Which quantity is a vector quantity?
A.
displacement
B.
distance
C.
mass
D.
temperature
E.
volume

Answers

Answer 1

Explanation:

displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.


Related Questions

Sian wants to measure the number of seconds that it takes for the contents of a beaker to change from clear to purple. which of these tools should she use for this purpose? an electronic balance a stopwatch a barometer a graduated cylinder

Answers

Sian wants to count the number of seconds it takes for a beaker's contents to become purple from clear. She should utilize a stopwatch as her instrument for this job.

What is a stopwatch?

Watch that, when turned on and off, measures the amount of time that has passed since a specific time.

Sian wants to measure the number of seconds that it takes for the contents of a beaker to change from clear to purple. Stopwatch is the tool she should utilize for this purpose.

Hence, option B is correct.

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Answer: Sian wants to count the number of seconds it takes for a beaker's contents to become purple from clear. She should utilize a stopwatch as her instrument for this job.

option b

Explanation:

Which best describes deena’s error? the line for constant velocity is not horizontal; it is diagonal and slopes downward. the area of the rectangle and the triangle under the line should be added together for constant acceleration find acceleration by finding the area of the rectangle above the line. find velocity by calculating the slope of the line.

Answers

The statement best describes deena's error is: Find acceleration by finding the area of the rectangle above the line.

What is acceleration?

Acceleration is given by the ratio of Resultant or total force acting on any object and the its mass.

Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with constant velocity.

In the  velocity time graph, the area under the curve shows the displacement of the object and the slope represents the acceleration.

Thus, the deena's error is  Find acceleration by finding the area of the rectangle above the line.

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Answer:

What the other dude said

Explanation:

The source of all magnetic fields is:
- moving charges
- the earth's gravity
- the aurora borealis
- solar fields

Answers

Answer:

Moving charges

Explanation:

The source of all magnetic fields is moving electric charge: whether it is current in a wire, unpaired electrons in an atomic orbital, convection currents in the earth's liquid nickle /iron core, plasma in the sun, etc. moving electric charge is the source of all magnetic fields.

Which of the following desribes a displacement vs. time graph that looks like
this?
Time
A. constant non-zero acceleration
B. increasing velocity
C. constant velocity
D. decreasing acceleration

Answers

It would a constant non-zero acceleration because acceleration (the second derivative of position) is what determines concavity, and if it is positive, the graph of position/displacement will be concave UP. The acceleration is constant, so velocity is increasing at a constant rate. Therefore, position would be increasing at an exponential rate.

Two astronauts are taking a spacewalk outside the International Space Station. The first astronaut has a mass of 85.2 kg. The second has a mass of 65.4 kg. Initially, both astronauts have zero velocity relative to each other. Then, the astronauts push against each other, giving the first astronaut a final velocity of 1.2 m/s to the left. If the momentum of the system is conserved, what is the final velocity of the second person?
A. 1.3 m/s to the left
B. 1.6 m/s to the right
C. 1.6 m/s to the left
D. 1.3 m/s to the right

Answers

The final velocity of the second person after the collision is determined as 1.6 m/s to the right.

Final velocity of the second person

The final velocity of the second person is determined by applying the principle of conservation of linear momentum.

m1u1 + m2u2 = m1v1 + m2v2

85.2(0) + 65.4(0) = 85.2(-1.2) + 65.4(v2)

0 = -102.24 + 65.4v2

65.4v2 = 102.24

v2 = 1.56 m/s to the right

Thus, the final velocity of the second person after the collision is determined as 1.6 m/s to the right.

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The centers of two 350 kg spheres are separated by 2.00 m. what is the gravitational force between them?

Answers

The gravitational force between them is 3000 gravity’s

V=I/R correctly expresses the relationship between voltage, current, and resistance.

True or False?

Answers

The correct answer is true

Answer:

False

Explanation:

It is actually I = V/R and V = I × R

A crane does exactly 1800 J of work to lift a steel beam from the ground. The beam is accidentally dropped and falls back to its starting position in 0.9 s. What is the mass of the beam

Answers

Answer:

Explanation:

1800x0.9=1620kg

A man pushes a shopping cart full of groceries at a constant velocity. What happens if the man DECREASES the force of his push on the cart?

A. The cart slows down.
B. The cart speeds up.
C. The cart moves at the same speed.
D. The cart becomes less massive.

Answers

If the man DECREASES the force of his push on the cart, the cart slows down.

Force acting on body

The force applied to an object is determined by applying Newton's second law of motion.

F = ma

where;

m is mass of the bodya is acceleration of the body

a = Δv/t

F = (mΔv)/t

mΔv = Ft

Δv = Ft/m

From the equation above, when the applied force decreases, the change in velocity decreases.

Thus, if the man DECREASES the force of his push on the cart, the cart slows down.

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Three objects have velocities that vary with time

Answers

#21

initial velocity=u=5m/sTime=t=2sAcceleration=a=1.3m/s²

According to first equation of kinematics

v=u+atv=5+1.3(2)v=5+2.6v=7.6m/s

#22

#a

v1=2+3(3)=2+9=11m/sv2=-8-4(3)=-20m/sv3=1-5(3)=-14m/s

The order is

v2<V3<v1

#b

for speed find absolute velocity

S1=|11|=11m/sS2=|-20|=20m/sS3=|-14|=14m/s

So order is

S1<S3<S2

Answer:

See below ~

Explanation:

Question 21 :

⇒ v = u + at

⇒ v = 5 + 1.3 (2)

⇒ v = 5 + 2.6

⇒ v = 7.6 m/s

=============================================================

Question 22 : At t = 3

Subpart (a)

⇒ Object 1 : v = 2 + 3(3) = 11 m/s

⇒ Object 2 : v = -8 - 4(3) = -20 m/s

⇒ Object 3 : v = 1 - 5(3) = -14 m/s

⇒ Hence, their velocities are in the order : Object 2 < Object 3 < Object 1

Subpart (b)

⇒ Object 1 : v = | 2 + 3(3) | = 11 m/s

⇒ Object 2 : v = | -8 - 4(3) | = 20 m/s

⇒ Object 3 : v = | 1 - 5(3) | = 14 m/s

⇒ Hence, their speeds are in the order : Object 1 < Object 3 < Object 2

An electromagnetic wave has a wavelength of 10 nm. Calculate its frequency and identify to which part of the electromagnetic spectrum the wave belongs.

Answers

The frequency of an electromagnetic wave with wavelength of 10nm will be 3 × 10∧7 Hz and would belong to the X-ray or ultraviolet part of the electromagnetic spectrum due to its wavelength

What is frequency?

Frequency is defined as the number of oscillations of a wave per unit time and is measured in hertz(Hz).

It is also inversely proportional to the wavelength.

How to calculate the frequency

The frequency of an electromagnetic wave can be calculated using the formula;

frequency = velocity of light divided by the wavelength

f = v ÷ λ

Note that the velocity of light = 3 × 10 ∧8 m/s

Wavelength = 10nm

Frequency, f = 3 × 10∧8 ÷ 10 = 3 × 10∧7 Hz

Hence, the frequency of an electromagnetic wave with wavelength of 10nm will be 3 × 10∧7 Hz and would belong to the X-ray or ultraviolet part of the electromagnetic spectrum due to its wavelength.

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Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time. Your challenge is to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.

Answers

The diagram is labelled to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.

What is refraction?

When a light ray falls on the interface of two medium like air and water, then the portion of light is reflected and another portion of the light is refracted into the water medium. The angle of incidence is equal to the angle of reflection but the angle of incidence is larger then the angle of refraction.

Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time.

Thus, the diagram is labelled.

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Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it completely and throws Sheila forward onto the pavement.

If there is no net force on the system, what is Sheila’s velocity immediately after she is thrown from the bike?

1.8 m/s
2.0 m/s
5.0 m/s
5.7 m/s

Answers

From the calculation, Sheila’s velocity immediately after she is thrown from the bike is 5.7 m/s.

What is momentum?

Momentum is the product of mass and velocity. We know that the momentum before collision is equal to the momentum after collision.

Hence;

Momentum before collision = 340 kg • m/s.

Momentum after collision = 60v

Thus;

340 kg • m/s = 60v  kg • m/s

v = 340 kg • m/s/60 Kg

v = 5.7 m/s

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Parallel light rays are refracted _______and_____ to a point called as focal point after passing through convex lens.

Answers

left and right to a point called ad focal point after passing through convex lens

An object is placed 14.0 cm from a diverging lens. If a virtual image appears 10.0 cm from the lens on the
same side as the object, what is the focal length of the lens?

Answers

Object distance=u=14cmImage distance=v=-10cm

Use lens formula

1/f=1/v-1/u1/f=1/-10-1/141/f=-7-5/701/f=-12/70f=70/-12f=-5.8cm

The focal length of the lens is 5.8 cm.

To find the focal length, the given values are:

Image distance - 10 cm

Object distance - 14 cm

What is focal length and how it was calculated?

      The distance between the convex lens or a concave mirror and the focal point of a lens or mirror is called the focal length. This is the parallel line which meet at the distance from the lens or mirror.

                1/Focal length = 1/Image distance + 1/Object distance ( cm )

                                    1/f = 1/v-1/u

                                    1/f = 1/-10-1/14

                                    1/f = -7-5/70

                                    1/f = -12/70

                                      f = 70/-12

                                      f = -5.8cm

The focal length of the lens is - 5.8 cm.

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A metal sign for a car dealership is a thin, uniform right triangle with base length b and height h. the sign has mass m.

required:
a. what is the moment of inertia of the sign for rotation about the side of length h?
b. if m = 4.40 kg ,b = 1.30 m and h = 1.30 m , what is the kinetic energy of the sign when it is rotating about an axis along the 1.30-m side at 2.40 rev/s ?

Answers

(a) The moment of inertia of the sign for rotation about the side of length h is 1.24 kgm².

(b) The kinetic energy of the sign when it is rotating about an axis is 141.37 J.

Moment of inertia of the triangular sign

The moment of inertia of the sign for rotation about the side of length h is calculated as follows;

I = 2 x ¹/₃M(b/2)²

I = 2 x ¹/₃Mb² x ¹/₄

I = ¹/₆Mb²

I = ¹/₆ x 4.4 x 1.3²

I = 1.24 kgm²

Rotational kinetic energy of the ball

K.E(rot) = ¹/₂Iω²

where;

ω is angular speed = 2.4 rev/s = 2.4 x (2π rad)/s = 15.1 rad/s

K.E(rot) = ¹/₂(1.24)(15.1)²

K.E(rot) = 141.37 J

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If it takes you 10 seconds to move a chair 5 meters across the floor, using a force of 2 Newtons, how much power did you put out?

20 joules per second

100 joules per second

O 1 joules per second

4 joules per second

Answers

Answer:

power=work done÷time taken

2×5=10

10÷10=1

ans 1J per second

-1 A 4m long wire of cross-sectional area 2.5 X 10 m² has a resistance of 5. The conductivity of the wire is (a) 2.5 X 10' m (b) 4.0 X 10' m (c) 2.5 X 10'' m¹ -1 -1 (d) 4.0 X 10''m'​

Answers

Answer:

3.2 [tex]10^{-2} ohm^{-1} m^{-1}[/tex]

Explanation:

Resistance=5 ohm

Length=4m

Cross sectional area=2.5 x 10

Conductivity = 1/ resistivity

                      =[tex]\frac{length}{resistance x cross sectional area}[/tex]

Conductivity=4 /5 x 2.5 x 10

Conductivity=4/125

Conductivity=3.2x[tex]10^{-2}[/tex][tex]ohm^{-1} m^{-1}[/tex]

The mass of a bicyclist and a bicycle together is 53.0 kg. How much work has been
done if the bicyclist slows the bicycle from a speed of 3.84 m/s to 1.27 m/s?
(A) -68.1 J
(B) -136 J
(C) -348 J
(D) -696 J

Answers

Answer:

Approximately [tex](-348\; {\rm J})[/tex], assuming that the bike was on level ground.

Explanation:

If an object of mass [tex]m[/tex] is moving at a speed of [tex]v[/tex], the kinetic energy of that object would be [tex](1/2)\, m\, v^{2}[/tex].

At a speed of [tex]v = 3.84\; {\rm m\cdot s^{-1}}[/tex], the kinetic energy of the bike and the cyclist- combined- would be:

[tex]\begin{aligned} &\frac{1}{2}\, m\, v^{2} \\=\; &\frac{1}{2}\times 53.0\; {\rm kg} \times (3.84\; {\rm m\cdot s^{-2}})^{2} \\ \approx \; & 390.76\; {\rm J}\end{aligned}[/tex].

At a speed of [tex]v = 1.27\; {\rm m\cdot s^{-1}}[/tex], the kinetic energy of the bike and the cyclist- combined- would be:

[tex]\begin{aligned} &\frac{1}{2}\, m\, v^{2} \\=\; &\frac{1}{2}\times 53.0\; {\rm kg} \times (1.27\; {\rm m\cdot s^{-2}})^{2} \\ \approx \; &42.741 \; {\rm J}\end{aligned}[/tex].

The energy change was approximately:

[tex]390.76\; {\rm J} - 42.741\; {\rm J} \approx 348\; {\rm J}[/tex].

If the bike was on level ground, the friction on the bike and the cyclist would have done a work of [tex](-348\: {\rm J})[/tex] to reduce the kinetic energy of the bike and the cyclist by that amount.

Answer: C) -348J

Explanation:

42.741 - 390.76 (the kinetic energy of the two speeds) is equal to -348.

i need help with this!!​

Answers

Answer:

183

Explanation:

Ohm's Law states that Resistance = Voltage / Current, so:

220/1.2 = 183.333

Gravitation always does negative work. question 48 options: true false

Answers

The statement indicating that 'Gravitation always does negative work' is FALSE.

What is Gravitation?

Gravitation is a fundamental physical force that makes objects attract each other in the Universe.

This force (Gravitation) is required to maintain both constant positions and movement of objects.

In conclusion, the statement indicating that 'Gravitation always does negative work' is FALSE.

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Answer:false

Explanation:

a carmboard 4ft x 4ft Square has the queen at the centre the queen is hit by the striker moves to the front edge, rebounds and goes inta hole behind the striking line. find the magnitude of displacement of queen a) from the centre to front edge b) from the front end edge to hole (c) from centre to hole.​

Answers

Diagonal of cardboard=displacement to hole

√4²+4²4√2

So displacement till edge

4√2/22√2

Total distance

4√2+2√26√2ft

From centre to hole displacement

2√2

What would happen if the atmosphere consisted of pure oxygen.

Answers

Answer:

Then our fires would become massive.

Explanation:

Hope this helps

4) An electron in a mercury atom changes from
energy level b to level e. This energy-level
change occurs as the atom.
(1) absorbs a 2.03-eV photon
(2) absorbs a 5.74-eV photon
(3) emits a 2.03-eV photon
(4) emits a 5.74-eV photon

Answers

The energy-level change occurs as the atom is absorbs a 2.03-eV photon.

Energy change of the mercury atom

The energy change of the mercury atom is calculated as follows;

Energy emitted by a photon when it falls from level b to energy level e is calculated as follows;

ΔE = -3.71 eV - (-5.74 eV)

ΔE =  -3.71 eV + 5.74 eV

ΔE = 2.03 eV

When electron jumps from  lower energy level to higher energy level, energy is absorbed, thus, the energy-level change occurs as the atom is absorbs a 2.03-eV photon.

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Maria throws two stones from the top edge of a building with a speed of 20 m/s. She throws one straight down and the other straight up. The first one hits the street in a time t1. How much later is it before the second stone hits

Answers

Maria throws two stones from the top edge of a building at a speed of 20 m/s, The time is mathematically given as

t=4.5 sec.

How much later is it before the second stone hits?

Generally, the equation for speed  is mathematically given as

V = u+at

Therefore

0 = 22-9.8xt.

t = 22 /9.8 sec

t = 2.24489.

The same time will be taken from max^m height to point O

The extra time is taken

t=4.49 sec.

t=4.5 sec.

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The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?

Answers

Answer:

4.0208 x 10^16 meters

Explanation:

speed of light in m/s   *      # seconds in a year      * 4.25 years =

2.99792 x 10^8   *        3600*24*365.25  *     4.25 = 4.0208 x 10^16 m

Under water, Zachary can hear waves that travel with frequencies up to 15,000 Hz. What is the velocity of sound in water if a wave with this frequency has a wavelength of 1.2 m?

Answers

Answer:

18 000 m/ s

Explanation:

speed = wavelength * frequency

speed =  1.2  * 15 000 = 18 000 m/s

uppose you are an astronaut and you have been stationed on a distant planet. You would like to find the acceleration due to the gravitational force on this planet so you devise an experiment. You throw a rock up in the air with an initial velocity of 6 m/s and use a stopwatch to record the time it takes to hit the ground. If it takes 6.8 s for the rock to return to the same location from which it was released, what is the acceleration due to gravity on the planet

Answers

Answer:

g = -3.143 m/s²

Explanation:

To determine acceleration due to the gravitational force, it can be used the following formula:

v = v₀ + gt, where:

v₀ is the initial velocity;

g is acceleration due to gravity

t is the time to return to the point of origin

In a hard disk drive, a constant torque of 14 N⋅m is applied to the magnetic disk when the drive starts recording data. The magnetic disk has a mass of 0.2 kg and radius 2m. Determine the magnitude of the angular acceleration of the disk? [please solve if you know]

Answers

The magnitude of the angular acceleration of the magnetic disk is determined as 35 rad/s².

Angular acceleration of the disk

The angular acceleration of the disk is determined from the principle of conservation of angular momentum as follows;

τ = Iα

where;

α is angular acceleration

I is moment of inertia of the disk

I = 0.5MR²

I = 0.5 x 0.2 x 2²

I = 0.4 kgm²

τ = Iα

α = τ/I

α = (14)/(0.4)

α = 35 rad/s²

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the yacht shown below has a mass of 8300kg. determine its weight in air [ Acceleration due to gravity, g = 10 N kg¹
[tex]w = mg [/tex]

Answers

Answer:

83000kg

Explanation:

mass=8300kg

g=10

w=mg

8300×10=83000kg

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