solve for x. round to the nearest tenth of a degree, if necessary.​

Answer:

2⁴ × 3³ × 5

Step-by-step explanation:

By prime factorisation,

→ 2160 = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5

→ 2160 = 2⁴ × 3³ × 5

Answer:

x = 25

Step-by-step explanation:

Correct question

In a right triangle Sin (40-x)=cos(3x) what is the value of x

Since Sin theta = Cos(90-theta)

Sin (40-x) = Sin(90-3x)

40 - x = 90 - 3x

-x+3x = 90 - 40

2x = 50

x = 25

Hence the value of x is 25

Answer:

Triangle A:

- smaller leg = 3

- longer leg = 10

- hypotenuse = 10.4

Traingle B:

- smaller leg = 4

- longer leg = 13

- hypotenuse = 13.6

Triangle C:

- smaller leg = 5

- longer leg = 7

- hypotenuse = 8.6

Step-by-step explanation:

Let's find the distance of the legs for the 3 right triangles.

Triangle A

The smaller leg (SL) is from (2,5) to (2,8), so the length is given by the distance in the y-axis:

[tex] SL_{A} = 8 - 5 = 3 [/tex]

Hence, the lenght of the smaller leg is 3.

The longer leg (LL) is from (-8, 8) to (2, 8), so the length is given by the distance in the x-axis:

[tex] LL_{A} = 2 - (-8) = 10 [/tex]

Then, the length of the longer leg is 10.  

Now, we can find the hypotenuse (H) by using Pitagoras:

[tex] H_{A} = \sqrt{SL_{A}^{2} + LL_{A}^{2}} = \sqrt{3^{2} + 10^{2}} = 10.4 [/tex]

Triangle B

The SL is from (3, -9) to (7, -9)

The length of the SL is:

[tex] SL_{B} = 7 - 3 = 4 [/tex]

The LL is from (7, -9) to (7, 4)

The length of the LL is:

[tex] LL_{B} = 4 - (-9) = 13 [/tex]

The hypotenuse is:

[tex] H_{B} = \sqrt{4^{2} + 13^{2}} = 13.6 [/tex]

Triangle C

The SL is from (-10, -6) to (-10, -1)

The length of the SL is:

[tex] SL_{C} = -1 - (-6) = 5 [/tex]

The LL is from (-10, -6) to (-3, -6)  

The length of the LL is:

[tex] LL_{C} = -3 - (-10) = 7 [/tex]

The hypotenuse is:

[tex] H_{C} = \sqrt{5^{2} + 7^{2}} = 8.6 [/tex]

I hope it helps you!

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Answer:

[tex]sin 2 \theta = \frac{4 \sqrt5}{9}[/tex]

Step-by-step explanation:

Identities used :

[tex]1. sin^2 \theta = 1 - cos^2\theta\\\\2. tan^2 \theta + 1 = sec^2 \theta\\\\3.cos \theta = \frac{1}{sec \theta} \\\\4. sin 2 \theta = 2 sin\theta cos\theta[/tex]

[tex]Given \ tan \theta = -\frac{2 \sqrt5}{5}\\[/tex]

[tex]we \ know \ tan ^2 \theta + 1 = sec^2\theta[/tex]

            [tex](-\frac{2 \sqrt 5}{5})^2 + 1 = sec^2 \theta\\\\\frac{4 \times 5}{25 } + 1 = sec^2 \theta \\\\\frac{20 + 25}{ 25} = sec^2 \theta \\\\\frac{45}{25} = sec^2 \theta \\\\sec \theta = \sqrt{ \frac{45}{25}}\\\\sec \theta = \sqrt{ \frac{9 \times 5}{5 \times 5}} \\\\sec \theta = \frac{3 \sqrt {5}}{5}\\\\[/tex]

[tex]We \ know \ cos \theta = \frac{1}{ sec \theta}[/tex]

[tex]So , \cos \theta = \frac{5}{3 \sqrt5}[/tex]

[tex]Next \ sin^2 \theta = 1 - cos^2 \theta[/tex]

                 [tex]= 1 - (\frac{5}{3 \sqrt5})^2\\\\=1 - \frac{25}{9 \times 5}\\\\=1 - \frac{25}{45}\\\\=\frac{45 - 25}{45}\\\\=\frac{20}{45}\\\\=\frac{4}{9}[/tex]

    [tex]sin \theta = \sqrt{ \frac{4}{9}} = \frac{2}{3}[/tex]

[tex]Find \ sin 2 \theta[/tex]

[tex]sin 2 \theta = 2 (sin \theta \times cos \theta)[/tex]

        [tex]= 2 \times \frac{2}{3} \times \frac{5}{3\sqrt5}\\\\= \frac{4 \times \sqrt5 \times \sqrt5}{9 \times \sqrt 5}\\\\=\frac{4 \sqrt5}{9}[/tex]

Answer:

Compressions

Step-by-step explanation:

The third type is compressions

Answer:

13

Step-by-step explanation:

The IQR = Interquartile Range is the difference between the first and third quartile

Rearranged data set:

3, 7, 16, 17, 20, 45

Step 1

We find the first quartile = Q1

= 1/4(n + 1)th number

n = 6

= 1/4(6 + 1)th

= 1/4(7)th

= 1 3/4th number

This = 7

Step 2

We find the third quartile = Q3

= 3/4(n + 1)th number

n = 6

= 3/4(6 + 1)th

= 3/4(7)th

= 21/4th number

= 5 1/4 th number

This = 20

Step 3

IQR = Q3 - Q1

= 20 - 7

= 13

Answer:

23,300 students

Step-by-step explanation:

1900 year, 3.7 * 10 ^ 3

3.7 * 10 * 10 * 10 = 3,700

1950 year,  2.7 * 10 ^ 4

2.7 * 10 * 10 * 10 * 10 = 27,000

So then you will subtract 1950 year by the year of 1900

27,000 - 3,700 = 23,300

a) Two angles are said to be complementary if their sum is equal to 90°

Given : 2x and 4x are complementary angles

⇒   2x + 4x = 90°

⇒   6x = 90°

⇒   x = 15°

Answer: The two angles are : 30° and 60°

b) Two angles are said to be supplementary if their sum is equal to 180°

Given : x and 5x are supplementary angles

⇒   x + 5x = 180°

⇒   6x = 180°

⇒   x = 30°

Answer: The two angles are : 30° and 150°

c) Two angles are said to be complementary if their sum is equal to 90°

Given : x and x + 50° are complementary angles

⇒   x + x + 50° = 90°

⇒   2x = 40°

⇒   x = 20°

Answer: The two angles are : 20° and 70°

d) If two angles form a linear pair, then the sum of the angles should be equal to 180°

Given : 2x + 10° and 3x + 10° form a linear pair

⇒   2x + 10° + 3x + 10° = 180°

⇒   5x = 160°

⇒   x = 32°

⇒  2x + 10° = 2(32) + 10° = 74°

⇒  3x + 10° = 3(32) + 10° = 106°

Answer: The two angles are 74° and 106°

Step-by-step explanation:

(-) + (-) = (+)

=........ +1

Answer:

-1

Step-by-step explanation:

Answer:

In picture

Step-by-step explanation:

Hope I answered it correctly.

Please give me brainliest if it help you, thanks!

Answer:

its the 2nd one

hope that helps<3

Answer:

jhkkkhj

Step-by-step explanation:

jkjkjkjkj

Answer:

Sorry for the late response, I had to have lunch.

1. >

2. =

3. <

4. >

Step-by-step explanation:

Have a great summer :)

Answer:

8

The missing digit is going to be eight, because if we are rounding to the nearest tenth the 3 won't change anything.

Step-by-step explanation:

Have a nice day! :-)

Answer:

8

Step-by-step explanation:

because the 8 is on the tenths place and with three in the hundredths place I can't round up

Answer:

Perimeter: 8x+8

Area: 16x+16

Step-by-step explanation:

Combine only like terms

(4x+2) + (4x+2) +2+2= 8x+8

(4x+2) x (4x+2) x 2 x 2= 16x+16

Answer:

2300 mm^2

Step-by-step explanation:

Answer:

Step-by-step explanation:

A?

Answer:

Step-by-step explanation:

[tex] {10}^{ - 3} [/tex]

Answer:

8

Step-by-step explanation:

a + b^3 - a

Simplify

b^3

Let b=2

2^3

8

Answer:

11

Step-by-step explanation:

If a = 3, and b = 2, then;

=> a + b³

=> 3 + 2³

=> 3 + 8

=> 11

Hope this helps!

Answer:

T = 3.5m

T is trash in pounds

m is members of family

Step-by-step explanation:

Answer:

1. option c

2. option b

3. option b

Step-by-step explanation:

1 . option C

Square of longer side = sum of squares of other side

a)

5, 6 , 11

[tex]121 = 25 + 36\\does\ not \ satisfy[/tex]

b)

9, 12, 16

[tex]256 = 144 + 81\\Does\ not \ satisfy[/tex]

c)

7, 24, 25

[tex]625 = 576 + 49\\Does\ satisfy[/tex]

d)

12, 20, 25

[tex]625 = 400 + 144\\does \ not \ satisfy[/tex]

2. Option B

Square of longer side = sum of squares of other side

15 ² = 8 ² + r²

225 = 64 + r²

161 = r²

r = 12.688

r = 13ft

3 . Option b

To find length  of AB,  Use distance formula

[tex]AB = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2}[/tex]

    [tex]= \sqrt{(14-3)^2 + (6-1)^2}\\\\=\sqrt{11^2 + 5^2}\\\\=\sqrt{121 + 25}\\\\= \sqrt{146} \\= 12 \ ft[/tex]

Answer:

A. 20

B. 11 + 3tt

Step-by-step explanation:

A.  11 + 3(3) = 20

B.  11 + 3(tt)

Answer:

16 boxes large

Step-by-step explanation:

if the weigth is 1280 wilhich means its 1280÷80 =16

Answer:

35

Step-by-step explanation:

To find this, we are going to use the combination formula as follows;

nCr = n!/(n-r)!r!

In this case, n = 7 and r = 3

Substituting these values;

7C3 = 7!/(7-3)! 3! = 7!/4!3! = 35

Answer:

39.28cm^2

Step-by-step explanation:

Simple work out the area of a circle and halve it.

3.142xr^2

3.142x5^2 = 78.55 cm^2 (Full circle area)

Now we must halve that answer to get the semicircle.

78.55/2 = 39.275 cm^2

However, we need it to 2dp. Therefore the answer is 39.28cm^2

first, you arrange all the numbers in ascending sequence, you should get:

62, 64, 65, 65, 67, 68, 68, 69, 69, 69, 70, 70, 70, 71, 71, 71, 73, 72, 72, 73

yes and now you can see there are 20 values all arranged in ascending order. from here, you find the 2 middle values since it is an even number.

it should be value 10 and 11 which is number 69 and 70

now you find the average which is:

[tex]\frac{69+70}{2}[/tex] = 69.5

so your center value is 69.5.

Answer:

Its B trustStep-by-step explanation

Step-by-step explanation:

Answer:

B and C

Step-by-step explanation:

B is correct because 5² is 25, which is less than 64

C is correct because (-3)² is 9, which is less than 64

Answer:

b c d f

Step-by-step explanation:

-8 ≤ x ≤ 8

Answers:

He has  27   quarters and  31   dimes

=========================================================

Work Shown:

d = number of dimes

q = number of quarters

d+q = 58 since there are 58 coins of only these two types

d = 58-q

10d+25q = 985 .... note that 985 cents is $9.85

10(58-q)+25q = 985 .... replace d with 58-q

580-10q+25q = 985

15q+580 = 985

15q = 985-580

15q = 405

q = 405/15

q = 27 ..... Mike has 27 quarters

d = 58-q

d = 58-27

d = 31 .... Mike also has 31 dimes

-----------

As a way to check:

d+q = 31+27 = 58 so that works out

and

10d+25q = 10*31+25*27 = 310+675 = 985

so that works out as well. The answer is confirmed.