What is another name for an X-Value
9TH GRADE ALGEBRA 1

A-output values
B- range
C- domain
D- function

Answer:

Choice B

Step-by-step explanation:

Given radical expression:

[tex] \sqrt[4]{1296 {x}^{16} {y}^{12} } [/tex]

To Find:

The Simpler form of this expression

Soln:

[tex] = \sqrt[4]{1296 {x}^{16} {y}^{12} } [/tex]

We could re-write the given expression, according to the law of exponents:

[tex] = \tt \sqrt[4]{(6x {}^{4}y {}^{3}) {}^{4} } [/tex]

Now we need to bring terms out of the radical as:

[tex] \tt = | 6x { }^{4} y {}^{3} | [/tex]

Bring out 6x^4 from the absolute & put y^3 only in it:

[tex] \tt = 6x {}^{4} |y {}^{3} | [/tex]

Choice B is accurate.

Answer:

Use given values of h and j, and find the value of k:

The equation is now:

Find the value of g when h is 2 and j is 3:

Correct choice is D

Answer:

D. 144

Step-by-step explanation:

The angle of triangle are ∠A = 86, ∠B = 55, ∠C = 39. The side of the triangles are a = 0.99, b = 0.81, c = 0.62.

Law of sines is a formula relating the length of the sides of a triangle to the angles of the triangle.

[tex]\dfrac{sin A}{a} = \dfrac{sin B}{b} = \dfrac{sin C}{c}[/tex]

We have given angles of the triangle as

∠A = 86

∠B = 55

∠C = 39

So,

[tex]\dfrac{sin 86}{a} = \dfrac{sin 55}{b} = \dfrac{sin 39}{c}[/tex]

Now,

a = 0.99

b = 0.81

c = 0.62

The side of the triangles are a = 0.99, b = 0.81, c = 0.62.

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Answer:

1&32 2&16 4&8

Step-by-step explanation:

Factor Pair Pair Factorization

1 and 32       1 x 32 = 32

2 and 16         2 x 16 = 32

4 and 8      4 x 8 = 32

You would likely score 4 goals in 12 games

The given parameters are:

The expected number of goals is calculated as:

E(x) = p * Total

This gives

E(x) = 33.3% * 12

Evaluate

E(x) = 4

Hence, you would likely score 4 goals in 12 games

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The ratio of the area of sector abc to the area of sector dbe is 4/3

For sector abc, we have:

Angle = x

Radius  = 2r

For sector dbe, we have:

Angle = 3x

Radius = r

The area of a sector is:

[tex]Area =\frac{\theta}{360}* \pi r^2[/tex]

So, we have:

[tex]ABC =\frac{x}{360}* \pi (2r)^2[/tex]

Evaluate

[tex]ABC =\frac{x* \pi r^2}{90}[/tex]

For DBE, we have:

[tex]DBE =\frac{3x}{360}* \pi (r)^2[/tex]

Evaluate

[tex]DBE =\frac{x}{120}* \pi r^2[/tex]

The ratio of both areas is:

[tex]Ratio = \frac{x}{90}* \pi r^2 : \frac{x}{120}* \pi r^2[/tex]

Cancel out the common factors

[tex]Ratio = \frac{1}{90} : \frac{1}{120}[/tex]

Express as fraction

[tex]Ratio = \frac{120}{90}[/tex]

Divide

[tex]Ratio = \frac{4}{3}[/tex]

Hence, the ratio of the area of sector abc to the area of sector dbe is 4/3

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4/3

its the answer edmentum

Answer: SAS similarity theorem

Proportional relationship:

[tex]\sf \dfrac{AB}{AC} = \dfrac{AM}{AN}[/tex]

insert values

[tex]\rightarrow \sf \dfrac{21+9}{14+6} = \dfrac{21}{14}[/tex]

simplify

[tex]\rightarrow \sf 1 = 1[/tex]

L.H.S = R.H.S

The triangles are congruent and follows the rule SAS similarity theorem.

The triangles has/starts from the same angle, corner (A).

Step-by-step explanation:

Here is the solution...hope it helps:)

Answer:

-1

Step-by-step explanation:

Find the difference of each sequence

19 - 15 = 4

15 - 11 = 4

11 - 7 = 4

7- 3 = 4

3 - ? = 4

Subtract 4 from the 3

3 - 4 = -1

Therefore, the next term is -1

Answer:

ELA

Step-by-step explanation:

you add ela to a bonus points

Answer:

PLA + ELA = 90

Step-by-step explanation:

lol

Answer:

B is true

C is false

D is false

Step-by-step explanation:

- B is true because two negative numbers are added together, the outcome is negative hence always less than 0

- C is false due to needing a negative number add to -1.5 to be less, a positive only makes the number greater

- D is false since you are adding 0.9 (9/10), anything less than this will m ake the sum be greater than 0

example: - 0.5 + 0.9 = 0.4 or - 0.8 + 0.9 = 0.1

Considering the definition of axis of symmetry, the axis of symmetry of the graph of the function f(x) = 3x²+ 12x+ 9 is x=-2.

An axis of symmetry is an imaginary reference line that, when dividing any shape into two parts, its opposite points are equidistant from each other, that is, they are symmetrical.

In other words, the axis of symmetry is a vertical line that divides the parabola into two congruent halves.

The axis of symmetry is the line perpendicular to the "x" axis that contains the vertex of the function, that is, it always passes through the vertex of the parabola. So the x-coordinate of the vertex is the equation of the axis of symmetry.

That is, in a quadratic function that has the form:

f(x)= ax² + bx + c

the axis of symmetry is a vertical line and it is defined as [tex]x=\frac{-b}{2a}[/tex].

In this case, you know:

Replacing in the definition of axis of symmetry:

[tex]x=\frac{-12}{2x3}[/tex]

Solving:

[tex]x=\frac{-12}{6}[/tex]

x= -2

Finally, the axis of symmetry of the graph of the function f(x) = 3x²+ 12x+ 9 is x=-2.

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Since the paper representing her desk is 1 1/4 inches by 2 1/4 inches, the actual dimensions of her desk are D: 2 ¹/₂ ft by 4 ¹/₂ ft

To answer the question, we need to know what scale is

A scale is the ratio of two dimension and it is given on a scale drawing.

Given that Chelsea makes a scale drawing of the room and cuts out pieces of paper to represent her furniture, and the paper representing her desk is 1 1/4 inches by 2 1/4 inches.

Since on the scale, we have 1/2 in = 1 foot ⇒ 1 in = 2 ft

So, the actual dimensions of her desk are

1 ¹/₄ in by 2 ¹/₄ in = 5/4 in by 9/4 in

= 5/4 × 1 in by 9/4 × 1 in

= 5/4 × 2 ft by 9/4 × 2 ft

= 5/2 ft by 9/2 ft

= 2 ¹/₂ ft by 4 ¹/₂ ft

So, the actual dimensions of her desk are D: 2 ¹/₂ ft by 4 ¹/₂ ft

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Answer:

x = 2

Step-by-step explanation:

This is a 45-45-90 special right triangle. The legs in this triangle are equal and the hypotenuse is leg multiplied with √2. Refer to the picture at the bottom.

One leg is x, the second leg is x and hypotenuse x√2.

[tex]x \sqrt{2} = 2 \sqrt{2} \\\\\text{Divide both sides with } \sqrt{2} \text{ to isolate } x.\\\frac{x \sqrt{2}}{\sqrt{2}} = \frac{2 \sqrt{2}}{\sqrt{2}}\\\\x = 2[/tex]

The exponent for the expression, 5 × 5 × 5 × 5 × 5, would be expressed as: [tex]5^5[/tex].

An exponent can be defined as the power to which the base is to b e raised.

For example, a × a × a can be expressed in  exponent form as a³.

In the same vein, given the expression, 5 × 5 × 5 × 5 × 5, we would expressed this in exponent form as: [tex]5^5[/tex].

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Answer:

So for a quadratic function, the axis of symmetry is the line that divides the curved line in the middle, which is the h value, it can be found by using the formula -b/2a, so for here it would be 4/2(1) = 2, so x =2

Hope that answers your question

Step-by-step explanation:

The number of books Alisha did not sell after making a profit of £490 is 45 books

How to find how many book she sell base on the profit?

She buys 200 books costing £3 each.

Therefore,

cost = 3 × 200 = £600

Hence,

She sells 2/5 of the books at £8 each.

total amount = 2 / 5 of 200 × 8

total amount = 80 × 8

total amount = £640

Alisha then reduces the price of the remaining books by a quarter.

She then sells some of the remaining books.

Therefore,

the remaining book = 120

She sold some of the remaining books.

profit = selling price - cost price

490  = selling price - 600

selling price = 490 + 600

selling price = £1090

Therefore,

the cost of the remaining book she sold = 1090 - 640 = £450

Hence,

let

x = number of book sold

6(x) = 450

x = 450 / 6

x = 75

The number book she did not sell = 120 - 75 = 45

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the answer is 40 minute's 250-210 is 40

Answer:  B. They are one-dimensional objects

This applies to line segments and lines as well.

One dimensional objects are such that they only have one component to them when it comes to determining a location on that object.

For instance, a number line is one dimensional because we only need one number to determine where a location is.

A ray is effectively a half-line, or put another way, a line is the combination of two rays glued together. Basically a ray points forever in one direction only, as a line will point in two opposite directions.

Extra side notes:

Answer: B

Step-by-step explanation:

prolly 4.36 just use the Pythagorean theorem

well, we know the discount is 4975 - 3781 = 1194.

if we take 4975 to be the 100%, what is 1194 off of it in percentage?

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 4975 & 100\\ 1194& x \end{array} \implies \cfrac{4975}{1194}~~=~~\cfrac{100}{x}\implies \cfrac{26}{6}=\cfrac{100}{x} \\\\\\ 26x = 600\implies x=\cfrac{600}{26}\implies x\approx 23.08[/tex]

Answer:

0.76

Step-by-step explanation:

4975 × 0.76 = 3781

the discount percent given is .76%

[tex]-3x^3 +12x^2 -15x +6\\\\=-3(x^3 -4x^2 +5x-2)\\\\=-3(x^3 -2x^2-2x^2 +4x+x-2)\\\\=-3\textbf{[} x^2(x-2) -2x(x-2)+ (x-2)\textbf{]}\\\\=-3(x-2)(x^2 -2x +1)\\\\=-3(x-2)(x-1)^2[/tex]

Answer:

$43 + $6l

Step-by-step explanation:

Hello!

She spends $43 and bus several $6 laces.

We don't know how many she buys, but we know that we can represent that number using l.

That means she spends $43 + $6l.

The algebraic expression is $43 + $6l.

We can determine the price if we know the number of laces she buys. We can simply plug in the number of laces she bought, and we can plug it in for l in the equation.

Answer:

43= 6(x)

Explanation:

43 is the total,  and each of them are 6$ each. X is the variable that we don't know.

Answer:

40 L cranberry juice; 80 L apple juice

Step-by-step explanation:

Let x = number of liters of cranberry juice.

The total volume is 120 L, so the volume of apple juice is

120 - x.

The value of the cranberry juice is 0.5x.

The value of the apple juice is 0.35(120 - x).

The value of the mixture is 0.4(120) = 48

The value of the cranberry juice plus the value of the apple juice equals the value of the mixture.

0.5x + 0.35(120 - x) = 48

0.5x + 42 - 0.35x = 48

0.15x = 6

x = 6/0.15

x = 40

120 - x = 120 - 40 = 80

Answer: 40 L cranberry juice; 80 L apple juice

The solution to the question is:

c is 6 = [tex]\sqrt{a^{2} + b^{2} -2abcosC }[/tex]

b is 5 = [tex]\sqrt{a^{2} + c^{2} -2accosB }[/tex]

cosB is 2 = [tex]\frac{a^{2} + c^{2} - b^{2} }{2ac}[/tex]

a is 4 = [tex]\sqrt{b^{2} + c^{2} -2bccosA }[/tex]

cosA is 3 = [tex]\frac{b^{2} + c^{2} -a^{2} }{2bc}[/tex]

cosC is 1 = [tex]\frac{b^{2} + a^{2} - c^{2} }{2ab}[/tex]

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] -2ab cos C-----------------1

then c =  [tex]\sqrt{a^{2} + b^{2} -2abcosC }[/tex]

if b is the side facing the included angle B, then

[tex]b^{2}[/tex] = [tex]a^{2}[/tex] + [tex]c^{2}[/tex] -2accosB-----------------2

b =  [tex]\sqrt{a^{2} + c^{2} -2accosB }[/tex]

from equation 2, make cosB the subject of equation

2ac cosB =  [tex]a^{2}[/tex] +  [tex]c^{2}[/tex] - [tex]b^{2}[/tex]

cosB =  [tex]\frac{a^{2} + c^{2} - b^{2} }{2ac}[/tex]

if a is the side facing the included angle A, then

[tex]a^{2}[/tex] = [tex]b^{2}[/tex] + [tex]c^{2}[/tex] -2bccosA--------------------3

a =  [tex]\sqrt{b^{2} + c^{2} -2bccosA }[/tex]

from equation 3, making cosA subject of the equation

2bcosA =  [tex]b^{2}[/tex] +  [tex]c^{2}[/tex]  - [tex]a^{2}[/tex]

cosA =  [tex]\frac{b^{2} + c^{2} -a^{2} }{2bc}[/tex]

from equation 1, making cos C the subject

2abcosC =  [tex]b^{2}[/tex] + [tex]a^{2}[/tex] -  [tex]c^{2}[/tex]

cos C =  [tex]\frac{b^{2} + a^{2} - c^{2} }{2ab}[/tex]

In conclusion,

c is 6 = [tex]\sqrt{a^{2} + b^{2} -2abcosC }[/tex]

b is 5 = [tex]\sqrt{a^{2} + c^{2} -2accosB }[/tex]

cosB is 2 = [tex]\frac{a^{2} + c^{2} - b^{2} }{2ac}[/tex]

a is 4 = [tex]\sqrt{b^{2} + c^{2} -2bccosA }[/tex]

cosA is 3 = [tex]\frac{b^{2} + c^{2} -a^{2} }{2bc}[/tex]

cosC is 1 = [tex]\frac{b^{2} + a^{2} - c^{2} }{2ab}[/tex]

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The answer is Y

Step-by-step explanation:

You have to compare the numbers with conditions both in Rows and Columns.

The number of rows in the arena is 26

The hockey arena illustrates an arithmetic sequence, and it has the following parameters:

The number of rows (i.e. the number of terms) is calculated using:

[tex]S_n = \frac{n}{2}(2a + (n -1) * d)[/tex]

So,we have:

[tex]10920 = \frac{n}{2}(2 * 220 + (n -1) * 16)[/tex]

Evaluate the terms and factors

[tex]21840 = n(440 + 16n -16)[/tex]

Evaluate the like terms

21840 = n(424+ 16n)

Expand

21840 = 424n + 16n^2

Rewrite as:

16n^2 + 424n - 21840 = 0

Using a graphical tool, we have:

n = 26

Hence, the number of rows in the arena is 26

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The sequence whose first term is - 4 and defined recursively by the formula f(n + 1) = f(n) + 3 have the element - 1 as the next term. (Correct choice: B)

In mathematics, sequences are sets whose elements observe at least a condition, which is represented by a recursion formula in this question:

f(n + 1) = f(n) + 3

Thus, the following term of the sequence is:

f(2) = f(1) + 3

f(2) = - 4 + 3

f(2) = - 1

The sequence whose first term is - 4 and defined recursively by the formula f(n + 1) = f(n) + 3 have the element - 1 as the next term. (Correct choice: B)

The statement is poorly formatted and reports typing mistakes. Correct statement is:

A sequence is defined recursively by the formula f(n + 1) = f(n) + 3. The first term of the sequence is - 4. What is the next term in the sequence? a) - 7, b) - 1, c) 1, d) 7

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keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]5x-y=-7\implies 5x-y+7=0 \\\\\\ \stackrel{\stackrel{m}{\downarrow }}{5} x+7=y\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

so a line perpendicular to that one above will have a slope of

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{5\implies \cfrac{5}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{5}}}[/tex]