Answer:
c) 6
Step-by-step explanation:
Given :
⇒ f(x) = x³ + 7x² - x
⇒ g(x) = x² - 3
===============================================================
Finding the degree of g(f(x)) :
⇒ Degree of f(x) = 3
⇒ Degree of g(x) = 2
⇒ Therefore, degree of g(f(x)) = degree of f(x) × degree of g(x)
⇒ Degree of g(f(x)) = 3 × 2
⇒ Degree of g(f(x)) = 6
Degree of g(f(x))
Use Pascal's law
3×26Option C
The volume of a rectangular prism is 400 cm3 . If the length is 16 cm and the width is 5cm, what is its height?
Answer:
H = 5
Step-by-step explanation:
rectangular prism:
V = L x W x H
400 cm3 = 16 x 5 x H
400 cm3 = 80 x H
400/80 = 5
h = 5 cm
95% sure this is correct! :)
Answer:
5 cm
Step-by-step explanation:
Formula used :
Volume of the rectangular prism = Length × Width × Height
=========================================================
Given :
⇒ Volume = 400 cm³
⇒ Length = 16 cm
⇒ Width = 5 cm
===========================================================
Solving :
⇒ 400 cm³ = 16 cm × 5 cm × Height
⇒ Height = 400 cm³ / 80 cm²
⇒ Height = 5 cm
Priya is comparing two functions: (x) = 10 . y? and g(x) = 3 - 2* to find out which
one has greater output values as x gets very large.
She notices that f(1) = 10 and f(2) = 40. However, g(1) = 6 and g(2) = 12. She
concludes that as x continues to grow, the values of f will be greater than the values
of g.
Explain why priyas conclusion is incorrect
Answer:
help me to find Xian pleaseee:( i miss him so much:(
sorry for answering Non sense po i hope u understand me ty po!
TRUE OR FALSE
1. Standard units gives a consistent and accurate of the volume of a container.
TRUE OR FALSE ?
Answer:
True
Step-by-step explanation:
Cant really provide step by step per se.
Which of the following choices lists the values of the side lengths of a triangle with 45-45-90 degree angles and a hypotenuse = 24?
√2, √2, 24
24√2, 24√2, 12
24, 24, 24√2
12√2, 12√2, 24
The sides of the triangle are (d) 12√2, 12√2, 24
How to determine the side lengths?The given parameters are:
Hypotenuse = 24Angle = 45-45-90 degree anglesIn a 45-45-90 degree angle triangle, we have:
Hypotenuse = Opposite√2 and Hypotenuse = Adjacent√2
This means that:
Opposite =Adjacent
So, we have:
24 = Adjacent√2
Divide both sides by √2
Adjacent = 24/√2
Evaluate
Adjacent = 12√2
This means that:
Opposite = 12√2
Hence, the sides of the triangle are (d) 12√2, 12√2, 24
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The first term in an arithmetic sequence is -3. If the sequence has a common difference of 8, what is the 30th term in the sequence?
Will give brainliest to right answer :))
Answer:
229
Step-by-step explanation:
(my work for the problem is in the photo I attached)
(I also wrote this step-by-step in the photo because I can explain things better as I do them)
This will be a little bit confusing without me writing out the numbers, so mainly this is if you can't read my handwriting
-3 + 8 = 5 ; 5 + 8 = 13
(1st term) (2nd term) (3rd term)
Instead of adding 8 repeatedly (repeated addition), we can use multiplication.
To get the 3rd term in this sequence, we had to add 8 twice, which could also be done by multiplying 8 twice (8 x 2)
13 + 8 = 21
(4th term)
to get the 4th term, we added 8 three times (or, 8 x 3)
So, if we are looking for the 30th term in a sequence, we will have to add 8, 29 times (8 x 29) to our original term.
8 x 29 = 232
-3 + 232 = 229
This means that the 30th term of the sequence will be 229.
4X+8<28
ayudenme por favor
Answer:
x < 5.
Step-by-step explanation:
Creo que esto es correcto. :')
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
A= units^2
Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.
[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}[/tex]
[tex](\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}[/tex]
Tyger buys his car for $6900 he spends some Time repairing it and improving it. He sells it for $9200. What is his percentage profit?
If Tyler sold his car for $9200, then the approximate percentage profit for this product is 33.3%.
How to calculate the percentage?Final price - initial price
$9200 - $6900 = 2300Calculate the percentage $2300 is equivalent to by using the information you already have.
6900 = 1002300 = xx= 100 x 2300/ 6900x= 33.3%33.3% is the profit percentage.
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The archway of the main entrance of a university is modeled by the quadratic equation y = -x2 6x. the university is hanging a banner at the main entrance at an angle defined by the equation 4y = 21 − x. at what points should the banner be attached to the archway?
The banner attached to the archway will be at (1, 5) and (5.25, 3.938).
What is the parabola?It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.
The archway of the main entrance of a university is modeled by the quadratic equation
y = -x² + 6x ....1
The university is hanging a banner at the main entrance at an angle defined by the equation
4y = 21 − x ....2
Then the banner attached to the archway will be
From equations 1 and 2, we have
4(-x² + 6x) = 21 - x
-4x² + 24x = 21 - x
4x² - 25x + 21 = 0
4x² - 21x - 4x + 21 = 0
x(4x - 21) - 1(4x - 21) = 0
(4x - 21)(x - 1) = 0
x = 5.25, 1
Then the value of y will be
When x = 5.25, then we have
y = -(5.25)² + 6(5.25)
y = 3.938
When x = 1, then we have
y = -(1)² + 6(1)
y = 5
The banner attached to the archway will be at (1, 5) and (5.25, 3.938).
The graph is given below.
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What is the period of f(x) = sin (8x)?
X/8
X/4
4
8
Answer: B- x/4
Step-by-step explanation:
The period is the horizontal distance needed for the values to repeat themselves.
whats equlvlent to 3√6
Answer:
Important: 3
6
looks like a fraction, but it is actually an improper fraction.
There is an infinity number of equivalent fractions to 3
6
.
To find an equivalent fraction to 3
6
, or to any other fraction, you just need to multiply (or divide, if the fraction is not yet reduced), both the numerator and the denominator of the given fraction by any non-zero natural number. For example:
By dividing the original fraction by 3, we get:
3 ÷ 3
6 ÷ 3
= 1
2
By multiplying the original fraction by 2, we get:
3 × 2
6 × 2
= 6
12
Step-by-step explanation:
Brad took 5 kicks and made 4 goals: 4/5
Sydney will take 10 shots and she wants to make an equivalent fraction of the goals. How many goals must She make?
4/5 x ?/? = ?/10
Answer: 8/10
Step-by-step explanation: so you have to multiply 5 times x u till you get 10 so you’ll multiply it 2 times and since you multiplied the left 5 times two you have to multiply the 4 by 2 also to keep everything equal so the final answer is 8/10
Part b
what is the area of the target that earns at least 30 points on a throw?
select the correct from the drop-down menu.
the area is ____ square inches.
a) 16
b) 49
c) 121
d) 144
If f(x)=3x-2 and g(x)=2x+1,find (f+g)(x)
Answer:
f(x) + g(x) = 3x - 2 + 2x + 1
(f + g)(x) = 5x - 1
solve for x. x^2+12x<-11
x²+12x<-11
x²+12x+11<0
x²+12x+11=0
(x+11)(x+1)=0
x+11=0 x+1=0
x= -11 x= -1
Solution: ] -11 , -1 [
What is the slope of the line that passes through the points (-6, 8) and (-9, 7)? Write your answer in simplest form.
Answer:
m=1/3
equation y=1/3x+10
Step-by-step explanation:
Find the rise and run.
1. -6--9=run=3
2. 8-7=rise=1
Hi student, let me help you out! :)
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
We are asked to find the slope of the line that passes through (-6, 8) and (-9, 7).
[tex]\triangle~\fbox{\bf{KEY:}}[/tex] (formula for Slope)
[tex]\longmapsto\bf{\cfrac{y2-y1}{x2-x1}}[/tex]
y2 & y1 = the y-coordinates of the two points
x2 & x1 = the x-coordinates of the two points
[tex]\ddot\bigstar[/tex] Remember this...
[tex]\fbox{y2\;and\;y1\;are\;y-coordinates\;of\;the\;two\;points,\;and\;x2\;and\;x1\;are\;x-coordinates}}[/tex]
So we substitute the values and obtain:
[tex]\bf{\cfrac{7-8}{-9-(-6)}[/tex]
Simplifying:
[tex]\bf{\cfrac{-1}{-9+6}}[/tex]
Simplifying more:
[tex]\bf{\cfrac{-1}{-3}}[/tex]
Divide the top and bottom by -1:
[tex]\bf{\cfrac{1}{3}}[/tex]
There's the slope.
Hope it helps you out! :D
Ask in comments if any queries arise.
~Just a smiley person helping fellow students
0/1
What is the equation of
the line in y=mx+b form?
(Photo)
Answer:
y=-15x+100
Step-by-step explanation:
the multiplication law of exponents says that for any numbers b, n, and m,
b^n.b^m=b^n+m
a. true
b. false
Since the exponents were added based on the product rule, hence the multiplication law of exponents is TRUE
Law of indicesIndices are written in term of exponents. Some of the laws of indices;
[tex]a^m\times a^n=a^{m+n}[/tex] (product law of indices)
For the quotient law of indices
[tex]\dfrac{a^m}{a^n} =a^{m-n}[/tex]
According to the given expression, we are to determine if it is true or false
Check:
[tex]b^n.b^m=b^{n+m[/tex]
Since the exponents were added based on the product rule, hence the multiplication law of exponents is TRUE
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The question is in the picture.
Answer:
x² - 22x + y² + 18y + 58 = 0
Step-by-step explanation:
Using the equation of a circle :
(x - h)² + (y - k)² = r²
Solving :
Substitute 11, -9, 12 in place of h, k and r respectively.
(x - 11)² + (y + 9)² = (12)²x² - 22x + 121 + y² + 18y + 81 = 144x² - 22x + y² + 18y + 202 = 144x² - 22x + y² + 18y + 58 = 0Fiona recorded the mean math exam grade for six random samples of students from the entire seventh-grade class. Sample Sample Mean Grade 1 65 2 92 3 78 4 45 5 95 6 70 Why is a valid prediction for the mean of the population not possible using these samples?
The reason why Fiona cannot make a valid prediction based on the mean of the population is that the variation of Fiona’s samples is too large.
Why can't Fiona use the means she recorded?Mean is quite sensitive to outliers so it is best used when the variation between variables is not too much.
In Fiona's case, there variation is quite high with high variable of 95 compared to a low value of 45.
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Answer: just confirming/
Step-by-step explanation:
What is the value of x?
2
3
6
7
Answer: 2
Step-by-step explanation:
DE * CE = AE * BE (Two Secants Segment Theorem)
▪︎ DE = 1 + x + 4
▪︎ CE = x + 4
▪︎ AE = 11 + x + 1
▪︎ BE = x + 1
=> (1 + x + 4)(x + 4) = (11 + x + 1)(x + 1)
=> (x + 5)(x+4) = (x + 12)(x + 1)
=> x^2 + 9x + 20 = x^2 + 13x + 12
=> 9x + 20 = 13x + 12
20 - 12 = 13x - 9x
8 = 4x
x = 2
A catapult hurls a pumpkin from a height of 32 feet at an initial velocity of 96 feet per second. the function h(t)=-16t^2+96t+32 represents the heights of the pumpkin h(t) in terms of time t. what is the max height the pumpkins will reach and what time will it reach that height?
The maximum height of the pumpkin is 3 feet
We have given that,
A catapult hurls a pumpkin from a height of 32 feet at an initial velocity of 96 feet per second.
The function h(t)=-16t^2+96t+32 represents the heights of the pumpkin h(t) in terms of time t.
We have to determine the maximum height.
What is the maxima?
At the point of maxima f'(x)=0
first, find the maxima
Therefore differentiate the given function with respect to t we get,
[tex]h'(t)=-32t+96[/tex]
h'(t)=0
Then we get,
[tex]0=-32t+96\\-32t=-96\\t=\frac{-96}{-32} \\t=3[/tex]
Therefore the maximum height of the pumpkin is 3 feet.
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What is the missing probability from the line?
Give your answer as a decimal.
The missing probability from the line in the diagram attached is 0.5.
What is a missing probability from the number line?The number line is a graduated straight line system showing the value of each real number from (-∞, +∞).
The probability of a number line in the diagram below is halfway (middle) between the impossible event and a certain event.
Thus,
Probability from the line = 1/2Probability from the line = 0.5 (decimal)Learn more about missing probability here:
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Part 1: Come up with and describe two scenarios: one that models a direct variation situation and one that models an inverse variation situation. Do not state explicitly which scenario is which, but provide at least four data pairs for each situation. Your classmates will have to determine which of the scenarios is a direct variation and which is an inverse variation, and the value of k for each.
Answer:
1. I went to a store four days in a row and only bought chocolate bars each day. All chocolate bars were the same and cost the same. On the first day, I bought 2 chocolate bars for $2.38. On the second day I bought 1 chocolate bar for $1.19. On the third day, I bought 10 chocolate bars for $11.90. On the fourth day, I bough 4 chocolate bars for $4.76.
2. A sink is full. It contains 20 gallons of water. The stopper is removed and water starts draining out. One minute after the stopper is removed, the volume of water in the sink is 18 gallons. Two minutes after the stopper is removed, the volume of water in the sink is 16 gallons. Four minutes after the stopper is removed, the volume of water in the sink is 12 gallons. Ten minutes after the stopper is removed, the sink is empty.
what is 15/56 in simplest form
Answer:
15/56
Step-by-step explanation:
15 and 56 have a GCF of 1.
d. If f¹(x+2) =X-1/x+1x not equal to 1 then find f(x) and f¹(4).
I assume by f¹, you actually mean f⁻¹ as in the inverse of f. I also assume you are asked to find f(x) (as in the inverse of f⁻¹) and f⁻¹(4).
Given that
[tex]f^{-1}(x+2) = \dfrac{x-1}{x+1}[/tex]
with x ≠ 1, we can find f⁻¹(x) by replacing x + 2 with x :
[tex]f^{-1}(x + 2) = \dfrac{x-1}{x+1} = \dfrac{(x+2) - 3}{(x + 2) - 1} \implies f^{-1}(x) = \dfrac{x-3}{x-1}[/tex]
Then when x = 4, we have
[tex]f^{-1}(4) = \dfrac{4-3}{4-1} = \dfrac13[/tex]
Of course, we also could have just substituted x = 2 into the definition of f⁻¹(x + 2) :
[tex]f^{-1}(4) = f^{-1}(2+2) = \dfrac{2-1}{2+1} = \dfrac13[/tex]
To find f(x), we fall back to the definition of an inverse function:
[tex]f^{-1}\left(f(x)\right) = x[/tex]
Then by definition of f⁻¹, we have
[tex]f^{-1}\left(f(x)\right) = \dfrac{f(x)-3}{f(x)-1} = x[/tex]
Solve for f :
[tex]f(x) - 3 = x (f(x) - 1)[/tex]
[tex]f(x) - 3 = x f(x) - x[/tex]
[tex]f(x) - x f(x) = 3 - x[/tex]
[tex](1 - x) f(x) = 3-x[/tex]
[tex]f(x) = \dfrac{3-x}{1-x} = \dfrac{x-1}{x-3}[/tex]
A school sold all but 5 of ta school sold all but 5 of their old computers for r1200 each the school received r18000 from the sale. how many comps did the school originally old computers for r1200 each the school received r18000 from the sale. how many comps did the school originally have
Answer:
20
Step-by-step explanation:
The proceeds from the sale can be described by an equation involving the original number of computers.
__
setupLet n represent the number of computers the school originally had. Then n-5 is "all but 5" and is the number sold. Each is sold for ₹1200, and the value of the sale is ₹18000. This can be expressed by the equation ...
(n -5)×1200 = 18000
__
solutionThis 2-step linear equation can be solved by dividing by the coefficient, and adding the opposite of the constant.
n -5 = 18000/1200 = 15 . . . . . divide by 1200
n = 15 +5 = 20 . . . . . . . . . . add the opposite of -5
The school originally had 20 computers.
Anna and Brian share £24.50
in the ratio 2:5. How much
does each person get?
Fill out the chart please!
The dot plot and the box plot shown both represent Manuel’s data. Determine which visual display is more useful for answering each of the questions listed in the table, and explain your reasons.
1. Mean of the data: 8
2. Median: 8
3. IQR = 4
4. Members that use the facility 10 days a month is: 2.
See reasons below.
What is the Mean, Median, and Interquartile Range of a Data?Mean = sum of all values ÷ number of data values (easily solved using a dot plot
Median = middle value (easily found using a box plot).
Interquartile range (IQR) = Q3 - Q1 (easily found using a box plot).
1. Mean of the data: use the dot plot.
Reasoning: (3 + 3 + 5 + 6 + 6 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 11 + 12 + 14)/15 = 8
2. Median of the data set: Using the box plot, it is the value indicated by the vertical line that divides the box.
Median = 8
3. IQR = Q3 - Q1 = 10 - 6
IQR = 4
4. Members that use the facility 10 days a month, using the dot plot is: 2. 10 has 2 dots.
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Q). Express each of the following recurring decimal as a rational numbers . 1) 0.5 2) 0.13 3) 0.341
The following recurring decimal as a rational number are 1/2, 13/100 and 341 / 1000
What is rational number?A rational number is a number that is expressed as the quotient or fraction of two integers, a numerator and a non-zero denominator such as;
3/4. where,
Numerator = 3Denominator = 4Therefore,
0.5
= 5/10
= 1/2
0.13
= 13/100
0.341
= 341 / 1000
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