I NEED HELP ASAP

The volume of a cylinder is 14,130 ft 3 . If the diameter is 30 feet, calculate the height of the cylinder

Answer:

19

Step-by-step explanation:

hope this helps with the problem

Answer:

6957  inches squared

Step-by-step explanation:

surface area of a cone  = πr × (r + √[h² + r²])

h = height

r = radius = 4/2 = 2 inches

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

(3.14 x 2) x (2 + √5² + 2²) = 6.28  x 7.39 = 46.38 inches squared

the amount of coated paper needed for 1 cup is 46.38 inches squared

Amount needed for 150 cups = 46.38 x 150 = 6957

x 150

Answer:

A cylinder

Step-by-step explanation:

When you rotate the rectangle you are make a circle but since its volume the original height of the rectangle is the height of the circle which would mean a cylinder.

Answer:

CYLINDER

Step-by-step explanation:

Answer:

Complementary, x=10

Step-by-step explanation:

Complementary angles mean they add up to 90 degrees.

So 29+(6x+1)=90.

30+6x=90

6x=60

x=10

Answer:

Complementary-------- x= 10

Step-by-step explanation:

only 90 degrees

-----------------------------

3. 6x = 60

=======================

x= 10

Answer:

sorry i don't know

Answer:369.15

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

First, you have to convert 20% into a decimal.

Explanation:

20 ÷ 100 = 0.2

Now multiply 0.2 by 150

Explanation:

0.2 × 150 = 30.

Therefore, 20% of 150 is 30.

Answer:

[tex]A = 74.7^\circ[/tex]

[tex]B = 42.5^\circ[/tex]

[tex]C = 62.8^\circ[/tex]

Step-by-step explanation:

Given

[tex]A = (-1,2) \to (x_1,y_1)[/tex]

[tex]B = (2,8) \to (x_2,y_2)[/tex]

[tex]C = (4,1) \to (x_3,y_3)[/tex]

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2[/tex]

For AB

[tex]A = (-1,2) \to (x_1,y_1)[/tex]

[tex]B = (2,8) \to (x_2,y_2)[/tex]

[tex]d = \sqrt{(-1 - 2)^2 + (2 - 8)^2[/tex]

[tex]d = \sqrt{(-3)^2 + (-6)^2[/tex]

[tex]d = \sqrt{45[/tex]

So:

[tex]AB = \sqrt{45[/tex]

For BC

[tex]B = (2,8) \to (x_2,y_2)[/tex]

[tex]C = (4,1) \to (x_3,y_3)[/tex]

[tex]BC = \sqrt{(2 - 4)^2 + (8 - 1)^2[/tex]

[tex]BC = \sqrt{(-2)^2 + (7)^2[/tex]

[tex]BC = \sqrt{53[/tex]

For AC

[tex]A = (-1,2) \to (x_1,y_1)[/tex]

[tex]C = (4,1) \to (x_3,y_3)[/tex]

[tex]AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2[/tex]

[tex]AC = \sqrt{(-5)^2 + (1)^2[/tex]

[tex]AC = \sqrt{26[/tex]

So, we have:

[tex]AB = \sqrt{45[/tex]

[tex]BC = \sqrt{53[/tex]

[tex]AC = \sqrt{26[/tex]

By representation

[tex]AB \to c[/tex]

[tex]BC \to a[/tex]

[tex]AC \to b[/tex]

So, we have:

[tex]a = \sqrt{53[/tex]

[tex]b = \sqrt{26[/tex]

[tex]c = \sqrt{45[/tex]

By cosine laws, the angles are calculated using:

[tex]a^2 = b^2 + c^2 -2bc \cos A[/tex]

[tex]b^2 = a^2 + c^2 -2ac \cos B[/tex]

[tex]c^2 = a^2 + b^2 -2ab\ cos C[/tex]

[tex]a^2 = b^2 + c^2 -2bc \cos A[/tex]

[tex](\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A[/tex]

[tex]53 = 26 +45 - 2 * 34.21 * \cos A[/tex]

[tex]53 = 26 +45 - 68.42 * \cos A[/tex]

Collect like terms

[tex]53 - 26 -45 = - 68.42 * \cos A[/tex]

[tex]-18 = - 68.42 * \cos A[/tex]

Solve for [tex]\cos A[/tex]

[tex]\cos A =\frac{-18}{-68.42}[/tex]

[tex]\cos A =0.2631[/tex]

Take arc cos of both sides

[tex]A =\cos^{-1}(0.2631)[/tex]

[tex]A = 74.7^\circ[/tex]

[tex]b^2 = a^2 + c^2 -2ac \cos B[/tex]

[tex](\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B[/tex]

[tex]26 = 53 +45 -97.67 * \cos B[/tex]

Collect like terms

[tex]26 - 53 -45= -97.67 * \cos B[/tex]

[tex]-72= -97.67 * \cos B[/tex]

Solve for [tex]\cos B[/tex]

[tex]\cos B = \frac{-72}{-97.67}[/tex]

[tex]\cos B = 0.7372[/tex]

Take arc cos of both sides

[tex]B = \cos^{-1}(0.7372)[/tex]

[tex]B = 42.5^\circ[/tex]

For the third angle, we use:

[tex]A + B + C = 180[/tex] --- angles in a triangle

Make C the subject

[tex]C = 180 - A -B[/tex]

[tex]C = 180 - 74.7 -42.5[/tex]

[tex]C = 62.8^\circ[/tex]

Answer:

I dont know for sure but I would have to guess DC because there's no line connecting the 2

Please do answer DC at your own risk though.

Answer:

DC

Step-by-step explanation:

Because there not connected to eachother

Answer:

[tex]x = \frac{50 + 92}{2} = 71[/tex]

Answer:

960 cm³ I think it may be correct

Answer:

C

Step-by-step explanation:

I believe the answer would be C because its the only actual line on a graph.

A Is a line segment

D is a ray

(I'm not sure what the exact name for the one on graph B is.)

Answer:

the answer ic C!

Step-by-step explanation:

AP EX

Answer:

3

Step-by-step explanation:

Answer:

2 tickets

Step-by-step explanation:

a + c = 5

9a + 4c = 30

let a = 5-c

substitute:

9(5-c) + 4c = 30

45 - 9c + 4c = 30

45 - 5c = 30

-5c = -15

c = 3

a = 2

Answer:

(- 2, - 1 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 3 → (1)

y = 3x + 5 → (2)

Substitute y = 3x + 5 into (1)

3x + 5 = 2x + 3 ( subtract 2x from both sides )

x + 5 = 3 ( subtract 5 from both sides )

x = - 2

Substitute x = - 2 into either of the 2 equations and evaluate for y

Substituting into (1)

y = 2(- 2) + 3 = - 4 + 3 = - 1

solution is (- 2, - 1 )

Answer:

Choice A, 20(3n-m)

Step-by-step explanation:

First, lets combine like terms for the question 54n - 20m + 6n,

60n - 20m.

Next, lets rule out the choices that are visibly wrong. This includes Choice B, because it wouldn't equal what is above and Choice C, as it ignores unlike terms.

Now, it is down to Choices A and D. Let's use the distributive property to simplify these options.

Choice A:

20(3n-m)

60n-20m

Choice D:

20(m-3n)

20m-60m

With this, it can be concluded that the correct answer is Choice A since it equals 60n-20m, which is equal to the original question when like terms are combined.

Answer:

Which inequality has the solution set shown on the graph?

-54n < 1080

-54n > 1080

594 > -11n <<<<<This one

594 < -11n

Step-by-step explanation: I couldnt find my question so here is the answer if you have this on edg :))))

Answer:

250 lifeguards

(P.S, i dunno if i got it right or not should be correct tho)

Step-by-step explanation:

15 km divide 0.06 for every life guard. therefore, there are 250 lifeguards

There will be 9 lifeguards

.6 x 15 = 9

0.06 x 15 = 0.9

0.9 as a whole number = 9

Therefore There will be 9 lifeguards

Answer:

No

Step-by-step explanation:

To find out if 2 is a solution, replace all the x's with 2.

4(2 - 1) - 3(2 - 2) =8

4(1) - 3(0) = 8

4 - 0 = 8

4 = 8

Nope!  False!  2 is not a solution.

Answer:

Step-by-step explanation:

c circle

Answer:

Step-by-step explanation:

im not sure but i think its 5

Answer:

x = 2

4 x 4 = 16

25% of 16 = 4

2 x 2 = 4

i chose 2 bc i said it x -= 25% of the larger squares area meaning it would be 2

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

4^4 or 4 * 4 * 4 * 4 is 256.

Answer:

[tex] \sqrt[4]{256} [/tex]

[tex] \sqrt[4]{ {4}^{4} } [/tex]

=±4 is a required answer

Answer:

z = 20 , x = 5

Step-by-step explanation:

Answer:

70 degrees

Step-by-step explanation:

Answer:

1 2/18

Step-by-step explanation:

I need 20 more words to answer so here you so hope you d good on your test/quiz :D

Answer:

B

Step-by-step explanation:

use y=mx+c

follow the flow

Answer:

I belive the answer for the first box is 9.67

I belive the answer for the second box is 71.

I hope I helped

Answer:

19.7°

Step-by-step explanation:

In ΔTUV, the measure of ∠V=90°, UV = 3.3 feet, and TU = 9.8 feet. Find the measure of ∠U to the nearest degree.

We make use of sine rule

TU/sin V = UV/sin U

9.8/sin 90 = 3.3/sin U

Cross Multiply

sin 90 × 3.3 = 9.8 × sin U

sin U = sin 90 × 3.3 /9.8

U = arc sin ( sin 90 × 3.3/9.8)

U = 19.7°

Answer:

16.50

Step-by-step explanation:

divide it to the upper thanks

Answer:

100 times

Step-by-step explanation:

you have a 3/6 chance of rolling less than 4 once

so you multiply 3/6 times 200- you get 600/6

you simplify 600/6 to 100

100 times is the answer.

Have a fantasical day.