Solve the system using substitution.
y=-x-2,3x+3y=6

Answers

Answer 1

Step-by-step explanation:

x = -2-y

3(-2-y) +3y =6

-6-3y +3y=6

у=0

O=-x-2

х=-2


Related Questions

The endpoints of wx are w (5,-3) and x (-1,-9) what is the length of wx ?

Answers

Using the distance formula, the length of WX is approximately: 8.5.

How to Find the Length of a Segment Using the Distance Formula?

Distance formula is, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex].

Given the endpoints:

W(5,-3) = (x1, y1)

X(-1,-9) = (x2, y2)

Plug in the values:

WX = √[(−1−5)² + (−9−(−3))²

WX = √[(−6)² + (−6)²]

WX = √72

WX ≈ 8.5

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Answer:

6 2 with the little check mark line in the midddle

Step-by-step explanation:

A new amusement park presold discounted tickets for the opening day as well as upon arrival at the park. the opening day ticket sales for the park, including presales, is represented by this function, where is the number of tickets sold h hours after opening at 7:00 a.m. what is the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m.? a. tickets per hour b. tickets per hour c. tickets per hour d. tickets per hour

Answers

The approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

How to determine the rate of change?

The missing part of the question is represented by the following function:

[tex]T(h) = \frac{386 + 110h}{h}[/tex]

10:00 a.m is 3 hours after 7:00 am and 1:00 p.m is 6 hours after 7:00 am.

This means that:

h = 3 at 10:00 am

h = 6 at 1:00 pm

Next, we calculate T(3) and T(6)

[tex]T(3) = \frac{386 + 110*3}{3} =238.7[/tex]

[tex]T(6) = \frac{386 + 110*6}{6} =174.3[/tex]

The average rate of change is then calculated as:

[tex]T'(h) = \frac{T(3) - T(6)}{3 - 6}[/tex]

This gives

[tex]T'(h) = \frac{238.7 - 174.3}{-3}\\[/tex]

Evaluate

T'(h) = -21

This means that the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

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the prom committee is made up of 8 boys and girls. If there are 12 boys and 15 girls in the group to pick the committee from, how many ways can the committee be organized?

1). 1860 ways

2). 3185325 ways

3). 2220075 ways

4). 675675 ways

Thanks guys!!

Answers

The number of ways can the committee be organized will be 2220075. Then the correct option is 3.

What are permutation and combination?

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

The prom committee is made up of 8 boys and girls.

If there are 12 boys and 15 girls in the group to pick the committee from.

Then the number of ways can the committee be organized will be

Then the number of ways is given by the combination formula. Then we have

Number of ways = ¹²C₀ x ¹⁵C₈ + ¹²C₁ x ¹⁵C₇ + ¹²C₂ x ¹⁵C₆ + ¹²C₃ x ¹⁵C₅ + ¹²C₄ x ¹⁵C₄ + ¹²C₅ x ¹⁵C₃ + ¹²C₆ x ¹⁵C₂ + ¹²C₇ x ¹⁵C₁ +¹²C₈ x ¹⁵C₀

Number of ways = 6435 + 77220 + 330330 + 660660 + 675675 + 360360 + 97020 + 11880 + 495

Number of ways = 2220075

Thus, the correct option is 3.

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what is the solution to the inequality below 14-2(x+1)< -4

Answers

Answer:

x > 8

Step-by-step explanation:

14 - 2(x + 1) < - 4 ← distribute parenthesis and simplify left side

14 - 2x - 2 < - 4

12 - 2x < - 4 ( subtract 12 from both sides )

- 2x < - 16

divide both sides by - 2 , reversing the symbol as a result of dividing by a negative quantity.

x > 8

Omar paid $8.64 for 5.4 pounds of grapes. what was the cost of 1 pound of grapes?

Answers

Answer: $1.6

Exp: 8.64/5.4 = 1.6 ,

checking my work 1.6 * 5 = 8 and 1.6 * 0.4 = 0.64 so 8+0.64 = 8.64 so now I know 1 pound of grapes is $1.6 also 8/5 = 1.6

Explain how the expression 32 relates to the diver's depth

Answers

Answer:

See below

Step-by-step explanation:

Each 32 feet of depth is 1 more atmosphere of pressure on the diver  

What is 95x9 divided by 14?

Answers

Answer:

213.75

Step-by-step explanation:

95×9=855

855÷4=213.75

A lake near the Arctic Circle is covered by a thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a rate of 0.2 meters per week. After 7 weeks, the sheet is only 2.4 meters thick.
Let y represent the ice sheet's thickness (in meters) after x weeks.

Complete the equation for the relationship between the thickness and number of weeks.
y=_____

Answers

The equation for the relationship between the thickness and number of weeks is y = 3.8 - 0.2x

How to write equation?

Ice lost per week = 0.2 metersIce remaining after 7 weeks = 2.4 metersNumber of weeks = xRelationship between the thickness and number of weeks = y

Ice lost at 7 weeks = 7(0.2) = 1.4 meters

Total thickness of ice before loss = Ice remaining after 7 weeks + Ice lost at 7 weeks

= 2.4 + 1.4

= 3.8 meters

The equation:

y = Total thickness of ice before loss - (Ice lost per week × Number of weeks)

= 3.8 - (0.2 × x)

y = 3.8 - 0.2x

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how to find the volume of a room

Answers

multiply the height x the length x the width to find the volume of a room (or another 3d object)

Solve- x/x+1 - 1/2 = -1/x+1

Answers

Answer:

Step-by-step explanation:

Remark

x/(x+1) - 1/2 = -1 /(x + 1) is the equation to be solved. Add 1/(x + 1 to both sides

x/(x+1) + 1/(x+1) - 1/2 = -1/(x + 1) + 1/(x + 1)              Combine

x/(x+1) + 1/(x + 1) - 1/2 = 0                                      Combine x/(x+1) + 1/(x+1)

(x + 1)/(x + 1) - 1/2 = 0                                            Cancel (x+1)/(x+1) = 1

1 - 1/2 = 0                                                              No solution

Answer: No solution

Given: ΔABC (to the right)
AB=15
BD=9
AD⊥BC
m∠C=30°
Find Perimeter of ABC

Answers

Applying the Pythagorean theorem and the trigonometric ratios, the perimeter of triangle ABC is: 68.8 units.

What is the Perimeter of a Triangle?

The perimeter of a triangle = sum of its 3 sides.

Given the following:

AB = 15 BD = 9m∠C=30°

Use the Pythagorean theorem to find AD considering triangle ADB as a right triangle:

AD = √(15² - 9²)

AD = 12 units

Use the trigonometric ratios to find DC and AC:

sin 30 = AD/AC

sin 30 = 12/AC

AC = 12/sin 30

AC = 24 units

tan 30 = AD/DC

tan 30 = 12/DC

DC = 12/tan 30

DC ≈ 20.8 units

BC = BD + DC = 9 + 20.8

BC = 29.8 units.

Perimeter of triangle ABC = BC + AB + AC

Perimeter of triangle ABC = 29.8 + 15 + 24

Perimeter of triangle ABC = 68.8 units.

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Explain the difference between 2(7x-4) and (7x-4)^2

Answers

2(7x-4) is the equation being multiplied by two and (7x-4)^2 is the equation being multiplied by itself twice

Answer:

2(7x-4) = 7x(2)-4(2) = 14x-8

but

(7x-4)^2 = (7x-4) (7x-4)

Please help me, greatly appreciate it!

Answers

Answer: See the screenshots below

I'm answering in this format because the questions aren't numbered, so its hard to reference them consistently (so we're both on the same page).

All decimal values are approximate. I decided to round to 4 decimal places, but feel free to use another level of precision.

100 POINTS PLEAS please help
(-2u3 + 5u - 1) + (7u3 - 2u2 + 9)

A) 5 u3 - 2 u2 + 5 u + 8
B) -5 u3 - 2 u2 + 5 u + 10
C)5 u3 + 3 u + 8

Answers

Answer:

[tex]\textsf{A)} \quad 5u^3-2u^2+5u+8[/tex]

Step-by-step explanation:

Given expression:

[tex](-2u^3+5u-1)+(7u^3-2u^2+9)[/tex]

Remove parentheses:

[tex]\implies -2u^3+5u-1+7u^3-2u^2+9[/tex]

Collect like terms:

[tex]\implies -2u^3+7u^3-2u^2+5u-1+9[/tex]

Combine like terms:

[tex]\implies 5u^3-2u^2+5u+8[/tex]

(-2u³+5u-1)+(7u³-2u²+9)-2u³+5u-1+7u³-2u²+95u³-2u²+5u-1+95u³-2u²+5u+8

Option A

Slope of (-9,-2) and (-9,-6)

Answers

Answer:

Slope is undefined.

Step-by-step explanation:

5 pts
Question 5
A model rocket is launched 25 feet from you. When the rocket is at height h, the
distance d between you and the rocket is given by d = √216 +h2 where h and d
are measured in feet. What is the rocket's height when the distance between you and
the rocket is 100 feet? Round to 3 decimal places
Question 6
5 pts

Answers

The rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet

How to determine the rock's height?

The function is given as:

d = √216 +h²

At a distance of 100 feet, it means that:

d = 100

So, we have:

√216 +h² = 100

Take the square of both sides

216 +h² = 10000

Subtract 216 from both sides

h²= 9784

Take the square root of both sides

h = 98.9

Hence, the rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet

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Sherri solved the equatjon 1/5(x-20)=45. For each step, write the name of the property sherri used

Answers

Answer: The awnser is linear.

I hope this helped.

Step-by-step explanation:

what’s the area of the base

Answers

Answer:

16 square units

Step-by-step explanation:

16 square units

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with outward normal orientation away from the origin

Answers

Parameterize S by the vector function

[tex]\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle[/tex]

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

[tex]\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle[/tex]

The integral of the field over S is then

[tex]\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}[/tex]

Select the correct answer.
To solve this system of equations using substitution, what could be substituted in place of y in the first equation?
4x=5-2y
y-2x=7

Answers

Answer: y=2x+7

(this is a rearranged version of y-2x=7 from question)

Step-by-step explanation:

4x=5-2y

y-2x=7

i would rearrange the 2nd value into y intercept form y=mx+b

so move the -2x to the other side of the = sign by doing the opposite, +2x on both sides to isolate the y

y=2x+7

you didn't give any options for "correct answer" so i can't give

you A B C or D answers

The circumference of the hub cap of a tire is 80.07 centimeters. find the area of this hub cap. use
3.14 for it. if the circumference of the hub cap were smaller, explain how this
would change the area of the hub cap.
the area of this hub cap is about how many
square centimeters?

Answers

The area of this hub cap is about  510.44625 cm².

What is Area of Circle?

The area of circle is pi times the square of the radius.

Area of circle =π r²

Circumference (C) = 2π r

80.07 = 2 (3.14) r

76.87/ (2x 3.14) =r

r = 12.75 cm

now, Area be

=π r²

= 3.14*12.5*12.75

=510.44625 cm²

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1 soda + 1 cupcake+1popsicle=$22.00
1 soda +3cupcakes+3popsicle=$40.00
if a cupcake cost,$2:00 more than a popsicle,find the cost of the following

a)1 cupcake

b)1 popsicle ​

Answers

Answer:

a)  1 cupcake = $5.50

b)  1 Popsicle = $3.50

Step-by-step explanation:

Let s = cost of one soda

Let c = cost of one cupcake

Let p = cost of one Popsicle

From the given information we can create 3 equations:

Equation 1:   s + c + p = 22Equation 2:   s + 3c + 3p = 40Equation 3:   c = p + 2

Subtract Equation 1 from Equation 2 to eliminate the variable s:

    s + 3c + 3p = 40

-        s + c + p = 22

          2c + 2p = 18

Substitute Equation 3 into this new equation and solve for p:

⇒ 2c + 2p = 18

⇒ 2(p + 2) + 2p = 18

⇒ 2p + 4 + 2p = 18

⇒ 4p = 14

⇒ p = 3.5

Substitute the found value of p into Equation 3 and solve for c:

⇒ c = p + 2

⇒ c = 3.5 + 2

⇒ c = 5.5

To find the cost of a soda (s), substitute the found values of p and c into Equation 1:

⇒ s + c + p = 22

⇒ s + 5.5 + 3.5 = 22

⇒ s = 13

Therefore,

1 soda costs $131 cupcake costs $5.501 Popsicle costs $3.50

Segment GH is shown on the graph.

What are the coordinates of the point that divides the
segment into a 3:2 ratio?
O (-7.5, 0.5)
O (0.5, -7.5)
O (-1.2,-2.2)
O (-2.2,-1.2)

Answers

The coordinates of the point that divides the segment into a 3:2 ratio is (-2.2, -1.2)

How to determine the coordinate?

The points are given as:

G = (-4,3)

H = (-1,-4)

Ratio, m : n = 3 : 2

The coordinate of the point is calculated using:

[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{3 + 2} * (3 * -1 + 2 * -4, 3 * -4 + 2 * 3)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (-11, -6)[/tex]

Evaluate the product

(x,y) = (-2.2, -1.2)

Hence, the coordinate of the point is (-2.2, -1.2)

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i donnt know ..............

Answers

Answer:

7

Step-by-step explanation:

[tex]\dfrac 13(15+6)\\\\\\=\dfrac{21}3\\\\\\=7[/tex]

A light bulb consumes 1440 watt-hours per day. How long does it take to consume 6480 watt-hours?

Answers

The number of days it will take to consume the given power = 4.5 days

Calculation of energy consumption

The amount of power consumed per day = 1440watt-hours

Therefore X days = 6480 watt-hours?

Make X the subject formula;

X = 1 × 6480/1440

X = 4.5 days

Therefore, The number of days it will take to consume the given power = 4.5 days.

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Use synthetic division to evaluate (3x2 − 6x + 3) ÷ (x − 1). 3x − 9 3x2 − 3x 3x − 3 3x2 − 6

Answers

Answer:

[tex]\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]
[tex]\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{-3\left(x^4+41x^2+x+2\right)}[/tex]
[tex]\frac{\left(x-1\right)^2}{-\left(x^4+41x^2+x+2\right)}[/tex]
[tex]-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]

Answer:

3x-3

Step-by-step explanation:

use synthetic division

What is the slope of the line graphed below?
(-2,2)
(3, 1)

Answers

Answer:

-1/5

Step-by-step explanation:

To find the slope, the formula is y2-y1/x2-x1

1-2/3-(-2) = -1/5

Answer:

‐1/5

Step-by-step explanation:

hope this helps!!!!

If you pull a card from a standard deck of 52 and then pull a second card without replacing the first card, you have about a ____ chance(round to nearest percent) of pulling out a face card, followed by on ace.

Answers

The probability that you pull a card from a standard deck of 52 and then pull a second card without replacing the first card is 2%

How to determine the probability?

The given parameters are:

Cards = 52

Face card = 12

Ace = 4

The probability of selecting a face card is:

P(Face card) = 12/52

Now, there are 51 cards.

The probability of selecting an ace is:

P(Ace) = 4/51

The required probability is:

P = 12/52 * 4/51

Evaluate

P = 0.0181

Express as percentage

P = 1.81%

Approximate

P = 2%

Hence, the probability is 2%

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Which is the standard form of the equation of a parabola with a focus of (8, 0) and directrix x = –8?

Answers

Answer:

Hi,

Step-by-step explanation:

directrix: x=-8

focus=(8,0)

[tex]x=\dfrac{(y-0)^2}{2*(8+8)}+\dfrac{8-8}{2}\\\\\boxed{x=\dfrac{y^2}{32}}[/tex]

find the angle of elevation of the sun if a building 325 feet tall casts a shadow 296 feet long

Answers

Answer:

Step-by-step explanation:

SOH CAH TOA

we have the (opposite) --> 325
we have the (adjacent) --> 296

so do the inverse tan of opposite over adjacent...
[tex]tan^{-1} (\frac{325}{296} ) = 47.67[/tex] degrees

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