calculate the factor by which a reaction rate is increased by an enzyme at 37c if it lowers the reaction activiation energy from 15 kcal

Answers

Answer 1

Solving this equation gives a factor of approximately 2.5, which means that the reaction rate is increased by 2.5 times with the help of the enzyme.

Enzymes are proteins that catalyze chemical reactions, which means they increase the rate of a reaction without being consumed in the process. This is achieved by lowering the activation energy, which is the energy required for a chemical reaction to occur. The factor by which a reaction rate is increased by an enzyme can be calculated using the Arrhenius equation. At 37°C, the factor can be calculated using the formula:

Factor = e^(ΔEa/R(1/T2 - 1/T1))

where ΔEa is the change in activation energy (in this case, -15 kcal), R is the gas constant (1.987 cal/mol*K), T1 is the initial temperature (in Kelvin), and T2 is the final temperature (310K, since 37°C is equivalent to 310K).

Plugging in the values, we get:

Factor = e^(-15,000 cal/mol)/(1.987 cal/mol*K*(1/310K - 1/298K))

Solving this equation gives a factor of approximately 2.5, which means that the reaction rate is increased by 2.5 times with the help of the enzyme.


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Related Questions

add electron dots and charges as necessary to show the reaction of calcium and oxygen

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The reaction between calcium and oxygen can be represented by the formation of calcium oxide (CaO), where calcium loses two electrons and oxygen gains two electrons to achieve stability.

Calcium has an atomic number of 20 and its electron configuration is 2, 8, 8, 2. Oxygen has an atomic number of 8 and its electron configuration is 2, 6. To achieve a stable electron configuration, calcium tends to lose two electrons, resulting in a 2+ charge (Ca2+). Oxygen tends to gain two electrons, resulting in a 2- charge (O2-). In the reaction between calcium and oxygen, each calcium atom will lose two electrons to form Ca2+ ions, and each oxygen atom will gain two electrons to form O2- ions. The resulting ions will combine to form calcium oxide (CaO), with the charges balancing out. The electron-dot structure can be represented as Ca(2+) + O(2-) → CaO.

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