Why is it important to isolate evidence-containing devices from the internet?
To save the battery
To hide their location
Devices can be remotely locked or wiped if connected
It is not important to isolate the devices

Answer:

the two programs to play multimedia products are;windows media player and VLC media player and the two programs to create multimedia products are;photoshop and PowerPoint

Answer:

A Web client typically refers to the Web browser in the user's machine or mobile device. It may also refer to extensions and helper applications that enhance the browser to support special services from the site.

hope this helps

have a good day :)

Explanation:

Answer: MrBeast is a y0utuber who has lots of money

Explanation:

Answer:

He is a You tuber who likes to donate do stunts and best of all spend money.

It's like he never runs out of money.

Explanation:

Answer:

e. volts through it

Explanation:

volts through it

The contents (top to bottom) left on the stack is volts through it. Thus, option E is correct.

When a computer program begins execution, standard streams are interconnected input and output channels of communication between the program and its surroundings. The three I/O connections are known as standard input (stdin), standard output (stdout), and standard error (stderr).

A negative sign in the input indicates that the stack should be popped, and the return value should be sent to standard output, whereas any other string means that the string should be pushed into the stack. Assume that the following input is processed: this parrot would not voom if I pushed — four thousand —- volts - through it.

The contents of the stack (from top to bottom) are volts via it. As a result, option E is correct.

Learn more about standard output here:

https://brainly.com/question/30054426

#SPJ5

Answer:

I don't know how to code C++

Explanation:

Answer:

The function in Java is as follows:

public static double func(double num){

       num = Math.abs(num);

       return num;

   }

Explanation:

This defines the function

public static double func(double num){

This determines the absolute function of num

       num = Math.abs(num);

This returns the calculated absolute value

       return num;

   }

Answer:

3 is the answer please mark me brainlist

Explanation:

ok

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

 public static void main (String[]args){

   Scanner input = new Scanner(System.in);

   double user[] = new double[2];    double dr1[] = new double[2];

   double dr2[] = new double[2];    double dr3[] = new double[2];    

   System.out.print("Enter user coordinates: ");

   for(int i =0;i<2;i++){        user[i] = input.nextDouble();    }

   System.out.print("Enter driver 1 coordinates: ");

   for(int i =0;i<2;i++){        dr1[i] = input.nextDouble();    }

   System.out.print("Enter driver 2 coordinates: ");

   for(int i =0;i<2;i++){        dr2[i] = input.nextDouble();    }

   System.out.print("Enter driver 3 coordinates: ");

   for(int i =0;i<2;i++){        dr3[i] = input.nextDouble();    }

   double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

   double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

   double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

   System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");

   System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");

   System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");

 }

}

Explanation:

The following array declarations are for the customer and the three drivers

   double user[] = new double[2];    double dr1[] = new double[2];

   double dr2[] = new double[2];    double dr3[] = new double[2];    

This prompts the user for the customer's coordinates

   System.out.print("Enter user coordinates: ");

This gets the customer's coordinate

   for(int i =0;i<2;i++){        user[i] = input.nextDouble();    }

This prompts the user for the driver 1 coordinates

   System.out.print("Enter driver 1 coordinates: ");

This gets the driver 1's coordinate

   for(int i =0;i<2;i++){        dr1[i] = input.nextDouble();    }

This prompts the user for the driver 2 coordinates

   System.out.print("Enter driver 2 coordinates: ");

This gets the driver 2's coordinate

   for(int i =0;i<2;i++){        dr2[i] = input.nextDouble();    }

This prompts the user for the driver 3 coordinates

   System.out.print("Enter driver 3 coordinates: ");

This gets the driver 3's coordinate

   for(int i =0;i<2;i++){        dr3[i] = input.nextDouble();    }

This calculates the distance between driver 1 and the customer

   double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

This calculates the distance between driver 2 and the customer

   double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

This calculates the distance between driver 3 and the customer

   double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

The following print statements print the estimated pickup time of each driver

  System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");

   System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");

   System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");

Answer:

hope this helps

Explanation:

import java.util.Scanner;

public class Problem3 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter start value: ");

       int start = in.nextInt();

       System.out.print("Enter end value: ");

       int end = in.nextInt();

       if (start > end) {

           int temp = start;

           start = end;

           end = temp;

       }

       for (int i = start; i <= end; i++) {

           if (i % 2 == 1) {

               System.out.print(i);

               if (i == end || i + 1 == end) {

                   System.out.println();

               } else {

                   System.out.print(", ");

               }

           }

       }

   }

}