What is 2 over 7 is greater than 4 over 12

Answer:

x=36

Step-by-step explanation:

2x+2x+70+78+68=360

4x+216=360

4x=360-216

4x=144

x=144/4=36

[tex]\dfrac{5-i}{4+3i}=\dfrac{(5-i)(4-3i)}{(4+3i)(4-3i)}=\dfrac{20-15i-4i-3}{16+9}=\dfrac{17-19i}{25}=\dfrac{17}{25}-\dfrac{19}{25}i[/tex]

He needs 20 more unit cubes to completely fill the prism

The dimension of the prism is given as;

4 by 3 by 3

The volume is calculated as:

Volume = 4 * 3 * 3

Volume = 36

He has already filled 16 units.

So, the units remaining is

Remaining = 36 - 16

Evaluate

Remaining = 20

Hence, he needs 20 more unit cubes to completely fill the prism

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Answer:

what is your from my from is province philippines

Answer:

Squares are the numbers, generated after multiplying a value by itself. Whereas square root of a number is value which on getting multiplied by itself gives the original value.

Step-by-step explanation:

Hence, both are vice-versa methods. For example, the square of 2 is 4 and the square root of 4 is 2.

B; the y axis is what moves up and down

Answer:

A and B

Step-by-step explanation:

In both of these relations, each input corresponds to one and only output.

Answer:

The area of the circle would be 530.93 sq ft.

Step-by-step explanation:

The formula is A = π r². We know that the radius or r is 13, meaning that the new equation is A = π 13². 13 to the second power is 169 meaning that the formula would now be A = π(169). 169 times π is 590.93 getting you your answer. I hope this helped! :)

The value of the composite function (p + q)(2) is 1

The function expression is given as:

(p + q)(2)

As a general rule

(p + q)(x) = p(x) + q(x)

Substitute 2 for x

(p + q)(2) = p(2) + q(2)

From the table, we have:

p(2) = 3 and q(2) =-2

So, we have:

(p + q)(2) = 3 - 2

Evaluate

(p + q)(2) = 1

Hence, the value of the composite function (p + q)(2) is 1

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Answer: (p+q)(2)=1

Step-by-step explanation:

Edge

Answer:

Step-by-step explanation:

In this numbers:

14.63

85.62

The two numbers where the digit 6 has a value of 0.6 are 14.63 and 85.62.

To determine in which two numbers the digit 6 has a value of 0.6, we need to examine the place value of 6 in each number.

Let's go through each number:

1. 16.7: The digit 6 is in the tens place, so its value is 6 * 10 = 60 (not 0.6).

2. 61.28: The digit 6 is in the ones place, so its value is 6 (not 0.6).

3. 14.63: The digit 6 is in the tenths place, so its value is 6 * 0.1 = 0.6.

4. 28.16: The digit 6 is in the hundredths place, so its value is 6 * 0.01 = 0.06.

5. 96.77: The digit 6 is in the tens place, so its value is 6 * 10 = 60 (not 0.6).

6. 85.62: The digit 6 is in the tenths place, so its value is 6 * 0.1 = 0.6.

The two numbers where the digit 6 has a value of 0.6 are 14.63 and 85.62.

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answer:

483.5

step by step explanation:

2x-45y=22

2x-45(21)=22

2x-945=22

2x =22+945

2x=967

x=483.5

Answer:

[tex]\huge\bold\color{pink}{- Magdonal -}[/tex]

Gamitin mo utak mo bleh

[tex]\red{\rule{10pt}{999999pt}}\orange{\rule{10pt}{999999pt}}\green{\rule{10pt}{999999pt}}\blue{\rule{10pt}{999999pt}}\purple{\rule{10pt}{999999pt}}[/tex]

[tex]\left(- \dfrac 38 \right) \div \left(-\dfrac 13 \right)\\\\\\=-\dfrac 38 \times (-3)\\\\\\=\dfrac 98[/tex]

Quadrilaterals are angles that has 4 sides and angles.  The measure of the angle m<SPQ is 110 degrees

Quadrilaterals are angles that has 4 sides and angles. The given quadrilateral is a rhombus with equal opposite sides.

Given the following angles

m<SPR = 2x + 15

m<QPR = 3x - 5

From the figure

m<SPR = m<QPR

Substitute

2x+ 15 = 3x - 5

2x - 3x = -5 - 15

x = 20

Determine the measure of <SPQ
m<SPQ = 3x - 5 +2x +15

m<SPQ = 5x + 10
m<SPQ =5(20) + 10
m<SPQ = 110 degrees

Hence the measure of the angle m<SPQ is 110 degrees

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Supplementary Angles:

[tex]\boxed{100°} and \boxed{80°}[/tex]

Arithmetically speaking, the closest 2 supplementary angles can get (in 3 and 2 digits respectively) is the upwritten.

Complementary Angles:

[tex]\boxed{45°} and \boxed{45°}[/tex]

Simply, in this case, for angles to be numerically as close as possible - make both the angles 45°.

Given that

[tex]\displaystyle \lim_{x\to0} f(x) = 4[/tex]

we can use the properties of limits to show

[tex]\displaystyle \lim_{x\to0} \frac14 f(x)^4 = \frac14 \lim_{x\to0} f(x)^4 = \frac14 \left(\lim_{x\to0} f(x)\right)^4 = \frac14 \times 4^4 = 4^3 = \boxed{64}[/tex]

Let's see

[tex]\\ \rm\Rrightarrow \lim_{x\to 0}\dfrac{1}{4}f(x)^4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{4}\lim_{x\to 0}f(x)^4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{4}\times 4^4[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{256}{4}[/tex]

[tex]\\ \rm\Rrightarrow 64[/tex]

Answer:

a^4

a^2×a^3= a^5(a^2+3)

a^5/a= a^4(a^5-1)

Answer:

11 students are present and 9 are absent.

Answer:

C

Step-by-step explanation:

[tex]\frac{25!}{(25-3)!} =13800[/tex]

Answer:

Step-by-step explanation:

16 - 4 = 12

16 + 4 = 20

then 20 ; 2 = 10

Half of 12 is 6, therefore the two numbers 10 - 6 = 4 and 10 + 6 = 16 will have a mean of 10 and a range of 12.

Answer:

Here is the ans ...hope it helps:)

Answer:

36.

Step-by-step explanation:

There were 10 elephants that were marked.  Only 4 of those were counted.  The other 26 were new elephants.  Because of this, we know that there were 6 other elephants that were not counted.  There were the 30 counted, and the other 6.  Add those and you get 36.

Answer:

  75 elephants

Step-by-step explanation:

This sort of population study assumes that the probability of catching any particular elephant is the same as for any other.

__

We are given that there is a population of 10 painted elephants, of which 4 of them are caught in a sample of 30 elephants. We know the total population of painted elephants is 10/4 = 2.5 times the number caught in the sample. This suggests the total population of elephants is 2.5 times the sample size.

  estimated population = 2.5 × 30 = 75 . . . elephants

If the team can only send four divers to a competition. Then the number of the ways will be 330.

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

There are eleven divers on a swim team. If the team can only send four divers to a competition.

Then the number of the ways will be

Number of ways = ¹¹C₄

Number of ways = 11! / [(11 - 4)! x 4!]

Number of ways = 330

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Step-by-step explanation:

p = 2r + pi×r

p = r(2 + pi)

r = p/(2 + pi)

Answer:

r = [tex]\frac{p}{2+\pi }[/tex]

Step-by-step explanation:

p = 2r + πr ← factor out r from each term

p = r(2 + π) ← divide both sides by (2 + π )

[tex]\frac{p}{2+\pi }[/tex] = r

Step-by-step Explanation:

the volume of a pyramid is:

volume = (1/3) • base_area • height

(area = length • width)

(area) • (height) = (volume)³

Example:

area = 12cm² (12 cm squared)

height = 4cm

12 • 4 = 48cm³ (48 cm cubed)

Answer:

area: 6 • 8 = 48(1/2) = 24cm²

height: 12

volume: 24 • 12 = 288cm³(1/3) = 96cm³

The measure of angle b is 112° and the measure of angle c is 68°

From the question, we are to determine the measures of the missing angles

From the diagram,

b = 112° (Vertically opposite angles)

∴ b = 112°

Also,

112° + c = 180° (Sum of angles on a straight line)

c = 180°- 122°

∴ c = 68°

Hence, the measure of angle b is 112° and the measure of angle c is 68°

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The expression that represents the width of the patio is (x+3) feet

From the question, we are to determine the width of the patio

The area of the patio = Length of the patio × Width of the patio

From the given information,

Length of the patio = (x+11) feet

Area of the patio = x^2+14x+33 = x²+14x+33

Putting the parameters into the formula,

x²+14x+33 = (x+11)  × Width of the patio

∴ Width of the patio = (x²+14x+33) / (x+11)

First, we will factor x²+14x+33

x²+14x+33

x²+11x+3x+33

x(x+11) +3(x+11)

(x+3)(x+11)

Thus,

Width of the patio = [(x+3)(x+11)] / (x+11)

∴ Width of the patio = (x+3) feet

Hence, the expression that represents the width of the patio is (x+3) feet

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For both problems, we can use the section formula.

1) [tex]P=\left(\frac{(1)(1)+(5)(-9)}{6}, \frac{(1)(8)+(5)(3)}{6} \right)=\boxed{\left(-\frac{22}{3}, \frac{23}{6} \right)}[/tex]

2) [tex]Z=\left(\frac{(2)(7)+(1)(1)}{3}, \frac{((2)(5)+(1)(2)}{3} \right)=\boxed{(5, 4)}[/tex]