Here's link to the answer:
bit.[tex]^{}[/tex]ly/3a8Nt8n
what's a rational number between 13 and 21
Answer:
21
Step-by-step explanation:
7. Which equation can be used to find V, the
volume of the triangular prism in cubic feet?
6
17
10
Answer:
V = 1/3 x base x height
A small bar of gold measures 20 mm by 250 mm by 2 mm. One cubic millimeter of gold weighs about
0.0005 ounces. Find the volume in cubic millimeters and the welght in ounces of this small bar of gold.
cubic millimeters and the weight of the bar is
The volume of the bar is
ounce(s).
Answer: 5 ounces
Step-by-step explanation:
volume is 20*250*2=10000 cubic mm
10,000*0.0005=5
find the area of the kite
Answer:
396
Step-by-step explanation:
The courtyard outside East Middle School is in the shape of a rectangle and half-circle.
What is the approximate area of the courtyard?
Answer:
The correct option is the third one counting from the top. (5892 m^2)
Step-by-step explanation:
First, we need to remember that:
For a rectangle of length L and width W, the area is:
A = L*W
For a circle of diameter D, the area is:
A = pi*(D/2)^2
Where pi = 3.14
In the image, we can see a rectangle and half a circle, the total area of the image will be equal to the area of the rectangle plus the area of the half circle.
In the image, we can see a rectangle of length L = 100m and width W = 50m
Then the area of the rectangle is:
A = 100m*50m = 5000m^2
And we can see that for the half-circle the diameter is D = 50m
Note that the area of a half-circle is half of the area of a complete circle, then the area of that half-circle is:
A = (1/2)*(3.14*(50m/2)^2) = 981.25 m^2
If we add these two areas we get:
Total area = 5000m^2 + 981.25 m^2 = 5981.25 m^2
If we round it up, we get:
Total area = 5982 m^2
The correct option is the third one counting from the top.
Please help .. would be appreciated
Answer:
x = 30
Step-by-step explanation:
[tex] \triangle JLK\sim\triangle PQR[/tex] (given)
[tex] \therefore \frac{JL}{PQ}=\frac{LK}{QR} [/tex]
(corresponding sides of similar triangles)
[tex] \therefore \frac{20}{x}=\frac{22}{33} [/tex]
[tex] \therefore \frac{20}{x}=\frac{2}{3} [/tex]
[tex] \therefore x=\frac{20\times 3}{2} [/tex]
[tex] \therefore x=\frac{60}{2} [/tex]
[tex] \therefore x=30 [/tex]
Or using scale factor:
Scale factor = 33/22 = 3/2
x = 20*3/2
x = 10*3
x = 30
What is the perimeter of a square with side length: 3 cm Do not include units (cm) in your answer. I also will be reporting any links as answers
Answer:
perimeter of a square is 3 + 3 + 3 + 3 = 12 (cm)
Step-by-step explanation:
Or use the formula P = 4a = 4(3) = 12 (cm)
Which graph represents an exponential function?
Help me? Product of a sum and a difference
Formula; (a + b)(a - b) = a^2 - b^2
Find the product of the following
1. (2x - 5)(2x + 5)
2. (5b - 6y)(5b + 6y)
3. (4k + 7)(4k - 7)
4. (y - 5)(y + 5)
5. (3x - 2)(3x + 2)
6. (13x + 2x^3)(13x - 2x^3)
7. (2a + 1)(2a - 1)
8. (9y^2 + 8)(9y^2 - 8)
Step-by-step explanation:
hey, hope this helps. :)
Answer:
The solution is 6-->4-->9-->7-->1
Step-by-step explanation:
Part A
What are the possible outcomes of rolling a six-sided die?
Answer:
the possible outcomes are :
one (1)two (2)three (3)four (4)five (5)six (6)Which graph shows a dilation?
Answer:
Step-by-step explanation:
Sorry but im struggling with this too :(
Simplify.
Remove all perfect squares from inside the square root. Assume x is positive.
√ 20x^8
Can someone help me pls
Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
The cost of 4 pounds of potatoes is $3.56. What is the constant of proportionality that relates the cost in dollars, y, to the number of pounds of potatoes, x? A $0.89 A $0.89 B $1.12 B $1.12 C $8.90 C $8.90 D $1.02
Answer:
A. $0.89
Step-by-step explanation:
To find the constant of proportionality, find the cost of one pound of potatoes
3.56/4
= 0.89
So, the constant of proportionality is $0.89
The correct answer is A. $0.89
Can someone help me please!
9514 1404 393
Answer:
B, C, E
Step-by-step explanation:
Distributing the minus sign in the given expression results in ...
6x +1 -3x -(-1)
6x +1 -3 +1 . . . . simplify
The two expressions that show the constant terms as +1 - 1 are erroneous. The two constant terms are +1 -(-1) or +1 +1.
The correct expressions are the 2nd, 3rd, and 5th ones (b, c, e).
What is the slope of the line that passes through the points (3, 4) and (0, -2)
Answer:
The slope is :
4-(-2)/0-3
4+2/-3
6/-3
-2
-2 is the slope
Plzzz guys help me ;( F(x)-mx+ b, f(-2)=3 and f(4)=1 , what is the value of m and b
Answer:
Plzzz guys help me ;( F(x)-mx+ b, f(-2)=3 and f(4)=1 , what is the value of m and
3) Emma has a loyalty card good for a 10% discount at her local pharmacy.
What would her total in dollars and cents be, after the discount and
before tax, if the total cost of all the items she wants to buy is $32.40?
Answer:
The price of the items before the discount was $36.
Step-by-step explanation:
Since Emma has a loyalty card good for a 10% discount at her local pharmacy, to determine what her total in dollars and cents be, after the discount and before tax, if the total cost of all the items she wants to buy is $ 32.40, the following calculation must be made:
100 - 10 = 90
90 = 32.40
100 = X
100 x 32.40 / 90 = X
3240/90 = X
36 = X
Therefore, the price of the items before the discount was $ 36.
An apartment complex stretched a string of decorative floats diagonally across a
rectangular pool. The width of the pool is 15 ft and the length of the pool is 20 ft.
What is the length of the a diagonal that the floats are stretched across ?
Answer:
25 feet
Step-by-step explanation:
Use the pythagorean theorem, where the width and length of the pool are the legs of the triangle.
Solve for c, the hypotenuse/diagonal
a² + b² = c²
15² + 20² = c²
225 + 400 = c²
625 = c²
25 = c
So, the length of the diagonal is 25 feet
200000*900000= what HELP PLEASE
I'll mark brainliest
Answer:
Step-by-step explanation:
1.8E11 is the correct answer
Answer:
200000*900000= 180000000000
Step-by-step explanation:
:))
PLEASE HELP!!! I GIVE 15 POINTS!
Flaws in a carpet tend to occur randomly and independently at a rate of one every 260 square feet. What is the probability that a carpet that is 7 feet by 14 feet contains no flaws?
Probability =
Enter your answer in terms of e.
Answer:
The probability that a carpet that is 7 feet by 14 feet contains no flaws is 99.996%.
Step-by-step explanation:
Given that flaws in a carpet tend to occur randomly and independently at a rate of one every 260 square feet, to determine what is the probability that a carpet that is 7 feet by 14 feet contains no flaws, the following calculation must be performed:
7 x 14 = 98
1/260 = 0.003
98 = 100
0.003 = X
0.003 x 100/98 = X
0.0039 = X
100 - 0.0039 = 99.996
Thus, the probability that a carpet that is 7 feet by 14 feet contains no flaws is 99.996%.
Calculus helpppppppppppppppp
Answer:
[tex]\displaystyle y' = \frac{5x^2 + 3}{3(1 + x^2)^\bigg{\frac{2}{3}}}[/tex]
General Formulas and Concepts:
Pre-Algebra
Equality PropertiesAlgebra I
FunctionsFunction NotationExponential Rule [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Algebra II
Logarithms and Natural LogsLogarithmic Property [Multiplying]: [tex]\displaystyle log(ab) = log(a) + log(b)[/tex]Logarithmic Property [Exponential]: [tex]\displaystyle log(a^b) = b \cdot log(a)[/tex]Calculus
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Logarithmic Derivative: [tex]\displaystyle \frac{d}{dx} [lnu] = \frac{u'}{u}[/tex]
Implicit Differentiation
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = x\sqrt[3]{1 + x^2}[/tex]
Step 2: Rewrite
[Equality Property] ln both sides: [tex]\displaystyle lny = ln(x\sqrt[3]{1 + x^2})[/tex]Logarithmic Property [Multiplying]: [tex]\displaystyle lny = ln(x) + ln(\sqrt[3]{1 + x^2})[/tex]Exponential Rule [Root Rewrite]: [tex]\displaystyle lny = ln(x) + ln \bigg[ (1 + x^2)^\bigg{\frac{1}{3}} \bigg][/tex]Logarithmic Property [Exponential]: [tex]\displaystyle lny = ln(x) + \frac{1}{3}ln(1 + x^2)[/tex]Step 3: Differentiate
ln Derivative [Implicit Differentiation]: [tex]\displaystyle \frac{d}{dx}[lny] = \frac{d}{dx} \bigg[ ln(x) + \frac{1}{3}ln(1 + x^2) \bigg][/tex]Rewrite [Derivative Property - Addition]: [tex]\displaystyle \frac{d}{dx}[lny] = \frac{d}{dx}[ln(x)] + \frac{d}{dx} \bigg[ \frac{1}{3}ln(1 + x^2) \bigg][/tex]Rewrite [Derivative Property - Multiplied Constant]: [tex]\displaystyle \frac{d}{dx}[lny] = \frac{d}{dx}[ln(x)] + \frac{1}{3}\frac{d}{dx}[ln(1 + x^2)][/tex]ln Derivative [Chain Rule]: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot \frac{d}{dx}[(1 + x^2)][/tex]Rewrite [Derivative Property - Addition]: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot \bigg( \frac{d}{dx}[1] + \frac{d}{dx}[x^2] \bigg)[/tex]Basic Power Rule]: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot (2x^{2 - 1})[/tex]Simplify: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot 2x[/tex]Multiply: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{2x}{3(1 + x^2)}[/tex][Multiplication Property of Equality] Isolate y': [tex]\displaystyle y' = y \bigg[ \frac{1}{x} + \frac{2x}{3(1 + x^2)} \bigg][/tex]Substitute in y: [tex]\displaystyle y' = x\sqrt[3]{1 + x^2} \bigg[ \frac{1}{x} + \frac{2x}{3(1 + x^2)} \bigg][/tex][Brackets] Add: [tex]\displaystyle y' = x\sqrt[3]{1 + x^2} \bigg[ \frac{5x^2 + 3}{3x(1 + x^2)} \bigg][/tex]Multiply: [tex]\displaystyle y' = \frac{(5x^2 + 3)\sqrt[3]{1 + x^2}}{3(1 + x^2)}[/tex]Simplify [Exponential Rule - Root Rewrite]: [tex]\displaystyle y' = \frac{5x^2 + 3}{3(1 + x^2)^\bigg{\frac{2}{3}}}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Implicit Differentiation
Book: College Calculus 10e
Junior's brother is 1 1/2
meters tall. Junior is 1 1/5
of his brother's height.
How tall is Junior?
Answer:
Step-by-step explanation:
1 1/5 of 1 1/2 meters
= (1+1/5) x (1+1/2)
= 1x1 + 1x1/2 + 1x1/5 + 1/5*1/2
= 1 + 1/2 + 1/5 + 1/10
= 1 + (1x5+1x2+1)/10
= 1 8/10
= 1 4/5 meters
Answer:
1 4/5 meters
Step-by-step explanation:
1 1/5 of 1 1/2 meters
= (1+1/5) x (1+1/2)
= 1x1 + 1x1/2 + 1x1/5 + 1/5*1/2
= 1 + 1/2 + 1/5 + 1/10
= 1 + (1x5+1x2+1)/10
= 1 8/10
= 1 4/5 meters
Can someone help me? Becks?
Answer:
Perimeter = 72
Step-by-step explanation:
Notice that the adjacent (next to) lengths by each corner are equal in length.
This occurs when the quadrilateral is circumscribed.
Since 4.2 is adjacent to the length which makes up the total side 20.
20 – 4.2 = 15.8.
And 15.8 + 4.2 = 20.
(7 + 9) + (9 + 4.2) + (4.2 + 15.8) + (15.8 + 7) =
(16) + (13.2) + (20) + (22.8) =
(16 + 20) + (13.2 + 22.8) =
36 + 36 =
72
2. The angles of a pentagon are 6x, (2x + 20°),(3x - 20%), 2x and 14x. Find x. Please answer please please
Answer:
x=20
Step-by-step explanation:
What is 1.23625 rounded to the nearest cent?
Answer:
1.24
Step-by-step explanation:
8. Daren and Josh are pretty good free throw shooters. Daren makes 75% of the
free throws he attempts. Josh makes 80% of his free throws. Suppose we take
separate random samples of 50 free throws each from Daren and Josh, and
record the proportion of free throws that are made by each. Which of the
following best describes the sampling distribution of PD - Pj?
Answer:
B) Approximately normal, with mean -0.05 and standard deviation 0.083
Step-by-step explanation:
The correct answer is (B). The shape is approximately normal since the expected number of makes and misses for both Daren and Josh are all greater than 10.
The distribution of pD = pJ is given by: Option B: Approximately normal, with mean -0.05 and standard deviation 0.083
What is the distribution of population proportion?For large enough sample, let the population proportion of a quantity be denoted by random variable [tex]p[/tex]
Then, we get:
[tex]p \sim N(\hat{p}, \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}})[/tex]
where
[tex]\hat{p}[/tex] = estimated(mean value) proportion of that quantity, and n = size of sample drawn.Suppose that a random variable X is formed by n mutually independent and normally distributed random variables such that:
[tex]X_i = N(\mu_i , \sigma^2_i) ; \: i = 1,2, \cdots, n[/tex]
And if
[tex]X = X_1 + X_2 + \cdots + X_n[/tex]
Then, its distribution is given as:
[tex]X \sim N(\mu_1 + \mu_2 + \cdots + \mu_n, \: \: \sigma^2_1 + \sigma^2_2 + \cdots + \sigma^2_n)[/tex]
Here, we're specified that:
For proportion of correct free throw attempts by Daren:
Sample size = n = 50Estimated proportion = [tex]\hat{p}_D = 75\% = 0.75[/tex]Let the population proportion be represented by variable [tex]p_D[/tex]For proportion of correct free throw attempts by Josh:
Sample size = n = 50Estimated proportion = [tex]\hat{p}_J = 80\% = 0.8[/tex]Let the population proportion be represented by variable [tex]p_J[/tex]And therefore, we have:
[tex]p_D \sim N\left (0.75, \sqrt{\dfrac{0.75 \times 0.25}{50}}\right )\\\\p_J \sim N\left (0.80, \sqrt{\dfrac{0.8 \times 0.2}{50}}\right )[/tex]
And therefore, we get:
[tex]-p_J \sim N\left (-0.80, \sqrt{\dfrac{0.8 \times 0.2}{50}}\right )[/tex] (standard deviation doesn't get affected by change of sign of the considered random variable, and mean gets affected linearly, so mean became negative 0.80 and standard deviation stays same).
Adding [tex]p_D[/tex] and [tex]-p_J[/tex], we get:
[tex]p_D + (-p_J) = p_D - p_j \sim N\left (0.75 -0.80, \sqrt{\dfrac{0.8 \times 0.2}{50} + \dfrac{0.75 \times 0.25}{50}}\right )\\\\p_D - p_J \sim N\left( -0.05, 0.0837\right)[/tex]
Thus, the distribution of pD = pJ is given by: Option B: Approximately normal, with mean -0.05 and standard deviation 0.083
Learn more about population proportion here:
https://brainly.com/question/7204089
PLEASEEE HELP PLS ASAPPP GIVING BRAINLIEST!!!!
Answer:
50 is the answer brainliest?
Step-by-step explanation:
Leonard wrote the sequence of numbers below. 9, 15, 21, 27,... Which expression did be use to form the sequence, where n is the term number?
A 3n + 3
B 3n - 3
C 6n+3
D 6n-3
Answer:
I think they took 3 * 3 is equals to 9
3 * 5 equals to 15
3 * 7 equals to 21
and 3 * 9 equals to 27.
Step-by-step explanation:
can can you realise that they skipped 3 * 4 3 * 6 and 3 * 8 and the difference between 9 and 15 is 6 meaning there's a gap of 6 at each sequence so I guess my answer is 3 and + 3 if it's not if this is not the answer please tell me if it is not matching with your book tell me so that i can ask the people around me. answer 3n + 3
Hauls Vegetable Market has the folloeing vegetables for sale.
Carrots cost 3.50$ per pound
Cucumbers cost 0.69$ per pound
Squash cost 2$ per pound
What will be the ckst for 2 1/2 pounds of carrots and 3/4 pound of squash cost
Answer:
The cost of 2 1/2 pounds of carrots and 3/4 pound of squash is $ 10.25.
Step-by-step explanation:
Since Hauls Vegetable Market sells carrots that cost $ 3.50 per pound, cucumbers that cost $ 0.69 per pound, and squash that cost $ 2 per pound, to determine what will be the cost for 2 1/2 pounds of carrots and 3/4 pound. of squash the following calculation must be performed:
1/2 = 0.5
3/4 = 0.75
Carrots: 3.50 x 2.5 = 8.75
Squash: 2 x 0.75 = 1.50
8.75 + 1.50 = 10.25
Thus, the cost of 2 1/2 pounds of carrots and 3/4 pound of squash is $ 10.25.