determine the radius and center of the circle with the following equation
x^2+y^2-12x+24y-10=6

The mean, median, standard deviation, and interquartile range for each data set is given below.

When arranged from lowest to highest, the IQR represents the central 50% of values.

Find the median (middle value) of the lower and higher half of the data to get the interquartile range (IQR).

These are the quartile 1 (Q1) and quartile 3 (Q3) values (Q3). The difference between Q3 and Q1 is the IQR.

Using the statistical tool, the following were arrived at:

Using the statistical tool, the following were arrived at:

See the respective Histograms attached.

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Answer:

a= 2x-3 b= 2x+5

ab= (2x-3)(2x+5)

= 2x*2x+ 2x*5- 3*2x- 3*5

= 4x+ 10x- 6x- 15

= 14x- 6x- 15

= 8x -15

x= 2

= 8(2)- 15

= 16-15

= 1

Answer:

a)  1 cupcake = $5.50

b)  1 Popsicle = $3.50

Step-by-step explanation:

Let s = cost of one soda

Let c = cost of one cupcake

Let p = cost of one Popsicle

From the given information we can create 3 equations:

Subtract Equation 1 from Equation 2 to eliminate the variable s:

    s + 3c + 3p = 40

-        s + c + p = 22

          2c + 2p = 18

Substitute Equation 3 into this new equation and solve for p:

⇒ 2c + 2p = 18

⇒ 2(p + 2) + 2p = 18

⇒ 2p + 4 + 2p = 18

⇒ 4p = 14

⇒ p = 3.5

Substitute the found value of p into Equation 3 and solve for c:

⇒ c = p + 2

⇒ c = 3.5 + 2

⇒ c = 5.5

To find the cost of a soda (s), substitute the found values of p and c into Equation 1:

⇒ s + c + p = 22

⇒ s + 5.5 + 3.5 = 22

⇒ s = 13

Therefore,

Applying the Pythagorean theorem and the trigonometric ratios, the perimeter of triangle ABC is: 68.8 units.

The perimeter of a triangle = sum of its 3 sides.

Given the following:

Use the Pythagorean theorem to find AD considering triangle ADB as a right triangle:

AD = √(15² - 9²)

AD = 12 units

Use the trigonometric ratios to find DC and AC:

sin 30 = AD/AC

sin 30 = 12/AC

AC = 12/sin 30

AC = 24 units

tan 30 = AD/DC

tan 30 = 12/DC

DC = 12/tan 30

DC ≈ 20.8 units

BC = BD + DC = 9 + 20.8

BC = 29.8 units.

Perimeter of triangle ABC = BC + AB + AC

Perimeter of triangle ABC = 29.8 + 15 + 24

Perimeter of triangle ABC = 68.8 units.

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The number of days it will take to consume the given power = 4.5 days

The amount of power consumed per day = 1440watt-hours

Therefore X days = 6480 watt-hours?

Make X the subject formula;

X = 1 × 6480/1440

X = 4.5 days

Therefore, The number of days it will take to consume the given power = 4.5 days.

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The equation for the relationship between the thickness and number of weeks is y = 3.8 - 0.2x

Ice lost at 7 weeks = 7(0.2) = 1.4 meters

Total thickness of ice before loss = Ice remaining after 7 weeks + Ice lost at 7 weeks

= 2.4 + 1.4

= 3.8 meters

The equation:

y = Total thickness of ice before loss - (Ice lost per week × Number of weeks)

= 3.8 - (0.2 × x)

y = 3.8 - 0.2x

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multiply the height x the length x the width to find the volume of a room (or another 3d object)

Answer:

-17, -10, -6, -5, 3, 8 only change is between 3 and 8

Using the distance formula, the length of WX is approximately: 8.5.

Distance formula is, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex].

Given the endpoints:

W(5,-3) = (x1, y1)

X(-1,-9) = (x2, y2)

Plug in the values:

WX = √[(−1−5)² + (−9−(−3))²

WX = √[(−6)² + (−6)²]

WX = √72

WX ≈ 8.5

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Answer:

6 2 with the little check mark line in the midddle

Step-by-step explanation:

The number of ways can the committee be organized will be 2220075. Then the correct option is 3.

A permutation is an act of putting things or elements in the right sequence. Combinations are a method of picking things or pieces from a collection of objects or sets when the sequence of the objects is irrelevant.

The prom committee is made up of 8 boys and girls.

If there are 12 boys and 15 girls in the group to pick the committee from.

Then the number of ways can the committee be organized will be

Then the number of ways is given by the combination formula. Then we have

Number of ways = ¹²C₀ x ¹⁵C₈ + ¹²C₁ x ¹⁵C₇ + ¹²C₂ x ¹⁵C₆ + ¹²C₃ x ¹⁵C₅ + ¹²C₄ x ¹⁵C₄ + ¹²C₅ x ¹⁵C₃ + ¹²C₆ x ¹⁵C₂ + ¹²C₇ x ¹⁵C₁ +¹²C₈ x ¹⁵C₀

Number of ways = 6435 + 77220 + 330330 + 660660 + 675675 + 360360 + 97020 + 11880 + 495

Number of ways = 2220075

Thus, the correct option is 3.

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The coordinates of the point that divides the segment into a 3:2 ratio is (-2.2, -1.2)

The points are given as:

G = (-4,3)

H = (-1,-4)

Ratio, m : n = 3 : 2

The coordinate of the point is calculated using:

[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{3 + 2} * (3 * -1 + 2 * -4, 3 * -4 + 2 * 3)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (-11, -6)[/tex]

Evaluate the product

(x,y) = (-2.2, -1.2)

Hence, the coordinate of the point is (-2.2, -1.2)

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Answer:

[tex]\textsf{A)} \quad 5u^3-2u^2+5u+8[/tex]

Step-by-step explanation:

Given expression:

[tex](-2u^3+5u-1)+(7u^3-2u^2+9)[/tex]

Remove parentheses:

[tex]\implies -2u^3+5u-1+7u^3-2u^2+9[/tex]

Collect like terms:

[tex]\implies -2u^3+7u^3-2u^2+5u-1+9[/tex]

Combine like terms:

[tex]\implies 5u^3-2u^2+5u+8[/tex]

Option A

Answer: y=2x+7

(this is a rearranged version of y-2x=7 from question)

Step-by-step explanation:

4x=5-2y

y-2x=7

i would rearrange the 2nd value into y intercept form y=mx+b

so move the -2x to the other side of the = sign by doing the opposite, +2x on both sides to isolate the y

y=2x+7

you didn't give any options for "correct answer" so i can't give

you A B C or D answers

Answer:

16 square units

Step-by-step explanation:

16 square units

The approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

The missing part of the question is represented by the following function:

[tex]T(h) = \frac{386 + 110h}{h}[/tex]

10:00 a.m is 3 hours after 7:00 am and 1:00 p.m is 6 hours after 7:00 am.

This means that:

h = 3 at 10:00 am

h = 6 at 1:00 pm

Next, we calculate T(3) and T(6)

[tex]T(3) = \frac{386 + 110*3}{3} =238.7[/tex]

[tex]T(6) = \frac{386 + 110*6}{6} =174.3[/tex]

The average rate of change is then calculated as:

[tex]T'(h) = \frac{T(3) - T(6)}{3 - 6}[/tex]

This gives

[tex]T'(h) = \frac{238.7 - 174.3}{-3}\\[/tex]

Evaluate

T'(h) = -21

This means that the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

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The probability that you pull a card from a standard deck of 52 and then pull a second card without replacing the first card is 2%

The given parameters are:

Cards = 52

Face card = 12

Ace = 4

The probability of selecting a face card is:

P(Face card) = 12/52

Now, there are 51 cards.

The probability of selecting an ace is:

P(Ace) = 4/51

The required probability is:

P = 12/52 * 4/51

Evaluate

P = 0.0181

Express as percentage

P = 1.81%

Approximate

P = 2%

Hence, the probability is 2%

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Answer:

See below

Step-by-step explanation:

Each 32 feet of depth is 1 more atmosphere of pressure on the diver  

Answer:

Step-by-step explanation:

Remark

x/(x+1) - 1/2 = -1 /(x + 1) is the equation to be solved. Add 1/(x + 1 to both sides

x/(x+1) + 1/(x+1) - 1/2 = -1/(x + 1) + 1/(x + 1)              Combine

x/(x+1) + 1/(x + 1) - 1/2 = 0                                      Combine x/(x+1) + 1/(x+1)

(x + 1)/(x + 1) - 1/2 = 0                                            Cancel (x+1)/(x+1) = 1

1 - 1/2 = 0                                                              No solution

Answer: No solution

Answer:

1029 minutes or 17.15 hours

Step-by-step explanation:

25+0.06M=86.74

0.06M=61.74

M=61.74/0.06=1029

Answer: The awnser is linear.

I hope this helped.

Step-by-step explanation:

Answer:

x > 8

Step-by-step explanation:

14 - 2(x + 1) < - 4 ← distribute parenthesis and simplify left side

14 - 2x - 2 < - 4

12 - 2x < - 4 ( subtract 12 from both sides )

- 2x < - 16

divide both sides by - 2 , reversing the symbol as a result of dividing by a negative quantity.

x > 8

Parameterize S by the vector function

[tex]\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle[/tex]

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

[tex]\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle[/tex]

The integral of the field over S is then

[tex]\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}[/tex]

Answer:

-1/5

Step-by-step explanation:

To find the slope, the formula is y2-y1/x2-x1

1-2/3-(-2) = -1/5

Answer:

Step-by-step explanation:

hope this helps!!!!

Answer:

7

Step-by-step explanation:

[tex]\dfrac 13(15+6)\\\\\\=\dfrac{21}3\\\\\\=7[/tex]

Answer: See the screenshots below

I'm answering in this format because the questions aren't numbered, so its hard to reference them consistently (so we're both on the same page).

All decimal values are approximate. I decided to round to 4 decimal places, but feel free to use another level of precision.

Answer:

A=πr^2

Step-by-step explanation:

A=π*r^2

Where, A is area of circle

r is radius of circle

π is constant

.

Hope it's help and I think I have give brainleist answer

Answer:

πr^2

Step-by-step explanation:

it's just πr^2.

easy

Answer:

Step-by-step explanation:

SOH CAH TOA

we have the (opposite) --> 325
we have the (adjacent) --> 296

so do the inverse tan of opposite over adjacent...
[tex]tan^{-1} (\frac{325}{296} ) = 47.67[/tex] degrees

Answer:

Hi,

Step-by-step explanation:

directrix: x=-8

focus=(8,0)

[tex]x=\dfrac{(y-0)^2}{2*(8+8)}+\dfrac{8-8}{2}\\\\\boxed{x=\dfrac{y^2}{32}}[/tex]

The area of this hub cap is about  510.44625 cm².

The area of circle is pi times the square of the radius.

Area of circle =π r²

Circumference (C) = 2π r

80.07 = 2 (3.14) r

76.87/ (2x 3.14) =r

r = 12.75 cm

now, Area be

=π r²

= 3.14*12.5*12.75

=510.44625 cm²

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