A sample of chlorine gas occupies a volume of 0.025L at 300 K. At 600K, what will the volume be?
A)808 L
B)50 L
C)0.050 L
D)0.088 L

Answers

Answer 1

Answer:  The volume at 600 K will be 0.050 L.

Explanation:

Given: [tex]V_{1}[/tex] = 0.025 L,    [tex]T_{1}[/tex] = 300 K

[tex]V_{2}[/tex] = ?,             [tex]T_{2}[/tex] = 600 K

Formula used is as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.025 L}{300 K} = \frac{V_{2}}{600 K}\\V_{2} = 0.050 L[/tex]

Thus, we can conclude that the volume at 600 K will be 0.050 L.


Related Questions


H2O2 (yield) H2O + O2


If 650 grams of hydrogen peroxide is allowed to decompose, how much water and
oxygen will be created? If 255 grams of oxygen are collected, what is the percent
yield?

Answers

The decomposition reaction is:
2 H2O2 = 2 H2O + O2

What is the number of moles of Sodium Chloride (NaCl) that is present in 29.22g sample of it?

Answers

there are 0.5 moles of NaCl present in a 29.22g sample.

to find moles of a compound you would look at the periodic table to find the mass. in this case, the mass of NaCl is 58.44 g/mol. now, you divide the sample mass of 29.22g by 58.44 g/mol. the grams will cancel each other out and you’re left with 0.5 mol in that sample

hope this helps!

Answer:

[tex]\boxed {\boxed {\sf 0.5000 \ mol \ NaCl}}[/tex]

Explanation:

We are asked to convert grams to moles. We must use the molar mass or the grams in 1 mole of a substance. These values are found on the Periodic Table as the atomic mass, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound sodium chloride or NaCl. Look up the molar masses of the individual elements.

Na:  22.9897693 g/mol Cl: 35.45 g/mol

The formula for the compound does not contain any subscripts, so there is 1 mole of each element in 1 mole of the compound. Add the molar masses together to find sodium chloride's molar mass.

NaCl: 22.9897693 + 35.45= 58.4397693 g/mol

Now we can use the molar mass to create a ratio. We know there are 58.4397693 grams of NaCl in 1 mole of NaCl.

[tex]\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Multiply by the number of grams provided in the problem: 29.22

[tex]29.22 \ g\ NaCl*\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Flip the ratio so the units of grams of NaCl cancel.

[tex]29.22 \ g\ NaCl*\frac { 1 \ mol \ NaCl}{58.4397693 \ g \ NaCl}[/tex]

[tex]29.22*\frac { 1 \ mol \ NaCl}{58.4397693}[/tex]

[tex]\frac {29.22}{58.4397693} \ mol \ NaCl[/tex]

[tex]0.5000019738 \ mol \ NaCl[/tex]

The original measurement of grams has 4 significant figures, so our answer must have the same. For our answer, that is the ten-thousandth place. The 0 to the right of this place (0.5000019738) tells us to leave the 0 in the ten-thousandth place.

[tex]0.5000 \ mol \ NaCl[/tex]

There are approximately 0.5000 moles of sodium chloride in a 29.22 gram sample of sodium chloride.

down there (pls hurry!!)

Answers

If you crush it up its going to dissolve faster and so I think it’s going to be A

I can't do Miscellaneous calculations!

E.g.
How many moles of oxygen atoms are present in 2.5 mole of water molecules?

Answers

So just balance the eqn and take the numbers infront of it
take the unknown (the one that the qn is asking for) and ratio it with the known variable
and then put in the mol that you know for the known variable and just do math to get the answer for the unknown

Select all of the HOMOGENEOUS mixtures from this list (click all that apply).

A. Paint
B. Chili
C. Blood
D. Soil
E. Salt water

Answers

Answer:

E is answer

Explanation:

salt water is the answer

Answer:

E.Salt water

Explanation:

Salt water  is  a homogeneous because the dissolved salt is evenly distributed throughout the entire salt water sample. The amount of salt in the salt water can vary from one sample to another.

2. what is the factor in an experiment that a scientist wants to observe, which may change in response to
the manipulated variable; also known as a dependent variable​

Answers

I believe the answer is observation

A 3.5L container has a gas pressure of 5.3atm. If the volume is decreases to 1.4L. What will be the new pressure inside the container?​

Answers

Answer:

your answer for that problem is 34.5

34.5 it’s so easy lol like try

What is the concentration of a sodium hydroxide solution if 14.5 mL of it are exactly neutralized by 30.0 mL of a 0.500 M hydrochloric acid solution?

Answers

Answer:

1.03 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

30.0 mL (0.0300 L) of 0.500 M HCl react.

0.0300 L × 0.500 mol/L = 0.0150 mol

Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.

Step 4: Calculate the molar concentration of NaOH

0.0150 moles of NaOH are in 14.5 mL (0.0145 L).

M = 0.0150 mol/0.0145 L = 1.03 M

Can someone pls pls help me with these questions?!?!

Answers

Answer:

13) What common form of energy (not including kinetic or potential) is not included in the “Energy Symbols” key that would normally be present in these examples?

1) Sound Energy

2) Magnetic Energy

14)Look carefully at each of the four systems shown above. Knowing what we have discussed about energy conversions, identify (list) at least three different places where this form of energy (sound) should be “produced”.

1) When you open the water tap, in the turbine and the sound of the light bulb.

2) In the light bulb

3) The sound of the kettle, the turbine and when water is boiling.

4) The movement of the wheel of the bicycle, the turbine and the light bulb.

What mass of potassium would need 2350 J of energy in order to raise its temperature from 44.3°C to 57.8°C? (cpotassium = 0.753 J/g°C)

Answers

Answer:

Explanation:

q = mCΔT

m =CΔT/q

ΔT = 57.8°C - 44.3°C = 13.5°C

m = (0.753*13.5)/2350

m = 0.00433 g

The mass of potassium that will need 2350 J of energy in order to raise its temperature from 44.3°C to 57.8°C is 231.17 g

Data obtained from the question Heat (Q) = 2350 JInitial temperature (T₁) = 44.3 °CFinal temperature of water (T₂) = 57.8 °CChange in temperature (ΔT) = 57.8 – 44.3 = 13.5 °C Specific heat capacity (C) = 0.753 J/gºC Mass (M) =?

Q = MCΔT

2350 = M × 0.753 × 13.5

2350 = M × 10.1655

Divide both side by 10.1655

M = 2350 / 10.1655

M = 231.17 g

Learn more about heat transfer:

https://brainly.com/question/6363778

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Calculate the hydrogen ion concentration of a Nitric acid solution with a pH of 2.11.

[H] = _____ (round to 2 decimal places)

Answers

Answer:

0.01 M

Explanation:

The hydrogen ion concentration can be found by finding the antilog of the pH

[tex]pH = - log [ {H}^{+} ][/tex]

We have

[tex]2.11 = - log({H}^{+}) \\ find \: \: antilog \: of \: both \: \: sides \\ \\ |{H}^{+}| = {10 }^{ - 2.11} \\ = 0.00776...[/tex]

We have the final answer as

0.01 M to 2 decimal places

Hope this helps you

Name the process by which oxygen moves from alveoli to blood

Answers

diffusion...........the blood through the capillaries lining the alveolar walls. Once in the bloodstream, oxygen gets picked up by the hemoglobin in red blood cells.

A radioisotope has a half-life of 5 minutes. What fraction of material would remain after
half an hour?

Answers

It should be 1/32 after half an hour.

Does melting sea ice in the Arctic increase sea level directly? Why or why not? How would melting over Antarctica be different?

Answers

Explanation:

The ice melting would make more water because ice is water and if it melts it make water.

hope this helps :)

Which of the following processes is not an example of physical weathering?

A. acidification
B. abrasion
C. frost action
D. exfoliation

Answers

Answer:

acidification

Answer:

I think its A

Explanation:

Hope this helps: )

What is the fixer solution equation?

Answers

Answer:

Fixation involves these chemical reactions (X = halide, typically Br−): AgX + 2 S2O32− → [Ag(S2O3)2]3− + X. AgX + 3 S2O32− → [Ag(S2O3)3]5− + X. In addition to thiosulphate the fixer typically contains mildly acidic compounds to adjust the pH and suppress trace amounts of the developer.

13 : 22
MI SEC
23. Which of the following solutions will reach dynamic equilibrium?
a Supersaturated solution
b Unsaturated solution
C Saturated solution
d None of the above

Answers

Answer:

C

Explanation:

The solution that will reach dynamic equilibrium is a saturated solution. The correct option is C.

What is an unsaturated solution?

A chemical solution in which the solute concentration is less than its equilibrium solubility is known as an unsaturated solution.

The solvent dissolves the entire solute.

When a solute (typically a solid) is mixed with a solvent (commonly a liquid), two reactions take place at the same time.

Thus, the correct option is C, the saturated solution.

Learn more about saturated solutions.

https://brainly.com/question/1851822

Is Ca +O2 ?-->CaO balanced ? explain why or why not

Answers

no. on the left side you will notice there is one Ca, and 2 oxygen. therefore on the right side there must be 1 Ca, and 2 oxygen. The correct answer would be Ca + O2 -> CaO2

The table below shows the speed of sound waves from musical sound sources at 20°C.

Which conclusion can be made based on the information in the table?

Wave speed and wave lengths can vary inversely to produce the same frequency.
Frequency and wave speed can vary directly to produce the same wavelength.
Wavelengths and frequency can vary inversely to produce the same wave speed.
Frequency and wave speed can vary directly to produce the same wave speed.

Answers

Answer:

C

Explanation:

Wavelengths and frequency can vary inversely to produce the same wave speed

Answer:

C) Wavelengths and frequency can vary inversely to produce the same wave speed.

Explanation:

edge

How would the number of atoms in a 2.02g sample of hydrogen compare to the number of atoms in a 32.00g sample of oxygen

Answers

Answer:

Number of atoms is equal.

Explanation:

1 mol of anything contains NA particles.

NA is known as Avogadro's number, 6.02×10²³

We determined the moles of each compound. Both molecules are dyatomic,

H₂  → 2.02 g . 1mol / 2.016 g = 1 mol

O₂ →  32 g . 1mol / 32g = 1 mol

Both have the same amount of moles.

In conclussion, the number of atoms is the same in both samples.

The Lewis diagram for AlF3 is:
:F:
The electron-pair geometry around the Al atom in AlF3 is
There is/are
lone pair(s) around the central atom, so the geometry of AlF3 is
Submit Answer
Retry Entire Group
9 more group attempts remaining

Answers

Answer:

25,000 pairs

Explanation:

Need help. Will pay if needed, or give away points. CHEMISTRY

Answers

Answer:

C. So electrons can flow from one electrode to another

Explanation:

An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.

An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.

Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.

Calculate the molarity when 3.55 moles of NaCl are dissolved to make 0.200 L of solution

Answers

Answer: The molarity of given solution is 17.75 M.

Explanation:

Given: Moles = 3.55 mol

Volume of solution = 0.2 L

Molarity is the number of moles of a solute present in liter of solution.

Hence, molarity of the given solution is calculated as follows.

[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{3.55 mol}{0.2 L}\\= 17.75 M[/tex]

Thus, we can conclude that the molarity of given solution is 17.75 M.

How many moles of SO3 are in 2.4 *10^23 cules?

Answers

Answer:

0.4 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

[tex]n = \frac{2.4 {10}^{23} }{6.02 \times {10}^{23} } = \frac{2.4}{6.02} \\ = 0.3986...[/tex]

We have the final answer as

0.4 moles

Hope this helps you

74g of Ca(OH)2 (74 g/mol) in 340 ml solution

Answers

Answer:

This question is asking to calculate the molarity of the solution based on the information provided.

The answer is 2.94M

Explanation:

Molarity of Ca(OH)2 solution = number of moles (n) ÷ volume (V)

Using the formula below to calculate number of moles of Ca(OH)2.

mole = mass/molar mass

Molar mass of Ca(OH)2 = 74 g/mol

mole = 74g/74g/mol

mole = 1mol

Volume of Ca(OH)2 solution = 340ml = 340/1000 = 0.340 L

Molarity = 1/0.340

Molarity = 2.94M

Which of the following is not a fossil fuel?

o copper
natural gas
O petroleum
O coal

Answers

Answer:

copper

Explanation:

coal, petroleum, and natural gas are all related to fossil fuels.

Copper is not a fossil fuel and the correct option is option 1.

What are fossil fuels?

Fossil fuels are compound mixtures made of fossilized plant and animal remnants from millions of years ago. The creation of fossil fuels—either oil, natural gas, or coal—from these fossils is determined by the type of fossil, the amount of heat, and the amount of pressure.

Fossil fuels are a non-renewable source of energy. Most of the energy used by us is obtained by the burning of fossil fuels. These fossil fuels are used up at a faster rate. They cannot be regrown at a scale compared to their consumption.

Therefore, Copper is not a fossil fuel and the correct option is option 1.

Learn more about Fossil fuels, here:

https://brainly.com/question/3371055

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How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃?


4FeCl3+3O2->2Fe2O3+3Cl2


The 2 for the second half of the equation is not a coefficient it’s supposed to be for 2Fe2 Not 2O3.

26.3 mol

46.7 mol

23.3 mol

10.0 mol

Answers

Answer:

26.3 mol O₂

Explanation:

Step 1: Write the balanced equation

4 FeCl₃ + 3 O₂ ⇒ 2 Fe₂O₃ + 6 Cl₂

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of FeCl₃ to O₂ is 4:3.

Step 3: Calculate how many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃

We will use the previously established molar ratio.

35.0 mol FeCl₃ × 3 mol O₂/4 mol FeCl₃ = 26.3 mol O₂

An organ, such as the eye or the heart, is composed of cells and________.

A. tissues
B. water

Answers

Answer is Tissues (A)

if you traveled 100 miles in 5 hours what is your speed

Answers

Answer:

20 MPH (miles per hour)

Explanation:

You do miles / time (miles divided by time) to calculate the average speed!

Hope this helped ^^

The answer to that would be “20 miles per hour”

A student carried out a titration using HC2H3O2(aq)HC2H3O2(aq) and NaOH(aq)NaOH(aq). The net ionic equation for the neutralization reaction that occurs during the titration is represented above. The NaOH(aq)NaOH(aq) was added from a buret to the HC2H3O2(aq)HC2H3O2(aq) in a flask. The equivalence point was reached when a total of 20.0mL20.0mL of NaOH(aq)NaOH(aq) had been added to the flask. How does the amount of HC2H3O2(aq)HC2H3O2(aq) in the flask after the addition of 5.0mL5.0mL of NaOH(aq)NaOH(aq) compare to the amount of HC2H3O2(aq)HC2H3O2(aq) in the flask after the addition of 1.0mL1.0mL of NaOH(aq)NaOH(aq), and what is the reason for this result

Answers

Answer:

The amount of HC₂H3₃2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.

Explanation:

Equation of the reaction between acetic acid, HC₂H₃O₂(aq) and sodium hydroxide, NaOH(aq) is given below:

CH₃COOH (aq) + NaOH (aq) ----> CH₃COONa (aq) + H₂O

The equation of the reaction shows that acetic acid andsodium hydroxide will react in a 1:1 ratio

Since the concentration of NaOH was not given, we can assume that the concentration is 0.01 M

Moles of NaOH in 5.0 mL of 0.01 M NaOH = 0.01 × 5/1000 = 0.00005 moles

Moles of NaOH in 1.0 mL of 0.01 M NaOH = 0.01 ×1/1000 = 0.0001 moles

Ratio of moles of NaOH in 5.0 mL to 1.0 mL = 0.00005/0.00001 = 5

There are five times more moles of NaOH in 5.0 mL than in 1.0 mL and this means that 5 times more the quantity of HC₂H₃O2(aq) required to react with 1.0 mL NaoH is needed to react with 5.0 mL NaOH.

Therefore, the amount of HC₂H₃O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.

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