4) Jenee made a 99, 86, 76, and 95 on her first four spelling tests. Her mother told her
that her spelling test average had to be a 91 for Jenee to get a new video game. What
does Jenee need to make on her next test?

Answer:

$-69.94

Step-by-step explanation:

Amount left after the withdrawal to fix the furnace = $400.56 - $450.50 = $-49.94

He has a negative balance for 4 days. this would attract a 5 dollar fee per day. the total fee would be $20 ( 5 x 4)

Total amount left in his account = $-49.94 - $20

Answer:

x is 5

Step-by-step explanation:

You want math problems???

Answer:

Hᴇʏᴀᴀᴀ!! ᴍʏ ɴᴀᴍᴇ ɪꜱ ᴘɪɴᴋʏ ᴀɴᴅ ɪ ᴀᴍ ʜᴇʀᴇ ᴛᴏ ᴀɴꜱᴡᴇʀ ʏᴏᴜʀ Qᴜᴇꜱᴛɪᴏɴ!!ʕ ꈍᴥꈍʔ☆

Step-by-step explanation:

ɪ ᴅᴏɴ'ᴛ ʀᴇᴀʟʟʏ ʟɪᴋᴇ ᴍᴀᴛʜ ʙᴜᴛ ɪꜰ ɪ ʜᴀᴅ ᴛᴏ ᴄʜᴏᴏꜱᴇ ᴀ ꜰᴀᴠᴏʀɪᴛᴇ ɪᴛ ᴡᴏᴜʟᴅ ʙᴇ ᴀʟɢᴇʙʀᴀ!!  (◕ᴗ◕✿)

  ʜᴀᴠᴇ ᴀɴ ᴀᴍᴀᴢɪɴɢ ɴɪɢʜᴛ ᴏʀ ᴅᴀʏ!

      *:･ﾟ✧*:･ﾟꜰʀᴏᴍ ʏᴏᴜʀ ᴏɴᴇ ᴀɴᴅ ᴏɴʟʏ ᴘɪɴᴋʏ  ʕ ﾟ ● ﾟʔ✧✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ

Answer:

I think 12 is 5he right answer

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

The measure of ∠3 is 96° and measure of ∠4 is 64°.

What is Triangle?

A triangle is a three sided polygon , which has three vertices and three angles with sum 180 degree.

Given that;

In triangle,

Measure of first angle (m ∠1 ) = 43°

Measure of second angle (m ∠2) = 41°

Let measure of ∠4 = x degree

Now, Sum of all angles in a triangle be 180 degree.

So, We can formulate;

m∠1 + m∠2 + m∠3 = 180°

43° + 41° + x = 180°

84° + x = 180°

x = 180° - 84°

x = 96°

So, measure of ∠3 = 96°

Since, The measure of ∠3 and measure of ∠4 are supplementary angles.

Hence, We get;

m ∠3 + m ∠4 = 180°

96° + m ∠4 = 180°

m ∠4 = 180° - 96°

m ∠4 = 64°

Thus, The measure of ∠3 is 96° and measure of ∠4 is 64°.

Learn more about the supplementary angle visit:

https://brainly.com/question/17706490

#SPJ2

Answer:

60%

Step-by-step explanation:

5 hours - 100%

1 hour - 100/5 = 20%

3 hours - 20 x 3 = 60%

Answer:

P

[tex] \alpha [/tex]

1/q²

P=k/Q²

K=P×Q²

Where P=9

Q=8

K=?

K=9×8²

K=9×64

K=573

So where K= 573

Q=3

P=?

P=K/Q²

P=573/3²

P=573/9

P=63.67

Answer:

8/56

Step-by-step explanation:

Add up all other marble colors then find the difference from the total.

Answer:

1/7

Step-by-step explanation:

there are 8 green marbles out of 56 so the probability would be 8/56 which simpliefies to 1/7 or 14.285714%

Answer: (6,8)

Step-by-step explanation:

Answer:

(6, 8)

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

Not correct

Step-by-step explanation:

Given:

x² - 6x - 7 = 0

The following equation can be solved correctly by factoring Thus,

x² - x + 7x - 7 = 0

x(x - 1) +7(x - 1) = 0

(x - 1)(x + 7) = 0

(x - 1) = 0

x - 1 = 0

x - 1 + 1 = 0 + 1

x = 1

Or

(x + 7) = 0

x + 7 = 0

x + 7 - 7 = 0 - 7

x = -7

Therefore, the solution would be x = 1 or x = -7

Lateena solution is therefore NOT CORRECT because she used a wrong method.

Answer:

B

Step-by-step explanation:

MOVE TO THE RIGHT 9 TIMES!!

With this prism, first separate it into a rectangular prism and a right triangle prism.

First, with the rectangular prism, it would have the units 5 * 5 * 6.3. Then with the right triangle prism, it would take the rest of the remaining space of it, being 3 * 5 * 6.3

The equation for the volume of a rectangular prism is L*W*H and the equation for the volume of a right triangle prism is (L*W*H) / 2.

With this, plug the numbers in for both prisms to get the volume of each of them:

Rectangular prism Volume

5*5*6.3

157.5

Right triangle prism Volume

(3*5*6.3) / 2

94.5 / 2

47.25

Lastly, combine these two values to get the total volume:

157.5 + 47.25 = 204.75 (Round Up) -->

204.8 cm^3 = Total Volume

Next, with the surface area of the prism. For this, lets combine all of the faces of the prism then add them all up.

First, lets do the bottom of the prism, or the base. It uses the lengths 8 cm and 6.3 cm. Lets do L * W to get the area of this face:

8 * 6.3 = 50.4

Next, lets do the slant side of it, which has the lengths 5.8 and 6.3.

5.8 * 6.3 = 36.54

Then, the top side with the lengths 5cm and 6.3 cm.

5.3 * 6.3 = 33.39

After that, the left side face that opposite to the slantly one:

5 * 6.3 = 31.5

Saving the most tedious part of it for last, the right trapezoids. Luckily, there is an equation for this:

1/2 x (Sum of parallel sides) x (perpendicular distance between the parallel sides).

So, within each of these right trapezoids, there's the parallel sides of 5 and 8. There's also a perpendicular side of 5cm. With this, we can plug this into the equation to solve for this part:

1/2 x (5+8) * (5)

1/2 x (13) * (5)

1/2 x (65)

32.5

Since there's two of them, times this by 2:

32.5 * 2 ---> 65.

Now, with the area of all of the faces, these can be added up for the total surface area:

50.4 + 36.54 + 33.39 + 31.5 + 65 ---> 216.83 (Round Down)-->

216.8 cm^2 = Total Surface Area

Answer:

Volume of salt shaker  = 42.4 cm³ (Approx.)

Step-by-step explanation:

Given:

Height of salt shaker = 5 cm

Diameter of salt shaker = 3 cm

Find:

Volume of salt shaker

Computation:

Radius of salt shaker = Diameter of salt shaker / 2

Radius of salt shaker  = 3 / 2

Radius of salt shaker = 1.5 cm

Volume of salt shaker  = Volume of cylinder + Volume of Hemisphere

Volume of salt shaker  = πr²h + (2/3)πr³

Volume of salt shaker  = (3.14)(1.5)²(5) + (2/3)(3.14)(1.5)³

Volume of salt shaker  = (3.14)(2.25)(5) + (0.667)(3.14)(3.375)

Volume of salt shaker  = 35.325 + 7.068

Volume of salt shaker  = 42.4 cm³ (Approx.)

Answer:

[tex]Total = 38^7[/tex]

Step-by-step explanation:

Given

[tex]Plate\ Number = 7\ characters[/tex]

[tex]Letters \to 26[/tex] [tex]\to [A- Z][/tex]

[tex]Numbers \to 10[/tex] [tex]\to [0 - 9][/tex]

[tex]Dash \to 1[/tex] [tex]\to [ - ][/tex]

[tex]Ampersand \to 1[/tex] [tex]\to [\&][/tex]

Required

Number of possible characters

Since the order and ways of selecting each character is not selected, then it means that any of the permissible character can occupy any of the 7 available spaces, with repetition.

The total possible characters (n) is:

[tex]n = 26 +10 + 1 + 1[/tex]

[tex]n = 38[/tex]

Any of the 38 characters can occupy any of the 7 spaces.

Hence, the total number of character is:

[tex]Total = n^7[/tex]

[tex]Total = 38^7[/tex]

Answer:

B

Step-by-step explanation:

Its really not hard. Just look at the chart. Find the 96 in the chart. What is it under? Flowers ordered. Which flower? Petunias. So its B. I'm sure you could have figured that out on your own. Not being rude, just telling you.

Answer: five and a half weeks.

Step-by-step explanation: 20 times 2 (the twice a week deposit) = 40. 220 (the negative checking) divided by 40 (the deposits each week) equals 5.5

Answer:

D. 0.62

Step-by-step explanation:

I calculated it logically

Answer:

2.25, or 2 1/4 or 9/4.

Step-by-step explanation:

3/4 times 3 = 9/4

Answer:

55.5 is the I guess........

Answer:

OMG

Step-by-step explanation:

I had the same question

Answer:

$10.79

Step-by-step explanation:

x =  original cost of one t shirt

We can build this equation

x - (20/100) x + 3x- 5 = 36

-1/5x + 4x = 41

-x + 20x = 205

19x  = 205

x = $10.79

Answer: D, All of the above

Step-by-step explanation:

Answer:

[tex] \displaystyle \angle2 = {49}^{ \circ} [/tex]

Step-by-step explanation:

remember that,

if a side of a triangle is extended then exterior angle so formed equal to the sum of the two opposite interior angles

thus our equation is

[tex] \displaystyle \angle2 + {86}^{ \circ} = {135}^{ \circ} [/tex]

cancel out 86° from both sides:

[tex] \displaystyle \angle2 = {49}^{ \circ} [/tex]

hence,

the measure of the missing angle is 49°

Answer:

Solution given'

<2+45+86=180°[sum of interior angle of a triangle]

<2=180-131

<2=49°

9 × 8 = 8 × 9 equation is true

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.