A tau lepton decays into an electron, an electron antineutrino and a tau neutrino. Write out this reaction in symbolic (equation) form and show that charge and lepton number is conserved. 2. What is the total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

The total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons is 12 quarks.

Any of a family of particles (such as electrons, muons, and neutrinos) that have spin quantum number ¹/₂ and that experience no strong forces.

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

Charge on the left side = -1

Charge on the right side = -1+0+0 = -1

As the charge on the electron antineutrino,  [tex]{\bar{\nu }}[/tex] e and the tau neutrino,  [tex]\nu\tau[/tex] are zero each.

Thus, charge on left side = charge on right side

Or, the equation is in accordance with charge conservation.

Lapton number of left side = 1

Laptop number of right side = 1-1+1 = 1

This is because, lapton number of the particles involved are,

Tau lapton, [tex]\tau[/tex]-1 = 1,

Electron, e-1 = 1,

Electron antineutrino,  [tex]{\bar{\nu }}[/tex]e = -1,

Tau neutrino, [tex]\nu\tau[/tex]= 1,

Thus, lapton number of left side = lapton number of right side

So, the equation obeys lapton number conservation.

2.

The total number quarks in a helium nucleus which is composed of 2 protons (positively charged particle) and 2 neutrons (uncharged particle) is:

Since there 3 quarks in each nucleon, 4 nucleons would have a total of 12 quarks.

Just simply multiply 3 quarks by the number of nucleons:

So, 3 (quarks) x 4 (nucleons) = 12 quarks

Therefore, there are 12 quarks in 4 nucleons.

Learn more about lepton decays here:

https://brainly.com/question/12044097

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