Globular star clusters form from tightly packed groups and/or older ancient stars.
What are globular star clusters?Globular star clusters can be defined as ancient stars packed in a spherical and/or symmetrical shape.
Globular star clusters represent the most common types of groups (i.e., clusters) of ancient stars.
These groups of stars (globular) are characterized to be densest in the center of the cluster.
In conclusion, globular star clusters form from tightly packed groups and/or older ancient stars.
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Why is diffraction used in soil profiles?
Answer:X-ray diffraction (XRD) is the technique most heavily relied on in soil mineralogical analysis. X-ray diffraction is a technique that provides detailed information about the atomic structure of crystalline substances. It is a powerful tool in the identification of minerals in rocks and soils.
Explanation:
XRD is used to identify the minerals composing clay-rich, hydrothermally altered rocks that occur on several Cascade volcanoes. Such rocks are believed to play an important role in the generation of large landslides and mudflows. XRD is used to analyze saline minerals, including borates.
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Below is a single of DNA, What is the complementary base pair for RNA?
AGC, CGT, ATA, GAT
Genes consist portions of _____.
Fundamentally, pressure is defined as force per unit area. What is the source of the force in a gas sample? A) The force is from gravity acting on the particles. B) The force is composed of the sum of the collisions only between gas molecules. C) The force is composed of the sum of the collisions only between the gas molecules and the container. D) The force is composed of the sum of all collisions--between the gas molecules, each other and the container. E) The force was imparted to the container in its initial filling, a transfer of momentum.
Answer:
Option C
Explanation:
Given
Pressure = Force /Area
For any gas sample, force is defined as basically the force exerted by the gas molecules when they strike the surface (with in which they are contained) and bounce back.
Hence, Option C is the correct
Two Brothers are playing soccer on the beach. One brother kicks the ball really hard and the ball lands in the water, about 50 meters from the beach. They wonder if the ball will float back to the beach.
Answer:
Due to wind and waves of water.
Explanation:
They wonder that the ball will float back to the beach because of the wind and the waves of the water. The wind blows towards the beach which moves the water in the form of waves towards the beach so if the ball lands in the water, it will floats on the surface of water and move towards the beach with the help of wind and waves of the sea. The ball floats on the water due to its lighter weight and lower density as compared to water.
An element in a similar period to carbon would be
A chlorine
B. hydrogen
C. fluorine
D. magnesium
Answer: C: Fluorine
Explanation:
Carbon is in period two on the periodic table of elements. The only other elements in this period are lithium, borilliym, boron, nitrogen, oxygen, flourine, and neon. Therefore, the answer must be C.
Describe how an oscilloscope should be used to measure the frequency of the sound wave from the sonometer
Answer:
T = reading (cm) time base (s / cm)
f = 1 / T
Explanation:
An oscilloscope is a piece of equipment that allows you to visualize and measure a wave that reaches you, in the case of having a sonometer this transforms the sound wave into an electrical signal to be introduced through one of the voltage channels of the equipment, on the screen we will see the oscillating alternating signal, if it is fixed we can make the reading, if it is moving the time base and the trigger must be adjusted to stop it.
In the oscilloscope we can read the period of the signal, this is the time it takes for the signal to repeat itself with this value, we can calculate the frequency with the formula, for the reading of the period the distance is measured on the labeled screen and multiplied by the time base
T = reading (cm) time base (s / cm)
f = 1 / T
Two vehicles A and B accelerate uniformly from rest.
Vehicle A attains a maximum velocity of 30ms - in los
while B attains a maximum velocil) ol 40ms in the same
time. Both vehicles maintain these velocities for 6s belore
they are decelerated to rest in 6s and 4s respectively
Sketch on the same axes, velocity time graphs
for the motion of the vehicles
Calculate the velocity of each vehicle 18s aftur
the start. (VA
= 20ms -land vs
and vs = 20ms-')
How far will the two vehicles be from one
another during the moment in (ii) above?
(SA = 380m and SB
= 500m: SAB
120m). plz help
Answer:
(i) Please find attached the required velocity time graphs plotted with MS Excel
(ii) The velocity of vehicle A at the 18th second = 20 m/s
The velocity of vehicle B at the 18th second = 0 m/s
(iii) The distance between the two vehicles at the moment in (ii) above is 60 meters
Explanation:
The given parameters of the motion of vehicles A and B are;
The acceleration of vehicles A and B = Uniform acceleration starting from rest
The maximum velocity attained by vehicle A = 30 m/s
The time it takes vehicle A to attain maximum velocity = 10 s
The maximum velocity attained by vehicle B = 30 m/s
The time it takes vehicle B to attain maximum velocity = The time it takes vehicle A to attain maximum velocity = 10 s
The time duration vehicle A maintains its maximum velocity = 6 s
The time duration vehicle B maintains its maximum velocity = 4 s
(i) From the question, we get the following table;
[tex]\begin{array}{ccc}Time &V_A&V_B\\0&0&0\\10&30&40\\14&30&40\\16&30&20\\18&20&0\\22&0&\end{array}[/tex]
From the above table the velocity time graphs of vehicles A and B is created with MS Excel and can included here
(ii) The velocity of vehicle A at the start = 0 m/s
After accelerating for 10 seconds, the velocity of vehicle A = The maximum velocity of vehicle A = 30 m/s
The maximum velocity is maintained for 6 seconds which gives;
At 10 s + 6 s = 16 s, the velocity of vehicle A = 30 m/s
The time it takes vehicle A to decelerate to rest = 6 s
The deceleration of vehicle A, [tex]a_A[/tex] = (30 m/s - 0 m/s)/(6 s) = 5 m/s²
Therefore, we get;
v = u - [tex]a_A[/tex]·t
At the 18th second, the deceleration time, t = 18 s - 16 s = 2 s
u = 30 m/s
∴ v₁₈ = 30 - 5 × 2 = 20
The velocity of vehicle A at the 18th second, [tex]V_{18A}[/tex] = 20 m/s
For vehicle B, we have;
At the 14th second, the velocity of vehicle B = 40 m/s
Vehicle B decelerates to rest in, t = 4 s
The deceleration of vehicle B, [tex]a_B[/tex] = (40 m/s - 0 m/s)/(4 s) = 10 m/s²
For vehicle B, at the 18th second, t = 18 s - 14 s = 4 s
∴ [tex]v_{18B}[/tex] = 40 m/s - 10 m/s² × 4 s = 0 m/s
The velocity of the vehicle B at 18th second, [tex]v_{18B}[/tex] = 0 m/s
(iii) The distance covered by vehicle A up to the 18th second is given by the area under the velocity-time graph as follows;
The area triangle A₁ = (1/2) × 10 × 30 = 150
Area of rectangle, A₂ = 6 × 30 = 180
Area of trapezoid, A₃ = (1/2) × (30 + 20) × 2 = 50
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = A₁ + A₂ + A₃
∴ [tex]S_A[/tex] = 150 + 180 + 50 = 380
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = 380 m
The distance covered by the vehicle B in the 18th second is given by the area under the velocity time graph of vehicle B as follows;
Area of trapezoid, A₅ = (1/2) × (18 + 4) × 40 = 440
The distance covered by the trapezoid, [tex]S_B[/tex] = 440 m
The distance of the two vehicles apart at the 18t second, [tex]S_{AB}[/tex] = [tex]S_B[/tex] - [tex]S_A[/tex]
∴ [tex]S_{AB}[/tex] = 440 m - 380 m = 60 m
The distance of the two vehicles from one another at the 18th second, [tex]S_{AB}[/tex] = 60 m.
Question 4
The diagram represents the motion of a sound wave. The distance between points A and C is 9 meters (m), and it initially takes the wave 3 seconds (s) to travel.
What will be the wavelength of the sound wave if the velocity of the wave remains constant but the pitch is tripled?
A 3 meters
B 6 meters
с 9 meters
D 18 meters
Answer:A
Explanation:
The wavelength of the sound wave will be 3 meters.
What is wavelength?
The wavelength of any wave is defined as the distance between two max adjacent amplitudes, or the distance between two successive troughs or crest.
Now it is given that:
Distance =9 meters
time = 3 seconds
pitch=1/3 seconds
The velocity of the sound will be
[tex]V=\dfrac{d}{t}=\dfrac{9}{3}=3\ \frac{m}{s}[/tex]
Now from the question the wavelength of the sound wave if the velocity of the wave remains constant but the pitch is tripled
so [tex]f=3\times \dfrac{1}{3}=1 herts[/tex]
Now the velocity of the sound will be
[tex]v=f\times \lambda[/tex]
[tex]\lambda=\dfrac{v}{f}=\dfrac{3}{1}=3\ m[/tex]
Thus the wavelength of the sound wave will be 3 meters.
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NEED HELP The main difference between kinetic energy and potential energy is thatSingle choice.
(2 Points)
kinetic energy involves position, and potential energy involves motion.
kinetic energy involves motion, and potential energy involves position.
although both energies involve motion, only kinetic energy involves position.
although both energies involve position, only potential energy involves motion.
Answer:
kinetic energy involves motion, and potential energy involves position.although both energies involve position, only potential energy involves motion.hope it is helpful to you ☺️☺️✌️
Help help help help help
If F=15 N, a=3 m/s², m=? *
45 Kg
5 kg
0.2 kg
0 kg
Answer:
5 kg
Explanation:
What is role of force on the speed of moving object?
Explanation:
this is the ans hope it works
Answer:
Forces make things speed up (or accelerate). When a force pushes or pulls the object, the object will move in the direction of the force. The bigger the force, and the lighter the object, the greater the acceleration.
Explanation:
The action from a force can cause an object to move or speed up (accelerate), to slow down (decelerate), to stop, or to change direction. Since any change in velocity is considered acceleration, it can be said that a force on an object results in the acceleration of an object.
A simple mathematical relationship exists between the mass of an object (m), the net force on the object (f) and its acceleration (a). The acceleration of an object is directly proportional to the net force and indirectly proportional to the object’s mass (a = f/m).
Which explanation describes why a balloon will stick to a wall?
Opposites attract.
Like repels like.
Answer: A is the correct answer :)
Explanation:
What is the electric field strenght in units of N/C if the flux through a 2.0m by 1.0m rectangular surface is 396Nm2/C, if the electric field is uniform, and if the plane of the surface is at an angle of π/3 radians with respect to the direction of the field ?
Answer:
The appropriate answer is "396 N/C".
Explanation:
The give values are:
Rectangular surface,
[tex]\Phi_e=396 \ N.m^2/C[/tex]
[tex]a = 2 \ m[/tex]
[tex]b = 1 \ m[/tex]
Angle,
[tex]\theta =\frac{\pi}{3} \ radian[/tex]
Now,
The area of rectangle (A) will be:
= [tex]a\times b[/tex]
= [tex]2\times 1[/tex]
= [tex]2 \ m^2[/tex]
hence,
The electric field strength will be:
⇒ [tex]\Phi_e=E.A Cos \theta[/tex]
or,
⇒ [tex]E=\frac{\Phi_e}{ACos \theta}[/tex]
On putting the given values, we get
⇒ [tex]=\frac{396}{2\times Cos(\frac{\pi}{3} )}[/tex]
⇒ [tex]=\frac{396}{2\times 0.5}[/tex]
⇒ [tex]=\frac{396}{1}[/tex]
⇒ [tex]=396 \ N/C[/tex]
A father is homo….zygou dominant for green eyes, the mother is heterozygous. How many of the offspring will have green eyes?
Answer:
100%
Explanation:
Father - EE
Mother - Ee
A 100kg linebacker runs with a velocity of 5m/s towards an 88kg quarterback, who begins to back up
with a velocity of 2m/s to avoid being sacked
a.What is the momentum of the linebacker-quarterback system?
b.the quarterback is unsuccessful in evading the linebacker and gets sacked. what is the velocity of the football players just after the linebacker dives in for a tackle if the 2 players move as one clump?
A very long cylindrical shell made of copper has an inner radius 2 cm and an outer radius of 3 cm. This shell concentrically surrounds a very long charged aluminum rod of radius 1 cm with a charge density of 4 pC/m. All charges on the aluminum rod reside at its surface. The inner surface of the copper shell has exactly opposite charge to that of the aluminum rod while the outer surface of the copper shell has the same charge as the aluminum rod. Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
Question:
Find the magnitude and direction of the electric field at points that are at the following distances from the center of the aluminum rod:
(a) 0.5 cm, (b) 1.5 cm, (c) 2.5 cm, (d) 3.5 cm, (e) 7.0 cm
Answer:
(a) 0
(b) 4.795 N/C
(c) 2.877 N/C
(d) 2.055 N/C
(e) 1.027 N/C
Explanation:
The given parameters are;
The inner radius of the copper = 2 cm
The outer radius of the copper - 3 cm
The radius of the aluminum rod, r = 1 cm
The radius of the aluminum rod = 4 pC/m
a) The charge at the 0.5 cm from the center of the aluminum rod, E = 0
There is no charge inside the rod given that the aluminum road is a conductor of electricity, having all the charge on its surface
b) At 1.5 cm, we have;
[tex]E = \dfrac{2 \cdot \lambda}{4 \cdot \pi \cdot r \cdot \epsilon_0}[/tex]
Where;
[tex]\dfrac{ \lambda}{4 \cdot \pi \cdot \epsilon_0} = 8.99 \times 10^9 \times 4 \times 10^{-12}[/tex]
r = 1.5 cm = 0.015 m
∴ E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.015 ≈ 4.795
The magnitude of the electric field, E = 4.795 N/C
The direction of the charge depends on the charge sign on the rod
c) At 2.5 cm, we have;
r = 2.5 cm = 0.025 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.025 ≈ 2.877
The magnitude of the electric field, E ≈ 2.877 N/C
d) At r = 3.5 cm, we have;
r = 3.5 cm = 0.035 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.035 ≈ 2.055
The magnitude of the electric field, E ≈ 2.055 N/C
e) At
r = 7.0 cm = 0.070 m
E = (2 × 8.99 × 10⁹ × 4 × 10⁻¹²)/0.07 ≈ 1.027
The magnitude of the electric field, E ≈ 1.027 N/C
6. Which of the following statements is true for displacement ?
a. It cannot be zero
b. Its magnitude is more than the distance covered by the object.
Both are false..........
The equation below is used to calculate the mechanical advantage of an ideal wheel and axle.
mechanical advantage =
wheel radius
__________
axle radius
A student compares two wheel-and-axle simple machines. Machine 1 has a wheel radius of 50 centimeters, and an axle radius of 10 centimeters. Machine 2 has a wheel radius of 100 centimeters, and an axle radius of 10 centimeters. What is true of these simple machines’ mechanical advantage?
A.
Machine 1’s mechanical advantage is greater, which means that this machine can do more work with less force than Machine 2.
B.
Machine 1’s mechanical advantage is greater, which means that this machine can move faster than Machine 2.
C.
Machine 2’s mechanical advantage is greater, which means that this machine can do more work with less force than Machine 1.
D.
Machine 2’s mechanical advantage is greater, which means that this machine can move faster than Machine 1.
Answer:
b
Explanation:
Machine 2’s mechanical advantage is greater, which means that this machine can do more work with less force than Machine 1.
Mechanical advantageThe term mechanical advantage is the ratio of the radius of wheel to the radius of the axle for a wheel and axle system.
The true statement about the two machines that were compared; 1 and 2 is that, machine 2’s mechanical advantage is greater, which means that this machine can do more work with less force than Machine 1.
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A juggler is throwing balls up in the air and catching them. An observer in the crowd makes the statement that the potential and kinetic energy of the ball is the same when the ball is halfway down from its highest point. In one paragraph, using your own words, explain using the relationship of mechanical energy, potential energy, and kinetic energy why the observer is correct.
Answer:
do you have the answer?
Explanation:
if so whats the answer?
if the voltage across a 12 ohm resistor is 4.0 volts. the current through the resistor is?
Answer:
Current = 0.33 Amperes
Explanation:
Given the following data:
Resistance = 12 ohm
Voltage = 4 v
To find the current;
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
Voltage = current * resistance
Substituting into the formula, we have;
4 = current * 12
Current = 4/12
Current = 0.33 Amperes
5. How do you represent the strength of a force in a free-body diagram?
Direction: Write TRUE if the statement is correct, and FALSE if it is not
correct
3. When light strikes a black surface, it is reflected by the surface and
nothing is absorbed.
4. Mirrors are used in telescopes because they have the ability to reflect
5. Transmission in the passing of light through some materials
-----------------------------------------------------------------------------------------------------------------
When light strikes a black surface, it is reflected by the surface and
nothing is absorbed This would be False because black absorbs the light not reflect
Mirrors are used in telescopes because they have the ability to reflect
True? Telescopes designed with mirrors avoid the problems of refracting telescopes. Because the light is reflected from the front surface only, flaws and bubbles within the glass do not affect the path of the light
Transmission in the passing of light through some materials
False? Some materials allow much of the light that falls on them to be transmitted through the material without being reflected. Materials that allow the transmission of light waves through them are called optically transparent. ... Materials which do not allow the transmission of any light wave frequencies are called opaque.
sheet of paper and a ball having same mass are dropped from the same height and obviously paper balls faster than a sheet of paper. what conclusion can be drawn from this acticity?
Answer:
In free fall, all items will fall at the same time. You were told that they have the same mass hence g×t which is constant.You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a 0.400-kg ball that is traveling horizontally at 10.0 m/s. Your mass is 70.0 kg. (a) If you catch the ball, with what speed do you and the ball move after ward
Answer:
0.38m/s
Explanation:
Given data
M1= 0.4kg
U1= 10m/s
M2= 70kg
U2= 0m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
0.4*10+ 70*0= (0.4+10)*V
4= 10.4V
4=10.4V
V= 4/10.4
V=0.38m/s
Hence the common velocity is 0.38m/s
a crane lifts a 450kg concrete to the top of a 50m building in 5s.assuming g=10m/s²,calculate a,the potential energy if the concrete
Answer:
The answer is 225,000Joules
What is the wavelength?
The half-life of iodine-131 is 8 days. If a sample originally contains 0.96 g of the isotope, how much will remain after 24 days?
Answer: you ever get the awnser?
Explanation:
Answer: 0.12 g
Explanation: I got it right on the quiz.