SAT High School

The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in. what percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%

Answers

Answer 1

Answer: The answer would be 5%

Explanation:

Answer 2

The closest answer choice is 2.5%, which is the closest value to 1.7% given in the answer choices.

What is z-score?

The Z-score is a statistical measure that describes the relationship of a value to the mean of a group of values.

To solve this problem, we can use the standard normal distribution and the z-score formula:

z = (x - μ) / σ

Where x is the value we want to find the probability for, μ is the mean of the distribution, and σ is the standard deviation of the distribution.

In this case, we want to find the percentage of snakes that are longer than 16.6 in., which corresponds to a z-score of:

z = (16.6 - 15) / 0.8 = 2.125

Using a standard normal distribution table or calculator, we can find that the percentage of values in the distribution that are greater than a z-score of 2.125 is approximately 1.7%. Therefore, approximately 1.7% of snakes are longer than 16.6 in.

Thus, the probable answer is 2.5%.

For more details regarding Z-score, visit:

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