What is the slope of the following equation?

y = 2x -3

Answer:

Second Option

Step-by-step explanation:

[tex]5^2 + 7^2 = PQ^2[/tex] (pythagorean theorem)

[tex]PQ^2 =74[/tex]

[tex]PQ = \sqrt{74}[/tex]

Answer:

1.8 in.

Step-by-step explanation:

Hi there!

1) Determine the radius of the base

[tex]V=\frac{1}{3} \pi r^2h[/tex] where r is the radius of the base and h is the height of the cone

Plug in the known values (h=4.2, V=3.6)

[tex]3.6=\frac{1}{3} \pi r^2(4.2)[/tex]

Isolate r; divide both sides by 4.2

[tex]\frac{3.6}{4.2} =\frac{1}{3} \pi r^2\\\frac{6}{7} =\frac{1}{3} \pi r^2[/tex]

Multiply both sides by 3

[tex]\frac{6}{7}*3 =\pi r^2\\\frac{18}{7}=\pi r^2[/tex]

Divide both sides by π

[tex]\frac{18}{7\pi }=r^2[/tex]

Take the square root of both sides

[tex]\sqrt{\frac{18}{7\pi }} =r[/tex]

2) Determine the diameter

Now that we have the radius, to find the diameter, multiply r by 2:

[tex]d=\sqrt{\frac{18}{7\pi }}*2\\d=1.8[/tex]

Therefore, the diameter is 1.8 in. when rounded to the nearest tenth.

I hope this helps!

Answer:

1.8 in

Step-by-step explanation:

we know the equation for the volume of a cone is pi*r^2 h/3=3.6

pi r^2 *4.2=10.8

solve for r

r is about 0.9 so diameter is 1.8 in

Answer:

[tex]\displaystyle x=\left\{\frac{\pi}{4}, \frac{5\pi}{4}\right\}[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]\cos(x)\tan(x)=\cos(x)[/tex]

On the interval [0, 2π).

First, we can subtract cos(x) from both sides:

[tex]\cos(x)\tan(x)-\cos(x)=0[/tex]

Factor:

[tex]\cos(x)\left(\tan(x)-1\right)=0[/tex]

Zero Product Property:

[tex]\cos(x)=0\text{ or } \tan(x)-1=0[/tex]

Solve for each case:

[tex]\cos(x)=0\text{ or }\tan(x)=1[/tex]

Using the unit circle:

[tex]\displaystyle x=\left\{\frac{\pi}{4}, \frac{\pi}{2}, \frac{5\pi}{4}, \frac{3\pi}{2}\right\}[/tex]

However, since tangent isn't defined for π/2 and 3π/2, we remove them from our solutions. Hence:

[tex]\displaystyle x=\left\{\frac{\pi}{4}, \frac{5\pi}{4}\right\}[/tex]

Step-by-step explanation:

to find area

A = Pi x r^2

r = d/2 = 10/2 = 5

Answer:

whats this? can you provide more context?

Step-by-step explanation:

Answer: She needs to get 99 on her next test.

Step-by-step explanation:

Answer:

For an approximate result, multiply the mass value by 28.35

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

The measure of ∠3 is 96° and measure of ∠4 is 64°.

What is Triangle?

A triangle is a three sided polygon , which has three vertices and three angles with sum 180 degree.

Given that;

In triangle,

Measure of first angle (m ∠1 ) = 43°

Measure of second angle (m ∠2) = 41°

Let measure of ∠4 = x degree

Now, Sum of all angles in a triangle be 180 degree.

So, We can formulate;

m∠1 + m∠2 + m∠3 = 180°

43° + 41° + x = 180°

84° + x = 180°

x = 180° - 84°

x = 96°

So, measure of ∠3 = 96°

Since, The measure of ∠3 and measure of ∠4 are supplementary angles.

Hence, We get;

m ∠3 + m ∠4 = 180°

96° + m ∠4 = 180°

m ∠4 = 180° - 96°

m ∠4 = 64°

Thus, The measure of ∠3 is 96° and measure of ∠4 is 64°.

Learn more about the supplementary angle visit:

https://brainly.com/question/17706490

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Answer:

b, c , a

Step-by-step explanation:

I am guessing

Answer:

B, C, D

Step-by-step explanation:

Answer: D, All of the above

Step-by-step explanation:

Answer:

D. 0.62

Step-by-step explanation:

I calculated it logically

Answer:

$-69.94

Step-by-step explanation:

Amount left after the withdrawal to fix the furnace = $400.56 - $450.50 = $-49.94

He has a negative balance for 4 days. this would attract a 5 dollar fee per day. the total fee would be $20 ( 5 x 4)

Total amount left in his account = $-49.94 - $20

Step-by-step explanation:

The graph of a quadratic equation in two variables (y = ax^2 + bx + c ) is called a parabola. The following graphs are two typical parabolas their x-intercepts are marked by red dots, their y-intercepts are marked by a pink dot, and the vertex of each parabola is marked by a green dot: (Given in attachment for diagram)

We say that the first parabola opens upwards (is a U shape) and the second parabola opens downwards (is an upside down U shape). In order to graph a parabola we need to find its intercepts, vertex, and which way it opens.

Given y = ax^2 + bx + c , we have to go through the following steps to find the points and shape of any parabola:

Label a, b, and c.

Decide the direction of the paraola:

If a > 0 (positive) then the parabola opens upward.

If a < 0 (negative) then the parabola opens downward.

Find the x-intercepts:

Notice that the x-intercepts of any graph are points on the x-axis and therefore have y-coordinate 0. We can find these points by plugging 0 in for y and solving the resulting quadratic equation (0 = ax^2 + bx + c). If the equation factors we can find the points easily, but we may have to use the quadratic formula in some cases. If the solutions are imaginary, that means that the parabola has no x-intercepts (is strictly above or below the x-axis and never crosses it). If the solutions are real, but irrational (radicals) then we need to approximate their values and plot them.

Find the y-intercept:

The y-intercept of any graph is a point on the y-axis and therefore has x-coordinate 0. We can use this fact to find the y-intercepts by simply plugging 0 for x in the original equation and simplifying. Notice that if we plug in 0 for x we get: y = a(0)2 + b(0) + c or y = c. So the y-intercept of any parabola is always at (0,c).

Find the vertex (h,k):

To find the x-coordinate for the vertex we use the following formula:

To find the y-coordinate for the vertex we plug in h in the original equation:

k = a(h)2 + b(h) + c

Plot the points and graph the parabola  

-Please Mark As Brainliest

9514 1404 393

Answer:

  no; √4 = 2

Step-by-step explanation:

If an integer is the square of another integer, its square root is rational. For example, 9 = 3², so √9 = 3, a rational number.

The square root of an integer is irrational if and only if the integer is not a perfect square.

Answer:

16.9

Step-by-step explanation:

We can use a proportion also in this case

51.6 : 23 = 38 : NO

NO = (38 x 23)/51.6 = 16.9

Answer:

c.prism is not solid figure

Answer:

rectangle

Step-by-step explanation:

rectangle isn't a solid figure

Answer:

c

Step-by-step explanation:

Answer:

i think c

Step-by-step explanation:

Answer:

Gross income for an individual—also known as gross pay when it's on a paycheck—is the individual's total pay from their employer before taxes or other deductions. This includes income from all sources and is not limited to income received in cash; it also includes property or services received.

Net income- In business and accounting, net income is an entity's income minus cost of goods sold, expenses, depreciation and amortization, interest, and taxes for an accounting period.

I think its B

Step-by-step explanation:

With this prism, first separate it into a rectangular prism and a right triangle prism.

First, with the rectangular prism, it would have the units 5 * 5 * 6.3. Then with the right triangle prism, it would take the rest of the remaining space of it, being 3 * 5 * 6.3

The equation for the volume of a rectangular prism is L*W*H and the equation for the volume of a right triangle prism is (L*W*H) / 2.

With this, plug the numbers in for both prisms to get the volume of each of them:

Rectangular prism Volume

5*5*6.3

157.5

Right triangle prism Volume

(3*5*6.3) / 2

94.5 / 2

47.25

Lastly, combine these two values to get the total volume:

157.5 + 47.25 = 204.75 (Round Up) -->

204.8 cm^3 = Total Volume

Next, with the surface area of the prism. For this, lets combine all of the faces of the prism then add them all up.

First, lets do the bottom of the prism, or the base. It uses the lengths 8 cm and 6.3 cm. Lets do L * W to get the area of this face:

8 * 6.3 = 50.4

Next, lets do the slant side of it, which has the lengths 5.8 and 6.3.

5.8 * 6.3 = 36.54

Then, the top side with the lengths 5cm and 6.3 cm.

5.3 * 6.3 = 33.39

After that, the left side face that opposite to the slantly one:

5 * 6.3 = 31.5

Saving the most tedious part of it for last, the right trapezoids. Luckily, there is an equation for this:

1/2 x (Sum of parallel sides) x (perpendicular distance between the parallel sides).

So, within each of these right trapezoids, there's the parallel sides of 5 and 8. There's also a perpendicular side of 5cm. With this, we can plug this into the equation to solve for this part:

1/2 x (5+8) * (5)

1/2 x (13) * (5)

1/2 x (65)

32.5

Since there's two of them, times this by 2:

32.5 * 2 ---> 65.

Now, with the area of all of the faces, these can be added up for the total surface area:

50.4 + 36.54 + 33.39 + 31.5 + 65 ---> 216.83 (Round Down)-->

216.8 cm^2 = Total Surface Area

Answer:

55.5 is the I guess........

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

10/4

Step-by-step explanation: