Answer:
See Explanation
Explanation:
The equation of the reaction is;
ZnO(s) + 2HNO3(aq) --------> Zn(NO3)2(aq) + H2O(l)
a) When you first add ZnO to aqueous HNO3, the powder dissolves as it mixes with the acid.
b) If the student keeps on adding more ZnO powder to the HNO3 after the reaction between the acid and metal oxide was complete, the powder will no longer dissolve in the acid. At this point, the reaction has attained equilibrium.
Can someone give me an example of balancing equations with a solution that is simple?
Explanation:
[tex]H _{2}O _{2(aq)} →H _{2}O _{(l)} + O _{2}(g) \\ solution : 2 \: and\: 2[/tex]
Which of these equations represent reactions that could be used in constructing an electrochemical c
Check all that apply
CH. +202 C02 +2H,0
Cr + Cu? → Cr?++ Cu
2 Ag*+Fe + 2Ag +Fe2
CI+Ag → AgCI
NH, *H* NH,
RETRY
Answer:
Cr+Cu2 -> Cr2+Cu
2Ag+Fe->2Ag+Fe2
Explanation: I did the assessment
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
What is the amount of the leftover reactant?
0.74 grams of methane
0.89 grams of methane
1.22 grams of oxygen
1.45 grams of oxygen
Answer:d
Explanation:
Find the % composition for each element in Zinc Chlorate
Answer:
chlorine ~ 30%
zinc ~ 28%
oxygen ~ 41%
Explanation:
Determine the number of moles in 1.5 x 10^25
atoms of iron.
Calculate the freezing point of a solution made by dissolving 13 g potassium sulfide in 150 g H2O Kf for water = 1.86 C/m
Answer:
[tex]T_F=-4.4\°C[/tex]
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to calculate the freezing point of an aqueous solution of potassium sulfide by using the following equation:
[tex]T_F=T_{solv}-i*m*Kf[/tex]
In such a way, we firstly calculate the molality of this solution according to:
[tex]m=\frac{\frac{13g}{110.262 g/mol} }{0.150kg} =0.79m[/tex]
Finally, since the Van't Hoff's factor for K2S is 3, the freezing point of the solution turns out to be:
[tex]T_F=0\°C-3*0.79m*1.86\°C/m\\\\T_F=-4.4\°C[/tex]
Regards!
pls help i need asap will mark brainlest
Answer:
B. 50%
Explanation:
2H₂ + CO → CH₃OHFirst we convert the given masses of the reactants into moles, using their respective molar masses:
4 g H₂ ÷ 2 g/mol = 2 mol H₂25 g CO ÷ 28 g/mol = 0.893 mol CO0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.
Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:
0.893 mol CO * [tex]\frac{1molCH_3OH}{1molCO}[/tex] = 0.893 mol CH₃OHThen we convert 0.893 moles of CH₃OH into grams, using its molar mass:
0.893 mol CH₃OH * 32 g/mol = 28.57 gFinally we calculate the percent yield:
14 g / 28.57 g * 100% = 49%How many valance electrons does He need to get to 8
Answer:
Any element in group 18 has eight valence electrons (except for helium, which has a total of just two electrons
A cylinder of gas with a pressure of 8.0 atm is heated from 300. K to 600. K. What will the new pressure of the gas be?
Answer:
[tex]P_2=16atm[/tex]
Explanation:
Hello there!
In this case, according to the given information, we can infer we need to use the Gay-Lussac's equation it order to understand this pressure-temperature relationship as shown below:
[tex]\frac{P_1}{V_1}=\frac{P_2}{V_2}[/tex]
Thus, we solve for P2 and plug in P1, T1 and T2, to obtain:
[tex]P_2=\frac{P_1T_2}{T_1}\\\\P_2=\frac{8atm*600K}{300K}\\\\P_2=16atm[/tex]
Regards!
Please help will give brainliest
Perform the following
mathematical operation, and
report the answer to the correct
number of significant figures.
328 x 0.125 = [?]
Answer: 41.0
Explanation: When you multiply the two numbers you get 41 but you need to have the same amount of significant numbers as the number in the problem with the least significant numbers. I hope this helps
is this correct im just asking because my little brother not sure for his answer
Control rods in nuclear reactors are made of materials that absorb free neutrons in order to
slow down the chain reaction.
True
False
Use the nutrition label to answer the following questions.
16.How much energy is contained in
the six-cookie serving size
recommended on the label?
17.How much energy in joules is provided by eating
six cookies? (1 cal = 4.184 J; ALSO: 1 Calorie = 1
kilocalorie)
Answer:
six cookies?(1 cal _4.184 j; ALSO: 1 Calorie -1 kilocalorie)
how to make 100 ml of 0.001 mM solution with 0.0405mM solution?
Answer:
Measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water
Explanation:
To make 100 mL of 0.001 mM solution from 0.0405mM solution, we need to determine the volume of 0.0405mM solution needed. This can be obtained as follow:
Molarity of stock (M₁) = 0.0405 mM
Volume of diluted (V₂) = 100 mL
Molarity of diluted solution (M₂) = 0.001 mM
Volume of stock solution needed (V₁) =?
M₁V₁ = M₂V₂
0.0405 × V₁ = 0.001 × 100
0.0405 × V₁ = 0.1
Divide both side by 0.0405
V₁ = 0.1 / 0.0405
V₁ = 2.47 mL
Therefore, to make 100 mL of 0.001 mM solution from 0.0405mM solution, measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water.
1st law of motion law of inertia in toy story 2
What is the name of Na
does the moon really change shape? why
If a particular ore contains 56.3 % % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg k g of phosphorus?
Answer:
34.44 kg
Explanation:
First we convert 1.00 kg of phosphorus (P) into moles, using its molar mass:
1.00 kg ÷ 32 kg/kmol = 0.03125 kmol PThen we convert 0.03125 kmoles of P into kmoles of Ca₃(PO₄)₂:
0.03125 kmol P * [tex]\frac{2kmolCa_3(PO_4)_2}{2kmolP}[/tex] = 0.0625 kmol Ca₃(PO₄)₂Now we calculate the mass of 0.0625 kmoles of Ca₃(PO₄)₂:
0.0625 kmol Ca₃(PO₄)₂ * 310.18 kg/kmol = 19.39 kgFinally we calculate the required mass of the ore, using the definition of content percentage:
% content = Mass of calcium phosphate / mass of ore * 100 %56.3 % = 19.39 kg / mass of ore * 100%Mass of Ore = 34.44 kgCan someone plss help me answer those 4 questions by tonight.Thank you !
Answer:
no problem hey I will help you
Use the scenario to answer the following question. A group of students working in a chemistry lab are planning a procedure to neutralize 10.0mL of 5.0 M hydrochloric acid (strong acid) with 5.0 M potassium hydroxide (strong base). In their procedure they plan on adding an equal volume of the base to the acid. What would be the expected outcome of carrying out this step as planned?
a- The resulting pH will be less than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.
b- The resulting pH will not be able to be determined because the concentrations of the acid and base are not the same.
c- The resulting pH will be greater than 7 because potassium hydroxide is less concentrated than the hydrochloric acid.
d- The resulting pH will be equal to 7 because a strong base will neutralize a strong acid.
Answer:
d- The resulting pH will be equal to 7 because a strong base will neutralize a strong acid.
Explanation:
The reaction between potassium hydroxide and hydrochloric acid of equal volume and equal concentration yields a solution of pH 7 at equivalence point. We must note that KOH is a strong base while HCl is a strong acid. This fact influences the pH of the system at equivalence point.
Owing to the fact that the acid is exactly neutralized by the base; at the equivalence point of such titration, it is expected that hydrogen ions(H+) and hydroxide ions (OH-) must have reacted to form water, this leads to a final pH of 7.
SOMEONE HELP ME
1. How many grams of C are present in 4.86 grams of carbon dioxide
?
grams C.
2. How many grams of carbon dioxide contain 1.73 grams of O ?
grams carbon dioxide.
Answer:
1. 1.33 gram of carbon
2. 2.38g of carbon dioxide
Explanation:
From the given information:
Total amount of CO₂ = 4.86 grams
Atomic mass of C = 12 g/mole
molar mass of CO₂ = 44 g/mole
∴
The mass of the Carbon (C) in grams is:
[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]
[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]
= 1.33 gram of carbon
2.
Here, the total amount of CO₂ = unknown
Atomic mass of O₂ = 32 g/mole
molar mass of CO₂ = 44 g/mole
amount of oxygen = 1.73 g
∴
The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]
[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]
= 2.38 g of carbon dioxide
Hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(g) H2(g) I2(g) K for the reaction is 0.016. Of 0.148 atm of HI(g) is sealed in a flask, what is the pressure of each gas when equilibrium is established
Solution :
Given :
Hydrogen iodide decomposes to hydrogen and iodine gas
[tex]$2 HI \ \ \ \Leftrightarrow \ \ \ \ H_2 \ \ \\ + \ \ I_2 $[/tex]
I 0.148 0 0
C -2a +a +a
E 0.148-2a a a
We know
[tex]$k_p=\frac{P(H_2)P(I_2)}{P(HI)^2}$[/tex]
[tex]$0.016=\frac{a^2}{(0.148-2a)^2}$[/tex]
[tex]$0.016^{1/2}=\frac{a}{0.148-2a}$[/tex]
[tex]$0.12649=\frac{a}{0.148-2a}$[/tex]
0.0187 = 1.2529 a
a = 0.0149
Therefore
P(HI) = 0.148 - 2a
= 0.148 - 2(0.0149)
= 0.1182 atm
P([tex]$H_2$[/tex]) = a
= 0.0149 atm
P([tex]$I_2$[/tex]) = a
= 0.0149 atm
For the following reaction conditions select the correct statement regarding the reaction below.
OH Cl OTs OTs N TsCl W X Y Z N
a. W is the correct product.
b. X is the correct product.
c. Y is the correct product.
d. Z is the correct product since pyridine acts as a nucleophile.
e. Both X and Y are both formed in this reaction as a racemic mixture
Answer:
B
Explanation:
The appropriate diagram of the question is shown in the first image attached below.
From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.
So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.
Thus, X is the appropriate and the correct product.
A sample of air was collected on a day when the total atmosphere
pressure was 592 mmHg. The sample contained only oxygen and
nitrogen gas. If the oxygen in the sample had a pressure of 261
mmHg, how much pressure did the nitrogen have?
A. 853 mm Hg
B. 0.206 mm Hg
C. 4.76 mm Hg
D. 331 mm Hg
E. Other________
(Please show me how you did it)
Answer:
D. 331 mm Hg
Explanation:
We can solve this problem by keeping in mind the law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of its components.
In other words:
P oxygen + P nitrogen = Total PWe input the given data:
261 mmHg + P nitrogen = 592 mmHgAnd calculate the pressure of the nitrogen:
P nitrogen = 331 mmHg If you have 600g of nitroglycerin, how many moles do you have?
help please
Answer:
600
Explanation:
there's 1 mole in every nitroglycerin
I think
Colligative properties of solutions include all of the following except: a. an increase in the osmotic pressure of a solution upon the addition of more solute b. elevation of the boiling point of a solution upon addition of a solute to a solvent c. an increase of reaction rate with increase in temperature d. depression of the freezing pont of a solution upon addition of a solute to a solvent e. depression of vapor pressure upon addition of a solute to a solvent
Answer:
Option C, an increase of reaction rate with increase in temperature
Explanation:
Colligative properties are as follows
a) Decrease of vapor pressure
b) Increase of boiling point
c) Reduction of freezing point
d) Increase of osmotic pressure
There is no impact on reaction rate and hence it is not a colligative property.
Thus, option c is the right choice
An increase of reaction rate with increase in temperature isn't an example
of colligative properties of solutions
Colligative properties of solutions depend on the ratio of the number of
solutes to that of the solvent(concentration) and not on the nature of the
substances involved.
Examples of colligative properties include vapor pressure lowering, boiling
point elevation, freezing point depression, and osmotic pressure. Increase of
reaction rate with increase in temperature is therefore not an example of
colligative properties of solutions.
Read more on https://brainly.com/question/24260365
If you have a solution that is 15 percent by mass of KCl in benzene, what is the new boiling point?
Answer:
https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186
Explanation: Thats your answer
How/what do I answer this?--> "heat of the chemical reactions"
like this is the question :/
Answer:
The heat of reaction is the energy that is released or absorbed when chemicals are transformed in a chemical reaction. It describes the change of the energy content when reactants are converted into products.
Explanation:
Yeah, that would confuse me a bit but then you read it and then you will get that answer above! Have a great rest of your day!
what is the major organic product obtained from the following sequence of reactions 1. naoch2ch3 ch3ch2oh 2. ph br 1. naoch2ch3 ch3ch2oh 2. br 1. lialh4 et2o 2. h3o
______ is the process of change from a liquid to a gas at temperatures below the boiling
point.
Answer:
evaporation is the process
Answer:
EvaporationExplanation:
Evaporation is the process of becoming a vapor. The process of extracting moisture as by heat.
Evaporation is the process of change from a liquid to a gas at temperatures below the boiling point.
Therefore, the final answer is evaporation.