Python The Sieve of Eratosthnes Prgram
A prime integer is any integer greater than 1 that is evenly divisible only by itself and 1. The Sieve of Eratosthenes is a method of finding prime numbers. It operates as follows:
Create a list with all elements initialized to 1 (true). List elements with prime indexes will remain 1. All other elements will eventually be set to zero.
Starting with list element 2, every time a list element is found whose value is 1, loop through the remainder of the list and set to zero every element whose index is a multiple of the index for the element with value 1. For list index 2, all elements beyond 2 in the list that are multiples of 2 will be set to zero (indexes 4, 6, 8, 10, etc.); for list index 3, all elements beyond 3 in the list that are multiples of 3 will be set to zero (indexes 6, 9, 12, 15, etc.); and so on.
When this process is complete, the list elements that are still set to 1 indicate that the index is a prime number. These indexes can then be printed. Write a program that uses a list of 1000 elements to determine and print the prime numbers between 2 and 999. Ignore element 0 of the list. The prime numbers must be printed out 10 numbers per line.
Sample Executions:

Prime numbers between 2 and 999 as determined by the Sieve of Eratosthenes.
2 357 11 13 17 19 23 29
31 37 41 43 47 53 59 61 67 71
73 79 83 89 97 101 103 107 109 113
127 131 137 139 149 151 157 163 167 173
179 181 191 193 197 199 211 223 227 229
233 239 241 251 257 263 269 271 277 281
283 293 307 311 313 317 331 337 347 349
353 359 367 373 379 383 389 397 401 409
419 421 431 433 439 443 449 457 461 463
467 479 487 491 499 503 509 521 523 541
547 557 563 569 571 577 587 593 599 601
607 613 617 619 631 641 643 647 653 659
661 673 677 683 691 701 709 719 727 733
739 743 751 757 761 769 773 787 797 809
811 821 823 827 829 839 853 857 859 863
877 881 883 887 907 911 919 929 937 941
947 953 967 971 977 983 991 997

Answer:

try this

Explanation:

def SieveOfEratosthenes(n):

  prime = [True for i in range(n+1)]

  p = 2

  while (p * p <= n):

      if (prime[p] == True):

          for i in range(p * p, n+1, p):

              prime[i] = False

      p +=1

  c=0

  for p in range(2, n):

      if prime[p]:

          print(p," ",end=" ")

          c=c+1

      if(c==10):

          print("")

          c=0

n= 1000

print("prime number between 2 to 999 as determined by seive of eratostenee ")

SieveOfEratosthenes(n)

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