Solve the equation for exact solutions over the interval​ [0, 2π​).

Solve The Equation For Exact Solutions Over The Interval [0, 2).

Answers

Answer 1

Answer:

[tex]\displaystyle x=\left\{0, \frac{2\pi}{3}, \frac{4\pi}{3}\right\}[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]-2\cos^2(x)=-\cos(x)-1[/tex]

Over the interval [0, 2π).

First, notice that this is in quadratic form. So, to make things simpler, we can let u = cos(x). Substitute:

[tex]-2u^2=-u-1[/tex]

Rearrange:

[tex]2u^2-u-1=0[/tex]

Factor:

[tex](2u+1)(u-1)=0[/tex]

Zero Product Property:

[tex]2u+1=0\text{ or } u-1=0[/tex]

Solve for each case:

[tex]\displaystyle u=-\frac{1}{2}\text{ or } u=1[/tex]

Back-substitute:

[tex]\displaystyle \cos(x)=-\frac{1}{2}\text{ or } \cos(x)=1[/tex]

Using the unit circle:

[tex]\displaystyle x=\left\{0, \frac{2\pi}{3}, \frac{4\pi}{3}\right\}[/tex]


Related Questions

A cylinder has a base area of 64π m2. Its height is equal to twice the radius. Identify the volume of the cylinder to the nearest tenth.

V = 6434.0 m3
V = 2804.2 m3
V = 1402.1 m3
V = 3217.0 m3

Answers

Answer:

3215 .36 m³ is the required volume.

Step-by-step explanation:

Base area of Cylinder = 64π m²

Height of cylinder is equal to twice the radius .

As we know that ,

★Base Area of Cylinder = πr²

where,

π is taken as 22/7 or 3.14

r is the radius of cylinder

Substitute the value we get

↝ 64 π = πr²

↝ 64 = r²

↝ √64 = r

↝ 8 = r

↝ r = 8 m

Now, it is given that height is equal to twice of radius

Therefore ,

height = 2r = 2×8 = 16 m

★Volume of Cylinder = πr²h

substitute the value we get

↝ volume of Cylinder = 3.14 × 8² × 16

↝volume of Cylinder = 3.14 × 64 × 16

↝volume of Cylinder = 3215 .36 m²

Hence, the required volume of cylinder is 3215 .36 m³.

Answer:

3217.0

Step-by-step explanation:

Find the area of the following figure and write your result in the empty box.

Answers

Answer:

Area = 406

Step-by-step explanation:

First things first: Divide the shape

Here is how I did it:

21 x 16

14 x 5

Now solve:

21 x 16 = 336

14 x 5 = 70

Now add:

336 + 70 = 406

So the area is 406

What is the value of y?
please hellpp!!!

Answers

Answer:

C=54°

Step-by-step explanation:

If u add each angle of a triangle should ways add up to 180°

A line segment AB has midpoint (2, 5). If the coordinates of A are (-1, -3), what are the coordinates of B?

Answers

Answer:

B (5; 13)

Step-by-step explanation:

Midpoint (x) = (-1 + bx)/2 = 2

Bx - 1 = 4

Bx = 5

Midpoint (y) = (-3 + By)/2 = 5

By - 3 = 10

By = 13

B (5; 13)

Suppose A and B are independent events. If P(A) = 0.6 and P(B) = 0.85, what is P(A and B)?
A. .34
B. .51
C. .17
D. .68

Answers

Answer:0.51 I just took the test

Step-by-step explanation:

-4, 1, 8, 4, 8, 7, 10, -5, -2, 7
Work out the mean temperature

Please help me the homework is due tomorrow

Answers

You have to add all the numbers then divide by how many there are, the mean is 3.4

Minutes No. of Homework
Problems
2 or Less
3-4
5-6
7-8
9 or more 8
4
2
0
3

What is the number of homework problems that took less than 5 minutes in the given table?
A.
4
B.
14
C.
12
D.
8

Answers

Could you please provide a picture of the table? This is very confusing.

Consider A TUV in the figure below.
The perpendicular bisectors of its sides are AD, BD, and CD. They meet at a single point D.
(In other words, D is the circumcenter of A TUV.)
Suppose CD= 36, BV=58, and UD = 60.
Find UV, VD, and TC.
Note that the figure is not drawn to scale.
U
V
UV - 10
D
VD = 0
TC -
Х
?

Answers

Answer:

Step-by-step explanation:

8

If A+B+C=[tex]\pi[/tex] show that tan A + tan B +tan C = tan A.tan B.tan C

Answers

Answer:

[tex]a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b) [/tex]

Step-by-step explanation:

we have:

[tex] \tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)[/tex]

we also have:

[tex] \tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)[/tex]

from (1)(2) => proven

f
Solve the equation + 22 = 17.
3

Answers

Answer: subtract 22 on both sides

Step-by-step explanation:

Now you would have -5 to solve take 3 and multiply on both sides to get f=-15

Hope this helps

Answer: -5

Step-by-step explanation:

A patient has been instructed to drink a gallon of water each day. How many cups does the patient
need to drink?
Thank

Answers

Answer:

16 cups a day

Step-by-step explanation:

The braking ability of two types of automobiles was compared. Random samples of 64 auto mobiles were tested for each type. The recorded measurement was the distance required to stop when the brakes were applied at 40 miles per hour. The computed sample means and variances were as follows:
y¯¯¯1=118,y¯¯¯2=109 s21=102,s22=87
. Do the data provide sufficient evidence to indicate a difference in the mean stopping distances of the two types of automobiles? Give the attained significance level.

Answers

Answer:

The data provide sufficient evidence to indicate a difference in the mean stopping distances of the two types of automobiles

Step-by-step explanation:

Formulate the null and alternate hypothesis as

H0: u1= u2  against the claim Ha: u1≠ u2

The data given is

y`1=118,    y`2=109     s21=102,   s22=87

The test statistic used is t= y1`- y2`/ Sp√1/n1+ 1/n2

n1= n2= 64

And

Sp² = (n1-1) s12 + (n2-1) s22 / n1+n2-2

Sp² = 63*102+6*87/64+64-2

Sp² = 94.5

Sp= 9.7211

Putting the values in the test statistic

t= 118-108/9.7211√1/64+1/64

t= 5.237

Now finding the value of t at ∝=0.01 for two tailed test

t( 126,0.005)= ±2.6154

At alpha= 0.01  the null hypothesis is rejected.

Now finding the value of t at ∝=0.05 for two tailed test

t( 126,0.025)= ±1.979

Even at alpha= 0.05 the null hypothesis is rejected.

Also at alpha= 0.05 the null hypothesis is rejected because the critical value is  ±1.657

Hence it is concluded that the data provide sufficient evidence to indicate a difference in the mean stopping distances of the two types of automobiles

How much money would you have in an account after 15 years if you earned 9,3% annually and you started with R573,00?​

Answers

Given:

Principal = R573.00

Rate of interest = 9.3% annually

Time = 15 years.

To find:

The amount after 15 years.

Solution:

Formula for amount is:

[tex]A=P\left(1+\dfrac{r}{n}\right)^{nt}[/tex]

Where, P is principal, r is the rate of interest in decimal, n is the number of time interest compounded in an year and t be the number of years.

The interest is compounded annually, so n=1.

Putting [tex]P=573,r=0.093,n=1,t=15[/tex] in the above formula, we get

[tex]A=573\left(1+\dfrac{0.093}{1}\right)^{1(15)}[/tex]

[tex]A=573\left(1+0.093\right)^{15}[/tex]

[tex]A=573\left(1.093\right)^{15}[/tex]

[tex]A=2174.98893[/tex]

[tex]A\approx 2174.99[/tex]

Therefore, the amount in the account after 15 years is about  R2174.99.

questionon on picture​

Answers

Answer:

yes this option is correct

Solve for each unknown angle measure...


Please help! This a a test btw so please give me the right answer!​

Answers

Answer:

because l1//l2 => z + 65 = 180

y + 65 = 90

x + 65 = 90

<=> z = 115

y = 25

x = 25

Answer:

x=25

y=25

z=115

Step-by-step explanation:

x congruent to y

180-90-65=25

180-65=115

Luke is driving from his house to the store. After driving 16 miles at a constant speed of 0.8 mile/minute, he realizes that he forgot his wallet. So, he turns around and drives all the way back to his house at the same speed. The equation below models Luke's distance, in miles, from home as he drives for t minutes. Using the given equation, match the number of minutes since Luke started driving from his house to his distance from the house. 12 minutes 27 minutes 31 minutes 7 minutes 10.4 miles on his return trip arrowRight 5.6 miles on his trip to the restaurant arrowRight 9.6 miles his trip to the restaurant arrowRight 7.2 miles on his return trip arrowRight

Answers

Answer:

The number of minutes since Luke started driving from his house to his distance from the house is 40 minutes. :)

Step-by-step explanation:

(08.06 LC)
Identify the factors of x2 + 16y? (5 points)
O (x + 4y)(x + 4y)
O (x + 4y)(x - 4y)
Prime
O (x - 4y)(x - 4y)

Answers

Answer:

Prime

Step-by-step explanation:

2(x?)+16y

O(x+4y)(x+4y)

x²+4xy+4xy+16y²

x²+8xy+16y²

O(x+4y)(x-4y)

x²-4xy+4xy-16y²

x²-16y

Prime

O(x-4y)(x-4y)

x²-4xy-4xy+16y²

x²-8xy+16y²

All are incorrect except prime, so the answer is prime.

---

hope it helps

please help asap !!!!​

Answers

Answer:

P = 3/8

q = 1/2

Step-by-step explanation:

(3/8)^3/8 × (3/8)^1/8 = P^q

Because of the same base, pick one of the bases

Then, add the powers

(3/8)^3/8 × (3/8)^1/8 = P^q

= (3/8)^3/8 + 1/8

= (3/8)^(3+1)/8

= (3/8)^4/8

= (3/8)^1/2

Therefore,

P^q = (3/8)^1/2

Where,

P = 3/8

q = 1/2

P^q = (3/8)^1/2

= √(3/8)

In circle F with mZEFG = 30 and EF =
30 and EF = 11 units, find the length of arc EG.
Round to the nearest hundredth.
F
G
E

Answers

Answer:

5.76 units

Step-by-step explanation:

Length of arc EG = central angle/360 × 2πr

Where,

central angle = 30°

radius (r) = 11 units

Plug in the values into the formula

Length of arc EG = 30/360 × 2 × π × 11

Length or arc EG ≈ 5.76 units (to nearest hundredth)

What is the volume of the container below? ​

Answers

Answer:

124 would be the volume............ but I don't see that

Shoemakers of America forecasts the following demand for the next six months: 5000 pairs in month 1; 6000 pairs in month 2; 7000 pairs in month 3; 9000 pairs in month 4; 6000 pairs in month 5; 5000 pairs in month 6. It takes a shoemaker 20 minutes to produce a pair of shoes. Each shoemaker works 150 hours per month plus up to 40 hours per month of overtime. A shoemaker is paid a regular salary of $2000 per month plus $20 per hour for overtime. At the beginning of each month, Shoemakers can either hire or fire workers. It costs the company $1000 to hire a worker and $1200 to fire a worker. The monthly holding cost per pair of shoes is 5% of the cost of producing a pair of shoes with regular-time labor. The raw materials in a pair of shoes cost $10. At the beginning of month 1, Shoemakers has 15 workers and 500 pairs of shoes in inventory. Determine how to minimize the cost of meeting (on time) the demands of the next six months.

Answers

Answer:

5,000+6,000+7,000+,9,000+6,000+5,000= 38,000

Step-by-step explanation:

The minimum cost of meeting the demands of the next six months is $7475.00.

Here, we have,

To determine how to minimize the cost of meeting the demands of the next six months, we need to create a production and workforce plan that balances the demand for shoes with the available workforce and inventory.

Let's break down the problem into several steps:

Step 1: Calculate the regular production capacity and overtime capacity:

Regular production capacity: Number of regular working hours per month divided by the time it takes to produce a pair of shoes.

Overtime capacity: Number of overtime hours per month divided by the time it takes to produce a pair of shoes.

Given:

Regular working hours per month: 150 hours

Overtime hours per month: 40 hours

Time to produce a pair of shoes: 20 minutes (1/3 of an hour)

Regular production capacity = 150 hours / (1/3 hour) = 450 pairs per month

Overtime capacity = 40 hours / (1/3 hour) = 120 pairs per month

Step 2: Create a monthly production plan:

We will use the regular production capacity, overtime capacity, and inventory to fulfill the demand for each month.

Starting with the initial inventory of 500 pairs, we calculate the additional production needed for each month to meet the demand.

Month 1:

Demand: 5000 pairs

Additional production needed: 5000 - 500 = 4500 pairs

Month 2:

Demand: 6000 pairs

Additional production needed: 6000 - (500 + 4500) = 1000 pairs

Month 3:

Demand: 7000 pairs

Additional production needed: 7000 - (500 + 4500 + 1000) = 1000 pairs

Month 4:

Demand: 9000 pairs

Additional production needed: 9000 - (500 + 4500 + 1000 + 1000) = 2000 pairs

Month 5:

Demand: 6000 pairs

Additional production needed: 6000 - (500 + 4500 + 1000 + 1000 + 2000) = 0 pairs

Month 6:

Demand: 5000 pairs

Additional production needed: 5000 - (500 + 4500 + 1000 + 1000 + 2000) = 0 pairs

Step 3: Determine the hiring and firing decisions:

To minimize costs, we need to hire or fire workers based on the additional production needed for each month.

Based on the calculations from Step 2, we can identify the following hiring and firing decisions:

Month 1:

Additional production needed: 4500 pairs

Hire 5 workers (cost: 5 * $1000 = $5000)

Month 2:

Additional production needed: 1000 pairs

No hiring or firing needed (as the existing workforce can handle it)

Month 3:

Additional production needed: 1000 pairs

No hiring or firing needed

Month 4:

Additional production needed: 2000 pairs

No hiring or firing needed

Month 5:

Additional production needed: 0 pairs

No hiring or firing needed

Month 6:

Additional production needed: 0 pairs

No hiring or firing needed

Step 4: Calculate the costs:

Now, we can calculate the costs associated with hiring, firing, and production.

Hiring cost: $5000 (Month 1)

Firing cost: $0 (No firing needed)

Holding cost: 5% of the cost to produce a pair of shoes with regular-time labor, multiplied by the inventory at the beginning of each month.

Holding cost for Month 1: 0 (no inventory at the beginning of Month 1)

Holding cost for Month 2: 0.05 * ($2000 + 4500 * $10) = $237.50

Holding cost for Month 3: 0.05 * ($2000 + 5500 * $10) = $297.50

Holding cost for Month 4: 0.05 * ($2000 + 7500 * $10) = $475.00

Holding cost for Month 5: 0.05 * ($2000 + 7500 * $10) = $475.00

Holding cost for Month 6: 0.05 * ($2000 + 7500 * $10) = $475.00

Total cost:

Total cost = Hiring cost + Firing cost + Holding cost

= $5000 + $0 + ($237.50 + $297.50 + $475.00 + $475.00 + $475.00)

= $7475.00

Therefore, the minimum cost of meeting the demands of the next six months is $7475.00.

To earn more on addition click:

brainly.com/question/29560851

#SPJ4

Factorise a^2-b^2 but it has no indecies

Answers

Answer:

(a+b)(a-b)

Step-by-step explanation:

What is the first step in evaluating the expression below?
12 + 6 - 4 X (12-5)
Add 12 + 6
O Multiply 4 x 12
Subtract 5 from 12
O Multiply 4x7

Answers

PEMDAS so parentheses first meaning you subtract 5 from 12

URGENT NEED HELP CLICK TO SEE

Answers

Answer: 2*5^2-12

5 to the 2nd power is 25

2*25-12

2*25=50

50-12=38

the answer is C 38

hope this helps

Is this right? If not, what is it? PLEASE

Answers

Answer:

It is correct.

Step-by-step explanation:

Can i get some help solving this problem please. 2x=x-10

Answers

Answer:

x=3.33

Step-by-step explanation:

2x=x-10

2x+x=10

3x=10

x= 10/3

x= 3.33

write the coefficient of a in 7 a​

Answers

Given:

The term is 7a.

To find:

The coefficient of "a" in the given term "7a"​.

Solution:

In the product of a number and a variable, the number is called the coefficient of that variable.

In the expression "7a", the number is "7" and the variable is "a". It means the number 7 is the coefficient of "a".

Therefore, the coefficient of "a" in the given term "7a" is 7​.

Please help will give brainlyist

Answers

Number 11
Since the auditorium can hold 600 and the student body will be divide by four parts
The answer is
x ≤ 2400

1. What is the surface area of the composite figure? Show ALL your work.
2. What is the volume of the composite figure? Show ALL your work.

Answers

Answer:

1. 144.4 m²

2. 120 m³

Step-by-step explanation:

The figure is composed of a triangular prism and a rectangular prism

1. Surface area of the composite figure = (surface area of the triangular prism - area of the face joining the rectangular prism) + (surface area of the rectangular prism - the face joining the triangular prism)

✔️Surface area of the triangular prism = bh + (s1 + s2 + s3)*L

b = 5 m

h = 2 m

s1 = 3.2 m

s2 = 3.2 m

s3 = 5 m

L = 6 m

Plug in the values

Surface area of triangular prism = 5*2 + (3.2 + 3.2 + 5)*6

= 10 + (11.4)*6

= 78.4 m²

✔️Area of rectangular prism = 2(LW + LH + WH)

L = 6 m

W = 5 m

H = 3 m

Plug in the values

Area of rectangular prism = 2(6*5 + 6*3 + 5*3)

= 126 m²

✔️Area of the face joining both figures = L*W

L = 6 m

W = 5 m

Area = 6*5 = 30 m²

✅Surface area of the composite figure = (78.4 - 30) + (126 - 30)

= 48.4 + 96

= 144.4 m²

2. Volume of composite figure = volume of triangular prism + volume of rectangular prism

= ½*a*c*h + L*W*H

a = 2 m

c = 5 m

h = 6 m

L = 6 m

W = 5 m

H = 3 m

Plug in the values

Volume = ½*2*5*6 + 6*5*3

Volume = 30 + 90 = 120 m³

help I want to understand how to do this

Answers

9514 1404 393

Answer:

arc RS = 100°RS is a minor arcarc ST = 80°

Step-by-step explanation:

The measure of an arc of a circle is the same as the measure of the central angle it subtends. That is, arc RS has the same measure as central angle RPS, which is marked as 100°.

Of course, the total of all central angles, hence all arcs, of a circle is 360°. A diameter of a circle cuts the circle in half, so each semicircle has a central angle measure and arc measure of 180°.

Any arc that is more than a semicircle is called a "major" arc. If it is less than a semicircle, it is a "minor" arc. Arcs RS and ST are minor arcs.

As always in geometry, the whole is the sum of the parts, so arcs RS and ST are supplementary. They total the measure of semicircle RST, which is 180°. Then ST = 180° -RS = 180° -100° = 80°.

__

Additional comment

Usually, an arc identified only by its end points is a minor arc. If the major arc is intended, then it will either be described as "major arc RS" or a point on the major arc will be given, as "arc RTS". The measure of arc RTS is 280°.

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