Find the size of the resistor which would limit the current to a value of 2 mA when connected to an 8 V supply
Answer:
R = 4000 ohms
Explanation:
Given that,
Current, I = 2 mA
The voltage of the supply, V = 8 V
We need to find the resistance of the resistor. We know that, Ohm's law is as follows :
V = IR
Where
R is resistance
So,
[tex]R=\dfrac{V}{I}\\\\R=\dfrac{8}{2\times 10^{-3}}\\\\\\R=4000\ \Omega[/tex]
So, the resistance of the resistor is 4000 ohms.