Answer:
What is the question your asking?
Explanation:
All atoms of the same element have the same properties.
A tau lepton decays into an electron, an electron antineutrino and a tau neutrino. Write out this reaction in symbolic (equation) form and show that charge and lepton number is conserved. 2. What is the total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons
The equation in the symbolic form can be written as,
[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]
The total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons is 12 quarks.
What is the meaning of lepton?Any of a family of particles (such as electrons, muons, and neutrinos) that have spin quantum number ¹/₂ and that experience no strong forces.
The equation in the symbolic form can be written as,
[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]
Charge on the left side = -1
Charge on the right side = -1+0+0 = -1
As the charge on the electron antineutrino, [tex]{\bar{\nu }}[/tex] e and the tau neutrino, [tex]\nu\tau[/tex] are zero each.
Thus, charge on left side = charge on right side
Or, the equation is in accordance with charge conservation.
Lapton number of left side = 1
Laptop number of right side = 1-1+1 = 1
This is because, lapton number of the particles involved are,
Tau lapton, [tex]\tau[/tex]-1 = 1,
Electron, e-1 = 1,
Electron antineutrino, [tex]{\bar{\nu }}[/tex]e = -1,
Tau neutrino, [tex]\nu\tau[/tex]= 1,
Thus, lapton number of left side = lapton number of right side
So, the equation obeys lapton number conservation.
2.
The total number quarks in a helium nucleus which is composed of 2 protons (positively charged particle) and 2 neutrons (uncharged particle) is:
Since there 3 quarks in each nucleon, 4 nucleons would have a total of 12 quarks.
Just simply multiply 3 quarks by the number of nucleons:
So, 3 (quarks) x 4 (nucleons) = 12 quarks
Therefore, there are 12 quarks in 4 nucleons.
Learn more about lepton decays here:
https://brainly.com/question/12044097
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7. What is the mass of a piece of copper (Cu) that undergoes a 25.0 °C
temperature change with the loss of 428 J of energy?
Answer:
0.0428 kg or 42.8 g
Explanation:
Applying,
Q = cmΔt.............. Equation 1
Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.
make m the subject of the equation above
m = Q/cΔt.................. Equation 2
From the question,
Given: Q = 428 J, Δt = 25 °C
Constant: c = 400 J/kg.°C
Substitute these values into equation 2
m = 428/(25×400)
m = 0.0428 kg
m = 42.8 g
Question 4 (10 points)
If a sollition has a pOH of 5.2 the [OH-] of the solution is
оа
6x 10-6 M
Ob
6.3 x 10-6 M
Oc
1.58 x 10-5M
Od
2x10-5M
Answer:
Explanation:
NEED HELP ASAP THANKS
Answer:
its ionic
Explanation:
The lattice-like structure of a metal consists of negative metal ions in a "sea" of electrons.
O True
O False
Answer:
True
Explanation:
SOMEONE HELP ME
1. How many grams of C are present in 4.86 grams of carbon dioxide
?
grams C.
2. How many grams of carbon dioxide contain 1.73 grams of O ?
grams carbon dioxide.
Answer:
1. 1.33 gram of carbon
2. 2.38g of carbon dioxide
Explanation:
From the given information:
Total amount of CO₂ = 4.86 grams
Atomic mass of C = 12 g/mole
molar mass of CO₂ = 44 g/mole
∴
The mass of the Carbon (C) in grams is:
[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]
[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]
= 1.33 gram of carbon
2.
Here, the total amount of CO₂ = unknown
Atomic mass of O₂ = 32 g/mole
molar mass of CO₂ = 44 g/mole
amount of oxygen = 1.73 g
∴
The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]
[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]
= 2.38 g of carbon dioxide
Which of the following is an example of an environmental impact of agriculture?
high use of mineral resources
high use of water
high use of gold, copper, and silver
high use of rock supplies
Answer:
high use of mineral resources
Explanation:
brainliest pls
There are 6 different organisms in the picture above. Organize them into 2 or more groups AND defend your groups by
providing details about why you put them into the chosen groups.
Example on how to answer:
Group 1- XYZ
Group 2-LM
Group 3- PORS
I put XYZ in group 1 because...
I put LM together because...
I grouped PORS together because...
Explanation: they could be grouped by how they reproduce or they can be grouped by if there hetero or autotrophic
(NH4)2Cr2O7 Cr2O3 + N2 + H2O
If 4.7369 moles of H2O are produced, how many moles of (NH4)2Cr2O7 were reacted?
Answer:
the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).
Select the correct answer.
Using this activity chart, which reaction will happen when a piece of copper is placed in a lead nitrate solution?
A.
2Cu + 3Pb(NO3)2 3Cu(NO3)2 + 2Pb
B.
No reaction occurs.
C.
2Cu + 3Pb(NO3)2 2Cu(NO3)2 + 3Pb
D.
3Cu + 3Pb(NO3)2 3Cu(NO3)2 + 3Pb
E.
The answer cannot be determined from the information given.
Answer:
B, No reaction will occur
Explanation:
Copper as compared to lead is less reactive. This is the reason when lead is added to copper nitrate solution, it replaces the copper and itself combines with nitrate to form lead nitrate aqueous solution
Lead + Copper(II) nitrate → Copper + Lead (II) nitrate
The same is not the case when the reaction is revered i.e Cu is added to Pb NO3 solution.
Hence, option B is correct
A gas has a solubility of 2.45 g/L at a pressure of 0.750 atm. What pressure wold be required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature
Answer:
1.91 atm
Explanation:
Step 1: Calculate Henry's constant (k)
A gas has a solubility (C) of 2.45 g/L at a pressure (P) of 0.750 atm. These two variables are related to each other through Henry's law.
C = k × P
K = C/P
K = (2.45 g/L)/0.750 atm = 3.27 g/L.atm
Step 2: Calculate the pressure required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature.
We have C = 6.25 g/L and k = 3.27 g/L.atm. The required pressure is:
C = k × P
P = C/k
P = (6.25 g/L)/(3.27 g/L.atm) = 1.91 atm