can someone help me please?

Answer:

HK=42°

Step-by-step explanation:

because the arc of HK is two time bigger than HLK measurement

HLK=1/2HK

21°=1/2HK cross production

HK=2×21°

HK=42°

x^2 - 3x = x ( x - 3 )

ʜᴏᴘᴇ ʏᴏᴜ ɢᴇᴛ ᴡᴇʟʟ

Answer:

about 57

Step-by-step explanation:

Answer:

n = 4

Step-by-step explanation:

Combine like terms and solve.

n + n + 2 = 10

2n + 2 = 10

2n = 8

n = 4

Answer:

The answer is "It must be shown that both [tex]j(k(x))\ and \ k(j(x))=x[/tex]"

Step-by-step explanation:

Given:

[tex]j(x) = 11.6 e^{x} \\\\k(x) =\ln\frac{x}{11.6}[/tex]

To show that both are equal functions, and  show that both[tex]j(k(x))\ and\ k(j(x)) =x,[/tex]

For [tex]j(k(x));[/tex]  

[tex]j(k(x)) = j[(\ln \frac{x}{11.6})]\\\\j[(\ln (\frac{x}{11.6})] = 11.6e^{\ln (\frac{x}{11.6})}\\\\j[(\ln \frac{x}{11.6})] = 11.6(\frac{x}{11.6})\\\\[/tex](The natural logarithm is canceled by exponential function)  

[tex]j[(\ln \frac{x}{11.6})] = 11.6 \times\frac{x}{11.6}\\\\j[(\ln \frac{x}{11.6})] = x\\\\j[k(x)] = x\\\\for\ \ k[j(x)]:\\\\k[j(x)] = k[11.6e^x]\\\\k[11.6e^x] = \ln (\frac{11.6e^x}{11.6})\\\\k[11.6e^x] = \ln(e^x)[/tex]

Its natural logarithm leaving x will nullify expanding universe.

[tex]k[11.6e^x] = x\\\\k[j(x)] = x[/tex]

In the question, it is seen that[tex]j[k(x)] = k[j(x)] = x[/tex], shows that the functions [tex]j(x) = 11.6 e^{x} \ and \ k(x) = \ln \frac{x}{11.6}[/tex] is inverse functions.

Answer:

C

Step-by-step explanation:

Ed2021

Answer:

can you say me which chapter question is this

Answer:

Step-by-step explanation:

1. it takes 3.1 hours

2.27.08 miles is how far they travel in 25 minutes

please give me a brainliest, i worked pretty hard to find these out, if you need a explanation, i will add it

Answer:

C

Step-by-step explanation:

Answer:

Red is the correct answer

Step-by-step explanation:

Answer:

6 or 6 1\3 but i really think it is 6

Step-by-step explanation:

Answer:

Solution given:

relationship between base and hypotenuse is given by sin angle

sin angle =b/h

cos55=16/x

x=16/cos55°=27.89=28 is your answer .

Answer:

the answer is 84 being how you asked the question but I dont think thats what you meant to ask. if thars wrong just tell me and ill answer it the way you need it

Step-by-step explanation:

Answer:

84 miles

Step-by-step explanation:

Answer:

5:9

Step-by-step explanation:

20÷4=5

36÷4=9

If you divide 20 by 4 you get 5. If you divide 36 by 4 you get 9. You need to be able to divide each number in the ratio by the same number. In this case, that number is 4. You can tell that this ratio (5:9) is in simplest form because 5 is a prime number and cannot be simplified any more.

If you want to check this divide the ratio by 2 two times. Or just divide it by 4 once.

20÷2=10 → 10÷2=5

36÷2=18 → 18÷2=9

Answer:

P(12, 5) = 95040

P(8,8) = 40320

Answer:

29 square feet?

Step-by-step explanation:

yk im like 99.9% sure this is right, but that other 1% is just doubting me. So all I did to solve this was add up teh sides to find the perimeter of the shape, or in this case, the hole in the ground.

my answer is wrong d o. n o t. put my answer down

Answer:

the answer wouldbe 8585434930.123

Step-by-step explanation:

Answer:

2nd

Step-by-step explanation:

x=10

y²=x²+10²=200

y=10√2

Answer:

433 m²

Step-by-step explanation:

Find the side length of the square first.

Apply Pythagoras Theorem on 1 of the triangles on the right, to find its remaining side.

[tex] \sqrt{ {12}^{2} - {9.6}^{2} } [/tex]

=[tex] \sqrt{51.84} [/tex]

= 7.2 m

Therefore the side of the square is

7.2 ×2

= 14.4 m

The area of the square

= 14.4²

= 207.36 m²

You are able to find the area if of the 2 triangles.

(7.2 × 9.6)÷2 ×2

= 69.12 m²

The height of the pentagon

= 25.4 - 7.2

= 18.2 m

The area of the pentagon

= (10+7.2) × 18.2 ÷ 2

= 156.52 m²

Add up the areas of the 3 polygons.

The area of the shape

= 207.36 + 69.12 + 156.52

= 433 m²

Answer:

y = -5 + 6=1 is your answer

9514 1404 393

Answer:

Step-by-step explanation:

Locate the digit to the right of the place you're rounding to. If that digit is 5 or more, add 1 to the digit in the place you're rounding to. Drop all digits to the right of the one you're rounding to, unless it is left of the decimal point. In that case, zero any digits between the one you rounded and the decimal point. (See problem 3 for an example of this.)

If you're rounding to the ones place (nearest whole number), and that digit ends up being 0, then put a decimal point after it to indicate it is a significant digit.

The second attachment shows the names of the number places, if you need a reminder.

High tide at 6:00 a.m. and 6:00 p.m., depth 23 ft low tide at 12:00 noon and 12:00 midnight, depth 5 ft. Therefore, option B is the correct answer.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

The given trigonometric function is y=23-5cos(πt/6).

The given equation is y=23-5cos(πt/6), where y is the water depth in feet and t is the time in hours.

To find the high and low tide depths, we need to find the maximum and minimum values of y.

The maximum value of y is obtained when cos(πt/6) = -1, which gives y = 23 - 5(-1) = 28 ft.

The minimum value of y is obtained when cos(πt/6) = 1, which gives y = 23 - 5(1) = 18 ft.

To find the time when high and low tide occur, we need to find the values of t when cos(πt/6) equals -1 and 1 respectively.

When cos(πt/6) = -1, we get πt/6 = 3π/2, which gives t = 12 hours.

When cos(πt/6) = 1, we get πt/6 = 0, which gives t = 0 hours.

Since t = 0 represents 12:00 midnight, we can conclude that high tide will occur at 6:00 a.m. and 6:00 p.m., with a depth of 28 ft, and low tide will occur at 12:00 noon and 12:00 midnight, with a depth of 18 ft.

Therefore, option B is the correct answer.

To learn more about the function visit:

https://brainly.com/question/28303908.

#SPJ2

Answer:

See below.

Step-by-step explanation:

The formula for the volume of a sphere

= 4/3  π  r^3 where r = the radius.

So for number 1:

V = 4/3 π (5)^3

= 523 .60 mm^3   to nearest hundredth.

The others are solved in exactly the same way except where the diameter is given as in number 4 and 5 you get the radius r by dividing the diameter by 2. So in number 4,  r = 30/2 = 15.

x

2

−

3

x

+

7

−

24

x

+

3

Step-by-step explanation: brainly plz

Answer:

[tex] = \frac{({x}^{3} - 2x - 3)}{(x + 3)} \\ rationalise \: the \: denominator \\ = \frac{({x}^{3} - 2x - 3)(x - 3)}{(x + 3)(x - 3)} \\ = \frac{( {x}^{4 } - 3 {x}^{3} - {2x}^{2} + 6x - 3x + 9) }{( {x}^{2} - {3}^{2}) } \\ = \frac{( {x}^{4} - {3x}^{3} - {2x}^{2} + 3x + 9)}{( {x}^{2} - 9) } [/tex]

Answer:

???

Step-by-step explanation:

sorry can you format it?

Answer:

Surface area of the figure = 1,296π km²

Step-by-step explanation:

Given figure is a sphere;

Given:

Radius of sphere = 18 km

Find:

Surface area of the figure

Computation:

Surface area of the figure = Surface area of sphere

Surface area of sphere = 4πr²

Surface area of the figure = 4πr²

Surface area of the figure = 4π(18)²

Surface area of the figure = 4π(324)

Surface area of the figure = 1,296π km²

Answer:

y > 4x - 2

Step-by-step explanation:

The basic format of a line in slope-intercept form is,

[tex]y=mx+b[/tex]

This format undergoes no change when one implements it for the use of a two-variable inequality.

The parameter (m) represents the slope of a line, this can be found by using the formula ([tex]\frac{rise}{run}[/tex]). Traditionally, one would use a formula to find the slope of a line that is the following, ([tex]\frac{y_2-y_1}{x_2-x_1}[/tex]). However, in the given situation, one can simply count the number of boxes from one point with respect to the x-axis to another, and thus get (4).

The parameter (b) represents the point in which the graph intersects the y-axis, one can see that this point is (-2).

Since the line is dotted, one would only use the greater than symbol, not the greater than or equal-too-symbol.

Finally, since the area above the line is shaded, therefore one knows that it is (y) is greater than.