A boat is heading towards a lighthouse, whose beacon-light is 139 feet above the water. The boat’s crew measures the angle of elevation to the beacon, 11 degrees
∘
. What is the ship’s horizontal distance from the lighthouse (and the shore)? Round your answer to the nearest hundredth of a foot if necessary.

Answer:

Solve v + 6 = 5v − 2 to find the value of v.

Step-by-step explanation:

Answer:

Option 3

Step-by-step explanation:

The correct method to find Meg's and Victor's ages is to equate the equations for their ages.

Hence. the answer is :

Solve v + 6 = 5v − 2 to find the value of v.

Answer:

6-2w(w+2)

Step-by-step explanation:

6-2w²+4w

6-2w(w+2)

Answer:

BD = BE

Step-by-step explanation:

If BD = BE , angle BED = angle BDE.

Because they are in a same triangle.

And also they are congruent.

Answer:

A

Step-by-step explanation:

for the relation to be a function then each value of x in the domain must map to exactly one unique value of y in the range

this is the case for A

in B : 3 → 2 and 3 → 8 ← not a function

in C : - 2 → 5 and - 2 → 7 ← not a function

in D : 2 → 2 and 2 → 3 and 3 → 3 and 3 → 2 ← not a function

Answer:

P(AUB)=P(A)+P(B)

Step-by-step explanation:

I found it somewhereI don't know?Trust me:)

Answer:

The answer is option A

Step-by-step explanation:

The solution is in the image

Answer:

Slope: [tex]\frac{4}{1}[/tex]

Y - intercept: -1

Step-by-step explanation:

We can see from the graph that the slope is [tex]\frac{4}{1}[/tex].

We can also identify the y - intercept as -1.

Therefore, the linear equation would be y = [tex]\frac{4}{1}[/tex]x -1

Hope this helps:) Goodluck!

The angle opposite the side measuring 11 inches has one solution of approximately 43°. Thus, the correct option is B.

The sine rule of trigonometry helps us to equate the side of the triangles to the angles of the triangles. It is given by the formula,

[tex]\dfrac{Sin\ A}{\alpha} =\dfrac{Sin\ A}{\beta} =\dfrac{Sin\ A}{\gamma}[/tex]

where Sin A is the angle and α is the length of the side of the triangle opposite to angle A,

Sin B is the angle and β is the length of the side of the triangle opposite to angle B,

Sin C is the angle and γ is the length of the side of the triangle opposite to angle C.

Using the sine rule, the measurement of the angle of opposite the side measuring 11 inches can be done. Therefore, the measure can be written as,

8/ Sin(30°) = 11/ Sin(θ)

Sin(θ) = [11 × Sin(30°)]/8

Sin(θ) = 0.6875

θ = Sin⁻¹ (0.6875)

θ = 43.4325° ≈ 43°

Hence, The angle opposite the side measuring 11 inches has one solution of approximately 43°. Thus, the correct option is B.

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Answer:

∠ABC = 39°

Step-by-step explanation:

Since ED bisects ∠CBD :

∠EBD = ∠CBE = 30°

Now, ∠ABD = ∠ABC + ∠CBE + ∠EBD = 99°

Solving :

Answer:

See below

Step-by-step explanation:

y = -3 x^7   is NOT a parabola....   y = -3x^2  IS a parabola that opens downward due to the negative coefficient (-3)

From simplification of the given algebra, the correct answers are as shown below.

1) (a² - b)/(a³b²)

This reduces to;

(a²/(a³b²)) - b/(a³b²)

⇒ a/(ab²) - 1/(a³b)

2) The algebraic expression is;

(b - a)/a³b³

⇒ b/a³b³ - a/a³b³

⇒ 1/a³b² - 1/a²b³

3) The algebraic expression is;

(2 - ab²)/(a²b³)

⇒ (2/(a²b³)) - (ab²)/(a²b³)

⇒ 2/(a²b³)) - 1/(ab)

4) The algebraic expression is;

(2 - ab²)/(a²b³)

⇒ 2/(a²b³) - 1/ab

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Answer:

V = 3053.63 mm^3

Step-by-step explanation:

radius : 9mm

V = 4/3 * pi * r^3

V = 4/3 * (3.1415926535898...) * 9^3

V = 3053.63 mm^3

A quadratic equation is in the form of ax²+bx+c. It took 3seconds for the golf ball to reach the green.

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

A.) The time that the ball takes to reach the green can be found by equation the equation against zero. As the ball will have 0 height when it will be on the green,

t²+4t-21=0

t²+7t-3t-21=0

t(t+7)-3(t+7)=0

(t+7)(t-3)=0

t = -7, 3

Hence, it took 3seconds for the golf ball to reach the green.

B.) Since the time can not be negative the second value is wrong.

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Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is [tex](\pi)(27.8^{2})\left(\frac{150}{360} \right)[/tex].

Using the formula [tex]A=\frac{1}{2} ab \sin C[/tex], we get the area of the triangle is [tex]\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ})[/tex].

So, the area of the shaded sector is [tex](\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}[/tex]

The value of the function g(x) = x^3 + 6x^2 + 12x + 8 when x = -1 is 1

The equation of the function is given as:

g(x) = x^3 + 6x^2 + 12x + 8

When x = -1, we have:

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

Evaluate the expression

g(-1) = 1

Hence, the value of the function g(x) = x^3 + 6x^2 + 12x + 8 when x = -1 is 1

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Answer:

g(-1) = 1

Step-by-step explanation:

Answer:

C. d=15t

Step-by-step explanation:

it is C because you get the equivalent from the t and that t is the number 1 so 15×1 is 15

More information:

I hope this is able to help you, please feel free to give feedback if necessary :)

Answer:

The answer is C. Quadrant 3.

Step-by-step explanation:

Looking up a Unit Circle. We can see that 5pi/4 is in quadrant 3.

5pi/4 is also if in degree angle as 225°

Answer:

Vertex(1,7)

Vertex form: [tex]f(x)=-2\left(x-1\right)^2+7[/tex]

Step-by-step explanation:

Vertex form equations for x is [tex]v=-\frac{b}{2a}[/tex]

which the vertex here is

[tex]-\frac{4}{2\left(-2\right)}[/tex]

->

x = 1, plugin to find y, y = 7

The total cost for a person who purchases a car share and uses it for 72 hours is $1207.

The total cost is a function of the yearly fee and the cost per hour.

Total cost = yearly fee + (total hours the car was used for x cost per hour)

$199 + (72 x $14)

$199 + $1008 = $1207

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Answer:

$164.66

Step-by-step explanation:

Just subtract them from each other

if its diameter is 9, that means its radius is half that, or 4.5.

[tex]\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=4.5 \end{cases}\implies \begin{array}{llll} SA=4\pi (4.5)^2\implies SA=81\pi \\\\\\ SA\approx 254.47~in^2 \end{array}[/tex]

The surface area of the basketball with diameter of 9 in will be 254.34 in².

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

Given that, a basketball has a diameter of 9 inches we need to find its surface area,

Since, the basketball is in the shape of the sphere and the surface area of the sphere = 4π×radius²

Therefore, the surface area of the basketball =

= 4×3.14×(9/2)²

= 4×3.14×4.5×4.5

= 254.34 in²

Hence the surface area of the basketball with diameter of 9 in will be 254.34 in².

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Answer: ~96.83°

Step-by-step explanation:

1) It's obvious that the largest angle is the opposite to the largest side.

▪︎ QR = 18 (the largest side)

=> <QPR is the largest angle

2) Cosine Rule:

▪︎ QR^2 = QP^2 + PR^2 - 2*QP*PR*cos(QPR)

▪︎ 18*18 = 13*13 + 11*11 - 2*13*11*cos(QPR)

▪︎ 324 = 169 + 121 - 286*cos(QPR)

▪︎ 34 = -286*cos(QPR)

▪︎ cos(QPR) = -34/286

▪︎ <QPR = arccos(-34/286) = 96.827...°

The number of  people are working by force or under coercion stands at about 12.3 million.

The ILO is the acronym for International Labor Organization. It is the arm of the United Nations that is responsible for seeing to the Welfare of workers globally.

According to current statistics from the  International Labor Organization, the number of  people are working by force or under coercion stands at about 12.3 million.

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Answer:

c. 12.3 million

got it right on edge)))

Answer:

Given function:

[tex]f(x)=6x^2+x-2[/tex]

To find the zeros of the function, set the function to zero and factor:

[tex]\implies 6x^2+x-2=0[/tex]

[tex]\implies 6x^2+4x-3x-2=0[/tex]

[tex]\implies 2x(3x+2)-1(3x+2)=0[/tex]

[tex]\implies (2x-1)(3x+2)=0[/tex]

Therefore, the zeros are:

[tex]\implies (2x-1)=0 \implies x=\dfrac{1}{2}[/tex]

[tex]\implies (3x+2)=0 \implies x=-\dfrac{2}{3}[/tex]

If α and β are the zeros of the function:

Question 1

[tex]\begin{aligned}\implies \alpha^2+\beta^2 & =\left(\dfrac{1}{2}\right)^2+\left(-\dfrac{2}{3}\right)^2\\\\& = \dfrac{1}{4}+\dfrac{4}{9}\\\\& = \dfrac{9}{36}+\dfrac{16}{36}\\\\& = \dfrac{25}{36}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\implies \dfrac{1}{\alpha}+\dfrac{1}{\beta} & = \dfrac{1}{\frac{1}{2}}+\dfrac{1}{-\frac{2}{3}}\\\\& = 1 \times \dfrac{2}{1}+1 \times -\dfrac{3}{2}\\\\& = 2 - \dfrac{3}{2}\\\\& = \dfrac{1}{2}\end{aligned}[/tex]

Answer:

[tex]1) ~\alpha^2+\beta^2 = \dfrac{25}{36}\\\\\\2)~\dfrac 1 {\alpha} + \dfrac 1{\beta} = \dfrac 12[/tex]

Step-by-step explanation:

[tex]\text{Given that,}\\\\f(x) = 6x^2 +x -2~ \text{and the roots are}~ \alpha, \beta\\\\\text{Now,}\\\\\alpha + \beta = -\dfrac{b}{a} = -\dfrac{1}{6}~~~~~;[\text{Compare with the standard form}~ ax^2 +b x + c = 0]\\\\\alpha \beta = \dfrac ca = -\dfrac2 6 = - \dfrac 13\\\\\\\textbf{1)}\\\\\alpha^2 +\beta^2\\\\\\=\left(\alpha +\beta \right)^2 - 2 \alpha \beta \\\\\\=\left( -\dfrac 16 \right)^2 -2 \left(- \dfrac 13 \right)\\\\\\=\dfrac{1}{36}+\dfrac 23\\\\\\=\dfrac{25}{36}[/tex]

[tex]\textbf{2)}\\\\\dfrac 1{\alpha} + \dfrac 1{\beta} \\\\\\=\dfrac{\alpha + \beta}{\alpha \beta }\\\\\\=\dfrac{-\tfrac16}{-\tfrac 13}\\\\\\=\dfrac{1}{6} \times 3\\\\\\=\dfrac{1}{2}[/tex]

When a problem has no solution you'll end up with a statement that's false. For example: 0=1 This is false because we know zero can't equal one. Therefore we can conclude that the problem has no solution.

Answer: A problem with no solution is a problem with no applicable answer or the answer is not a real number or x ∉ R

Answer:

a) Length= (x+2) and breadth=(x-1) b) 4 m^2 c) R1000

Answer:

answers in photo / +explanation

Step-by-step explanation:

a)

length: x+2

width/breadth: x-1

b)

length: 4m

width/breadth: 1m

area: 4m²

c)

R1000

Answer: 1

Step-by-step explanation:

The tangent on the unit circle is y/x

The point on the unit circle is given as:

Point = (x,y)

By default

(cos(ø), sin(ø)) = (x,y)

This means that:

cos(ø) = x

sin(ø) = y

The tangent of an angle is:

tan(ø) = sin(ø)/cos(ø)

So, we have:

tan(ø) =y/x

Hence, the tangent on the unit circle is y/x

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