find the area and the circumference of a circle with the diameter 6 yards

Answer:

10,800 kilograms

Step-by-step explanation:

(24 x 30) x 15 = 10,800

or (24 x 15) x 30

Answer:

In terms of Pi: [tex]3\pi + 6[/tex] km

Exact value (rounded): 15.42477 km

Approximated (3.14): 15.42 km

Step-by-step explanation:

Hello!

A semicircle's perimeter can be found using the formula: [tex]P = \pi r + 2r[/tex]

We can plug in the values to solve for the perimeter.

In terms of Pi, it is [tex]3\pi + 6[/tex],

Exact value of Pi, it is 15.42477

Approximation of Pi (3.14), it is = 15.42

Answer: 1

Step-by-step explanation:

First, we will translate this into an algebraic expression.

-> Quotient means we will be using divison

-> Product means we will be using multiplciation

     the quotient of 12 and the product of 3 and 4

     [tex]\displaystyle \frac{12}{\text{the product of 3 and 4}}[/tex]

     [tex]\displaystyle \frac{12}{3*4}[/tex]

Now, I will simplify.

     Given:

      [tex]\displaystyle \frac{12}{3*4}[/tex]

     Multiply:

     [tex]\displaystyle \frac{12}{12}[/tex]

     Divide:

     1

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Answer: x=15, y=3

Step-by-step explanation:

Subtracting the two equations, we get -3y=-9, meaning y=3.

Substituting this into the first equation, we get that x-3=12, and thus, x=15.

The value of this equation is x = 0

The representation of an equation of the first degree - is given by:

[tex] \boxed{ \large \sf ax + b = 0}[/tex]

This representation is also defined in a first degree function.

— To solve this expression, let's: add or subtract the real terms. Then we will do the division.

⚘ Resolution

[tex] \large \sf{-3+8x-5=-8}[/tex]

[tex] \large \sf{-8+8x=-8}[/tex]

[tex] \large \sf{8x=0}[/tex]

[tex] \large \sf{x=0 \div 8}[/tex]

[tex] \green{ \boxed{ \boxed{ \blue{ \large \sf{x=0}}}}} \\ [/tex]

Therefore, the value of this equation will be x = 0

Answer:

The angle Sita here is called Amplitude

Answer: 0.5 or - 0.834

Step-by-step explanation: Here is the explanation!

Answer:

Hi,

Step-by-step explanation:

sin(a-b)=sin(a) cos(b)+ cos(a) sin(b)

a=45° and b=30°

[tex]sin(45^o-30^o)=sin(45^o)*cos(30^o)+cos(45^o)*sin(30^o)\\\\=\dfrac{\sqrt{2}}{2}* \dfrac{\sqrt{3}}{2}+\dfrac{\sqrt{2}}{2}*\dfrac{1}{2}\\\\\\\boxed{sin(15^o)=\dfrac{\sqrt{2}}{4}*(1+\sqrt{3} )}\\[/tex]

Answer:

r = - 18/5

I hope this helps! ^^

( This problem has 13 steps, so it would take a lot of time to type them in ^^)

Answer:

By proportional method

[tex] \frac{4}{6} = \frac{5}{x} [/tex]

4x= 30

x= 7.5

The algebraic expression of the situation above is 4x - 100 = 400

Let

the amount of ice cream they serve in July = x + 100

the amount of ice cream they serve in June = x

They served twice as many customers in august as they did in June.

Therefore,

the amount of ice cream they serve in August = 2(x)

the amount of ice cream they serve in August = 2x

Therefore,

2x + x  + x + 100 = 400

4x - 100 = 400

4x = 500

x = 500 / 4  

x = 125  

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Answer: even

Step-by-step explanation:

A function is even if f(x)=f(-x), and odd if f(x)=-f(-x). If a function satisfies neither of these, it is neither even nor odd.

[tex]f(x)_=-6x^{2}-5x^{2}-2=-11x^{2}-2\\\\f(-x)=-11(-x)^{2}-2=-11x^{2}-2\\\\\therefore f(x)=f(-x)[/tex]

Therefore, the function is even.

Given that ABCD is a parallelogram, the sum of its interior angles is:
360°

A parallelogram is a rectilinear two-dimensional figure with four sides whose opposite sides are parallel. See the image attached.

The sum of the exterior angles of any Triangle or any polygon is 360°. Hence, the sum of the exterior angles of CHFE (a polygon) is 360°.

The sides that are parallel to CE are:

FH

AD and

The side that are perpendicular to CE is side side HH, hence we can state that:

CE ⊥ EH, because both lines intersect each other at right angles.

Because the sum of angles in a triangle is 180° and we already have ∠CEH to be equal to ∠90° hence,

∠C + ∠H? = 180° - 90°

= 90°

The measure of the exterior angles of a regular pentagon is 72°

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Answer:

(2,0)

Step-by-step explanation:

The intersecting points of the two lines is the solution for the two equations.

(2,0) is the solution.

The dimensions the rug should have is 20 by 29

The dimension of the rug is given as:

22 ft by 31 ft

The area of the carpet is given as:

Area = 580

Represent the length of the empty space with x.

So, the dimension of the carpet is:

22 - 2x by 31 - 2x

The area is calculated as:

Area = (22 - 2x) * (31 - 2x)

Expand

Area = 682 - 62x - 44x + 4x^2

Evaluate the difference

Area = 682 -106x + 4x^2

Substitute Area = 580

682 -106x + 4x^2 = 580

Subtract 580 from both sides

102 -106x + 4x^2 = 0

Rewrite as:

4x^2 - 106x +102 = 0

Using a graphing calculator, we have:

x = 1 and x = 22.5

Substitute these values in 22 - 2x by 31 - 2x

So, we have:

Length = 22 - 2(1) = 20 or Length = 22 - 2(22.5) = -23

Width = 31 - 2(1) = 29 or Length = 31 - 2(22.5) = -14

The dimensions cannot be negative.

So, we have:

Length = 20 and Width = 29

Hence, the dimensions the rug should have is 20 by 29

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Given the following formula, w=x-y/2 -z. The value of y is y = x - 2w + wz .

Usually, simplification involves proceeding with the pending operations in the expression.

Like, 5 + 2 is an expression whose simplified form can be obtained by doing the pending addition, which results in 7 as its simplified form.

Simplification usually involves making the expression simple and easy to use later.

Given the following formula,

w=x-y/2 -z

We need to solve for y.

[tex]w = \dfrac{x-y}{2 -z}[/tex]

By cross multiplication

[tex]w\times (2 -z)= {x-y}\\\\2w - wz = x - y[/tex]

subtract x both side

2w - wz -x = x - y -x

y = x - 2w + wz

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Answer:

[tex]x=\frac{3}{4},\:x=-1[/tex]

Keys:

For this problem, you need the quadratic formula(listed below).

When you see ± in a quadratic equation, you must know there is going to be at least 2 solutions.

Step-by-step explanation:

solving for x₁ and x₂

[tex]4x^2+x=3\\4x^2+x-3=3-3\\4x^2+x-3=0\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot 4\left(-3\right)}}{2\cdot 4}\\[/tex]

[tex]1^2=1\\=\sqrt{1-4\cdot \:4\left(-3\right)}\\=\sqrt{1+4\cdot \:4\cdot \:3}\\=\sqrt{1+48}\\=\sqrt{49}\\=\sqrt{7^2}\\\sqrt{7^2}=7\\=7[/tex]

[tex]x_{1,\:2}=\frac{-1\pm \:7}{2\cdot \:4}\\x_1=\frac{-1+7}{2\cdot \:4},\:x_2=\frac{-1-7}{2\cdot \:4}\\[/tex]

solve for x₁

[tex]\frac{-1+7}{2\cdot \:4}[/tex]

[tex]=\frac{6}{2\cdot \:4}[/tex]

[tex]=\frac{6}{8}[/tex]

[tex]= \frac{6\div2}{8\div2}[/tex]

[tex]=\frac{3}{4}[/tex]

solve for x₂

[tex]\frac{-1-7}{2\cdot \:4}[/tex]

[tex]=\frac{-8}{2\cdot \:4}[/tex]

[tex]=\frac{-8}{8}[/tex]

[tex]=-\frac{8}{8}[/tex]

[tex]=-1[/tex]

Hope this helps!

Answer:

1.43

Step-by-step explanation:

12 tenths ⇒ 1.2

23 hundredths ⇒ 0.23

0.23 + 1.2 = 1.43

Answer:

i believe the answer is A

Step-by-step explanation:

Answer:

1) 5
2) 0.8
3)  -1.3

4) -[tex]\frac{4}{9}[/tex]

5) ±10

6) ±[tex]\frac{7}{12}[/tex]

Step-by-step explanation:

Answer:

8x

Step-by-step explanation:

We can add all of the side lengths of the triangle to figure out the perimeter. 3x-1+3x+1=6x+2x=8x

Answer:

67m²

Step-by-step explanation:

12m + 6m + 4m + 36 m 8m = 67m²

Answer:

deviation is 10

this will help you

Based on the calculations, the area of the shaded region is equal to 22 square foot.

By critically observing the geometric shapes, the area of the shaded region can be calculated by using this formula:

Area of shaded region = Area of square - Area of circle.

Note: The diameter of this circle is equal to the side length of the square because the circumference of this circle lies on the circumference of the square.

Radius = diameter/2 = 10/2 = 5 feet.

For the area of square, we have:

Area of square = S²

Area of square = 10²

Area of square = 100 square foot.

For the area of circle, we have:

Area of circle = πr²

Area of circle = 3.14 × 5²

Area of circle = 78.5 square foot.

Substituting the parameters into the formula, we have;

Area of shaded region = Area of square - Area of circle.

Area of shaded region = 100 - 78.5

Area of shaded region = 21.5 ≈ 22

Area of shaded region = 22 square foot.

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Find the area to the nearest square foot of the shaded region below, consisting of a square with a circle cut out of it. Use 3.14 as an approximation for π.

Answer:

  4 square units

Step-by-step explanation:

The vertices of the figure are on grid points, so it is appropriate to use Pick's theorem to find the area.

__

Pick's theorem tells you the area is ...

  A = i +b/2 -1

where i is the number of grid points interior to the figure (0), and b is the number of grid points on the boundary (10).

Using the counted values in the formula, we find the area to be ...

  A = 0 +10/2 -1 = 4

The area of the polygon is 4 square units.

_____

Additional comment

There are several other ways to find the area. Here are a couple:

decompose the figure

A horizontal line 1 unit up from the bottom will divide the figure into a trapezoid and a triangle. The trapezoid has bases 4 and 1, and height 1, so its area is ...

  A = 1/2(b1 +b2)h = 1/2(4 +1)(1) = 5/2

The triangle has base 1 and height 3, so its area is ...

  A = 1/2bh = 1/2(1)(3) = 3/2

Then the total area is 5/2 +3/2 = 8/2 = 4 square units.

subtract empty space

The figure occupies a 4×4 square with triangles removed from the left side and the top. Each of those triangles has a base of 4 and a height of 3. The remaining (shaded) area is ...

  A = s² -1/2bh -1/2bh

  A = 4² -1/2(4)(3) -1/2(4)(3) = 16 -12 = 4 square units

Answer:

  (b)  -7.275i -4.244j

Step-by-step explanation:

The projection of vector u onto vector v is the product of the unit vector v, the magnitude of vector u, and the cosine of the angle between them.

__

The dot product gives the product of the magnitudes of the two vectors and the cosine of the angle between them. To find the projection, we must divide the dot product by the magnitude of v and multiply by the unit vector in the direction of v.

  [tex]proj(u,v)=(\vec{u}\cdot\vec{v})\cdot\dfrac{\vec{v}}{|\vec{v}|^2}=\dfrac{((-8)(-12)+(-3)(-7))(-12\vec{i}-7\vec{j})}{(-12)^2+(-7)^2}\\\\=\dfrac{-(96+21)(12\vec{i}+7\vec{j})}{144+49}=-\dfrac{117}{193}(12\vec{i}+7\vec{j})\approx\boxed{-7.275\vec{i}-4.244\vec{j}}[/tex]

Answer:

81

Step-by-step explanation:

for example log2 8=3 is the same as 2^3=8, so if you switch around the variables from your question, your able to do 3^4, which is 81

Answer:

the prime numbers between 30 and 40 are 31 and 37 come on its so easy