Answer:
Explanation:
a. The amplitude is the measure of the height of the wave from the midline to the top of the wave or the midline to the bottom of the wave (called crests). The midline then divides the whole height in half. Thus, the amplitude of this wave is 9.0 cm.
b. Wavelength is measured from the highest point of one wave to the highest point of the next wave (or from the lowest point of one wave to the lowest point of the next wave, since they are the same). The wavelength of this wave then is 20.0 cm. or [tex]\lambda=20.0cm[/tex]
c. The period, or T, of a wave is found in the equation
[tex]f=\frac{1}{T}[/tex] were f is the frequency of the wave. We were given the frequency, so we plug that in and solve for T:
[tex]50.0=\frac{1}{T}[/tex] so
[tex]T=\frac{1}{50.0}[/tex] and
T = .0200 seconds to the correct number of sig fig's (50.0 has 3 sig fig's in it)
d. The speed of the wave is found in the equation
[tex]f=\frac{v}{\lambda}[/tex] and since we already have the frequency and we solved for the wavelength already, filling in:
[tex]50.0=\frac{v}{20.0}[/tex] and
v = 50.0(20.0) so
v = 1.00 × 10³ m/s
And there you go!
A constant force (3,0,4)N moves a body from point (-5,3,1)m to the point (4,3,3)m. If the initial velocity of the body is (6,1,1)m/s, determine the work done by the force and the angle between the force and the initial velocity of the body
The net displacement of the body is
∆x = (4, 3, 3) m - (-5, 3, 1) m = (9, 0, 2) m
so the work done by F = (3, 0, 4) N in the direction of ∆x is
F • ∆x = (3, 0, 4) • (9, 0, 2) N•m = (27 + 0 + 8) N•m = 35 J
The angle between the force and initial velocity v₀ is θ, such that
F • v₀ = ||F|| ||v₀|| cos(θ)
(3, 0, 4) • (6, 1, 1) N•m/s = √(3² + 0² + 4²) √(6² + 1² + 1²) cos(θ) N•m/s
==> cos(θ) = (18 + 0 + 4) / (√25 × √38) = 22/(5√38)
==> θ = arccos(22/(5√38)) ≈ 44.5°
Which of these samples of water has the most internal energy?
1kg Liquid Water
2kg Steam
1kg Steam
2kg Ice
Answer:
1kg steam will have the maximum energy
The electric motor of an elevator(lift) uses 630kJ of electric energy when raising the elevator and passengers, of total mass 12,500N, through a vertical height of 29m.Calculate the efficiency of the elevator. pppppplease need helpp willl markk the brrainliest
Answer:
Efficiency = 0.575 = 57.5%
Explanation:
First, we will calculate the output energy of the elevator, which is equal to the potential energy acquired by the load.
[tex]O = Potential\ Energy\\O = mgh[/tex]
where,
O = Output = ?
mg = W = Weight = 12500 N
h = height = 29 m
Therefore,
[tex]O = (12500\ N)(29\ m) \\O = 362500\ J = 362.5\ KJ[/tex]
The input is given as:
I = 630 KJ
Thus the efficiency will be:
[tex]Efficiency = \frac{O}{I} = \frac{362.5\ KJ}{630\ KJ}\\\\[/tex]
Efficiency = 0.575 = 57.5%
Which of the following exercises would be BEST for improving muscular strength and endurance?
A.
walking
B.
running
C.
push-ups
D.
bicycling
Answer:
Push-ups
explanation:
Answer:
the anser for your qestion is
c. push- ups
A 3.0 kg hard steel ball collides head on with a 1.0 kg hard steel ball. The balls are moving at 2 m/s in opposite directions before they collide. Upon colliding, the 3.0 kg ball stops. What is the velocity of the 1.0 kg ball after the collision?
Answer:
Explanation:
The Law of Momentum Conservation applies and its equation is:
[tex][(m_1v_1)+(m_2v_2)]_b=[(m_1v_1)+(m_2v_2)]_a[/tex] and filling in and solving for v2:
[tex][(3.0*2.0)+(1.0*-2.0)]_b=[(3.0*0)+(1.0v_2)]_a[/tex] and
6.0 - 2.0 = 0 + 1.0v₂ and
4.0 = v₂ in the initial direction of the 3.0 kg ball (since the velocity of the 3.0 kg ball is positive and the velocity of the 1.0 kg ball is negative and our answer is positive).
5. A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 6400 m away?
Answer:
8.89 secs
Explanation:
720m = 1 sec
6400m = ?
6400/720 = 8.89 secs
Because the pressure falls, water boils at a lower temperature with increasing altitude. Consequently, cake mixes and boiled eggs, among other foods, must be cooked different lengths of time. Determine the boiling temperature of water at 1000 and 2000 m elevation on a standard day, and compare with the sea-level value
Answer:
1) The boiling point of water reduces by 3.28°C at 1,000 m above sea-level
2) The boiling point of water reduces by 6.56°C at 2,000 m above sea-level
Explanation:
The variation of the boiling point of water with elevation is given as follows
The boiling point reduces by 0.5°C for every 152.4 meter increase in elevation
At sea-level, the boiling point temperature of water = 100°C
1) At 1,000 m elevation, the boiling point temperature, T = 100 - (1,000/152.4) × 0.5 ≈ 96.72 °C
Therefore, the boiling point of water reduces by 100° - 96.72° = 3.28°C at 1,000 m above sea-level
2) At 2,000 m elevation, the boiling point temperature, T = 100 - (2,000/152.4) × 0.5 ≈ 93.44°C
The boiling point of water reduces by 100° - 93.44° = 6.56°C at 2,000 m above sea-level
Un punto se ubica en un sistema de coordenadas polar por las coordenadas r = 7.6 m y = 30°. Encuentre las coordenadas x y y de este punto (en m), suponiendo que los dos sistemas de coordenadas tienen el mismo origen.
Answer:
Las coordenadas del punto son [tex](x,y) = (6.582\,m, 3.8\,m)[/tex].
Explanation:
La relación entre un vector en formato polar y uno con formato rectangular con respecto al mismo origen queda sintetizado por la siguiente expresión:
[tex](x, y) = r\cdot (\cos \theta, \sin \theta)[/tex] (1)
Donde:
[tex]r[/tex] - Magnitud de la distancia del punto con respecto al origen, medido en metros.
[tex]\theta[/tex] - Dirección del punto con respecto del semieje +x, medido en grados sexagesimales.
[tex]x,y[/tex] - Coordenadas rectangulares del punto con respecto al origen, medidas en metros.
Si sabemos que [tex]r = 7.6\,m[/tex] y [tex]\theta = 30^{\circ}[/tex], entonces las coordenadas rectangulares del punto con respecto al origen son:
[tex](x,y) = (7.6\,m)\cdot (\cos 30^{\circ}, \sin 30^{\circ})[/tex]
[tex](x,y) = (6.582\,m, 3.8\,m)[/tex]
Las coordenadas del punto son [tex](x,y) = (6.582\,m, 3.8\,m)[/tex].
Which is a characteristic of atoms?
A) They come in ten major types.
B) They are the smallest units of matter.
C) They can be found in nonliving things only.
D) They cannot combine together.
Answer:
c
Explanation:
c
Whay is the other name of negative acceleration.
Answer:
deceleration? I think because the prefix de means to like not or to slow down
Enunciado del ejercicio n° 1
Se lanza un cuerpo verticalmente hacia abajo con una velocidad inicial de 7 m/s.
a) ¿Cuál será su velocidad luego de haber descendido 3 s?
b) ¿Qué distancia habrá descendido en esos 3 s?
c) ¿Cuál será su velocidad después de haber descendido 14 m?
d) Si el cuerpo se lanzó desde una altura de 200 m, ¿en cuánto tiempo alcanzará el suelo?
e) ¿Con qué velocidad lo hará?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 7 m/s
t = 3 s
y = 200 m
h = 14 m
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 2
Se lanza un cuerpo verticalmente hacia arriba con una velocidad inicial de 100 m/s, luego de 4 s de efectuado el lanzamiento su velocidad es de 60 m/s.
a) ¿Cuál es la altura máxima alcanzada?
b) ¿En qué tiempo recorre el móvil esa distancia?
c) ¿Cuánto tarda en volver al punto de partida desde que se lo lanzo?
d) ¿Cuánto tarda en alcanzar alturas de 300 m y 600 m?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 100 m/s
vf = 60 m/s
t = 4 s
y1 = 300 m
y2 = 600 m
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 3
Un observador situado a 40 m de altura ve pasar un cuerpo hacia arriba con una cierta velocidad y al cabo de 10 s lo ve pasar hacia abajo, con una velocidad igual en módulo pero de distinto sentido.
a) ¿Cuál fue la velocidad inicial del móvil?
b) ¿Cuál fue la altura máxima alcanzada?
Usar g = 10 m/s²
Desarrollo
Datos:
t = 10 s
y = 40 m
Fórmulas:
(1) vf = v0 + g·t
(2) y = y0 + v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 4
Desde un 5° piso de un edificio se arroja una piedra verticalmente hacia arriba con una velocidad de 90 km/h, ¿cuánto tardará en llegar a la altura máxima?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 90 km/h
v0 = 25 m/s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 5
Un auto choca a 60 km/h contra una pared sólida, ¿desde qué altura habría que dejarlo caer para producir el mismo efecto?
Usar g = 10 m/s²
Desarrollo
Datos:
vf = 60 km/h
vf = 16,67 m/s
v0 = 0 m/s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 6
Se lanza una pelota hacia arriba y se recoge a los 2 s, calcular:
a) ¿Con qué velocidad fue lanzada?
b) ¿Qué altura alcanzó?
Usar g = 10 m/s²
Desarrollo
Datos:
t = 2 s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 7
Se lanza una pelota de tenis hacia abajo desde una torre con una velocidad de 5 m/s.
a) ¿Qué velocidad tendrá la pelota al cabo de 7 s?
b) ¿Qué espacio habrá recorrido en ese tiempo?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 5 m/s
t = 7 s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 8
Se lanza un cuerpo verticalmente hacia arriba con una velocidad de 60 km/h, se desea saber la altura máxima alcanzada, la velocidad que posee al cabo de 4 s y 30 s, la altura alcanzada a los 8 s, el tiempo total que se encuentra en el aire.
Desarrollo
Datos:
v0 = 60 km/h = (60 km/h)·(1.000 m/km)·(1 h/3.600 s) = 16,67 m/s
t1 = 4 s
t2 = 30 s
t3 = 8 s
Usar g = 10 m/s²
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 9
Se dispara verticalmente hacia arriba un objeto desde una altura de 60 m y se observa que emplea 10 s en llegar al suelo. ¿Con que velocidad se lanzo el objeto?
Desarrollo
Datos:
h0 = 60 m
t = 10 s
g = 9,81 m/s²
Fórmulas:
Δy = v0·t + ½·g·t²
Enunciado del ejercicio n° 10
Se lanza verticalmente hacia abajo una piedra de la parte alta de un edificio de 14 pisos, llega al suelo en 1,5 s, tomando en cuenta que cada piso mide 2,6 m de altura. Calcular la velocidad inicial de la piedra y la velocidad al llegar al piso.
Desarrollo
Datos:
Número de pisos = 14
Altura de cada piso = 2,6 m
t = 1,5 s
g = 9,81 m/s²
Fórmulas:
1) Δh = v0·t + ½·g·t²
2) vf = v0 + g·t
*xfv se que es mucho pero e visto videos pero no me sale muy bien los resultados con mis compañeros. xfv alguien que me ayude
Answer:
34
Explanation:
El peso(w) de una persona en la Tierra es 550N. Determinar la masa (m) de la persona y el peso (w) de la misma en la Luna
The question is: The weight (w) of a person on Earth is 550N. Determine the mass (m) of the person and the weight (w) of the person on the Moon.
Answer: The mass (m) of the person is 550 N and the weight (w) of the person on the Moon is 891 kg.
Explanation:
Given: Mass = 550 N
When a person moves towards moon then its mass will remain the same but there will occur change in its weight because the acceleration due to gravity on moon is different than that on Earth.
Therefore, formula used to calculate the weight of person on moon is as follows.
[tex]W = m \times g_{m}[/tex]
where,
m = mass
[tex]g_{m}[/tex] = acceleration due to gravity on moon = 1.62 [tex]m/s^{2}[/tex]
Substitute the values into above formula as follows.
[tex]W = m \times g_{m}\\= 550 N \times 1.62 m/s^{2}\\ (1 N = 1 kg \times m/s^{2})\\= 891 kg[/tex]
Thus, we can conclude that the mass (m) of the person is 550 N and the weight (w) of the person on the Moon is 891 kg.
Why don't gorilla evolve to human if scientist was about to said that human evolve from gorilla to human?
Answer:
"Man's mind is far too advanced for his survival needs."
See also "Wallace", Darwin's junior partner who couldn't explain the gap in intelligence.
1) An average soccer ball has a mass of .4 kg. If a soccer ball is kicked with a force of 750 Newtons, what is the acceleration of the soccer ball after it has been kicked?
2) If a tiger runs at a speed of about 12.3 m/s, how far will it travel in 25 seconds?
Answer:
Explanation:
#1 uses Newton's 2nd Law: F = ma so filling in:
750 = .4a and
a = 1875 m/s/s
#2 uses d = rt so
d = 12.3(25) and
d = 307.5 m
Question 2 of 10
A wave has a wavelength of 0.05 m and a wave speed of 10 m/s. What is the
frequency of the wave?
O A. 5.0 Hz
B. 200 Hz
C. 2.0 Hz
O D. 0.50 Hz
Explanation:
everything can be found in the picture
If an object of mass 70kg falls from a height of 500 m, what is the maximum velocity of the object?
Answer:
H = 1/2 * g * t^2 since initial velocity is zero
v = g * t where v is the final velocity
t = v / g
H = 1/2 g * v^2 / g^2 = 1/2 v^2 / g
v = (2 * H * g)^1.2
v = (2 * 500 * 9.8)^1/2 = 99 m/s
Check: t = v / g = 99 / 9.8 = 10.1 sec
H = 1/2 * 9.8 * 10.1^2 = 500 m
what happens when a candle burns?
a) oxygen is used up
b) nitrogen is used up
c) hydrogen is produced
d) carbon dioxide is consumed
Answer:
oxygen is used up is the answer
Explanation:
These vaporized molecules are drawn up into the flame, where they react with oxygen from the air to create heat, light, water vapor (H2O) and carbon dioxide (CO2).
A student conducted a scientific investigation on the magnetic properties of iron. She used a magnet to try to pick up
iron nails
After making several observations, which question can she answer?
O Which part of a magnet is strongest at attracting iron?
O How fast does iron lose its magnetism?
O What is the importance of studying the magnetic field of a magnet?
How does the color of iron change with exposure to air?
Mark this and return
Save and Exit
RE
S
Answer:
she can answer : which part of the magnet is said strongest at attracting iron & how fast does iron lose its magnetism?
What is the final temperature of 100g of water at -15°C added to a styrofoam cup filled with 220 g of water at 32°C?
Answer:
Explanation:
First off, let's call the -15 degree water solution1, and the 32 degree water solution2. The formula for this is
[tex]t_f=\frac{(m_1*spheat_1*temp_1)+(m_*spheat_2*temp_2)}{(m_1*spheat_1)+(m_2*spheat_2)}[/tex]
where spheat is specific heat of water that I found to be 4182 J/(kgC). This means that we need our masses in kg and they are currently in g.
100 g = .100 kg and
220 g = .220 kg. Now we're ready to plug everything in:
[tex]t_f=\frac{(.100*4182*-15)+(.220*4182*32)}{(.100*4182)+(.220*4182)}[/tex] and
[tex]t_f=\frac{-6273+29441.28}{418.2+920.04}[/tex] and
[tex]t_f=\frac{23168.28}{1338.24}[/tex] so
[tex]t_f=17.3[/tex] °C
if a person can jump 2m in earth surface how high can he jump in the moon (g of moon = 1.66m/s, g of earth = 9.8 m/s) [hint: use w=mgh since work done and mass of a person is same everywhere
Answer:
[tex]h_{moon} = 11.8\ m[/tex]
Explanation:
Since the work done is same everywhere in the universe. Hence, the work done in jumping will be same for the person on moon and earth:
[tex]W_{moon} = W_{earth}\\\\P.E_{moon} = P.E_{earth}\\\\mg_{moon}h_{moon} = mg_{earth}h_{earth}\\\\g_{moon}h_{moon} = g_{earth}h_{earth}\\\\(1.66\ m/s^2)h_{moon} = (9.8\ m/s^2)(2\ m)\\\\h_{moon} = \frac{(9.8\ m/s^2)(2\ m)}{1.66\ m/s^2}\\\\h_{moon} = 11.8\ m[/tex]
What is meant by electric current?
Explanation:
the electric current is ratio of electric poer to the voltage
If r=BT^2 I + ct^3 j, where b and c are positive constants. When does the position vector make an angle 45 with x and y axes
Answer: [tex]t=\dfrac{b}{c}[/tex]
Explanation:
Given
The position vector is [tex]\vec{r}=bt^2\hat{i}+ct^3\hat{j}\\[/tex]
So, the angle made by position vector is [tex]45^{\circ}[/tex] at
[tex]\Rightarrow \tan 45^{\circ}=\dfrac{r_y}{r_x}\\\\\Rightarrow \tan 45^{\circ}=\dfrac{ct^3}{bt^2}\\\\\Rightarrow bt^2=ct^3\\\\\Rightarrow t=\dfrac{b}{c}[/tex]
At [tex]t=\dfrac{b}{c}[/tex], position vector makes [tex]45^{\circ}[/tex] with x and y axes
A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the car? (ii) what is the the distance cover ded by the car?
Answer: [tex]3.5\ km[/tex]
Explanation:
Given
Car starts from the state of rest and acquires a velocity of [tex]70\ km/hr[/tex] in 6 minutes
Final velocity in m/s is [tex]v=70\approx 19.44\ m/s[/tex]
Using equation of motion
[tex]v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2[/tex]
Distance covered in 360 s
[tex]\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km[/tex]
Convection occurs when thermal energy is transferred by the movement of what
Explanation:
You may know that electricity flows through wires. Wires are good conductors of electricity. Heat too can be transferred, or conducted, through some types of materials. The term conduction refers to the transfer of energy. Conduction occurs when energy is passed between objects.
The transfer of thermal energy is called heat. Particles of matter are in constant motion. Sometimes they collide with other particles. When they do, they transfer some of their energy. The energy is transferred from particle to particle. It is sort of like a row of dominoes falling over. In this process, thermal energy moves through a substance. It can even move into other nearby substances conduction occurs between particles of the metal in the pot. It also occurs between particles of the pot and the water. Figure below shows additional examples of conduction. Did you ever cook over a campfire? The man in Figure below is cooking his lunch. He waits as his food absorbs energy. First, the energy from the fire needs to heat the water. Soon, all the water in the pot will be boiling hot. The man also feels warm. He feels the heat from the flames. He feels the warmth even though he is not touching the flames. Thermal energy is transferred from the fire to his hands.
converts light energy to electrical energy
this electric current produced can be stored in another rechargeable cell.
If the collector of the cell is covered the voltage is higher
The current shown is real current
All of the above
None of the above
Answer:
If the collector of the cell is covered, the voltage is higher
Explanation:
The collector of the a passive, active, or photovoltaic (PV) solar cell is the device that takes the Sun's energy by the absorption of the Sun's radiation which is then transformed into electricity and heat. The ability to absorb the Sun's energy is given by the material type and the coating of solar collector
Therefore, the device requires access to energy from Sunlight to get the energy which can be stored in a rechargeable cell and well the collector's cell is covered, access to Sunlight is denied and therefore energy is not supplied to the cells and current is not generated and there is no flow of electricity and the voltage in the circuit is lower or there is no voltage in the circuit
The statement which is wrong about the solar cell is therefore, that if the collector of the cell is covered, the voltage is higher
The diagram shows a stone tied to a string in circular
motion. If the string breaks, what will be the direction of
motion of the stone?
Answer:
Newton's First Law of motion states that an object will continue to move in a straight line or remain at rest unless a force acts on it
The stone is able to move in circular motion because a (centripetal) force acts through the string on it, which maintains the circular motion, by turning the stone to the circular path as the stone moves with momentary velocity along a straight line which is (therefore) tangential to the circle
Therefore, at the point the spring breaks, the centripetal force is no longer acting on the stone to change its path and the motion of the continues on the tangent to the initial circular motion path at that point
Explanation:
Which resource would be the best choice to learn more information about studying martial arts?
Dance studio
Local bait shop
Phone book
Public Golf Course
Answer:
Dance studio
Explanation:
Martial art use to defend ourself from any dangerous. Dance is a way to learn it
Answer:
The answer is A.) Dance studio.
Explanation:
See screenshot below
Hope this helps! :D
(Can you mark me brainliest?)
- ❤ 7272033Alt ❤
2. 2. A drawing that shows the outline of an object is called
Calculate the answer to the correct number of significant digits. 105 + 62.4
Answer: 105
Explanation:
Answer:
167.4
Explanation:
105+62.4
167.4 is the answer
4 signficant digits
In the circuit below, lamps P and Q are identical. The reading on the ammeter is 3A. The cell shown is of
emf. 6V