There is a bag filled with 6 blue and 5 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting at least 1 blue?

Answer:

8 > u > 6

Step-by-step explanation:

We have to solve this inequality as 2 separate inequalities.

==============================================================

Inequality 1 :

⇒ 10 > 5u/4

⇒ 5u < 10 × 4

⇒ 5u < 40

⇒ u < 8 [Box 1]

============================================================

Inequality 2 :

⇒ 5u/4 > 15/2

⇒ 5u/2 > 15

⇒ u/2 > 3

⇒ u > 3 × 2

⇒ u > 6 [Box 2]

============================================================

Solution :

⇒ 8 > u > 6

Step-by-step explanation:

(−424.9) × (-0.1) = 42.49

2.7 × (−0.5) = -1.35

Answer: Heyaa! ~

Your Answers when Multiped are...

Step-by-step explanation:

     - Multiplied. -

 Hopefully this helps you! ~

Outlet A sold the greatest number of copies of album x in July and August

The tables of values are given as:

July

Album X Album Y Album Z

Outlet A 14 8 6

Outlet B 7 13 4

Outlet C 2 11 1

August

Album X Album Y Album Z

Outlet A 12 14 10

Outlet B 5 12 8

Outlet C 16 12 7

In July, the total sales of album x are:

Outlet A  = 14

Outlet B = 7

Outlet C = 2

In August, the total sales of album x are:

Outlet A  = 12

Outlet B = 5

Outlet C = 16

Add both sales

A = 14 + 12 = 26

B = 7 + 5 = 12

C = 2 + 16 = 18

26 (in outlet A) is greater than 12 and 18

Hence, outlet A sold the greatest number of copies of album x in July and August

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Answer:

Outlet D

Step-by-step explanation:

they sold 28 of album x

outlet a only sold 26

Answer:

Answer is $2,637.38

Step-by-step explanation:

Answer:

[tex]\dfrac 32[/tex]

Step-by-step explanation:

[tex]~~~~~~~2^{2x} = 2^3\\\\\implies \ln\left(2^{2x} \right) = \ln (2^3)\\\\\implies 2x \ln(2) = 3 \ln(2) \\\\\implies 2x = 3\\\\\implies x = \dfrac 32[/tex]

Answer:

B

Step-by-step explanation:

The equations of the graphed line and function can be written as:

f(x) = 1/2x + 2

y - 3 = 1/2(x - 2)

y - 1 = 0.5(x + 2)

Equation of a graphed line can be expressed in:

Slope-intercept form as y = mx + b, where m = slope, b = y-intercept; or

Point-slope form as y - b = m(x - a), where (a, b) is a point and m = slope.

Find the slope (m) of the line:

Slope (m) = change in y / change in x = 1/2 = 0.5

y-intercept (b) = 2

To express the graphed line in slope-intercept form, substitute m = 1/2 and b = 2 into f(x) = mx + b:

f(x) = 1/2x + 2.

Using the point-slope form, write the equation by substituting m = 1/2 and (a, b) = (2, 3) into y - b = m(x - a):

y - 3 = 1/2(x - 2)

Or substitute m = 0.5 and (a, b) = (-2, 1) into y - b = m(x - a):

y - 1 = 0.5(x - (-2))

y - 1 = 0.5(x + 2)

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Answer:

Total area = 187.65 cm^2

Step-by-step explanation:

AREA of a triangle = 1/2 base * height

THREE sides    3     * 1/2 *9 *  11.3  = 152.55 cm^2

Bottom                       1/2 * 9 * 7.8  = 35.1 cm^2

  total = 187.65  cm^2

Any time we have a single positive tile pair up with a single negative tile, those two tiles cancel out.

Three positive tiles and three negative tiles will pair up and cancel out. We're left with two positive tiles only. This represents the number 2.

In other words, 5 + (-3) = 5 - 3 = 2

Answer:

D1×D2/2sq

445×5= 225

225/2

=112.5

Answer:

36

Step-by-step explanation:

Question:

[tex] \bigg(\cfrac{10}{2} \bigg)\times 7 + 5 - 4[/tex]

Solution:

Here, we need to use PEMDAS rule, where:

There's a rule as well, the sum given is need to solved from the left, whichever sign is there.

Solved:

[tex]\bigg(\cfrac{10}{2} \bigg)\times 7 + 5 - 4[/tex]

Solve for parentheses first:

[tex] = 5 \times 7 + 5 - 4[/tex]

Then multiplication of course:

[tex] = 35 + 5 - 4[/tex]

Then addition:

[tex] = 4 0 - 4[/tex]

[tex] =36[/tex]

Hence, the answer is 36.

Answer:

13.2 Kilometers an Minute, or 220 Kilometers an Hour

Step-by-step explanation:

26,400 divided by 2 = 13.2 (Minutes) Divided by 60 = 220 (Hours).

Answer:

119 4/7

Step-by-step explanation:

Perimeter is all of the lengths of the sides added together. I started by adding all of the whole numbers:

35+10+12+15+24+12+10=118

Then I added the fractions (after making the denominators equal by multiplying the 3/7, 1/7, 2/7 all by 2)

6/14+2/14+4/14+3/14+1/14+4/14+2/14= 22/14

Then I subtracted 14 from 22 to take out our whole number (which would be 14/14 or 1), and see that we are left with 8.

This means that our answer is 119 8/14 or 119 4/7

Answer: 453.592 grams

Step-by-step explanation:

I searched it up online. But if you're going to use this to calculate. Use 454 grams.

Answer:

453.592 rounded would be 454* grams witch is equal to 1 pound

Step-by-step explanation:

1 pound is equivalent to __453.592 or just say 454*__ grams.

Had to fix that hehehe

Hope This Helped

The method which is best for solving the system of equations when you remove one variable by adding them is B Elimination

To answer the question, we need to know what system of equations are

System of equations are pairs of equations that contain two unknowns

We have different ways of solving systems of equations which include

Since we have the system of equations

3x + 2y = 4

-3x + y = 2

The method which we can use to remove one variable by adding them is the elimination method.

Adding them, we have

3x + 2y = 4

+

-3x + y = 2

3y = 6

y = 6/3

y = 2

So, the method which we can use to remove one variable by adding them is B Elimination

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Answer: pi/4 and -1

Step-by-step explanation:

Step-by-step explanation:

y + 1 = 2(x + 5) = 2x + 10

y - 9 = 2x

2x - y = -9

Answer:

180

Step-by-step explanation:

Answer:

Negative 3 less-than y less-than-or-equal-to 3

Step-by-step explanation:

By looking at a coordinate plane, we can easily see the range

remember, a closed dot means includes , and an open dot means does not include

[closed dot]

(open dot)

the range is all possible y-values. so, all y values shown are

3               which it includes

to -3            which it excludes  / does not include

so, all y values are greater than -3 and less than or equal to 3

Answer:

(2+3)+4 = 2+(3+4) this is an example of associative property

Answer:

37

20

C

a

→

37

19

K

+

0

+

1

e

This equation shows us the parent atom, which is calcium-37. The mass number is written above the atomic number for the atom. The arrow indicates the decay process with the products to the right of the arrow. The products are an atom of potassium-37 and a positron, which is similar to an electron but it carries a charge of +1 instead of a charge of -1. We can see that the transition of a proton to a neutron in positron decay decreases the atomic number of the atom from 20 to 19, but the mass number of 37 remains the same.

Step-by-step explanation:

Answer:

37

20

C

a

→

37

19

K

+

0

+

1

e

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

Sine function would be easiest

  in a right triangle   sin = opposite leg / hypotenuse

sin 57 =   10.8 / x    

then   x = 10.8 / sin 57               then x = 12.88 units

By evaluating the piecewise function, we get:

g(-2) = 0.

g(4) = 4.

A piecewise function is a function that behaves differently in different parts of its domain.

Here, we first want to get g(-2). x = -2 belongs to the second domain, then we use that part:

g(-2) = 0.

For x = 4, it belongs to the third domain, then we have:

g(4) = 4.

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Component form of u is (-18,13) and The magnitude of u is 22.2

A vector is a two-dimensional entity with both magnitude and direction. A vector can be visualized geometrically as a directed line segment.

The component form of a vector is an ordered pair that describes the change in x and y values

This is mathematically expressed as (Δx, Δy) where Δx=x₂-x₁ and Δy=y₂-y₁

Given ;

Initial points of the vector as (14,-6)

The terminal point of the vector is (-4,7)

Here x₁=14,x₂=-4, y₁=-6,y₂=7

The component form of the vector u is (-4-14,7--6) =(-18,13)

Finding the Magnitude of the vector

u=√(x₂-x₁)²+(y₂-y₁)²

u=√-18²+13²

u=√324+169

u=√493

u=22.2

Therefore the Component form of u is (-18,13) and The magnitude of u is 22.2

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Answer:

see the attachment photo!

Offer B is the best value for money because each kg cost is £0.61 and in offer 'A' each kg cost is £0.7.

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:
2 bags for £35

2 bags means 50 kg (2×25)

Each kg cost = 35/50 = £0.7 per kg

3 bags for £92.50

3 bags means 150 kg

Each kg cost = 92.50/150 = £0.61 per kg

As we can see, offer B has a low cost per kg

Thus, offer B is the best value for money because each kg cost is £0.61 and in offer 'A' each kg cost is £0.7.

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Answer:

$50 interest

Step-by-step explanation:

Simple interest formula

I = Prt

where:

Given:

Substitute the given values into the formula and solve for I:

⇒ I = 500 · 0.02 · 5

⇒ I = 50

Therefore, Frank will earn $50 interest in 5 years.

The weighted average cost of capital for the firm will be 11.25%.

The weighted average cost of capital is the calculation of the cost of capital for a firm where each category of capital is weighted.

Here, the weighted average cost of capital will be:

= 0.5(10%)(1 - 15%) + 0.5(14%)

= 0.5(0.1)(0.85) + 0.5(0.14)

= 11.25%

The corporate value at 70% debt when WACC is 11.94% will be:

= (EBIT)(1 - T)/WACC

= (13.24)(1 - 0.15)/0.1194

= $94.26 million

The corporate value at 30% debt when WACC is 11.14% will be:

= (EBIT)(1 - T)/WACC

= (13.24)(1 - 0.15)/0.1114

= $101.02 million

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Step-by-step explanation:

[tex]4 {x}^{2} -5x-6=0 [/tex]

Solve using quadratic formula

Solution:

We know that

[tex] \rm \: Quadratic \: Formula = \cfrac{ - b± \sqrt{ {b}^{2} - 4(ac) } }{2a} [/tex]

ATQ,here,

Substitute the values into the quadratic formula.

[tex]\rm\implies x = \cfrac{5 ± \sqrt{( - 5) {}^{2} - 4 \times (4 \times - 6) } }{2 \times 4} [/tex]

[tex]\rm\implies{x} = \cfrac{5 ± \sqrt{25 - 4 \times (24) } }{2 \times 4} [/tex]

[tex] \implies \rm \: x = \cfrac{5 ± \sqrt{25 - 96} }{8} [/tex]

[tex] \implies \rm \: x = \cfrac{5± \sqrt{121} }{8} [/tex]

[tex] \implies \rm \: x = \cfrac{5± \sqrt{11 \times 11} }{8} [/tex]

[tex] \implies \rm \: \: x = \cfrac{5±11}{8} [/tex]

[tex]\boxed{x = 2}[/tex]

OR

[tex]x = \boxed{- \cfrac{3}{4}} [/tex]