3) The following reaction produces chlorine molecules:
Energy + HCl (g) + CINO3 (8) Cl₂ (8) + HNO3 (8)
a) Describe 4 ways you could increase the concentration of chlorine molecules.
b) How would cooling shift the equilibrium of this reaction?

From the calculations, we can see that the theoretical yiled of NO2 is 100L of NO2

The theoretical yield is that calculated from the stoichiometry of the reaction.

We can see that 1 mole of O2 produced 2 moles of NO2. Thus;

2.23 moles of O2 will produce 4.46 moles of NO2

Since 1 mole of NO2 occupies 22.4 L

4.46 moles of NO2 occupies 100L of NO2

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The given equilibrium reaction indicates the reaction between carbon monoxide and the oxygen and forms carbon dioxide. In this reaction, by increasing the concentration of the carbon monoxide, the equilibrium shifts towards the right. Since, the reactant concentration increases, the equilibrium stress decreases the concentration of the reactants and therefore, the equilibrium shift towards the right side of the equation.

reaction indicates that carbon monoxide reacts with oxygen and forms carbon dioxide gas.

By increasing the concentration of carbon monoxide image, the equilibrium in the reaction shifts towards the right.

The effect of change of pressure, concentration and temperature on the state of equilibrium can be predicted with the help of a principle known as Le Chatelier's principle. Here by increasing the concentration of CO₂, the amount of CO formation can increase.

If a system in equilibrium is subjected to a change in concentration, pressure or temperature, the equilibrium shifts in the direction that tends to reduce or to counteract the effect of change. When the concentration of any substance in equilibrium is increased, the equilibrium shifts in the direction which decreases the concentration of that substance.

On other hand, increasing the concentration of any of the products results in shifting the equilibrium in the backward reaction forming more products. So here increasing the amount of CO₂, shifts equilibrium in the backward direction and forms more amount of CO.

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5.1434 contains 5 significant figures and 4 decimals.

All zeros that occur between any two non-zero digits are significant. For example, 108.0097 contains seven significant digits.

Calculation:

5.1234 + 0.033÷ 1.650 = 5.1434

5.1434 contains 5 significant figures and 4 decimals. 5.1434 rounded to 4 sig figs is 5.143, to 3 sig figs is 5.14, and to 2 sig figs is 5.1.

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No of molecules=26.02×10²³molecules

No of moles

Molar mass

Mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{Molecules}{Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{26.02\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=4.32mol[/tex]

We need the mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles\times molar\:mass[/tex]

[tex]\\ \tt{:}\longrightarrow 32(4.32)[/tex]

[tex]\\ \tt{:}\longrightarrow 138.24g[/tex]

Volume=1600cm³=1.6dm³=1.6L

Temperature=25°C=273+25=298K

Pressure=75000Pa

Now

Apply ideal gas equation

The number of moles needed is

n=48.43mol.

Calculations

Given the values of the volume and temperature, we would convert them to the required units.

Volume=1600cm³=1.6dm³=1.6L

Temperature=25°C=273+25=298K

Pressure=75000Pa

We would use the ideal gas equation

PV=nRT

n=PV/RT

n=75000(1.6)/8.314(298)

n=48.43mol

Answer:

A.DNA

Explanation:

Ahaa Its gona be right

Answer:

D.N.A.

Explanation:

Hi student! Let me help you out on this question.

D.N.A. is the molecule which carries instructions for inherited traits.

[tex]\therefore,Option\quad A \quad is \quad correct[/tex]

Hope that this helped! have a good day ahead.

Answer:

Here's your answer.

M(C3H8) = 44 g/mol

n(C3H8) = 5000 (g)/44 (g/mol) = 113,6 mol

[tex] N = n \times N_{a} = 113,6 \times 6,02 \times {10}^{23} \\ \\ = 684,1 \times 10 ^{23} \sf{molecules} [/tex]