If each collectible coin weighs 2.5 grams, how much do 3 collectible coins weigh all together?
A) 9.5 grams
B) 8.5 grams
7.5 grams
D 6.5 grams

Answer: p= -3,2

q= -3,8

R= -8,8

s=-8,2

Step-by-step explanation:

Answer:

D. 0.62

Step-by-step explanation:

I calculated it logically

Answer: 1/12 or 8.3%

Step-by-step explanation:

probability of a 2 on the cube: 1/6

probability of tails on the quarter: 1/2

1/6*1/2=1/12

1/12 or 8.33333% (round to 8.3%)

Answer:

76

Step-by-step explanation:

10+9= 19

19*4=76

Answer:

76

Step-by-step explanation:

1 Simplify  10+910+9  to  1919.

4\times 19

4×19

2 Simplify.

76

76

Answer:

A. (-6,-5)

Step-by-step explanation:

A: Correct because -6+-5=-11------True

    and 2(-6)-3(-5) is equal to -12-(-15) and a - plus a - equals a +

    so our new equation is -12+15=3-----True

  -Your welcome and I hope this helps you, please rate 5 stars =D

Answer:

c

Step-by-step explanation:

Answer:

B. 37.5 sq in

Step-by-step explanation:

sana po makatulong ☺️

Answer:

Is that all to the problem?

Step-by-step explanation:

Answer:

Is there supposed to be more information?

Step-by-step explanation:

Answer:

23

Step-by-step explanation:

6x3=18

18+5=23

Answer

this is wrong

Step-by-step explanation:

this is an equation not an expression. Equations have = and expressions dont. Please rewrite this and I will help.

Answer:

volume

Step-by-step explanation:

9514 1404 393

Answer:

  C.  $1.50

Step-by-step explanation:

The graph is a straight line through the origin, so the revenue is proportional to the number of tickets. The ratio of revenue to tickets will tell you the money raised for each ticket sold. Pick any point on the graph and divide the revenue value by the number of tickets.

The division can be easy if the number of tickets is 10. We see that the revenue for 10 tickets is $15, so the amount raised for each ticket is ...

  $15/10 = $1.50 . . . . raised per ticket sold

Answer:

B, d, e

Step-by-step explanation:

The formula for the area of a triangle is 1/2×base (b)×height (h)

For b

Half of 3 is 1.5 × 8 = 12

For d

Half of 6 is 3 × 4= 12

For e

Half of 12 is 6 × 2= 12

Answer:

12

Step-by-step explanation:

x = number of $1 bills

y = number of $5 bills

z = number of $10 bills

We know that:

x + y + z = 25 (total amount of bills)

x + 5y + 10z = 100 (total amount of money)

y = 4z (Given)

Substitute the third equation into the first one.

x + 4z + z = 25

x = 25 - 5z

Put this into the second equation.

(25 - 5z) + 5 (4z) + 10z = 100

Simplify and solve.

25 - 5z + 20z + 10z = 100

25z + 25 = 100

25z = 75

z = 3

Substitute this into y = 4z

y = 4 * 3

y = 12

So, there are 12 $5 bills.

Answer:

12 $5 bills

Step-by-step explanation:

Represent the number of each kind of bill by x, y and z:  there are x $1 bills, y $5 bills and z $10 bills.

According to the problem statement,

x + y + z = 25 and y = 4z (or z = y/4).  Also, the values of the bills add up to $100:

($1)x + ($5)y + ($10)z = $100.  Eliminate z by typing y/4 in its place:

x + y + (y/4) = 25 and

x  + 5y + 10(y/4) = 100

Doing this has reduced the number of variables to two:  x and y.  Combining like terms in both equations, we get:

1x + (5/4)y = 25 and

1x +  (30/4)y       =100

Subtracting the 1st equation from the 2nd, we get:

(25/4)y = 75, or

(4/25)(25/4)y = (4/25)(75) , or y = 12.

If y = 12, z = 12/4, or 3.

Then x + 12 + 3 = 25 coins in all; therefore, x = 15 = 25, and x = 10

There are 10-$1 bills, 12-$5 bills and 3-$10 bills.

Answer:

gradient m = - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

y = - x - 3 ← is in slope- intercept form

with gradient m = - 1

Answer:

[tex]\rm Slope = -1[/tex]

Step-by-step explanation:

Given :-

And we need to find out the gradient of the line. The gradient of the line is the " slope " of the line. The given equation is in slope Intercept Form , which is ,

Slope intercept form :-

[tex]\rm\implies y = mx + c [/tex]

[tex]\implies \rm Slope (m) = (-1)[/tex]

Hence the gradient of the line is (-1) .

Answer:

x=94

Step-by-step explanation:

I hope I'm correct. Here's my explanation: x+9 and 2x-111 would equal 180, hence the line (supplementary). So x+9+2x-111=180

x=94

hope this helps.

Step-by-step explanation:

x+9=2x-111( being corresponding angles )

x=2x-111-9

x-2x=-120

-x=-120

x=120

Answer:

[tex]g(2) = 3[/tex]

Step-by-step explanation:

Given

See attachment

Required

[tex]g(2)[/tex]

To solve this, we make use of:

[tex]g(x) = |7 - x^2|[/tex]

Because [tex]x \le 2[/tex]

i.e. [tex]2 \le 2[/tex]

So, we have:

[tex]g(2) = |7 - 2^2|[/tex]

[tex]g(2) = |7 - 4|[/tex]

[tex]g(2) = |3|[/tex]

Remove absolute brackets

[tex]g(2) = 3[/tex]

Answer: 20

Step-by-step explanation:

if 4x4=16 then 16 divided by 2 =8 witch is diviseble by 20

Answer:

13. A

14. B

15. C

16. B

17. C

Step-by-step explanation:

Answer:

(d)

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 96t[/tex]

Required

The intercepts

The x intercepts are where the graph crosses x axis.

From the attached plot, they are:

[tex]x = (0,0)[/tex] and [tex]x = (6,0)[/tex]

These represent the start and end of the ball that is launched.

Hence, (d) is true

Answer:

55.5 is the I guess........

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

15.1 yd

Step-by-step explanation:

Since the circumference formula is C = πd, d = C/π

and in this case d = (47.5 yd) / 3.14 = 15.1 yd

The approximate diameter of the pad is 15.1 yd.

The approximate diameter of the helicopter pad is,

⇒ d = 15.12 yards

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

A helicopter pad has a circumference of 47.5 yards.

Now,

We know that;

Circumference of circle = 2πr

Hence, We get;

⇒ 47.5 = 2 × 3.14 × r

⇒ 47.5 = 6.28r

⇒ r = 47.5 / 6.28

⇒ r = 7.56

Thus, the approximate diameter of the helicopter pad is,

⇒ d = 2r

⇒ d = 2 × 17.56

⇒ d = 15.12 yards

Learn more about the circle visit:

https://brainly.com/question/24810873

#SPJ3

Answer: She needs to get 99 on her next test.

Step-by-step explanation:

Complete question :

When Hiroto is writing, there is 0.92 probability that there will be no spelling mistakes on a page. One day, Hiroto writes an essay that is 11 pages long.

Assuming that Hiroto is equally likely to have a spelling mistake on each of the 11 pages, what is the probability that he will have a spelling mistake on at least one of the pages?

Answer:

0.60

Step-by-step explanation:

The question meets the requirement for a binomial probability distribution :

Recall:

P(x = x) = nCx * p^x * q^(n-x)

Given :

Probability of making a spelling mistake = 1 - p(not making) = 1 - 0.92 = 0.08

Hence,

p = 0.08 ; q = 0.92

n = 11

P(x ≥ 1) = 1 - p(x = 0)

P(x = 0) = 11C0 * 0.08^0 * 0.92^11

P(x = 0) = 1 * 1 * 0.3996373778857415671808

P(x = 0) = 0.399

P(x ≥ 1) = 1 - p(x = 0)

P(x ≥ 1) = 1 - 0.399

P(x ≥ 1) = 0.601

P(x ≥ 1) = 0.60

Answer:

60,000

Step-by-step explanation:

Answer:

60,000

Step-by-step explanation:

Answer:

sorry but I am not able to answer the question

Answer:

A. 32

Step-by-step explanation:

y varies inversely as x

y = k/x

-------------------------

y = 24 when x = 4

find k, the constant of variation

24 = k/4

multiply both sides by 4

96 = k

----------------------------

find y when x = 3

using k = 96

y = 96/3

y = 32