than other common minerals in granite.
C. All minerals weather at the same rate.
D. Every mineral is affected by every type of chemical weathering reaction.

Answers

The true statement is Most of the minerals in granite weather to clay except quartz.

So, the correct answer is A.

This is because quartz is a very hard and durable mineral that is resistant to weathering. Other minerals in granite, such as feldspar and mica, are more susceptible to weathering and break down into clay minerals over time.

This process is known as chemical weathering, where minerals are altered or dissolved by chemical reactions with water and other substances in the environment.

While some minerals may weather more quickly than others, the overall rate of weathering depends on a variety of factors such as climate, topography, and the composition of the rock.

Hence, the answer of the question is A.

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calculate the factor by which a reaction rate is increased by an enzyme at 37c if it lowers the reaction activiation energy from 15 kcal

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Solving this equation gives a factor of approximately 2.5, which means that the reaction rate is increased by 2.5 times with the help of the enzyme.

Enzymes are proteins that catalyze chemical reactions, which means they increase the rate of a reaction without being consumed in the process. This is achieved by lowering the activation energy, which is the energy required for a chemical reaction to occur. The factor by which a reaction rate is increased by an enzyme can be calculated using the Arrhenius equation. At 37°C, the factor can be calculated using the formula:

Factor = e^(ΔEa/R(1/T2 - 1/T1))

where ΔEa is the change in activation energy (in this case, -15 kcal), R is the gas constant (1.987 cal/mol*K), T1 is the initial temperature (in Kelvin), and T2 is the final temperature (310K, since 37°C is equivalent to 310K).

Plugging in the values, we get:

Factor = e^(-15,000 cal/mol)/(1.987 cal/mol*K*(1/310K - 1/298K))

Solving this equation gives a factor of approximately 2.5, which means that the reaction rate is increased by 2.5 times with the help of the enzyme.

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