Answer:
Could you give information about the lab
Explanation:
Answer:
The spectrum of each astronomical object
Explanation:
I took the test and got it right
An object with a mass of 1298 kg is accelerating at a rate of 17 m/s² when a net force is applied to it. What is the magnitude of the net force that is acting on the object?
Answer:
Explanation:
This is a simple F = ma equation. We have the mass and we have the acceleration, so
F = 1298(17) and
F = 22066 which rounds correctly to
F = 22000N
The magnitude of the net force of object with a mass of 1298 kg is accelerating at a rate of 17 m/s² is 22066N
HOW TO CALCULATE NET FORCE:
The net force of a body can be calculated by multiplying the mass of the body by its acceleration. That is;Force (N) = mass (kg) × acceleration (m/s²)According to this question, an object with a mass of 1298 kg is accelerating at a rate of 17 m/s². The net force can be calculated as follows:F = 1298Kg × 17m/s²F = 22066NTherefore, the magnitude of the net force of object with a mass of 1298 kg is accelerating at a rate of 17 m/s² is 22066N.Learn more at: https://brainly.com/question/23245710?referrer=searchResults
Define Acceleration.
Ty!
Answer:
Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.
Wax, like all matter, comes in many phases. What are the three possible
phases?
A. Mixtures
B. Gas
C. Liquid
D. Solid
Multiple choice pls help
Answer:
A and d
Explanation:
Mixture and solid
An air track car with a mass of 0.55 kg and velocity of 5.8 m/s to the right collides and couples with a 0.45 kg car moving to the left with a velocity of 3.9 m/s. What is the combined velocity of the cars just after the collision?
Explanation:
Given:
m1 = 0.55 kg
m2 = 0.45 kg
vi1 = +5.8 m/a
vi2 = -3.9 m/a
Solve for V
m1vi1 + m2vi2 = (m1 + m2)V
(0.55 kg)(+5.8 m/s) + (0.45 kg)(-3.9 m/s) = (0.55 + 0.45)V
V = +1.46 m/a
This means that the combined mass after the collision is moving to the right at 1.46 m/s
A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circuit. The bar covers 1.50 m2 of area in 1.00 second. An EMF of 3.57 V is induced in the circuit. What is the strength of the magnetic field in Tesla?
Answer:
2.38 T
Explanation:
Since the number of coils and the change in time are both 1, I set it up as 3.57=1.50(x) and then solved for x to be 2.38 T.
Describe how an oscilloscope should be used to measure the frequency of the sound wave from the sonometer
Answer:
T = reading (cm) time base (s / cm)
f = 1 / T
Explanation:
An oscilloscope is a piece of equipment that allows you to visualize and measure a wave that reaches you, in the case of having a sonometer this transforms the sound wave into an electrical signal to be introduced through one of the voltage channels of the equipment, on the screen we will see the oscillating alternating signal, if it is fixed we can make the reading, if it is moving the time base and the trigger must be adjusted to stop it.
In the oscilloscope we can read the period of the signal, this is the time it takes for the signal to repeat itself with this value, we can calculate the frequency with the formula, for the reading of the period the distance is measured on the labeled screen and multiplied by the time base
T = reading (cm) time base (s / cm)
f = 1 / T
Below is a single of DNA, What is the complementary base pair for RNA?
AGC, CGT, ATA, GAT
5. How do you represent the strength of a force in a free-body diagram?
what instrument used measure
to volume of water
Answer: A Graduated Cylinder or A Beaker ?
Explanation:
Which best illustrates how the carrier wave would appear after pulse modulation?
Answer is the second one
After extensive, detailed calculation, contemplation, investigation, and consideration, my tentative guess is that the second choice is the correct one.
Two vehicles A and B accelerate uniformly from rest.
Vehicle A attains a maximum velocity of 30ms - in los
while B attains a maximum velocil) ol 40ms in the same
time. Both vehicles maintain these velocities for 6s belore
they are decelerated to rest in 6s and 4s respectively
Sketch on the same axes, velocity time graphs
for the motion of the vehicles
Calculate the velocity of each vehicle 18s aftur
the start. (VA
= 20ms -land vs
and vs = 20ms-')
How far will the two vehicles be from one
another during the moment in (ii) above?
(SA = 380m and SB
= 500m: SAB
120m). plz help
Answer:
(i) Please find attached the required velocity time graphs plotted with MS Excel
(ii) The velocity of vehicle A at the 18th second = 20 m/s
The velocity of vehicle B at the 18th second = 0 m/s
(iii) The distance between the two vehicles at the moment in (ii) above is 60 meters
Explanation:
The given parameters of the motion of vehicles A and B are;
The acceleration of vehicles A and B = Uniform acceleration starting from rest
The maximum velocity attained by vehicle A = 30 m/s
The time it takes vehicle A to attain maximum velocity = 10 s
The maximum velocity attained by vehicle B = 30 m/s
The time it takes vehicle B to attain maximum velocity = The time it takes vehicle A to attain maximum velocity = 10 s
The time duration vehicle A maintains its maximum velocity = 6 s
The time duration vehicle B maintains its maximum velocity = 4 s
(i) From the question, we get the following table;
[tex]\begin{array}{ccc}Time &V_A&V_B\\0&0&0\\10&30&40\\14&30&40\\16&30&20\\18&20&0\\22&0&\end{array}[/tex]
From the above table the velocity time graphs of vehicles A and B is created with MS Excel and can included here
(ii) The velocity of vehicle A at the start = 0 m/s
After accelerating for 10 seconds, the velocity of vehicle A = The maximum velocity of vehicle A = 30 m/s
The maximum velocity is maintained for 6 seconds which gives;
At 10 s + 6 s = 16 s, the velocity of vehicle A = 30 m/s
The time it takes vehicle A to decelerate to rest = 6 s
The deceleration of vehicle A, [tex]a_A[/tex] = (30 m/s - 0 m/s)/(6 s) = 5 m/s²
Therefore, we get;
v = u - [tex]a_A[/tex]·t
At the 18th second, the deceleration time, t = 18 s - 16 s = 2 s
u = 30 m/s
∴ v₁₈ = 30 - 5 × 2 = 20
The velocity of vehicle A at the 18th second, [tex]V_{18A}[/tex] = 20 m/s
For vehicle B, we have;
At the 14th second, the velocity of vehicle B = 40 m/s
Vehicle B decelerates to rest in, t = 4 s
The deceleration of vehicle B, [tex]a_B[/tex] = (40 m/s - 0 m/s)/(4 s) = 10 m/s²
For vehicle B, at the 18th second, t = 18 s - 14 s = 4 s
∴ [tex]v_{18B}[/tex] = 40 m/s - 10 m/s² × 4 s = 0 m/s
The velocity of the vehicle B at 18th second, [tex]v_{18B}[/tex] = 0 m/s
(iii) The distance covered by vehicle A up to the 18th second is given by the area under the velocity-time graph as follows;
The area triangle A₁ = (1/2) × 10 × 30 = 150
Area of rectangle, A₂ = 6 × 30 = 180
Area of trapezoid, A₃ = (1/2) × (30 + 20) × 2 = 50
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = A₁ + A₂ + A₃
∴ [tex]S_A[/tex] = 150 + 180 + 50 = 380
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = 380 m
The distance covered by the vehicle B in the 18th second is given by the area under the velocity time graph of vehicle B as follows;
Area of trapezoid, A₅ = (1/2) × (18 + 4) × 40 = 440
The distance covered by the trapezoid, [tex]S_B[/tex] = 440 m
The distance of the two vehicles apart at the 18t second, [tex]S_{AB}[/tex] = [tex]S_B[/tex] - [tex]S_A[/tex]
∴ [tex]S_{AB}[/tex] = 440 m - 380 m = 60 m
The distance of the two vehicles from one another at the 18th second, [tex]S_{AB}[/tex] = 60 m.
The half-life of iodine-131 is 8 days. If a sample originally contains 0.96 g of the isotope, how much will remain after 24 days?
Answer: you ever get the awnser?
Explanation:
Answer: 0.12 g
Explanation: I got it right on the quiz.
Direction: Write TRUE if the statement is correct, and FALSE if it is not
correct
3. When light strikes a black surface, it is reflected by the surface and
nothing is absorbed.
4. Mirrors are used in telescopes because they have the ability to reflect
5. Transmission in the passing of light through some materials
-----------------------------------------------------------------------------------------------------------------
When light strikes a black surface, it is reflected by the surface and
nothing is absorbed This would be False because black absorbs the light not reflect
Mirrors are used in telescopes because they have the ability to reflect
True? Telescopes designed with mirrors avoid the problems of refracting telescopes. Because the light is reflected from the front surface only, flaws and bubbles within the glass do not affect the path of the light
Transmission in the passing of light through some materials
False? Some materials allow much of the light that falls on them to be transmitted through the material without being reflected. Materials that allow the transmission of light waves through them are called optically transparent. ... Materials which do not allow the transmission of any light wave frequencies are called opaque.
differences between weightlessness in space and weightlessness in earth
Answer:
it depends on a person's own weight
Answer:
The gravity is roughly the same. The inverse square law applies to gravity and that means that being 60 miles above Earth is about the same as being on Earth. The thing is, they are going really fast in an orbit and thus falling around the Earth. The weightlessness comes from a sort of cancellation of gravity pulling them down and their going perpendicular to that force. The forces are cancelling and making them relatively “weightless”. It’s not really weightlessness but just an equilibrium reached between the two accelerations of gravity and their motion against the pull of the Earth.
Explanation:
HELLPPPPPPP FASTTTTBDJEJDJDJSJJWJWJW
The Drake Equation The Drake Equation Provides an estimate of how many planets there are in the Solar System that may harbor technically communicative life-forms. Provides an estimate of how many planets there are in our galaxy that may harbor technically communicative life-forms. Provides an estimate of how many planets there are in our galaxy that may harbor life-forms of any kind, no matter how primitive they may be. Provides an estimate of how many planets there are in the Universe that may harbor technically communicative life-forms.
Answer:
Provides an estimate of how many planets there are in our galaxy that may harbor technically communicative life-forms.
Explanation:
A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.
Basically, the planets are divided into two (2) main categories and these includes;
I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.
II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.
These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.
Some examples of the planet are Mars, Venus, Earth, Mercury, Neptune, Jupiter, Saturn, Uranus, etc.
The Drake equation provides an estimate of how many planets there are in our galaxy that may harbor technically communicative life-forms. It is a probabilistic mathematical expression.
Answer:
The correct answer would be:
B.
the number of communicating civilizations in the cosmos
#PLATOFAM
Have a nice day!
Formula:
F = ma
m = F/a
a = F/m
1. What is the force of the object, if it has a mass of 25kg moving 3 m/s2?
Answer:
55N
Explanation:
Using Newton's second law of motion:
F=ma
Force=mass × acceleration
F=25×2.2
F=55N
So 55 Newtons are needed
Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
for the following equation answer the following:
Al + O2+ heat -----> Al203
1. Balance this chemical reaction
2. What type of chemical reaction is this?
3. is this endothermic or an exothermic reaction
Answer:
4Al + 3O2 + heat ------> 2Al2O3
Explanation:
It is endothermic reaction.
sheet of paper and a ball having same mass are dropped from the same height and obviously paper balls faster than a sheet of paper. what conclusion can be drawn from this acticity?
Answer:
In free fall, all items will fall at the same time. You were told that they have the same mass hence g×t which is constant.Un cuerpo se mueve por una carretera que tiene rozamiento.¿Podríamos aplicar el principio de conservación de la energía mecánica? ¿Qué requisitos se han de cumplir para poder aplicarla?
Answer:
Sí se puede aplicar el Principio de Conservación de la Energía Mécanica siempre y cuando se considere los efectos de pérdida de energía a causa del rozamiento, de lo contrario, no se cumpliría el requisito de conservación derivado del citado principio de conservación.
Explanation:
Consideremos que el cuerpo representa nuestro sistema de estudio, el cual se desplaza por una carretera y experimenta rozamiento, significando cambios en la energía cinética y potencial gravitacional. La presencia de rozamiento indica una disipación de la energía del cuerpo, cuya energía mecánica total disminuye, significando un sistema no conservativo.
Sí se puede aplicar el Principio de Conservación de la Energía Mécanica siempre y cuando se considere los efectos de pérdida de energía a causa del rozamiento, de lo contrario, no se cumpliría el requisito de conservación derivado del citado principio de conservación.
NEED HELP The main difference between kinetic energy and potential energy is thatSingle choice.
(2 Points)
kinetic energy involves position, and potential energy involves motion.
kinetic energy involves motion, and potential energy involves position.
although both energies involve motion, only kinetic energy involves position.
although both energies involve position, only potential energy involves motion.
Answer:
kinetic energy involves motion, and potential energy involves position.although both energies involve position, only potential energy involves motion.hope it is helpful to you ☺️☺️✌️
True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces. (dont answer)
anyways free p o i n ts...
Answer:
truuuuuuuuuuuuuuuuuuuuuuuuujuuuuuuuur
Answer:
true
Explanation:
I took a test this year and I know the answer
What is the electric field strenght in units of N/C if the flux through a 2.0m by 1.0m rectangular surface is 396Nm2/C, if the electric field is uniform, and if the plane of the surface is at an angle of π/3 radians with respect to the direction of the field ?
Answer:
The appropriate answer is "396 N/C".
Explanation:
The give values are:
Rectangular surface,
[tex]\Phi_e=396 \ N.m^2/C[/tex]
[tex]a = 2 \ m[/tex]
[tex]b = 1 \ m[/tex]
Angle,
[tex]\theta =\frac{\pi}{3} \ radian[/tex]
Now,
The area of rectangle (A) will be:
= [tex]a\times b[/tex]
= [tex]2\times 1[/tex]
= [tex]2 \ m^2[/tex]
hence,
The electric field strength will be:
⇒ [tex]\Phi_e=E.A Cos \theta[/tex]
or,
⇒ [tex]E=\frac{\Phi_e}{ACos \theta}[/tex]
On putting the given values, we get
⇒ [tex]=\frac{396}{2\times Cos(\frac{\pi}{3} )}[/tex]
⇒ [tex]=\frac{396}{2\times 0.5}[/tex]
⇒ [tex]=\frac{396}{1}[/tex]
⇒ [tex]=396 \ N/C[/tex]
A very long cylindrical shell made of copper has an inner radius 2 cm and an outer radius of 3 cm. This shell concentrically surrounds a very long charged aluminum rod of radius 1 cm with a charge density of 4 pC/m. All charges on the aluminum rod reside at its surface. The inner surface of the copper shell has exactly opposite charge to that of the aluminum rod while the outer surface of the copper shell has the same charge as the aluminum rod. Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
Question:
Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
(a) 0.5 cm, (b) 1.5 cm, (c) 2.5 cm, (d) 3.5 cm, (e) 7.0 cm
Answer:
(a) 0
(b) 4.795 N/C
(c) 2.877 N/C
(d) 2.055 N/C
(e) 1.027 N/C
Explanation:
The given parameters are;
The inner radius of the copper = 2 cm
The outer radius of the copper - 3 cm
The radius of the aluminum rod, r = 1 cm
The radius of the aluminum rod = 4 pC/m
a) The charge at the 0.5 cm from the center of the aluminum rod, E = 0
There is no charge inside the rod given that the aluminum road is a conductor of electricity, having all the charge on its surface
b) At 1.5 cm, we have;
[tex]E = \dfrac{2 \cdot \lambda}{4 \cdot \pi \cdot r \cdot \epsilon_0}[/tex]
Where;
[tex]\dfrac{ \lambda}{4 \cdot \pi \cdot \epsilon_0} = 8.99 \times 10^9 \times 4 \times 10^{-12}[/tex]
r = 1.5 cm = 0.015 m
∴ E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.015 ≈ 4.795
The magnitude of the electric field, E = 4.795 N/C
The direction of the charge depends on the charge sign on the rod
c) At 2.5 cm, we have;
r = 2.5 cm = 0.025 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.025 ≈ 2.877
The magnitude of the electric field, E ≈ 2.877 N/C
d) At r = 3.5 cm, we have;
r = 3.5 cm = 0.035 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.035 ≈ 2.055
The magnitude of the electric field, E ≈ 2.055 N/C
e) At
r = 7.0 cm = 0.070 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.07 ≈ 1.027
The magnitude of the electric field, E ≈ 1.027 N/C
What is role of force on the speed of moving object?
Explanation:
this is the ans hope it works
Answer:
Forces make things speed up (or accelerate). When a force pushes or pulls the object, the object will move in the direction of the force. The bigger the force, and the lighter the object, the greater the acceleration.
Explanation:
The action from a force can cause an object to move or speed up (accelerate), to slow down (decelerate), to stop, or to change direction. Since any change in velocity is considered acceleration, it can be said that a force on an object results in the acceleration of an object.
A simple mathematical relationship exists between the mass of an object (m), the net force on the object (f) and its acceleration (a). The acceleration of an object is directly proportional to the net force and indirectly proportional to the object’s mass (a = f/m).
During which radioactive decay process does the mass number of a nucleus change?
A. Beta Decay (Electron)
B. Beta Decay (Positron)
C. Alpha Decay
D. Gamma Decay
Answer:
Alpha decay
Explanation:
Answer:
C
Explanation:
Alpha Decay
A juggler is throwing balls up in the air and catching them. An observer in the crowd makes the statement that the potential and kinetic energy of the ball is the same when the ball is halfway down from its highest point. In one paragraph, using your own words, explain using the relationship of mechanical energy, potential energy, and kinetic energy why the observer is correct.
Answer:
do you have the answer?
Explanation:
if so whats the answer?
Fundamentally, pressure is defined as force per unit area. What is the source of the force in a gas sample? A) The force is from gravity acting on the particles. B) The force is composed of the sum of the collisions only between gas molecules. C) The force is composed of the sum of the collisions only between the gas molecules and the container. D) The force is composed of the sum of all collisions--between the gas molecules, each other and the container. E) The force was imparted to the container in its initial filling, a transfer of momentum.
Answer:
Option C
Explanation:
Given
Pressure = Force /Area
For any gas sample, force is defined as basically the force exerted by the gas molecules when they strike the surface (with in which they are contained) and bounce back.
Hence, Option C is the correct
If F=15 N, a=3 m/s², m=? *
45 Kg
5 kg
0.2 kg
0 kg
Answer:
5 kg
Explanation: