A lead ball is added to a graduated cylinder containing 50.6 ml of water, causing the level of the water to increase to 93.0 mL. What is the volume in milliliters of the lead ball, Vieras? Viead =

Answers

Answer 1

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

What is a graduated cylinder?

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

[tex]93.0 mL= V_(lead ball) +50.6 ml[/tex]

[tex]V_(lead ball) = 93.0 mL - 50.6 ml[/tex]

[tex]V_(lead ball) = 42.4 ml[/tex]

Hence, 42.4 ml is the volume in milliliters of the lead ball.

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Related Questions

3) The following reaction produces chlorine molecules:
Energy + HCl (g) + CINO3 (8) Cl₂ (8) + HNO3 (8)
a) Describe 4 ways you could increase the concentration of chlorine molecules.
b) How would cooling shift the equilibrium of this reaction?

Answers

The 4 ways to increase the concentration of chlorine molecules is listed below and the reaction will go into reverse if cooled.

What is Le Châtelier’s principle ?

Le Châtelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish an equilibrium.

Energy + HCl (g) + ClNO₃ ⇄  Cl₂  + HNO₃

a. So in this reaction when at equilibrium , To increase the concentration of Chlorine molecules

1. An increase in Temperature will favour the formation of Chlorine molecules.

2. Decrease in concentration of Chlorine , or partial removal of Chlorine will result the equation to go in forward direction.

3.An Increase in the concentration of HCl will favour formation of Chlorine molecules.

4.An Increase in the concentration of  CINO₃ will also favour formation of Chlorine molecules.

b. The cooling would shift the reaction into backward direction as it is an endothermic reaction in forward state.

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Could really use a few pointers on this question!

Answers

From the calculations, we can see that the theoretical yiled of NO2 is 100L of NO2

What is the theoretical yield?

The theoretical yield is that calculated from the stoichiometry of the reaction.

We can see that 1 mole of O2 produced 2 moles of NO2. Thus;

2.23 moles of O2 will produce 4.46 moles of NO2

Since 1 mole of NO2 occupies 22.4 L

4.46 moles of NO2 occupies 100L of NO2

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A gas cylinder contains 5.0 kg of propane. How many propane molecules are in the cylinder? The Avogadro constant, L = 6.022 x 1023 mol^-1
A 6.8 × 10^22
B 7.2 x 10^22
C 6.8 × 10^25
D 7.2 x 10^25
[1 mark]​

Answers

Answer:

Here's your answer.

M(C3H8) = 44 g/mol

n(C3H8) = 5000 (g)/44 (g/mol) = 113,6 mol

[tex] N = n \times N_{a} = 113,6 \times 6,02 \times {10}^{23} \\ \\ = 684,1 \times 10 ^{23} \sf{molecules} [/tex]

Hope it helps you from my side

ASAP 100 POINTS Which molecules carries instructions for inherited traits
A.DNA
B CARbohydrate
C.Protein
D.Lipid

Answers

Answer:

A.DNA

Explanation:

Ahaa Its gona be right

Answer:

D.N.A.

Explanation:

Hi student! Let me help you out on this question.

D.N.A. is the molecule which carries instructions for inherited traits.

[tex]\therefore,Option\quad A \quad is \quad correct[/tex]

Hope that this helped! have a good day ahead.

Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.

Answers

No of molecules=26.02×10²³molecules

No of moles

26.02×10²³/6.023×10²³4.3mol

Molar mass

C2H82(12)+8(1)24+832g/mol

Mass

Moles×Molar mass32(4.3)137.6g

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{Molecules}{Avagadro\:no}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=\dfrac{26.02\times 10^{23}}{6.023\times 10^{23}}[/tex]

[tex]\\ \tt{:}\longrightarrow No\:of\:moles=4.32mol[/tex]

Molar mass of Ethane=32g/mol

We need the mass

[tex]\\ \tt{:}\longrightarrow No\:of\:moles\times molar\:mass[/tex]

[tex]\\ \tt{:}\longrightarrow 32(4.32)[/tex]

[tex]\\ \tt{:}\longrightarrow 138.24g[/tex]

How many moles of a gas can be contained in a 1600-cm° flask at 25°C and 75 kPa?

Answers

Volume=1600cm³=1.6dm³=1.6L

Temperature=25°C=273+25=298K

Pressure=75000Pa

Now

Apply ideal gas equation

PV=nRTn=PV/RTn=75000(1.6)/8.314(298)n=48.43mol

The number of moles needed is

n=48.43mol.

Calculations

Given the values of the volume and temperature, we would convert them to the required units.

Volume=1600cm³=1.6dm³=1.6L

Temperature=25°C=273+25=298K

Pressure=75000Pa

We would use the ideal gas equation

PV=nRT

n=PV/RT

n=75000(1.6)/8.314(298)

n=48.43mol

Which two nuclides are isotopes of the same element

Answers

Answer:

1940K and 1939K Isotopes are two forms of the same element that have different numbers of neutrons in the nucleus. This means same symbol, and same atomic number (subscript), but different mass number (superscript).

Calculate 5.1234 + 0.033÷ 1.650 and report to the correct number of significant figures.

Answers

5.1434 contains 5 significant figures and 4 decimals.

What is a significant figure?

All zeros that occur between any two non-zero digits are significant. For example, 108.0097 contains seven significant digits.

Calculation:

5.1234 + 0.033÷ 1.650 = 5.1434

5.1434 contains 5 significant figures and 4 decimals. 5.1434 rounded to 4 sig figs is 5.143, to 3 sig figs is 5.14, and to 2 sig figs is 5.1.

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Consider the following reversible reaction:
2 CO(g) + O₂(g) 2CO₂(g). Describe a way to increase the CO concentration at equilibrium. Explain your reasoning.

Answers

The given equilibrium reaction indicates the reaction between carbon monoxide and the oxygen and forms carbon dioxide. In this reaction, by increasing the concentration of the carbon monoxide, the equilibrium shifts towards the right. Since, the reactant concentration increases, the equilibrium stress decreases the concentration of the reactants and therefore, the equilibrium shift towards the right side of the equation.

reaction indicates that carbon monoxide reacts with oxygen and forms carbon dioxide gas.

By increasing the concentration of carbon monoxide image, the equilibrium in the reaction shifts towards the right.

The effect of change of pressure, concentration and temperature on the state of equilibrium can be predicted with the help of a principle known as Le Chatelier's principle. Here by increasing the concentration of CO₂, the amount of CO formation can increase.

What is Le Chatelier's principle?

If a system in equilibrium is subjected to a change in concentration, pressure or temperature, the equilibrium shifts in the direction that tends to reduce or to counteract the effect of change. When the concentration of any substance in equilibrium is increased, the equilibrium shifts in the direction which decreases the concentration of that substance.

On other hand, increasing the concentration of any of the products results in shifting the equilibrium in the backward reaction forming more products. So here increasing the amount of CO₂, shifts equilibrium in the backward direction and forms more amount of CO.

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