The x-intercepts of f(x) are common to those of g(x) .
What is x-intercept?
The x-intercept is the point on the coordinate at which a line, curve or plane intersect with the x-axis. The value of y is equal to zero at x-intercept.
For me, it helps to graph everything on the same xy coordinate system. Start with the given graph and plot the points shown in the table. You'll get what you see in the diagram below.
The blue point C in that diagram is on the red parabola. This point is the x intercept as this is where both graphs cross the x axis. Therefore, they have a common x intercept.
Choice 1 is not true due to choice 4 being true. We have f(x) = g(x) when x = 2, which is why f(x) > g(x) is not true for all x.
Choice 2 is not true. Point B is not on the parabola.
Choice 3 is not true. There is only one known intersection point between f(x) and g(x), and that is at the x intercept mentioned above. Of course there may be more intersections, but we don't have enough info to determine this.
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what is pemdas? algebra 1
Answer:
p=Parentheses
e=Exponents
m=Multiplication
d=Division
a=Addition
s=Subtraction
its an order of solving a equation
f (10) = 10/2 = 5 . how to solve this problem
Answer:
f(10) means to input x = 10 into the function.
From inspection of the given function:
[tex]\sf f(10)=\dfrac{10}{2}=5[/tex]
the "10" is the numerator of the fraction.
Therefore, swap the "10" for "x" to give the function in terms of x:
[tex]\sf f(x)=\dfrac{x}{2}[/tex]
For a function
f(x)=yx is the input or domain
y is the output or range
Here
f(10)=10/2So
x=10
y=10/2
Hence the function is
f(x)=x/26^2-4(3-√25)^2/|4-8|
the answer is 5 but im not sure on the steps and how to get 5, please help tysm :)
I'm going to assume you start with
[tex]\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|}[/tex]
Let's simplify some pieces of this:
[tex]6^2 = 6\times6 = 36[/tex]
[tex]\sqrt{25} = \sqrt{5^2} = 5[/tex]
[tex](3 - \sqrt{25})^2 = (3 - 5)^2 = (-2)^2 = (-2)\times(-2) = 4[/tex]
[tex]|4 - 8| = |-4| = 4[/tex]
So as a first step we can reduce this to
[tex]\dfrac{6^2 - 4 (3 - \sqrt{25})^2}{|4 - 8|} = \dfrac{36-4\times4}4[/tex]
Now,
[tex]36 = 9\times4[/tex]
so every term contains a factor of 4 that we can cancel:
[tex]\dfrac{36-4\times4}4 = \dfrac{9\times4-4\times4}4 = \dfrac{9-4}1 = 9-4 = \boxed{5}[/tex]
as expected.
PLEASE HELP!!!!!!!!!
Answer:
CE = 4.6 ft
Step-by-step explanation:
(a)
given 2 secants drawn from an external point to the circle , then
the product of the external part of one secant and the entire secant is equal to the product of the other secant's external part and that entire secant, that is
BE × BC = AB × DB
(b)
substituting given values into the equation
BE × 10 = 3 × 18
10 BE = 54 ( divide both sides by 10 )
BE = 5.4 ft
then
CE = CB - BE = 10 - 5.4 = 4.6 ft
help solve these algebraic fractions please, with explanation would be great
Step-by-step explanation:
i answered it , and tried to give explanation too...
hope its helpful ,
which graph shows that Cindy reads about 3/4 of the time while riding in the car?
The graph that shows a unit rate of 3/4, which is the time Cindy reads while riding in the car is the graph attached below.
What is Unit Rate?Unit rate can be described as a constant or exactly how much of one quantity is per 1 unit of another quantity.
Unite rate (k) = x/y.
In the graph attached below, when x (hours driving) = 3, y (hours reading) = 4.
Therefore, unit rate = 3/4. We can then conclude that the graph that shows that Cindy reads 3/4 of the time she rides in a car is the graph attached below.
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Which is the equation of an ellipse with directrices at y = ±2 and foci at (0, 1) and (0, −1)?
x squared over 4 plus y squared over 1 equals 1
x squared over 1 plus y squared over 2 equals 1
x squared over 1 minus y squared over 4 equals 1
x squared over 1 minus y squared over 2 equals 1
The answer will be x squared over 4 plus y squared over 8 equals 1.
What is an ellipse?An ellipse is an oval shape geometry having two focuses and the curve is equidistant from the focus.
The general equation of the ellipse is given as;
(x²/a²) + (y²/b²) = 1
The coordinates of a foci are: (±c, 0) where;
c² = b² - a²
However, we know that equation of directrix is; x = ±a/e
Now, Directrix is given ±4
Thus, a/e = 4
a = 4e
We also know that c = ae from ellipse foci coordinates.
Thus, ae = 2
since ae = 2, then (4e)e = 2
4e² = 2
e² = 2/4
e = 1/2
Thus;
a = 4 × 1/2
a = 2
Since c² = b² - a²;
2² = b² - 2²
4 = b² - 4
b² = 8
From (x²/a²) + (y²/b²) = 1, we can put our values to get;
x²/4 + y²/8 = 1
Hence the answer will be x squared over 4 plus y squared over 8 equals 1.
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PLEASE HELP
good answer gets brainliest
Answer:
50
Step-by-step explanation:
90+40= 130
There are 180 degrees in a triangle.
180- 130 = 50
11. Find the coordinates of the point located six units behind the yz- plane, seven units to the right of the xz - plane, and eight units above the xy-plane. O x = -6, y = 7, z =-6 O x = -6, y = 7, z = 8 Ox=7, y = 7, z = 8 O x = 6, y= 7, z = 8
Answer: I think
Step-by-step explanation:Let the coordinate of the point be (x,y,z). Since the point is located 3 units behind the YZ− plane, 4 units to the right of XZ− plane and 5 units above the XY−plane ,x=−3,y=4 and z=5 Hence, coordinates of the required points are (−3,4,5)
write in standard form
(2×10³)+(4×10²)+(4×10¹)+(4×1)
can somebody answer this please.
c:
Answer: 2,444
Step-by-step explanation: We can find the answer to this problem by simplifying the scientific notation, and then adding. You would end up with 2,000 + 400 + 40 + 4 if done correctly. Hope this helps!
The formula for final velocity given acceleration and time is Vf=Vi+a•t
Rewrite the formula for solve Vi
Answer:
It is the third option
Step-by-step explanation:
Trust me
A tank contains 180 gallons of water and 15 oz of salt. water containing a salt concentration of 17(1+15sint) oz/gal flows into the tank at a rate of 8 gal/min, and the mixture in the tank flows out at the same rate.
the long-time behavior of the solution is an oscillation about a certain constant level. what is this level? what is the amplitude of the oscillation?
Let A(t) denote the amount of salt (in ounces, oz) in the tank at time t (in minutes, min).
Salt flows in at a rate of
[tex]\dfrac{dA}{dt}_{\rm in} = \left(17 (1 + 15 \sin(t)) \dfrac{\rm oz}{\rm gal}\right) \left(8\dfrac{\rm gal}{\rm min}\right) = 136 (1 + 15 \sin(t)) \dfrac{\rm oz}{\min}[/tex]
and flows out at a rate of
[tex]\dfrac{dA}{dt}_{\rm out} = \left(\dfrac{A(t) \, \mathrm{oz}}{180 \,\mathrm{gal} + \left(8\frac{\rm gal}{\rm min} - 8\frac{\rm gal}{\rm min}\right) (t \, \mathrm{min})}\right) \left(8 \dfrac{\rm gal}{\rm min}\right) = \dfrac{A(t)}{180} \dfrac{\rm oz}{\rm min}[/tex]
so that the net rate of change in the amount of salt in the tank is given by the linear differential equation
[tex]\dfrac{dA}{dt} = \dfrac{dA}{dt}_{\rm in} - \dfrac{dA}{dt}_{\rm out} \iff \dfrac{dA}{dt} + \dfrac{A(t)}{180} = 136 (1 + 15 \sin(t))[/tex]
Multiply both sides by the integrating factor, [tex]e^{t/180}[/tex], and rewrite the left side as the derivative of a product.
[tex]e^{t/180} \dfrac{dA}{dt} + e^{t/180} \dfrac{A(t)}{180} = 136 e^{t/180} (1 + 15 \sin(t))[/tex]
[tex]\dfrac d{dt}\left[e^{t/180} A(t)\right] = 136 e^{t/180} (1 + 15 \sin(t))[/tex]
Integrate both sides with respect to t (integrate the right side by parts):
[tex]\displaystyle \int \frac d{dt}\left[e^{t/180} A(t)\right] \, dt = 136 \int e^{t/180} (1 + 15 \sin(t)) \, dt[/tex]
[tex]\displaystyle e^{t/180} A(t) = \left(24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t)\right) e^{t/180} + C[/tex]
Solve for A(t) :
[tex]\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) + C e^{-t/180}[/tex]
The tank starts with A(0) = 15 oz of salt; use this to solve for the constant C.
[tex]\displaystyle 15 = 24,480 - \frac{66,096,000}{32,401} + C \implies C = -\dfrac{726,594,465}{32,401}[/tex]
So,
[tex]\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) - \frac{726,594,465}{32,401} e^{-t/180}[/tex]
Recall the angle-sum identity for cosine:
[tex]R \cos(x-\theta) = R \cos(\theta) \cos(x) + R \sin(\theta) \sin(x)[/tex]
so that we can condense the trigonometric terms in A(t). Solve for R and θ :
[tex]R \cos(\theta) = -\dfrac{66,096,000}{32,401}[/tex]
[tex]R \sin(\theta) = \dfrac{367,200}{32,401}[/tex]
Recall the Pythagorean identity and definition of tangent,
[tex]\cos^2(x) + \sin^2(x) = 1[/tex]
[tex]\tan(x) = \dfrac{\sin(x)}{\cos(x)}[/tex]
Then
[tex]R^2 \cos^2(\theta) + R^2 \sin^2(\theta) = R^2 = \dfrac{134,835,840,000}{32,401} \implies R = \dfrac{367,200}{\sqrt{32,401}}[/tex]
and
[tex]\dfrac{R \sin(\theta)}{R \cos(\theta)} = \tan(\theta) = -\dfrac{367,200}{66,096,000} = -\dfrac1{180} \\\\ \implies \theta = -\tan^{-1}\left(\dfrac1{180}\right) = -\cot^{-1}(180)[/tex]
so we can rewrite A(t) as
[tex]\displaystyle A(t) = 24,480 + \frac{367,200}{\sqrt{32,401}} \cos\left(t + \cot^{-1}(180)\right) - \frac{726,594,465}{32,401} e^{-t/180}[/tex]
As t goes to infinity, the exponential term will converge to zero. Meanwhile the cosine term will oscillate between -1 and 1, so that A(t) will oscillate about the constant level of 24,480 oz between the extreme values of
[tex]24,480 - \dfrac{267,200}{\sqrt{32,401}} \approx 22,995.6 \,\mathrm{oz}[/tex]
and
[tex]24,480 + \dfrac{267,200}{\sqrt{32,401}} \approx 25,964.4 \,\mathrm{oz}[/tex]
which is to say, with amplitude
[tex]2 \times \dfrac{267,200}{\sqrt{32,401}} \approx \mathbf{2,968.84 \,oz}[/tex]
The dimensions of the base of Box 1 are x by 3x.
The base area of Box 1 is:
O 3x
O 3x²
O 3x³
O4x
Answer:
3x^2
Step-by-step explanation:
Area = (length) x (width)
Area = (1x)*(3x)
Area = 3x^2
solve 5x^2=180 algebraically
Answer:
x = ± 6
Step-by-step explanation:
Hello!
Solve[tex]5x^2 = 180[/tex][tex]x^2 = 180/5[/tex][tex]x^2 = 36[/tex][tex]\sqrt{x^2} = \sqrt{36}[/tex][tex]x = \pm 6[/tex]The value of x is 6 or -6.
Hi...
Given:
[tex]\texttt{5x}[/tex]² [tex]\texttt{= 180}[/tex]
Solution:[tex]\texttt{5x}[/tex]² [tex]\texttt{= 180}[/tex]
Explanation:Divide both sides by 5
[tex]\hookrightarrow{\mathtt{\frac{5x^2}{5}} = {\mathtt{\frac{180}{5}}[/tex]
Simplify:
[tex]\hookrightarrow{\mathtt{x^2 = 36}[/tex]
[tex]\hookrightarrow{\mathtt{For \: x^2 \: = f(a) \: the \: solutions \: are \: x = \sqrt{f(a)}}[/tex] , [tex]\mathtt{- \sqrt{f(a)}}[/tex]
[tex]\hookrightarrow{\mathtt{x = \sqrt{36}}[/tex] , [tex]\mathtt{x = -\sqrt{36}}[/tex]
Factor the number: 36 = 6²
[tex]\mathtt{= \sqrt{6^2}}[/tex]
Apply radical rule: [tex]\mathtt{\sqrt[n]{a^n} \: = a}[/tex]
[tex]\mathtt{\sqrt{6^2} = 6} \\\mathtt{= 6}[/tex]
- [tex]\sqrt{36} = -6[/tex]
[tex]\boxed{\fbox{\bf{x = 6 , x = -6}}}[/tex]
Hope It Helps You...
If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?
The value of the x will be 12. The value of the x is obtained from the condition,(f – g)(x) = 0
What exactly is a function?A function is a statement, rule, or law that specifies the connection between two variables. Functions are common in mathematics and are required for the formulation of physical connections.
Given function;
f(x) = 16x – 30
g(x) = 14x – 6
⇒(f – g)(x) = 0
⇒(16x – 30)-(14x – 6)=0
⇒16x-30-14x+6=0
⇒2x-24=0
⇒x=24/2
⇒x=12
Hence, the value of the x will be 12.
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When accessing your credit card information online, you cannot ___
see statements
view the balance
make purchases
view the bill due dates
When accessing your credit card information online, you cannot makes purchase.
What is credit card?A credit card is a card that enables a card holder to buy or purchase things online on credit.
A credit card holder can carryout the following when accessing their credit card data online:
See their statementsView their balanceView their bill due datesTherefore the correct option is C.
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What is cos B?
A. 8/15
B. 15/8
C. 8/17
D. 15/17
Answer:
C. 8/17
Step-by-step explanation:
Given:
Hypotenuse = 17
BC = 8
Cos (B) = leg adjacent to ∠B / hypotenuse
= BC/BA
Substitute
Cos (B) = 8/17
Hence option C is correct
Write and simplify the expression equivalent to 2(7x + 3) + 9x.
Hi student, let me help you out! :)
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
We are asked to simplify the expression 2(7x+3)+9x.
[tex]\triangle~\fbox{\bf{KEY:}}[/tex]
We need to multiply 2 times 7x and 3, and then add 9x.So, let's compute...
\\\////\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\\///\\\////\\\///\\\///\\\///\\\///\\\///\\\//\\//\\\/
After performing multiplication we obtain
[tex]\star~\mathrm{14x+6+9x}[/tex]
Now add 9x:
[tex]\star~\mathrm{23x+6}[/tex]
Hope it helps you out! :D
Ask in comments if any queries arise.
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~Just a smiley person helping fellow students :)
If the measure of angle 4 is 132°, what is the measure of angle 7?
32°
48°
132°
148°
The sum of supplementary angles is 180 degrees. The measure of angle 7 is 48 degrees
Supplementary anglesThe sum of supplementary angles is 180 degrees.
Let the supplement of the angle be "x", so that;
x + 132 = 180
Subtract 132 from both sides
x + 132 - 132 = 180 - 132
x =. 180 - 132
x = 48 degrees
Hence the measure of angle 7 is 48 degrees
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I get the part A of the question its just the part B that i would really appreciate for someone to explain
Step-by-step explanation:
650065 = (a² + 1)(c² + 1)
and
650065 = (ac - 1)² + (a + c)² = the sum of 2 squared numbers (ac - 1)² and (a + c)².
we see that 5 and 13 and therefore 5×13=65 are all factor of 650065. and then 650065/65 = 10001.
and we know that 65 = (64 + 1) = (8² + 1)
and 10001 = (10000 + 1) = (100² + 1)
so, a = 8, c = 100
that means the 2 squared numbers summing up to 650065 are
(ac - 1)² = (8×100 - 1)² = 799² = 638,401
(a + c)² = (8 + 100)² = 108² = 11,664
650,065 = 638,401 + 11,664 = 799² + 108²
The slope of a line is 3. The y intercept of the same line is -12
Complete the slope intercept form equation
Answer:
y = 3x - 12
Step-by-step explanation:
Forming the slope-intercept equation :
y = mx + b
m = slopeb = y-interceptSubstitute m = 3 and b = -12 in the equation :
y = 3x - 12Answer:
y = 3x - 12
Step-by-step explanation:
The slope intercept form of a line is y = mx + b, where m is the slope and b is the y intercept. Here, m = 3 and b = -12. Therefore, the slope intercept form for this line is y = 3x - 12.
Why is P(A) •P(B/A) = P(B) • P(A/B)
HELP ME QUICK ASAP
Answer:
rawrrrrrrrrrrrrrrrrr
Step-by-step explanation:
Why is P(A) •P(B/A) = P(B) • P(A/B)
P/B + P = A
P/B/P
- A
Joshua has a ladder that is 15 feet long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 14.2 feet above the ground. For safety reasons, he wants the angle the ladder makes with the ground to be no greater than 78 degrees. Will the ladder be safe at this height? Show your work and label the diagram
Answer:
Step-by-step explanation:
An elevator began in the 9th floor. It went down 7 floors. Then, it went up 4 floors. On which floor did it stop?
Answer: Hope this helps you!
6th floor
Step-by-step explanation:
If it starts on the 9th floor and goes down 7 floors that is:
9 (9 floors) + -7 (down 7 floors)
which is also equal to 9-7
9-7 = 2
Next, we need to go up by 4 floors starting with 2, 2+4
2+4 = 6
Brainliest?
Mo buys a house for £120 000
He sells the house for £150 000
Work out the percentage profit that Mo makes.
Answer:
25%Step-by-step explanation:
The profit = 150 000 - 120 000 = 30 000
………………………………………………………
The profit percentage is :
[tex]=\frac{30000}{120000} \times 100=0.25 \times 100 = 25 \%[/tex]
a sticker shaped like a rectangle has an area of 56 square centimeters. it has a width of 7 centimeters.
Step-by-step explanation:
Soln:-
Given,
Area of sticker=56 cm^2
Width of sticker=7 cm
Length of sticker=?
We know that,
Area of rectangle=l×b
or,56=l×7
or,l=56÷7
•°•l=8
Hence,the required length of the sticker is 8 cm.
You have just invested 1,500 into a stock compounded yearly at a rate of 9%. How much money will be in your account in 60 days? (Please explain)
Answer:
1522.584
Step-by-step explanation:
1500(1+.09/12)^2=1522.584
Expand: In (4a)^3
help please
Answer: 3ln4 + 3lna
Step-by-step explanation:
[tex]\ln (4a)^{3}\\=3 \ln 4a\\=3(\ln 4+\ln a)\\=\boxed{3\ln 4+3\ln a}[/tex]
Answer:
C and second one is A
please help me ASAP
Answer:
c; 6
Step-by-step explanation:
to find the rate of change from x = 2 to x = 4 you use the (y2 - y1) / (x2 - x1) formula
so
(21 - 9) / (4 - 2)
12 / 2
6
the average rate of change is 6
n triangle ABC (see sketch), AD is the angle bisector of the angle A and BH is the height from side AC. The obtuse angle between BH and AD is four times the side of DAB. How big is the angle CAB?
A. 30 B.45 C.60 D.75 E.90
Answer: C
Step-by-step explanation:
We know that [tex]\angle AHB=90^{\circ}[/tex], and thus by the exterior angle theorem,
[tex]90^{\circ}+\alpha=4\alpha\\\\90=3\alpha\\\\\alpha=30^{\circ}[/tex]
Thus, [tex]\angle CAB=2\theta=\boxed{60^{\circ}}[/tex]