Which of the following linear functions have a y-intercept of 4? Select all that apply.
y = 4
x=4
Ug=2z 8
y=x+4
y=-2 +4

Step-by-step explanation:

Reflection in the x axis (x,y)—>(x,-y)

(-4,-3)—>(-4,3)

Answer:

 Numbers are 5 , 7

Step-by-step explanation:

  Let the two consecutive odd numbers be (2x + 1) and (2x + 3)

         Their product = 35

(2x + 1)(2x + 3) = 35

Use FOIL method.

       2x*2x + 2x*3  + 1*2x + 1*3 = 35

              4x² + 6x  + 2x + 3       = 35

      Combine like terms

                            4x² + 8x  + 3    = 35

                         4x² + 8x + 3 - 35 = 0

                            4x² + 8x  - 32   = 0

 Solving:

                 4x² + 8x - 32 = 0

Divide the entire equation by 2

                [tex]\sf \dfrac{4}{2}x^2 +\dfrac{8}{2}x - \dfrac{32}{2}=0[/tex]

                  2x² + 4x - 16 = 0

Sum = 4

Product = -32

Factors = 8 , (-4)

When we multiply 8*(-4) = -32 and when we add 8 + (-4) = 4.

Rewrite the middle term

2x² + 8x - 4x  - 16 = 0

 2x(x + 4) - 4(x + 4) = 0

   (x + 4) (2x - 4) = 0

2x - 4 = 0   {Ignore x +4 = 0  as it gives negative number}

2x = 4

   x = 4/2

   x= 2

2x + 1 = 2*2 + 1 = 5

2x + 3 = 2*2 +3 = 7

   The numbers are 5 , 7

Answer:

6

Step-by-step explanation:

We can think of the 10 black bags as 2 sets of 5-black bags (10 divided into groups of 5; 10 / 5 ; is 2 groups/sets). So, we would also have two sets of 3 (3 x 2 = 6), or 6 bags.

5 : 3 = 10 : 6

(multiply both numbers by 2)

Using proportions, it is found that the number of chaperones that the school needs is given by:

B. 8.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, 2 chaperones are needed for every 25 students. How many are needed for 100 students? The rule of three is given by:

2 chaperones - 25 students

n chaperones - 100 students

Applying cross multiplication:

25n = 2 x 100

n = 200/25

n = 8.

Hence option B is correct.

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Answer:

c

Step-by-step explanation:

edge 2023

The probability that event B occurs is 83%. Therefore, option C is the correct answer.

Dependent and independent variables are variables in mathematical modeling, statistical modeling and experimental sciences. Dependent variables receive this name because, in an experiment, their values are studied under the supposition or demand that they depend, by some law or rule, on the values of other variables.

Given that, events A and B are independent, and the probability that event A occurs is 83%.

If the outcome of one event has no bearing on the fate of the other, the two events are said to be independent events. Instead, we may say that an event is considered independent if it does not affect the likelihood of another event.

Since, the events A and B are independent, if the probability that event A occurs is 83%.

Then, the probability that event B occurs is 83%.

Therefore, option C is the correct answer.

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Answer:

-3(x+1)² + 2

Step-by-step explanation:

-3(x+1)² + 2 because the +2 indicates the y value of the turning point and the turning point is a maximum meaning the coefficient must be negative leaving this answer

let me answer the last one first

compound interest is just an exponential sequence really, where the next value is some exponential amount of the previous.

hmmm that can happen in say, a bouncing ball, the 1st bounce is high, let it keep on boucing by itself and the next bounce is usually a compounded value of the previous one, since it's smaller it'd be a Decay type of equation.

hmmm it also happens in say population growth, of any organism, humans, bees, amoebas.

now let's do the others

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3000\\ r=rate\to 2.6\%\to \frac{2.6}{100}\dotfill &0.026\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A=3000\left(1+\frac{0.026}{4}\right)^{4\cdot t}\implies \boxed{A=3000(1.0065)^t} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{after 15 years}}{t=15}\hspace{5em} A=3000(1.0065)^{15}\implies A\approx 3306.19 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3000\\ r=rate\to 2.6\%\to \frac{2.6}{100}\dotfill &0.026\\ t=years\dotfill &15 \end{cases} \\\\\\ A=3000e^{0.026\cdot 15}\implies A=3000e^{0.39}\implies A\approx 4430.94[/tex]

Mel did pass the class , Option B is the correct answer.

The missing options are

Mel does not like chemistry

Mel did pass the class

Mel did not achieve a passing grade for the class

Mel took math this semester

The statements that are based on fact and is assertive is a true statement and opposite of that is a false statement.

In the question it is mentioned that Mel received a C+ in Chemistry.

It is not known that she took maths test , she did achieve passing grades and by grades it cannot be said if she didn't like chemistry

This can make only Option B statement true , as she did pass the class.

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The exercise is designed to test the students knowledge of prepositions. The correct answer thus is (Option D) Yo estudio (which translates) "I study".

To understand the answer, you need to know what a preposition is. A preposition, in simple terms, is a word or group of words that comes before a noun.

The function of a preposition (much like an adjective) is to give clarity to the noun that it precedes.

Let us complete the Preposition phrase to give meaning to it:

"I study Mathematics". Where;

"Mathematics" is the noun;

"I Study" is the prepositional phrase. Hence the correction answer to the question above is Option D.

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Since both α and β are in the first quadrant, we know each of cos(α), sin(α), cos(β), and sin(β) are positive. So when we invoke the Pythagorean identity,

sin²(x) + cos²(x) = 1

we always take the positive square root when solving for either sin(x) or cos(x).

Given that cos(α) = √11/7 and sin(β) = √11/4, we find

sin(α) = √(1 - cos²(α)) = √38/7

cos(β) = √(1 - sin²(β)) = √5/4

Now, recall the sum identity for cosine,

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

It follows that

cos(α + β) = √11/7 × √5/4 - √38/7 × √11/4 = (√55 - √418)/28

Answer:

  68 texts per day

Step-by-step explanation:

The description of the variables in the equation tells you that you want to find t (texts sent per day) for the given value of 'a' (age in years).

__

Substitute the number (15) for the variable (a) and do the arithmetic:

  t = -1.63a +92.14

  t = -1.63(15) +92.14 = -24.45 +92.14

  t = 67.69

Keiko's trend line estimates a 15-year-old would send about 68 texts per day.

Each transaction has been an analyzed in the trial balance below by showing its effects on the accounting equation-specifically, identifying the accounts and amounts.

The Journal Entries are:

Cash                                                                                 6500

Photography equipment                                                33500

                  Capital                                                                       40000

Prepaid Insurance                                                           2100

                   Cash                                                                         2100

Office Supplies                                                                  880

                  Cash                                                                          880

Cash                                                                                   3331

           Revenue                                                                          3331

Utilities Expense                                                                 675

           Cash                                                                                 675

Cash account = 6500 - 2100 - 880 + 3331 - 675

Cash Account = 6176

                                                     Trial Balance

                                                                              Debit                         Credit

Cash                                                                       6176

Prepaid Insurance                                                  2100

Supplies                                                                   880

Revenue                                                                                                      3331

Utilities Expense                                                      675

Capital                                                                                                       40000

Photography Equipment                                         33500

Total                                                                         43331                       43331

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Answer:

A

Explanation:

Formula for the volume of a cone :Volume (cone) = 1/3πr²h

=========================================================

Given :

⇒ r = 4 units

⇒ h = 21 units

=========================================================

Solving :

⇒ Volume (cone) = 1/3 × π x 4² × 21

⇒ Volume (cone) = 16 × 7 × π

⇒ Volume (cone) = 112π units²

Answer:

36

Step-by-step explanation:

If x = 2 and y = -3...

xy^2=

(2)(-3)^2 =

-6^2 =

36

XY times 2=

(-6)(2) =

-12

Answer:

18

Step-by-step explanation:

First you must fill input the values into their variable counterparts:

xy^2 turns into: 2 * -3 ^2

Since there isn't a parenthesis around x AND y, the exponent only applies to the y value.

-3 ^2 = 9, so 2 x 9 = 18

xy^2 = 18 if x =2 and y = -3

The theorem that verifies that the two right angled triangles are similar is HA.

Two triangles are said to be similar if the ratio of their corresponding sides and the corresponding angles are equal.

Analysis:

From the diagrams KL = OQ ( hypotenuse)

∠L is equal to ∠Q which are acute.

so the two triangles are similar in hypotenuse and acute angle which is the HA theorem.

In conclusion, the HA theorem verifies that the two triangles are similar.

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Answer: Commutative property

−9x^4−18x^4y+27x^2y^2

Answer:

=−18x^4y−9x^4+27x^2y^2

Step-by-step explanation:

(−9x^2)(x^2+2x^2y−3y^2)

=(−9x^2)(x^2+2x^2y+−3y^2)

=(−9x^2)(x^2)+(−9x^2)(2x^2y)+(−9x^2)(−3y^2)

=−9x^4−18x^4y+27x^2y^2

=−18x^4y−9x^4+27x^2y^2

---

Hope I helped! Have a great day :)

Reason:

Refer to the diagram below. The tiny square angle markers tell us we have a 90 degree angle, meaning those lines are perpendicular.

You can think of the parallel lines being the metal part of train tracks, while the perpendicular line connecting the metal rails is the wooden part of the train tracks.

Answer:

Table D

Step-by-step explanation:

I have all of the tables listed below and the correct one circled! I used to tutor my cousin about this topic!

I hope this helps and please feel free to comment, ask questions, give feedback, and correct me if I am wrong!

Have a great day!

:)

The 4th table in the option is the correct one.

An equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Given that, Yolanda saves all the money from a regular baby-sitting job. The money in her savings account is increasing according to the equation y = 6x + 50, where x = number of hours worked and y = savings in dollars.

The given equation is y = 6x + 50

Put x = 0

y = 50

Put x = 5

y = 80

Put x = 10

y = 110

Put x = 15

y = 140

Creating the table,

                 x                                                                 y

                 0                                                                50

                 5                                                                80

                 10                                                               110

                 15                                                               140

Hence, we get the table.

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[tex]~~~~~~~\cos^2 \left(34^{\circ}\right) - \sin^2 \left( 34^{\circ} \right)=\cos A\\\\\implies \cos \left( 2 \cdot 34^{\circ} \right) = \cos A~~~~~~~~~~~~~;[\cos 2x = \cos^2 x -\sin^2 x]\\\\\implies \cos \left(68^{\circ}\right) = \cos A\\\\\implies A = 68^{\circ}[/tex]

Answer:

[tex]p = 3\\\\q= 1[/tex]

Step-by-step explanation:

[tex]x^2 -6x +10\\\\=x^2 -2 \cdot 3x +3^2 -3^2 +10\\\\=(x-3)^2 -9+10\\\\=(x-3)^2 +1\\\\\text{By comparing with}~ (x-p)^2 +q, \\\\p = 3\\\\q = 1[/tex]

Answer:

your answer is 4 my friend

Step-by-step explanation:

Answer:

by using pythagoras theorem

Step-by-step explanation:

the distance between sun and moon is hypoteneous

the distance between earth and sun is perpndicular

and distance between earth and moon is base

we can use,

tanx°=distance betwwen earth and sun/ distance betweenearth and moon

or,

sinx°= distance between earth and sun/ distance between sun and moon

we can use other formulas also same as above 2 examples

Hope ithelps

Answer:

The scientist can use trigonometry to figure out the distance between the Moon and Sun. More specifically, using sine (sin).

Step-by-step explanation:

Label the triangle first.

- x should be theta

- y would be opposite (o) as it is across/opposite from the side where x is

- the distance between the sun and moon would be hypotenuse (h), as it's opposite of the right angle.

The calculation that has o and h in it's formula is sine. The formula looks like :

Sin(Ф) = [tex]\frac{o}{h}[/tex]

To solve for the distance between the Sun and Moon, we plug it into the formula and solve

Sin(x) = [tex]\frac{d}{y}[/tex]

- where d is the distance between the Sun and Moon

hope this helps !! :D

(4)

1. 11.444 repeater

2. 0.58333 repeater

3. 6.7333 repeater

4. 27.5454 repeater (on both 5 and 4)

5. 1.482517482517 (482517 repeater)

6. 2.285714285714 (285714 repeater)

7. 7.5666 repeater

8. 60.60606060 (60 repeater)

(5)

1. 0.666 (repeater)

2. 0.3666 (repeater)

3. 1.1818181818 (18 repeater)

4. 0.418181818 (18 repeater)

Answer: C

Step-by-step explanation:

[tex]16x+8 \geq 12x+20\\ \\ 4x+8 \geq 20\\ \\ 4x \geq 12\\ \\ \boxed{x \geq 3}[/tex]

Answer:

Using PEMDAS we can see that P or parenthesis is first so we would subtract 5 from 5 in the beginning.  That would result in a 0 which would then get multiplied with 12 to still have 0.

[tex]12(5-5) + 3 * 5[/tex]

[tex]12(0) + 3 * 5[/tex]

[tex]0 + 3 *5[/tex]

Now that we completed that part, the only thing that we have left to do is to multiply the last two numbers, 3 and 5.

[tex]3*5[/tex]

[tex]15[/tex]

Therefore, our final solution is 15.

Hope this helps!

By solving a quadratic equation, we will see that the length is 10m and the width is 6.5m

For a rectangle of width W and length L, the area is:

A = W*L

In this case, we know that the area is 65m² and that the length is 3 meters less than 2 times the width, so:

L = 2*W - 3m

Then we can write:

65m² = (2*W - 3m)*W = 2*W² - 3m*W

This is a quadratic equation:

2*W² - 3m*W - 65m² = 0.

The solutions are given by the Bhaskara's formula:

[tex]W = \frac{3 \pm \sqrt{(-3)^2 - 4*2*(-65)} }{2*2} \\\\W = \frac{3 \pm 23 }{4}[/tex]

We only care for the positive solution, which is:

W = (3m + 23m)/4 = 26m/4 = 6.5m

Then the length is:

L = 2*6.5m - 3m = 10m

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