Answer:
A has larger grain size simple
Specimen B has a larger grain size compared to specimen A as per the given scenario.
What is ASTM grain size?The grain size number, which may be determined using micrography, is a unit of grain size defined by the ASTM committees.
Instead of counting grains, the comparison method compares the grain structure to a sequence of graded images, which can be shown on a wall chart, clear plastic overlays, or a reticle for grain counting eyepieces.
An indicator of grain size, the ASTM grain size number is an inverse measure; the lower the ASTM grain size number, the larger the grain size.
The ASTM grain size number for specimen A in this instance is 3, indicating a smaller grain size than specimen B's grain size, which is 8.
Thus, specimen B is the answer.
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The cost of hiring new employees outpaces the raises for established employees is
A.
Salary compression
B.
Occupational based pay
C.
Merit pay
D.
Need for Achievement
Answer:
do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or
For automobile engines, identify the best choice of motor oil.
A. High viscosity for Maine in the winter and low viscosity for Florida in the summer.
B. Low viscosity for Maine in the winter and low viscosity for Florida in the summer.
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
D. High viscosity for Maine in the winter and high viscosity for Florida in the summer.
E. It does not matter what the rating is for the motor oil.
Answer:
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
Explanation:
The choice of motor oil or engine oil depends on the type of engine and also on the type of climate on which the engine runs.
In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.
But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.
Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.
Therefore, option (c) is correct.
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is
Answer:
The answer is below
Explanation:
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is a) mercury b) water
Solution:
A manometer is a device used to measure pressure. A manometer is made up of a U shaped tube containing liquid. The difference of pressure in the two arms causes the liquid to reach different heights.
a) The density of mercury ([tex]\rho_{Hg}[/tex]) = 13600 kg/m³, Pressure (P) = 65 kPa and g = 9.8 m/s², h = distance between the two fluid levels
[tex]P=\rho_{Hg}*g*h\\\\h=\frac{P}{\rho_{Hg}*g} =\frac{65*10^3\ Pa}{13600*9.81}=0.487\ m[/tex]
b) For water, [tex]\rho_w[/tex] = 1000 kg/m³, hence:
[tex]P=\rho_{w}*g*h\\\\h=\frac{P}{\rho_{w}*g} =\frac{65*10^3\ Pa}{1000*9.81}=6.6\ m[/tex]
Find the value of L
I= 1.52-30A
Vcoil
+
225LO V
50 HZ
sout I VE
O 0.441 H
0 0.33 Н
O 0.451 H
O 0.562 H
Answer:
the value is 356732 Volt
An air-conditioning system is used to maintain a house at 70^\circ{} ∘ F when the temperature outside is 100^\circ{} ∘ F. The house is gaining heat through the walls and the windows at a rate of 800 Btu/min, and the heat generation rate within the house from people, lights, and appliances amounts to 100 Btu/min. Determine the minimum power input required for this air-conditioning system. Answer: 1.20 hp
Answer:
the minimum power input required for this air-conditioning system is 1.20 hp
Explanation:
Given the data in the question;
Temperature inside ( Sink ) T[tex]_L[/tex] = 70°F = ( 70 + 460 )R = 530 R
temperature outside ( source )T[tex]_H[/tex] = 100°F = ( 100 + 460 )R = 560 R
[tex]Q_W[/tex] = 800 Btu/min
[tex]Q_L[/tex] = 100 Btu/min
Now, from the equation of coefficient of performance of refrigerator;
[tex]COP_{Ref[/tex] = Desired output / Required input
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] --------- let this be equation 1
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
where [tex]Q_W[/tex] is the rate heat gained through the wall
[tex]Q_L[/tex] is the heat generation from people and lights and appliances.
Now, lets consider the equation coefficient of performance of refrigerator in terms of temperatures;
[tex]COP_{Ref[/tex] = [tex]T_L[/tex] / ( [tex]T_H[/tex] - [tex]T_L[/tex] )
we substitute
[tex]COP_{Ref[/tex] = 530 / ( 560 - 530 )
[tex]COP_{Ref[/tex] = 530 / 30
[tex]COP_{Ref[/tex] = 17.667
so we substitute into equation 1;
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] ---------
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
17.667 = ( 100 + 800 ) / [tex]W_{net[/tex]
17.667 = 900 / [tex]W_{net[/tex]
[tex]W_{net[/tex] = 900 / 17.667
[tex]W_{net[/tex] = 50.94 Btu/min
[tex]W_{net[/tex] = ( 50.94 / 42.53 ) hp
[tex]W_{net[/tex] = 1.198 hp ≈ 1.20 hp
Therefore, the minimum power input required for this air-conditioning system is 1.20 hp
what are the design steps of surface dressing at urban street??
1.1.2
Energy
1.1.3
Mass
1.1.4
Temperature
Power
1.1.5
1.2 State Ohm's law
1.3 State Joule's law
1.5 Name four factors that9 determine the resistance of the material
1.6 What is the SI Unit for current?
QUESTION 2
Answer:
the energy is sgdrh35679
You would like to use a simple water-filled barometer (an inverted tube in a container of water) to measure the atmospheric pressure on a day when the pressure is 102.5 kPa. What would be the minimum height required for such a barometer to work
Answer:
[tex]h=10.459m[/tex]
Explanation:
Pressure [tex]P=102.5kPa[/tex]
Atmospheric Pressure [tex]P=1000kg/m^3[/tex]
Generally the equation for Pressure P is mathematically given by
[tex]P=pgh[/tex]
[tex]P=1000*9.8*h[/tex]
[tex]h=\frac{102.5*10^3}{1000*9.8}[/tex]
[tex]h=10.459m[/tex]
______ are an idication that your vehicle may be developing a cooling system problem.
Answer:
The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is an idication that your vehicle may be developing a cooling system problem.
Explanation:
A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of square cross section (1 m x 1 m). The axis of the pipe is centered in the casing. The outer surfaces of the casing are maintained at 500 K. Calculate the heat loss per 1m length of the pipe. Please make sure to follow the rules required for all homework assignments.
Answer:
The correct answer is "1341.288 W/m".
Explanation:
Given that:
T₁ = 300 K
T₂ = 500 K
Diameter,
d = 0.2 m
Length,
l = 1 m
As we know,
The shape factor will be:
⇒ [tex]SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}[/tex]
By putting the value, we get
⇒ [tex]=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}[/tex]
⇒ [tex]=3.7258 \ l[/tex]
hence,
The heat loss will be:
⇒ [tex]Q=SF\times K(T_2-T_1)[/tex]
[tex]=3.7258\times 1\times 1.8\times (500-300)[/tex]
[tex]=3.7258\times 1.8\times (200)[/tex]
[tex]=1341.288 \ W/m[/tex]
Question 3 (12 points)
A pump of 1200rpm rotational speed is connected to a delivery pipe (rising main) of 500m
length and 0.025 Darcy friction factor. The following plot shows the pump performance and the
rising main curve.
40
Reming main
25
нер
20
15
100
Eficency
50
Pump
ES
10
20
50
60
Q (L.)
I
Answer the following short questions
1) The flow rate delivered by the pump when connected to the rising main is
2) The total head delivered by the pump when connected to the rising main is
3) The static lift (Hs) is:
4) What is the power produced (output) and consumed (input) by the pump?
5) What is the diameter of the rising main!
6) What is the sort of this pump
so long so long so long so long so long
Explanation:
so long so long so long so long so long so long so long so long so long so long
(1) Estimate the specific volume in cm3 /g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the virial equation and compare to the experimental values of 70.58 and 3.90, respectively.
(2) Estimate the specific volume in cm3/g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the compressibility factor charts and compare to the experimental values2 of 70.58 and 3.90, respectively.
Answer:
70.66 cm^3
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
Explanation:
Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----
Viral equation can also be rewritten as :
Z = 1 + B ( P/RT )
B ( function of time )
Temperature = 310 K
P1 = 8 bar
P2 = 75 bar
Determine the specific volume in cm^3
V = 70.66 cm^3
b) comparing the specific volumes to the experimental values
70.58 and 3.90
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
attached below is the detailed solution
Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final
Answer:
Take a 3 to 8 decoder with active low outputs
Assuming you are familiar with the functioning of decoders,
The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.
Next we examine the truth table of the full subtractor i formatted in the picture.
Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!
Explanation:
hopi it to help you!!
Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the account at the end of 10 years?
Answer:
2,160,000
Explanation:
8/100 × 200000/1 = 8/1 × 2000/1
2000 × 8 = 16,000 = interest
200,000 + 16,000 = 216,000
216,000 × 10 = 2,160,000 = amount in bank account
affect the amount and rate the alcohol reaches the
bloodstream.
Answer:
Answer to the following question is as follows;
Explanation:
The amount of alcohol consumption can be influenced by a variety of things, including food.
The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.
Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would you be most and least likely to do? (A). Reach out to your manager to discuss the situation.Try to identify the best way to support the new associates. (B).Remind your coworkers of performance expectations and that they need to be working harder to complete tasks. (C). Offer to help others complete their tasks; observe their work process and provide some tips that might help them. (D). Give your coworkers more time to figure out how to do the task; they likely just need more practice with what they've already learned.
explain the term electric current as used in engineering principles
Answer:
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.Current is directly proportional to voltage, inversely proportional to resistance. One of the most common electrical measurements you'll use is the watt, a unit of electrical power: W (Watts) = E (Volts) x I (Amperes). The quantity of electric charge is measured in coulombs.They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.
Explanation:
hey mate this is the best answer if you're studying engineering!
features of purpose student management system
Answer:
Cloud Enabled: ...
Student Behaviour Tracking and Analytics: ...
Campus Recruitment. ...
Communication & social features: ...
Admission Management: ...
Account Management: ...
Laboratory Management: ...
Profile Management:
Explanation:
features of purpose student management system
List five technology tools with respect to I.C.T
stating
their respective use.
Answer:
laptop printer scanner data
A horizontal piston/cylinder arrangement is placed in a constant-temperature bath. The piston sides in the cylinder with negligible friction and an external force holds it in place against an initial gas pressure of 14 bar. The initial gas volume is 0.03 m3. The external fore on the piston is reduced gradually and the gas expands isothermally as its volume triples. If the volume of the gas is related to its pressure so that the product PV is constant.
(a) What is the work by the gas in moving the external force?
(b) How much work would be done if the external force were suddenly reduced to half its initial value instead of being gradually
reduced?
Answer:
[tex]W=46141.72~J[/tex]
Explanation:
Given:
initial pressure, [tex]P_1=14~bar=1.4\times10^6~Pa[/tex]
initial volume, [tex]V_1=0.03~m^3[/tex]
After isothermal expansion:
final volume, [tex]V_2=3V_1=0.09~m^3[/tex]
a)
We have the work done in isothermal process as:
[tex]W=P_1.V_1\ln(\frac{V_2}{V_1} )[/tex]
[tex]W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )[/tex]
[tex]W=46141.72~J[/tex] is the work by the gas in moving the external force
b)
When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.
[tex]P_1V_1^{\gamma}=P_2V_2^{\gamma}[/tex]
[tex]14\times 0.03^{1.4}=P_2\times 0.09^{1.4}[/tex]
[tex]P_2=3~bar[/tex]
Now, using the formula for work done in adiabatic process:
[tex]W=\frac{P_1V_1-P_2V_2}{\gamma-1}[/tex]
[tex]W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}[/tex]
[tex]W=3750~J[/tex]
A projectile is fired horizontally with an initial speed of 50.0 m/s. Neglect air resistance.a) What is the magnitude of the displacement of the projectile 3.00 s after it is fired?b) What is the speed of the projectile 3.00 s after it is fired?c) What is the magnitude of the acceleration of the projectile 3.00 s after it is fired?
Answer:
a) 156 meters
b) 58 m/s
c) 9.8 m/s^2
Explanation:
a) The horizontal displacement X = V *t
X = 50 * 3 = 150 meters
Vertical displacement = y = – g * t² / 2
Y = -9.8 *3*3/2 = -4.9*9 = 44.1
Net Displacement = Sqrt (X^2 +Y^2) = 156.34 = 156 meters
b) Speed of the projectile
vx = 50 m/s
vy = t*g = 9.8*3 = 29.4
V = Sqrt (vx^2 + vy^2) = 58 m/s
c) Acceleration is the acceleration due to gravity = 9.8 m/s^2
The magnitude of the displacement of the projectile is equal to 156 meters.
Given the following data:
Initial speed = 50.0 m/s. Time = 3.00 seconds.Scientific data:
Acceleration due to gravity (g) = [tex]9.8 m/s^2.[/tex]How to calculate the displacement.Mathematically, the magnitude of the displacement of a projectile is given by this formula:
[tex]Horizontal\;displacement = Vt\\\\Horizontal\;displacement = 50.0 \times 3.00[/tex]
Horizontal displacement = 150.0 meters.
[tex]Vertical displacement =\frac{1}{2} gt^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 3^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 9[/tex]
Vertical displacement = 44.1 meters.
[tex]D^2 = X^2 +Y^2\\\\D =\sqrt{44.1^2+150^2}[/tex]
D = 156.34 ≈ 156 meters.
b. For the speed of the projectile:
Vertical speed = tg
[tex]V_y = tg = 9.8\times3\\\\ V_y = 29.4\;m/s[/tex]
[tex]D^2 = V_x^2 +V_y^2\\\\D =\sqrt{50^2+29.4^2}[/tex]
D = 58 m/s.
c) The magnitude of the acceleration of the projectile is equal to the acceleration due to gravity ([tex]9.8 \;m/s^2[/tex]).
Read more on acceleration here: brainly.com/question/247283
Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical brass spacers. Knowing that the average normal stress must not exceed 210 MPa in the bolts and 145 MPa in the spacers, determine the outer diameter of the spacers that yields the most economical and safe design.
Answer:
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Explanation:
For steel bolt
Stress = 210 MPa or 210 N/mm2
Pressure = Stress* Area
Pbolt = 210 N/mm2 * 16^2 *(pi)/4
Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6 N
For Brass spacer
Pressure = 42201.6 N
Area of Brass spacer = Pressure/Stress
Area of Brass spacer = 42201.6 N/145 N/mm^2 = 291.044 mm^2
Area of Brass spacer = (pi) (d^2 - 16^2)/4 = 291.044 mm^2
d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758
d^2 = 370.758 + 16^2
d^2 = 626.758
d = 25.03 mm
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Some_____
include peanut butter, bacon, and chocolate.
Snap traps baits
Glue boards
Catchalls
IGRs
Bait stations
Answer:
it’s IGS
Explanation:
because i read
Answer:
snap trap baits
Explanation: its kind of obvi, but i took the test and got it right.
What is the purpose of using state space representation?
Answer:
In control engineering, a state-space representation is a mathematical model of a physical system as a set of input, output and state variables related by first-order differential equations or difference equations.
Explanation:
A 5 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10ns propagation delay. The output of the inverter goes to the Y input of the OR gate.
a. Draw the circuit
b. Plot the output of the clock for two cycles. Show times and voltages.
c. Plot the output of the inverter in the same plot. Show times and voltages.
d. Plot the output of the OR gate in the same plot. Show times and voltages.
Answer:
Timing Diagrams 15 pts. A 10 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10 ns propagation delay. The output of the inverter goes to the Y input of the OR gate. a) Draw the circuit. 2 pts. b) Plot the output of the clock for two cycles. Show times and voltages. 5 pts. c) On the same page as part (b) plot the output of the inverter. Show times and voltages. 3 pts. d) On the same page as parts (b & c) plot the output of the OR gate. Show times and voltages. 5 pts.
During steady state operation, a gear box receives 60kW through the input shaft and delivers power through the output shaft. For the gearbox as the system, the rate of energy transfer by convection is given by Q=-hA(Tb - T) Where h 0.171kW/m2.k is the heat transfer coefficient, A=1.0m2 is the outer surface are of the gearbox. Tb 300k is the temperature at the outer surface and T 293 K is the temperature of the surrounding air. For the gearbox, evaluate the heat transfer rate and the power delivered through the output shaft, in kW.
Answer:
- the heat transfer rate is -1.197 kW
- the power delivered through the output shaft is 58.8 kW
Explanation:
Given the data in the question;
A gear box receives 60kW through the input shaft and delivers power through the output shaft
Heat received by gear box W₁ = - 60 kW
heat transfer coefficient h = 0.171k W/m².k
Area A = 1.0 m²
Outer surface temperature T_b = 300 K
Surrounding temperature T_f = 293 K
Now,
Heat transfer rate
Q = -hA( T_b - T_f )
we substitute
Q = -( 0.171 ) × 1.0 × ( 300 - 293 )
Q = -( 0.171 ) × 1.0 × 7
Q = -1.197 kW
Hence, the heat transfer rate is -1.197 kW
Now, from energy balance equation;
Heat transfer rate = Heat received by gearbox + Power delivered by output shaft
i.e
Q = W₁ + W₂
so we substitute
-1.197 = -60 + W₂
W₂ = 60 - 1.197
W₂ = 58.8 kW
Therefore, the power delivered through the output shaft is 58.8 kW
Determine the following parameters for the water having quality x=0.7 at 200 kPa:
a) the phase
compressed liquid
superheated vapor
saturated liquid
saturated vapor
saturated mixture
b) temperature (in °C)
c) specific volume, in m3/kg
d) specific energy, in kJ/kg
e) specific enthalpy, in kJ/kg
f) What is the enthalpy of 500 g of water (in kJ)?
Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T = [tex]$T_{saturated}$[/tex]
Temperature = 120.21°C
c). Specific volume
[tex]$v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$[/tex]
[tex]$v_x=v_f+x(v_g-v_f)$[/tex]
[tex]$=0.001061+0.7(0.88578-0.001061)$[/tex]
[tex]$=0.62036 \ m^3/kg$[/tex]
d). Specific energy ([tex]u_x[/tex])
[tex]$u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$[/tex]
[tex]$u_x=504.5 + 0.7(2024.6)$[/tex]
[tex]$=1921.72 \ kJ/kg$[/tex]
e). Specific enthalpy [tex]$(h_x)$[/tex]
At [tex]$h_f = 504.71, \ \ h_{fg} = 2201.6$[/tex]
[tex]h_x=504.71+(0.7\times 2201.6)[/tex]
[tex]$= 2045.83 \ kJ/kg$[/tex]
f). Enthalpy at m = 0.5 kg
[tex]$H=mh_x$[/tex]
[tex]$= 0.5 \times 2045.83$[/tex]
= 1022.91 kJ
what is the difference between a series circuit and a parallel circuit?
Answer:
In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.
Explanation:
I have 50 kVA delta-wye transformer with 3 single phases secondary (line-neutral) delivered to 3 houses, So if one of the 3 houses drown more power would that affect another 2 houses, or each phase can only handle certain amount of power separately?
Answer:
tie es que sumar restar y multiplicar
Explanation:
espero que sea así
Consider a 6-bit cyclic redundancy check (CRC) generator, G = 100101, and suppose that D = 1000100100. 1. What is the value of R? (10 pts)
Answer:
The value of R is 10101
Explanation:
As per the given data
D = 1000100100
G = 100101
Redundant bit = 6-bits - 1-bit = 5-bits
No add fice zero to D
D = 100010010000000
Now calculate R as follow
R = D / G
R = 100010010000000 / 100101
R = 10101
Workings are attached with this question