Answer: A 13.88 mL of the concentrated acid would be required to make 250. mL of a 1.00 M [tex]H_{2}SO_{4}[/tex] solution.
Explanation:
Given: [tex]M_{1}[/tex] = 18.0 M, [tex]V_{1}[/tex] = ?
[tex]M_{2}[/tex] = 1.00 M, [tex]V_{2}[/tex] = 250 mL
Formula used to calculate the volume of concentrated acid is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\18.0 M \times V_{1} = 1.00 M \times 250 mL\\V_{1} = \frac{1.00 M \times 250 mL}{18.0 M}\\= 13.88 mL[/tex]
Thus, we can conclude that 13.88 mL of the concentrated acid would be required to make 250. mL of a 1.00 M [tex]H_{2}SO_{4}[/tex] solution.