Physics High School

Excess charge of 9. 0 is placed 0. 17 m away with charge of -3. 2

Answers

Answer 1

By calculating this expression [tex]8.99 * 10^9 N m^2/C^2[/tex] and using the given values, we can find the force between the charges.

When an excess charge of 9.0 (let's call it Q1) is placed 0.17 meters away from a charge of -3.2 (Q2), we can determine the force between them using Coulomb's Law.

Coulomb's Law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for the electric force (F) between two charges is given by:

[tex]F = k * |Q1 * Q2| / r^2[/tex]

where k is the electrostatic constant.

Substituting the given values into the formula, we have:

[tex]F = k * |9.0 * (-3.2)| / (0.17)^2[/tex]

To determine the exact value of the force, we need the value of k. The electrostatic constant, k, is approximately [tex]8.99 * 10^9 N m^2/C^2[/tex].

Therefore, by calculating the expression using the given values, we can find the force between the charges.

To learn more about force from the given link

https://brainly.com/question/30236242

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