5+√2/4+√8
can be written in the form
where r and s are both integers.
What are the values of r and s?
r-s√2/4

Answer:

2ax + b + C

where C is a constant.

Answer:

y=4

y=x+4

y=-2+4

Step-by-step explanation:

the trick is to consider x as 0.

Answer:

47.1408

Step-by-step explanation:

They gave us the percentage of a number and wants us to find the whole

to do that we will use the following equation:

46.116*100/4.5 = 47.1408 is the number we are looking for.

Answer:

that's easy all you have to do is find out what is the value of x then divided by 2 once you divide by 2 subtract 3x 18 and 0

Answer:

[tex]x= -\dfrac {9}2 +\dfrac{\sqrt{57}}{2},~~x = -\dfrac {9}2 - \dfrac{\sqrt{57}}{2}[/tex]

Step-by-step explanation:

[tex]~~~~~~~x^2 +9x +12 = 6\\\\\implies x^2 +9x = 6-12\\\\\implies x^2 +9x = -6\\\\\implies x^2 +2 \cdot \dfrac 92 \cdot x +\left(\dfrac 92\right)^2 -\left( \dfrac 92 \right)^2 = -6\\\\\implies \left(x+ \dfrac 92 \right)^2 -\dfrac{81}{4}= -6\\\\\implies \left(x +\dfrac 92 \right)^2 = -6 + \dfrac{81}4\\\\\implies \left(x + \dfrac92 \right)^2 = \dfrac{57}{4}\\\\\implies x+ \dfrac 92 = \pm\sqrt{\dfrac{57}4}\\\\\implies x = -\dfrac {9}2 \pm\dfrac{\sqrt{57}}{2}[/tex]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]2x+3y=21\implies 3y=-2x+21\implies y=\cfrac{-2x+21}{3} \\\\\\ y=\cfrac{-2x}{3}+\cfrac{21}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

therefore then

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2}\implies \cfrac{3}{2}}}[/tex]

Answer:

2x+3y=21.

the answer is [tex]\frac{3}{2}[/tex]

simplify the answer I think. x = 2 + y = 3 = 21

x = 2
x + 1 = 3

y = 3

y - 1

2 + 1 = 3

3 - 1 = 2

The answer will only be [tex]\frac{3}{2}[/tex] no y = [tex]\frac{3}{2}[/tex] just  [tex]\frac{3}{2}[/tex]

Don't forget to look at the picture

Answer:

x = 7

Step-by-step explanation:

8*7 - 6 = 50

Answer:

Normally,in calculating the amount of space an object occupies...the volume method is require due to 3 dimensional rule,vice versa an area

The sine of ∠I is represented by the ratio 63:65

First, let's draw the triangle (see the picture below.)

We need to use it here.

-sin = opposite/hypotenuse

-cos = adjacent/hypotenuse

-tan = opposite/adjacent.

Assuming that ∠I is Ф,

we can see that its opposite side is equal to 63 and the hypotenuse is 65. Therefore,

[tex]sin(I)=\frac{63}{65} \\\\sinI=75^0[/tex]

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Answer:

0.18

Step-by-step explanation:

It’s right bc I got it correct with that answer

Answer:

B

About 16% of the books have fewer than 150 pages.

Step-by-step explanation:

Quizlet also said so

Answer:

B

Step-by-step explanation:

Hope this will help on the problem

An equation is formed of two equal expressions. The correct option is A.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Ms. Banerjee bought a car for $22,500. The amount she paid for her new car was twice the amount she paid for her previous car, which she bought 8 years ago. Therefore, the equation shows p, the price in dollars that she paid for her previous car,

Price of new car = 2 (Price of the previous car)

22,500 = 2p

Hence, the correct option is A.

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Answer: a

Step-by-step explanation:

A total of 720 tickets were sold for the school play. They were either adult tickets or student tickets is mathematically given as

Generally, the equation for a sold tickets is mathematically given as

S=x+72

Therefore

x+x+72=772

2x+72=772

2x=772-72

x=350

In conclusion, tickets sold was

x=350

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The angle BAC and DCA are alternate interior angles , Option D is the right answer.

What are Parallel Lines ?

The lines in a plane which never intersect and are at a same distance always are called Parallel Lines.

In the given question it is given that there are two lines FG and DE

The lines are parallel to each other , and transversal are AC and BC .

The angle BAC and DCA are alternate interior angles as AC is the transversal of the parallel lines.

Option D is the right answer.

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Answer:

there is no line

The linear equation that models the cost for having x additional family members added is:

c(x) = $75 + $10.99*x

Here we know that the plan has a fixed price of $75 plus $10.99 for each family member added beyond the primary account holder.

Then if there are x family members added, the cost will be:

$75 + $10.99*x

Then the linear equation that models the cost for having x additional family members added is:

c(x) = $75 + $10.99*x

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Answer:

see the attachment photo!

Answer: The correct answer is 135 in².

Step-by-step explanation: An area of a polygon is this:

Area = (number of sides × length of one side × apothem)/2

(5 x 6 x 9) / 2 = 135

Answer:c

Step-by-step explanation:heheh

Answer: C

Step-by-step explanation:

Answer:

m = 50h, where m is the distance traveled in miles

Answer:

See below

Step-by-step explanation:

h^2 - 5h = 84

h^2 - 5h - 84 = 0

Answer: 1.) 3 2/3  2.) 2 9/10  3.) 9 11/15   4.) 7 11/12

B. Question 2,

My answer is reasonable, because if we round 1 7/10 to 2 and 1 1/5 to 1

2+1=3 and my answer is 2 9/10. This estimate makes sense because 2 9/10 can be rouned to 3, meaning it is reasonable.

Step-by-step explanation:

1 1/6 + 2 3/6= 3 4/6

Simplifyed=3 2/3

1 7/10 + 1 2/10 = 2 9/10

7 5/15 + 2 6/15= 9 11/15

4 8/12 + 3 3/12= 7 11/12

Answer:

[tex]x = 2\\ \\x= -\dfrac 78[/tex]

Step-by-step explanation:

[tex]~~~~~~~8x^2 -9x -14=0\\\\\implies 8x^2+7x-16x-14=0\\\\\implies x(8x+7)-2(8x+7)=0\\\\\implies (x-2)(8x+7) = 0\\\\\implies x = 2,~ x= -\dfrac 78[/tex]

a. A critical point at x = 25 would mean f'(25) = 0 or doesn't exist. We have derivative

[tex]f(x) = x - k \sqrt x \implies f'(x) = 1 - \dfrac k{2\sqrt x}[/tex]

so that

[tex]f'(25) = 1 - \dfrac k{2\sqrt{25}} = 1 - \dfrac k{10} = 0 \implies \boxed{k=10}[/tex]

b. Taking the second derivative, we get

[tex]f''(x) = \dfrac k{4 x^{3/2}} = \dfrac5{2 x^{3/2}}[/tex]

At x = 25, the second derivative has a positive sign,

[tex]f''(25) = \dfrac 5{2 \times 25^{3/2}} = \dfrac 5{2\times5^3} = \dfrac1{50} > 0[/tex]

which means f(x) is concave upward around x = 25, so this critical point is a local minimum.

Answer:

  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

__

The general form of the equation of height for ballistic motion is ...

  [tex]h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}[/tex]

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

  h(t) = -16t² +10.5t +5

__

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

The solution is ...

  [tex]t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}= \dfrac{-10.5\pm\sqrt{10.5^2-4(-16)(5)}}{2(-16)}\\\\=\dfrac{10.5\pm\sqrt{430.25}}{32}=\dfrac{21\pm\sqrt{1721}}{64}[/tex]

The positive solution is ...

  t ≈ 0.976327 ≈ 0.98

Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

Additional comment

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

Answer:

Step-by-step explanation:

(a). In set notation:

B. { x | x < 2 }

(b).

( - ∞ , 2 )

(c). See attachment.

The solutions to the systems of equations are:

1. (2, 3) (see attachment below). [one solution]

2. no solution

3. (3, 13) [one solution]

The solution to a system of equations is the x-value and y-value that will make both equations true. It can be found either using a graph, by elimination method, or substitution method as explained below.

1. Using graph to solve y = 2x - 1 and y = 4x - 5:

The solution is the point where both lines intersect which is: (2, 3) (see attachment below). [one solution]

2. Solving using substitution method:

x = -5y + 4 ---> eqn. 1

3x + 15y = -1 ---> eqn. 2

Substitute x = -5y + 4 into eqn. 2

3(-5y + 4) + 15y = -1

-15y + 12 + 15y = -1

-15y + 15y = -1 - 12

0 = -13 (this shows that there is no solution)

3. Using elimination method:

14x = 2y + 16 ---> eqn. 1

5x = y + 2 ---> eqn. 2

1(14x = 2y + 16)

2(5x = y + 2)

14x = 2y + 16 ----> eqn. 3

10x = 2y + 4 -----> eqn. 4

Subtract

4x = 12

x = 12/4

x = 3

Substitute x = 3 into eqn. 2

5(3) = y + 2

15 = y + 2

15 - 2 = y

13 = y

y = 13

The solution is: (3, 13).

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Domain of f(x) is {x | x ≠ 6} and Domain of g(x) is {x | x ≠ +7 and x ≠ +7}.

The domain of a function is the set of all input values that make the function possible.

Now, for f(x) = (x + 6)/(x² - 12x + 36)

To find the domain, we equate the denominator to zero to find the numbers that can't be a domain. Thus;

x² - 12x + 36 = 0

Solving this using quadratic formula gives; x = 6. Thus, domain of f(x) is;

Domain = {x | x ≠ 6}

Now, for g(x) = (x + 7)/(x² - 49)

To find the domain, we equate the denominator to zero to find the numbers that can't be a domain. Thus;

x² - 49 = 0

Solving this using quadratic formula gives; x = +7 or -7. Thus, domain of g(x) is; Domain = {x | x ≠ +7 and x ≠ +7}

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Answer:

u should subract those not add

The number would you add to both sides of x² + 7x = 4 to complete the square option C 7²/2.

Suppose the considered quadratic equation is of the form

ax^2 + bx + c = 0

Then, completing the squares method tries to make a squared term in terms of x in the left side, so that x comes in linear form, instead of quadratic.

The given quadratic equation is

x² + 7x = 4

add  7²/2 to both sides of x² + 7x = 4 to complete the square

7²/2 = 49/4

x² + 7x + 49/4 = 4+ 49/4

(x + 7/2)² = 4+ 49/4

Thus, option C 7²/2 is correct.

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