Answer:
True.
Keys:
Manipulate left/right sidesStep-by-step explanation:
[tex]\tan \left(\theta\right)+\cot \left(\theta\right)=\sec \left(\theta\right)\csc \left(\theta\right)\\\tan \left(\theta\right)+\cot \left(\theta\right)\\=\frac{\cos ^2\left(\theta\right)+\sin ^2\left(\theta\right)}{\cos \left(\theta\right)\sin \left(\theta\right)}\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}\\\\\sec \left(\theta\right)\csc \left(\theta\right)\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}[/tex]
What was shown throughout this problem?
We showed that two different sides are capable of taking the same form.
Evaluate the series 12 + 6 + 3 + . .
A) 21
B) 1.5
C) 2
D) 24
All the numbers follow a pattern of division by 2
Therefore the next number is 3/2 which is equal to 1.5
solve 2(r+6) =(6+1/3r)
Answer:
r = - 18/5
I hope this helps! ^^
( This problem has 13 steps, so it would take a lot of time to type them in ^^)
calculates the first term of an arithmetic progression of 4 terms and ratio equal to 4 whose sum is 100
The first term of an arithmetic progression of 4 terms and ratio equal to 4 whose sum is 100 is 19.
How to calculate arithmetic progression?The first term of an arithmetic progression can be calculated using the following expression:
Sn = n/2 [2a + (n − 1)d]
Where;
a = first termUn = sumn = no of termsd = common ratio100 = 2 [2a + (4 - 1)4]
100 = 4a + 24
4a = 100 - 24
a = 76/4
a = 19
Therefore, the first term of an arithmetic progression of 4 terms and ratio equal to 4 whose sum is 100 is 19.
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A football club is the only one in its region and is therefore able to behave like a monopolist. It sells tickets to Adults (a) and Juniors (j), whose demand curves are given by:
Pa = 200 − Qa
Pj = 160 − Qj
Additionally, the club’s total costs are given by = 20Qi
The club hires an economist to consider its pricing strategy and receives the advice that it should charge different prices to each type of supporter. Find the prices it sets in both markets, the sales (output) in each and its overall level of profit and illustrate profit maximising outputs and prices of each consumer type on a graph (one graph for each type of consumer). Calculate consumer surplus in this case.
Answer:
Adult market
price: 110sales: 9900profit: 8100consumer surplus: 9000Junior market
price: 90sales: 6300profit: 4900consumer surplus: 5600Total profit: 13000
Total consumer surplus: 14600
Step-by-step explanation:
Given Adult (a) and Junior (j) demand equations Pa = 200 -Qa and Pj = 160 -Qj, and cost equation C = 20Q, you want to find the price in each market that maximizes profit, the sales in each market, and the consumer surplus, and a graph of profit-maximizing sales and prices.
RevenueEach demand equation is of the form P = Pmax -Q, where P is the price that will result in sales of Q tickets. The revenue (R) in each case is the product of numbers of tickets sold (Q) and the price at which they are sold (P).
R = QP = Q(Pmax -Q)
ProfitThe profit is the difference between revenue and cost.
Profit = R - C = Q(Pmax -Q) -20Q
Profit = Q(Pmax -20 -Q)
Writing the demand equation in terms of P, we find ...
Q = Pmax -P
Substituting this into the Profit equation gives ...
Profit = (Pmax -P)(Pmax -20 -(Pmax -P))
Profit = (Pmax -P)(P -20)
The profit function describes a downward-opening parabolic curve with zeros at P=Pmax and P=20. The maximum profit is on the line of symmetry of this curve, halfway between these values of P:
Price for maximum profit = (Pmax +20)/2 = Pmax/2 +10
PricesIn the adult market, Pmax = 200, so the profit-maximizing ticket price is ...
Pa = 200/2 +10 = 110 . . . . price for maximum profit in Adult market
In the Junior market, Pmax = 160, so the profit-maximizing ticket price is ...
Pj = 160/2 +10 = 90 . . . . price for maximum profit in Junior market
SalesUsing the revenue equation, we find the sales in each market to be ...
Qa = 200 -Pa = 200 -110 = 90
Ra = Qa·Pa = 90(110) = 9900 . . . . sales in Adult market
Qj = 160 -Pj = 160 -90 = 70
Rj = Qj·Pj = 70(90) = 6300 . . . . sales in Junior market
Overall ProfitThe profit in each market is ...
Adult market profit = 90(110 -20) = 8100
Junior market profit = 70(90 -20) = 4900
The overall profit will be the sum of the profits in each market:
Overall profit = 8100 +4900 = 13000
Consumer surplusThe consumer surplus in each market is the area below the demand curve and above the price point. It is half the product of the maximum price and the quantity actually sold.
CSa = (1/2)(200)Qa = 100(90) = 9000
CSj = (1/2)(160)(Qj) = 80(70) = 5600
The total consumer surplus is ...
CS = CSa +CSj = 9000 +5600 = 14,600 . . . . total consumer surplus
Graph
The first attachment shows the sales (output) in each market (red=Adult, purple=Junior) as a function of ticket price. It also shows the corresponding profit (orange=Adult, blue=Junior). The profit-maximizing price point is marked on each curve. You will note that it is different from the output-maximizing price point.
The second attachment illustrates the consumer surplus in each market. That graph has price on the vertical axis, and quantity on the horizontal axis. The colors correspond to the colors on the graph in the first attachment.
Expand and simplify: (-7y - 8) (y - 4)
To expand an expression, use FOIL method.
F - FirstMultiply the first term in each expression inside the parentheses.-7y and y are the first terms in each expression.
(-7y)(y) = -7y²
O - Outside Next is to multiply the terms outside. (The first term in the first expression and the last term in the second expression)-7y is the first term in the first expression
-4 is the last term of the second expression
(-7y)(-4) = 28y
I - InsideThe next step is to multiply the terms inside. (The last term in the first expression and the first term in the last expression)-8 is the last term in the first expression
y is the first term in the second expression
(-8)(y) = -8y
L - LastLast step is to multiply the last term in each expression.-8 is the last term of the first expression
-4 is the last term of the second expression
(-8)(-4) = 32
Combine all simplified terms.
-7y² + 28y - 8y + 32-7y + 20y + 32Answer:
-7y + 20y + 32Wxndy~~
I need help please , I don’t really know much about pre calculus
Answer:
The angle Sita here is called Amplitude
Find the area to the nearesy square foot of the shaded region below, consisting of a square with a circle cut out of it.
Based on the calculations, the area of the shaded region is equal to 22 square foot.
How to calculate the area of the shaded region?By critically observing the geometric shapes, the area of the shaded region can be calculated by using this formula:
Area of shaded region = Area of square - Area of circle.
Note: The diameter of this circle is equal to the side length of the square because the circumference of this circle lies on the circumference of the square.
Radius = diameter/2 = 10/2 = 5 feet.
For the area of square, we have:
Area of square = S²
Area of square = 10²
Area of square = 100 square foot.
For the area of circle, we have:
Area of circle = πr²
Area of circle = 3.14 × 5²
Area of circle = 78.5 square foot.
Substituting the parameters into the formula, we have;
Area of shaded region = Area of square - Area of circle.
Area of shaded region = 100 - 78.5
Area of shaded region = 21.5 ≈ 22
Area of shaded region = 22 square foot.
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Complete Question:Find the area to the nearest square foot of the shaded region below, consisting of a square with a circle cut out of it. Use 3.14 as an approximation for π.
3 (without using trig table) evaluate
It tan 60 x tan 30 divided by
Tan 60 + tan 30
Answer:
[tex]1.25332[/tex]
Step-by-step explanation:
[tex] tan(30 times tan(60 ) \div \tan(60 \div + 30) [/tex]
find the solution set. 4x^2+x=3
Answer:
[tex]x=\frac{3}{4},\:x=-1[/tex]
Keys:
For this problem, you need the quadratic formula(listed below).
[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex][tex]1^a=1[/tex][tex]\sqrt[n]{a}^n=a[/tex]When you see ± in a quadratic equation, you must know there is going to be at least 2 solutions.
Step-by-step explanation:
solving for x₁ and x₂
[tex]4x^2+x=3\\4x^2+x-3=3-3\\4x^2+x-3=0\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot 4\left(-3\right)}}{2\cdot 4}\\[/tex]
[tex]1^2=1\\=\sqrt{1-4\cdot \:4\left(-3\right)}\\=\sqrt{1+4\cdot \:4\cdot \:3}\\=\sqrt{1+48}\\=\sqrt{49}\\=\sqrt{7^2}\\\sqrt{7^2}=7\\=7[/tex]
[tex]x_{1,\:2}=\frac{-1\pm \:7}{2\cdot \:4}\\x_1=\frac{-1+7}{2\cdot \:4},\:x_2=\frac{-1-7}{2\cdot \:4}\\[/tex]
solve for x₁
[tex]\frac{-1+7}{2\cdot \:4}[/tex]
[tex]=\frac{6}{2\cdot \:4}[/tex]
[tex]=\frac{6}{8}[/tex]
[tex]= \frac{6\div2}{8\div2}[/tex]
[tex]=\frac{3}{4}[/tex]
solve for x₂
[tex]\frac{-1-7}{2\cdot \:4}[/tex]
[tex]=\frac{-8}{2\cdot \:4}[/tex]
[tex]=\frac{-8}{8}[/tex]
[tex]=-\frac{8}{8}[/tex]
[tex]=-1[/tex]
Hope this helps!
Cynthia beach wants to buy a rug for a room that is 22 ft wide and 31 ft long.she wants to leave a uniform strip of floor around the rug.she can afford to buy 580 square feet of carpeting.what dimensions should the rug have?
The dimensions the rug should have is 20 by 29
How to determine the dimension?The dimension of the rug is given as:
22 ft by 31 ft
The area of the carpet is given as:
Area = 580
Represent the length of the empty space with x.
So, the dimension of the carpet is:
22 - 2x by 31 - 2x
The area is calculated as:
Area = (22 - 2x) * (31 - 2x)
Expand
Area = 682 - 62x - 44x + 4x^2
Evaluate the difference
Area = 682 -106x + 4x^2
Substitute Area = 580
682 -106x + 4x^2 = 580
Subtract 580 from both sides
102 -106x + 4x^2 = 0
Rewrite as:
4x^2 - 106x +102 = 0
Using a graphing calculator, we have:
x = 1 and x = 22.5
Substitute these values in 22 - 2x by 31 - 2x
So, we have:
Length = 22 - 2(1) = 20 or Length = 22 - 2(22.5) = -23
Width = 31 - 2(1) = 29 or Length = 31 - 2(22.5) = -14
The dimensions cannot be negative.
So, we have:
Length = 20 and Width = 29
Hence, the dimensions the rug should have is 20 by 29
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what are the soltuions to the quadratic equation below? 12x squared + 4x -5=0
Answer: 0.5 or - 0.834
Step-by-step explanation: Here is the explanation!
What’s the range of this graph?
A) all real numbers
B) all real numbers greater than or equal to 0
C) all real numbers greater than or equal to 1
D) all real numbers greater than or equal to 2
Option d is the correct answer. All real numbers are greater than or equal to 2.
What are domain and range?Domain of a function--The domain of the function is the set or collection of all the x-values for which the function is well defined.
Range of a function--The range of a function is the set of all the values which are attained by a function in its defined domain.
By looking at the graph we observe that the function is continuously increasing and the function takes all the real values greater than as well as equal to 2( since there is a closed circle at (1,2). Hence, the range is: [2,∞).
Thus Option d is the correct answer. All real numbers are greater than or equal to 2.
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-3+8x-5=-8 solve for x
The value of this equation is x = 0
The representation of an equation of the first degree - is given by:
[tex] \boxed{ \large \sf ax + b = 0}[/tex]
This representation is also defined in a first degree function.
— To solve this expression, let's: add or subtract the real terms. Then we will do the division.
⚘ Resolution
[tex] \large \sf{-3+8x-5=-8}[/tex]
[tex] \large \sf{-8+8x=-8}[/tex]
[tex] \large \sf{8x=0}[/tex]
[tex] \large \sf{x=0 \div 8}[/tex]
[tex] \green{ \boxed{ \boxed{ \blue{ \large \sf{x=0}}}}} \\ [/tex]
Therefore, the value of this equation will be x = 0
x − y = 12
x + 2y = 21
Answer: x=15, y=3
Step-by-step explanation:
Subtracting the two equations, we get -3y=-9, meaning y=3.
Substituting this into the first equation, we get that x-3=12, and thus, x=15.
(write in algebraic expression) Ice cream shop is open within the month of june,july and august
The shop served 100 fewer customers than they did in july
They served twice as many customers in august as they did in june
In total they served 400 customers over these three months
The algebraic expression of the situation above is 4x - 100 = 400
How to form an algebraic expression?Let
the amount of ice cream they serve in July = x + 100
the amount of ice cream they serve in June = x
They served twice as many customers in august as they did in June.
Therefore,
the amount of ice cream they serve in August = 2(x)
the amount of ice cream they serve in August = 2x
Therefore,
2x + x + x + 100 = 400
4x - 100 = 400
4x = 500
x = 500 / 4
x = 125
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A researcher asks the first 10 people he meets at a shopping mall about their opinions on a certain brand of shampoo. This is an example of a ________________.
A. self-selecting sample
B. convenience sample
C. random sample
D. systematic sample
Answer:
i believe the answer is A
Step-by-step explanation:
Find each square root after supplying:
Answer:
1) 5
2) 0.8
3) -1.3
4) -[tex]\frac{4}{9}[/tex]
5) ±10
6) ±[tex]\frac{7}{12}[/tex]
Step-by-step explanation:
Please help me it’s for Plato on edmentum! Algebra 1 Quadratic relationships Mastery test
The equation of the function g(x) will be g(x) = (1/2) x². Then the correct option is B.
The complete question is attached below.
What is a function?Functions are found all across mathematics and are required for the creation of complex relationships.
The function f(x) is given below.
f(x) = x²
Then the function g(x) will be
g(x) = a · x²
Then the value of will be
From the graph, at x = 2, g(x) will be 2.
Then we have
2 = a · 2²
a = 1/2
Then the equation of the function g(x) will be g(x) = (1/2) x².
Then the correct option is B.
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Find the surface area of the shape below. Round your answer to two decimal places.
The surface area of the given shape is 285.01 ft²
Surface area of a coneFrom the question, we are to calculate the surface area of the given shape.
The given shape in the diagram is a cone.
The surface area of a cone is given by the formula,
[tex]S = \pi r(r+l)[/tex]
Where S is the surface area
r is the radius
and [tex]l[/tex] is the slant height
First, we will calculate the slant height of the cone
[tex]l^{2}=9^{2} +5.6^{2}[/tex] (Pythagorean theorem)
[tex]l^{2}=81+31.36[/tex]
[tex]l^{2}=112.36[/tex]
[tex]l}=\sqrt{112.36}[/tex]
[tex]l=10.6 \ ft[/tex]
∴ The slant height is 10.6 ft
Now, for the surface area
[tex]S = \pi \times 5.6(5.6+10.6)[/tex]
[tex]S = \pi \times 5.6(16.2)[/tex]
[tex]S = 90.72\pi \ ft^{2}[/tex]
[tex]S = 285.0053 \ ft^{2}[/tex]
S ≅ 285.01 ft²
Hence, the surface area of the given shape is 285.01 ft²
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Translate the given phrase into an algebraic expression and simplify if possible: the quotient of 12 and the product of 3 and 4.
Note: Enter only the simplified result.
Answer: 1
Step-by-step explanation:
First, we will translate this into an algebraic expression.
-> Quotient means we will be using divison
-> Product means we will be using multiplciation
the quotient of 12 and the product of 3 and 4
[tex]\displaystyle \frac{12}{\text{the product of 3 and 4}}[/tex]
[tex]\displaystyle \frac{12}{3*4}[/tex]
Now, I will simplify.
Given:
[tex]\displaystyle \frac{12}{3*4}[/tex]
Multiply:
[tex]\displaystyle \frac{12}{12}[/tex]
Divide:
1
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The weight of 1 cm³ of
water is exactly I g.
A small desk top fish
tank is pictured below.
How much does the
water in the tank weigh
in kilograms?
HELP
Answer:
10,800 kilograms
Step-by-step explanation:
(24 x 30) x 15 = 10,800
or (24 x 15) x 30
The radius of a semicircle is 3 kilometres. What is the semicircle's perimeter?
Answer:
In terms of Pi: [tex]3\pi + 6[/tex] km
Exact value (rounded): 15.42477 km
Approximated (3.14): 15.42 km
Step-by-step explanation:
Hello!
A semicircle's perimeter can be found using the formula: [tex]P = \pi r + 2r[/tex]
We can plug in the values to solve for the perimeter.
Solve[tex]P = \pi r + 2r[/tex][tex]P = \pi(3)+ 2(3)[/tex][tex]P = 3\pi + 6[/tex]In terms of Pi, it is [tex]3\pi + 6[/tex],
Exact value of Pi, it is 15.42477
Approximation of Pi (3.14), it is = 15.42
A con is tossed 400 times what is the standard deviation
Answer:
deviation is 10
this will help you
Simplify the expression.
Show your work.
4 √81m^8n^16
Answer:
hope you can understand
Answer:
3m²n⁴
Step-by-step explanation:
Given :
⇒ [tex]\sqrt[4]{81m^{8}n^{16} }[/tex]
=============================================================
Solving :
⇒ [tex]\sqrt[4]{81}[/tex] × [tex]\sqrt[4]{m^{8} }[/tex] × [tex]\sqrt[4]{n^{16} }[/tex]
⇒ [tex]\sqrt[4]{3^{4} }[/tex] × [tex]\sqrt[4]{(m^{2})^{4} }[/tex] × [tex]\sqrt[4]{(n^{4})^{4} }[/tex]
⇒ 3 × m² × n⁴
⇒ 3m²n⁴
I have 23 hundredths and 12 tenths. Who am I? Convince by using Base 10 Blocks
Answer:
1.43
Step-by-step explanation:
12 tenths ⇒ 1.2
23 hundredths ⇒ 0.23
0.23 + 1.2 = 1.43
find the exact value of sin 15 degrees
Answer:
Hi,
Step-by-step explanation:
sin(a-b)=sin(a) cos(b)+ cos(a) sin(b)
a=45° and b=30°
[tex]sin(45^o-30^o)=sin(45^o)*cos(30^o)+cos(45^o)*sin(30^o)\\\\=\dfrac{\sqrt{2}}{2}* \dfrac{\sqrt{3}}{2}+\dfrac{\sqrt{2}}{2}*\dfrac{1}{2}\\\\\\\boxed{sin(15^o)=\dfrac{\sqrt{2}}{4}*(1+\sqrt{3} )}\\[/tex]
Select ALL the correct answers. Consider the following graph of function f. Which transformations will change function f into function g given below. a vertical shift down 3 units a vertical shift down 5 units a vertical shift up 5 units a horizontal shift left 7 units a horizontal shift right 7 units a horizontal shift left 4 units
please help! what is the angle of depression from point C to point A
Answer:
The angle shows 90° so that means
90° - 42° = 48°
Therefore the angle of the depression is 48°
The angle of depression from C to point A 48°. The correct option is c. 48°
Angles of depressionFrom the question, we are to determine the angle of depression from C to point A
The angle of depression is the angle formed between the horizontal line and the line of sight when an observer looks downwards at an object
Thus, in the given diagram
The angle of depression is 90° - 42°
Angle of depression = 48°
Hence, the angle of depression from C to point A 48°. The correct option is c. 48°
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Find the lateral area of the prism. 8cm 6cm, I 1 13cm I 10cm Lateral Area = [?]cm² 2008-2012 International Academy of Science, All Rights Reserved. Aid Enter
The lateral area of the prism is 270cm²
What is the lateral area of a prism?
The lateral area of a prism is defined as the sum of the areas of its lateral faces.
How to determine the lateral area of a prismUsing the formula;
Lateral area = (a+ b+ c) h
Where a, b, c, are all the lateral faces and h is the height
Lateral area = (8 + 6 + 13) × 10 = 27 × 10 = 270cm²
Therefore, the lateral area of the prism is 270cm²
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Select the correct answer. Given the following formula, solve for y. w=x-y/2 -z
Given the following formula, w=x-y/2 -z. The value of y is y = x - 2w + wz .
What is a simplification of an expression?Usually, simplification involves proceeding with the pending operations in the expression.
Like, 5 + 2 is an expression whose simplified form can be obtained by doing the pending addition, which results in 7 as its simplified form.
Simplification usually involves making the expression simple and easy to use later.
Given the following formula,
w=x-y/2 -z
We need to solve for y.
[tex]w = \dfrac{x-y}{2 -z}[/tex]
By cross multiplication
[tex]w\times (2 -z)= {x-y}\\\\2w - wz = x - y[/tex]
subtract x both side
2w - wz -x = x - y -x
y = x - 2w + wz
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