Answer:
3.2 hours
Step-by-step explanation:
48x4=192
192 divided by 60 is 3.2
Answer:
3 hours and 12 minutes
Step-by-step explanation:
there are 15 sets of 4 in one hour, so 15 plus 15 equals 2 hours or 30 braids. Then you add one more hour and you get 45 braids and then for the last three braids its 12 minutes
if you want to thank me add me on insta at 904_donke
Find the area of the following figure and write your result in the empty box.
Answer:
Area = 406
Step-by-step explanation:
First things first: Divide the shape
Here is how I did it:
21 x 16
14 x 5
Now solve:
21 x 16 = 336
14 x 5 = 70
Now add:
336 + 70 = 406
So the area is 406
Minutes No. of Homework
Problems
2 or Less
3-4
5-6
7-8
9 or more 8
4
2
0
3
What is the number of homework problems that took less than 5 minutes in the given table?
A.
4
B.
14
C.
12
D.
8
Factorise a^2-b^2 but it has no indecies
Answer:
(a+b)(a-b)
Step-by-step explanation:
1. What is the surface area of the composite figure? Show ALL your work.
2. What is the volume of the composite figure? Show ALL your work.
Answer:
1. 144.4 m²
2. 120 m³
Step-by-step explanation:
The figure is composed of a triangular prism and a rectangular prism
1. Surface area of the composite figure = (surface area of the triangular prism - area of the face joining the rectangular prism) + (surface area of the rectangular prism - the face joining the triangular prism)
✔️Surface area of the triangular prism = bh + (s1 + s2 + s3)*L
b = 5 m
h = 2 m
s1 = 3.2 m
s2 = 3.2 m
s3 = 5 m
L = 6 m
Plug in the values
Surface area of triangular prism = 5*2 + (3.2 + 3.2 + 5)*6
= 10 + (11.4)*6
= 78.4 m²
✔️Area of rectangular prism = 2(LW + LH + WH)
L = 6 m
W = 5 m
H = 3 m
Plug in the values
Area of rectangular prism = 2(6*5 + 6*3 + 5*3)
= 126 m²
✔️Area of the face joining both figures = L*W
L = 6 m
W = 5 m
Area = 6*5 = 30 m²
✅Surface area of the composite figure = (78.4 - 30) + (126 - 30)
= 48.4 + 96
= 144.4 m²
2. Volume of composite figure = volume of triangular prism + volume of rectangular prism
= ½*a*c*h + L*W*H
a = 2 m
c = 5 m
h = 6 m
L = 6 m
W = 5 m
H = 3 m
Plug in the values
Volume = ½*2*5*6 + 6*5*3
Volume = 30 + 90 = 120 m³
Please help will give brainlyist
-3.5 + 7.75 + 6.9 (4.3)
Answer:
33.92
Step-by-step explanation:
Which of the following is not true? Select one: The data is symmetrical. The median is 1.25. The data is skewed right The spread of the data distribution is from 0 to 2.5
solve the inequality please
Answer:
The solution is 4 >/= -21
4 is greater than or equal to negative 21
Step-by-step explanation:
7x + 4 >/= 7(x - 3)
We'll start by distributing the y7 to the items in parentheses
7x + 4 >/= 7x - 21
Subtract 7x from both sides
4 >/= -21
What is the first step in evaluating the expression below?
12 + 6 - 4 X (12-5)
Add 12 + 6
O Multiply 4 x 12
Subtract 5 from 12
O Multiply 4x7
-4, 1, 8, 4, 8, 7, 10, -5, -2, 7
Work out the mean temperature
Please help me the homework is due tomorrow
a varies inversely with b. if a=9 when b=2, then find when b=6
Answer:
a[tex] \alpha [/tex]
1/b
a=k/b
k=a×b
where a=9
b=2
k=?
k=9×2
k=18
where a=?
b=6
k=18
a=k/b
a=18/6
a=3
Can i get some help solving this problem please. 2x=x-10
Answer:
x=3.33
Step-by-step explanation:
2x=x-10
2x+x=10
3x=10
x= 10/3
x= 3.33
How much money would you have in an account after 15 years if you earned 9,3% annually and you started with R573,00?
Given:
Principal = R573.00
Rate of interest = 9.3% annually
Time = 15 years.
To find:
The amount after 15 years.
Solution:
Formula for amount is:
[tex]A=P\left(1+\dfrac{r}{n}\right)^{nt}[/tex]
Where, P is principal, r is the rate of interest in decimal, n is the number of time interest compounded in an year and t be the number of years.
The interest is compounded annually, so n=1.
Putting [tex]P=573,r=0.093,n=1,t=15[/tex] in the above formula, we get
[tex]A=573\left(1+\dfrac{0.093}{1}\right)^{1(15)}[/tex]
[tex]A=573\left(1+0.093\right)^{15}[/tex]
[tex]A=573\left(1.093\right)^{15}[/tex]
[tex]A=2174.98893[/tex]
[tex]A\approx 2174.99[/tex]
Therefore, the amount in the account after 15 years is about R2174.99.
write the coefficient of a in 7 a
Given:
The term is 7a.
To find:
The coefficient of "a" in the given term "7a".
Solution:
In the product of a number and a variable, the number is called the coefficient of that variable.
In the expression "7a", the number is "7" and the variable is "a". It means the number 7 is the coefficient of "a".
Therefore, the coefficient of "a" in the given term "7a" is 7.
In circle F with mZEFG = 30 and EF =
30 and EF = 11 units, find the length of arc EG.
Round to the nearest hundredth.
F
G
E
Answer:
5.76 units
Step-by-step explanation:
Length of arc EG = central angle/360 × 2πr
Where,
central angle = 30°
radius (r) = 11 units
Plug in the values into the formula
Length of arc EG = 30/360 × 2 × π × 11
Length or arc EG ≈ 5.76 units (to nearest hundredth)
Shoemakers of America forecasts the following demand for the next six months: 5000 pairs in month 1; 6000 pairs in month 2; 7000 pairs in month 3; 9000 pairs in month 4; 6000 pairs in month 5; 5000 pairs in month 6. It takes a shoemaker 20 minutes to produce a pair of shoes. Each shoemaker works 150 hours per month plus up to 40 hours per month of overtime. A shoemaker is paid a regular salary of $2000 per month plus $20 per hour for overtime. At the beginning of each month, Shoemakers can either hire or fire workers. It costs the company $1000 to hire a worker and $1200 to fire a worker. The monthly holding cost per pair of shoes is 5% of the cost of producing a pair of shoes with regular-time labor. The raw materials in a pair of shoes cost $10. At the beginning of month 1, Shoemakers has 15 workers and 500 pairs of shoes in inventory. Determine how to minimize the cost of meeting (on time) the demands of the next six months.
Answer:
5,000+6,000+7,000+,9,000+6,000+5,000= 38,000
Step-by-step explanation:
The minimum cost of meeting the demands of the next six months is $7475.00.
Here, we have,
To determine how to minimize the cost of meeting the demands of the next six months, we need to create a production and workforce plan that balances the demand for shoes with the available workforce and inventory.
Let's break down the problem into several steps:
Step 1: Calculate the regular production capacity and overtime capacity:
Regular production capacity: Number of regular working hours per month divided by the time it takes to produce a pair of shoes.
Overtime capacity: Number of overtime hours per month divided by the time it takes to produce a pair of shoes.
Given:
Regular working hours per month: 150 hours
Overtime hours per month: 40 hours
Time to produce a pair of shoes: 20 minutes (1/3 of an hour)
Regular production capacity = 150 hours / (1/3 hour) = 450 pairs per month
Overtime capacity = 40 hours / (1/3 hour) = 120 pairs per month
Step 2: Create a monthly production plan:
We will use the regular production capacity, overtime capacity, and inventory to fulfill the demand for each month.
Starting with the initial inventory of 500 pairs, we calculate the additional production needed for each month to meet the demand.
Month 1:
Demand: 5000 pairs
Additional production needed: 5000 - 500 = 4500 pairs
Month 2:
Demand: 6000 pairs
Additional production needed: 6000 - (500 + 4500) = 1000 pairs
Month 3:
Demand: 7000 pairs
Additional production needed: 7000 - (500 + 4500 + 1000) = 1000 pairs
Month 4:
Demand: 9000 pairs
Additional production needed: 9000 - (500 + 4500 + 1000 + 1000) = 2000 pairs
Month 5:
Demand: 6000 pairs
Additional production needed: 6000 - (500 + 4500 + 1000 + 1000 + 2000) = 0 pairs
Month 6:
Demand: 5000 pairs
Additional production needed: 5000 - (500 + 4500 + 1000 + 1000 + 2000) = 0 pairs
Step 3: Determine the hiring and firing decisions:
To minimize costs, we need to hire or fire workers based on the additional production needed for each month.
Based on the calculations from Step 2, we can identify the following hiring and firing decisions:
Month 1:
Additional production needed: 4500 pairs
Hire 5 workers (cost: 5 * $1000 = $5000)
Month 2:
Additional production needed: 1000 pairs
No hiring or firing needed (as the existing workforce can handle it)
Month 3:
Additional production needed: 1000 pairs
No hiring or firing needed
Month 4:
Additional production needed: 2000 pairs
No hiring or firing needed
Month 5:
Additional production needed: 0 pairs
No hiring or firing needed
Month 6:
Additional production needed: 0 pairs
No hiring or firing needed
Step 4: Calculate the costs:
Now, we can calculate the costs associated with hiring, firing, and production.
Hiring cost: $5000 (Month 1)
Firing cost: $0 (No firing needed)
Holding cost: 5% of the cost to produce a pair of shoes with regular-time labor, multiplied by the inventory at the beginning of each month.
Holding cost for Month 1: 0 (no inventory at the beginning of Month 1)
Holding cost for Month 2: 0.05 * ($2000 + 4500 * $10) = $237.50
Holding cost for Month 3: 0.05 * ($2000 + 5500 * $10) = $297.50
Holding cost for Month 4: 0.05 * ($2000 + 7500 * $10) = $475.00
Holding cost for Month 5: 0.05 * ($2000 + 7500 * $10) = $475.00
Holding cost for Month 6: 0.05 * ($2000 + 7500 * $10) = $475.00
Total cost:
Total cost = Hiring cost + Firing cost + Holding cost
= $5000 + $0 + ($237.50 + $297.50 + $475.00 + $475.00 + $475.00)
= $7475.00
Therefore, the minimum cost of meeting the demands of the next six months is $7475.00.
To earn more on addition click:
brainly.com/question/29560851
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A line segment AB has midpoint (2, 5). If the coordinates of A are (-1, -3), what are the coordinates of B?
Answer:
B (5; 13)
Step-by-step explanation:
Midpoint (x) = (-1 + bx)/2 = 2
Bx - 1 = 4
Bx = 5
Midpoint (y) = (-3 + By)/2 = 5
By - 3 = 10
By = 13
B (5; 13)
A cylinder has a base area of 64π m2. Its height is equal to twice the radius. Identify the volume of the cylinder to the nearest tenth.
V = 6434.0 m3
V = 2804.2 m3
V = 1402.1 m3
V = 3217.0 m3
Answer:
3215 .36 m³ is the required volume.
Step-by-step explanation:
Base area of Cylinder = 64π m²
Height of cylinder is equal to twice the radius .
As we know that ,
★Base Area of Cylinder = πr²
where,
π is taken as 22/7 or 3.14
r is the radius of cylinder
Substitute the value we get
↝ 64 π = πr²
↝ 64 = r²
↝ √64 = r
↝ 8 = r
↝ r = 8 m
Now, it is given that height is equal to twice of radius
Therefore ,
height = 2r = 2×8 = 16 m
★Volume of Cylinder = πr²h
substitute the value we get
↝ volume of Cylinder = 3.14 × 8² × 16
↝volume of Cylinder = 3.14 × 64 × 16
↝volume of Cylinder = 3215 .36 m²
Hence, the required volume of cylinder is 3215 .36 m³.
Answer:
3217.0
Step-by-step explanation:
questionon on picture
Answer:
yes this option is correct
Is this right? If not, what is it? PLEASE
Answer:
It is correct.
Step-by-step explanation:
A patient has been instructed to drink a gallon of water each day. How many cups does the patient
need to drink?
Thank
Answer:
16 cups a day
Step-by-step explanation:
Suppose A and B are independent events. If P(A) = 0.6 and P(B) = 0.85, what is P(A and B)?
A. .34
B. .51
C. .17
D. .68
Answer:0.51 I just took the test
Step-by-step explanation:
Find the area in square inches. <3
help I want to understand how to do this
9514 1404 393
Answer:
arc RS = 100°RS is a minor arcarc ST = 80°Step-by-step explanation:
The measure of an arc of a circle is the same as the measure of the central angle it subtends. That is, arc RS has the same measure as central angle RPS, which is marked as 100°.
Of course, the total of all central angles, hence all arcs, of a circle is 360°. A diameter of a circle cuts the circle in half, so each semicircle has a central angle measure and arc measure of 180°.
Any arc that is more than a semicircle is called a "major" arc. If it is less than a semicircle, it is a "minor" arc. Arcs RS and ST are minor arcs.
As always in geometry, the whole is the sum of the parts, so arcs RS and ST are supplementary. They total the measure of semicircle RST, which is 180°. Then ST = 180° -RS = 180° -100° = 80°.
__
Additional comment
Usually, an arc identified only by its end points is a minor arc. If the major arc is intended, then it will either be described as "major arc RS" or a point on the major arc will be given, as "arc RTS". The measure of arc RTS is 280°.
(08.06 LC)
Identify the factors of x2 + 16y? (5 points)
O (x + 4y)(x + 4y)
O (x + 4y)(x - 4y)
Prime
O (x - 4y)(x - 4y)
Answer:
Prime
Step-by-step explanation:
2(x?)+16y
O(x+4y)(x+4y)
x²+4xy+4xy+16y²
x²+8xy+16y²
O(x+4y)(x-4y)
x²-4xy+4xy-16y²
x²-16y
Prime
O(x-4y)(x-4y)
x²-4xy-4xy+16y²
x²-8xy+16y²
All are incorrect except prime, so the answer is prime.
---
hope it helps
What is the value of x???
Answer:
x=63
Step-by-step explanation:
The degree measure of a line is 180 degrees.
180 degrees is made up of 117 and x
117+x=180
x=63
URGENT NEED HELP CLICK TO SEE
Answer: 2*5^2-12
5 to the 2nd power is 25
2*25-12
2*25=50
50-12=38
the answer is C 38
hope this helps
please help asap !!!!
Answer:
P = 3/8
q = 1/2
Step-by-step explanation:
(3/8)^3/8 × (3/8)^1/8 = P^q
Because of the same base, pick one of the bases
Then, add the powers
(3/8)^3/8 × (3/8)^1/8 = P^q
= (3/8)^3/8 + 1/8
= (3/8)^(3+1)/8
= (3/8)^4/8
= (3/8)^1/2
Therefore,
P^q = (3/8)^1/2
Where,
P = 3/8
q = 1/2
P^q = (3/8)^1/2
= √(3/8)
Luke is driving from his house to the store. After driving 16 miles at a constant speed of 0.8 mile/minute, he realizes that he forgot his wallet. So, he turns around and drives all the way back to his house at the same speed. The equation below models Luke's distance, in miles, from home as he drives for t minutes. Using the given equation, match the number of minutes since Luke started driving from his house to his distance from the house. 12 minutes 27 minutes 31 minutes 7 minutes 10.4 miles on his return trip arrowRight 5.6 miles on his trip to the restaurant arrowRight 9.6 miles his trip to the restaurant arrowRight 7.2 miles on his return trip arrowRight
Answer:
The number of minutes since Luke started driving from his house to his distance from the house is 40 minutes. :)
Step-by-step explanation:
If A+B+C=[tex]\pi[/tex] show that tan A + tan B +tan C = tan A.tan B.tan C
Answer:
[tex]a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b) [/tex]
Step-by-step explanation:
we have:
[tex] \tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)[/tex]
we also have:
[tex] \tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)[/tex]
from (1)(2) => proven