Which equation can be solved by using this system of equations?

StartLayout Enlarged left-brace 1st Row y = 3 x Superscript 5 Baseline minus 5 x cubed + 2 x squared minus 10 x + 4 2nd Row y = 4 x Superscript 4 Baseline + 6 x cubed minus 11 EndLayout

Answer:

+12 percentage points

Step-by-step explanation:

All options have positive percentage in themselves

So lesser marginal error should be more applicable as lower the marginal errors lower the probability of doing mistakes so higher marks .

Option B

histor Grammer

Step-by-step explanation:

lol bhsg HD tcvh by by by g

Answer: C

Step-by-step explanation:

We know that [tex]\angle AHB=90^{\circ}[/tex], and thus by the exterior angle theorem,

[tex]90^{\circ}+\alpha=4\alpha\\\\90=3\alpha\\\\\alpha=30^{\circ}[/tex]

Thus, [tex]\angle CAB=2\theta=\boxed{60^{\circ}}[/tex]

Answer:

y = 3x - 12

Step-by-step explanation:

Forming the slope-intercept equation :

y = mx + b

Substitute m = 3 and b = -12 in the equation :

Answer:

y = 3x - 12

Step-by-step explanation:

The slope intercept form of a line is y = mx + b, where m is the slope and b is the y intercept. Here, m = 3 and b = -12. Therefore, the slope intercept form for this line is y = 3x - 12.

Answer:

[tex] \large {\boxed{ \sf{y = 2x + 5}}}[/tex]

Step-by-step explanation:

Suppose the slope of the line is k.

So,

[tex] \large {\bold {k = \frac{7 - ( - 1)}{1 - (3)} = \frac{7 + 1}{1 + 3} = \frac{8}{4} = 2 }}\\ [/tex]

So the line:

[tex] \large \bold{ \frac{y - 7}{x - 1} = k = 2 } \\ [/tex]

[tex] \: [/tex]

So,

[tex] \large \bold{y - 7 = 2(x - 1)}[/tex]

[tex]\large \bold{y - 7 = 2x - 2}[/tex]

[tex]\large \bold{y = 2x - 2 + 7}[/tex]

[tex]\large \bold{y = 2x + 5}[/tex]

[tex]{\rule{200pt}{4pt}}[/tex]

[tex] \large \bold{-N} \frak{unx-}[/tex]

Using it's concept, it is found that the probability of tossing heads and rolling a number less than 3 is given by:

C. 1/6

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there were 12 trials. Of those, 2 are H1 and H2, which are heads and a number less than 3, hence the probability is given by:

p = 2/12 = 1/6.

Which means that option C is correct.

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Answer:

2, 10, 50, 250

Step-by-step explanation:

For geometric sequences, multiply the previous term by the common ratio.

Using the formula for geometric sequences [tex]a_{n} =ar^{n-1}[/tex] , with [tex]a_{n}[/tex] being the nth term (so n=4 for the fourth term), a being the first term, and r being the common ratio.

Our starting term is 2. So that is automatically the first term of the four.

Second term:

[tex]a_{2} =2*5^{2-1}=2*5^1=2*5=10[/tex]

Third term:

[tex]a_{3} =2*5^{3-1}=2*5^2=2*25=50[/tex]

Fourth term:

[tex]a_{4} =2*5^{4-1}=2*5^3=2*5*5*5=10*25=250[/tex]

The measures of center and variability for the

temperatures that were lower this week than last week include mean, range, mean absolute deviation.

It should be noted that a mean simply means the average set if numbers given.

Also, the range is the difference between the highest number and the lowest number in the data.

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Answer:

mean,range,mean absolute deviation

Step-by-step explanation:

just took it on edge

Answer:

C. 91.46

Step-by-step explanation:

Use BODMAS!

Answer:

C. 91.46

Step-by-step explanation:

Using Pemdas to solve:

5.9 (9 - 5) + 4^3 + 3.86

First you have to solve in the parenthesis

5.9 (9 - 5) + 4^3 + 3.86

= 4

New equation:

5.9 x 4 + 4^3 + 3.86

Now solve the exponent:

5.9 x 4 + 4^3 + 3.86

= 64

New equation:

5.9 x 4 + 64 + 3.86

Now we have to do multiplication:

5.9 x 4 + 64 + 3.86

= 23.6

New equation:

23.6 + 64 + 3.86

Now all you have to do is add all that together and you have your answer:

23.6 + 64 + 3.86

= 91.46

Hope this helps.

Answer:

[tex]\dfrac{1}{64}[/tex]

Step-by-step explanation:

Hemi-, demi- and semi- are prefixes which mean half.

When applied to musical notation, each time a prefix is added it means the note's value is halved.

Therefore, if a quaver is one-eighth of a semibreve, then a semiquaver is half of a quaver, which means it's one-sixteenth of a semibreve.

[tex]\large \begin{aligned}\sf quaver & = \sf\dfrac{1}{8}\:of\:a\:semibreve\\\\\implies \sf hemisemidemiquaver & = \sf \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{2} \times quaver\\\\& = \sf \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{8}\\\\& = \sf \dfrac{1}{64}\:of\:a\:semibreve\end{aligned}[/tex]

Therefore, a hemisemidemiquaver is one-sixty-fourth of a semibreve.

Answer:

C

Step-by-step explanation:

M is less than n because it comes before it in the number line

Answer:

w = 10

Step-by-step explanation:

First we take the two values for the breadth of the rectangle

So:

5x - 9 = 3x + 7

now we solve this equation as follows:

5x - 3x = 9 + 7

2x = 16

x = 8

now that we have found the value for x, we can substitute it in the equation, 5x - 9,or in the equation, 3x + 7.

when we substitute x in any of these equations, we get

5(8) - 9 = 31

3(8) + 7 = 31

now that we have the value for the breadth we can form the following equation:

31 × w = 310

31w = 310

w = 310/31 = 10

Answer:

10

Step-by-step explanation:

Firstly, we find the value of X

since 5X-9 and 3X+7 are lenghts

5X-9= 3X+7

5X-3X= 7+9

2X = 16

dividing bothsides by 2

2X/2= 16/2

X = 8

Hence,

5X-9= 5(8)-9= 40-9 = 31

3X+7=3(8)+7= 24+7= 31

To find the width

Area= lenght×width

310= 31×w

31w= 310

w= 310/31

W= 10

Answer:

  66°

Step-by-step explanation:

The angle sum theorem tells you the sum of angles in a triangle is 180°.

__

  79° +x +35° = 180°

  x = 180° -114° . . . . . . . . subtract 114° from both sides

  x = 66° . . . . . simplify

Answer:

x=5 and y=7

Step-by-step explanation:

Just substitute in y=x+2 into the equation 5x-4y=-3 to get 5x-4(x+2)=-3 which simplifies to x=5. Substitute x into y=x+2 to find y=7

Answer:

25.5

Step-by-step explanation:

I did the same assignment

The value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We know that:

P + Q are complementary, which means that

P+Q = 90°

Then R is a right angle, i.e. it measures 90°.

sin(90-x) = cos (x)

cos(90-x) = sin (x)

Then sinQ = 4/5  

cos(90-Q) = cosP = 4/5

Now sin²(P) + cos²(P) = 1

sin²(P) = 1 - cos²(P)

sin²(P) = 1 -[4/5]² =9/25

sin(P) = 3/5

cos(Q) = sin(P) = 3/5

cos(P) + cos(Q) = 4/5 + 3/5 = 7/5

Thus, the value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.

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Answer:

CE = 4.6 ft

Step-by-step explanation:

(a)

given 2 secants drawn from an external point to the circle , then

the product of the external part of one secant and the entire secant is equal to the product of the other secant's external part and that entire secant, that is

BE × BC = AB × DB

(b)

substituting given values into the equation

BE × 10 = 3 × 18

10 BE = 54 ( divide both sides by 10 )

BE = 5.4 ft

then

CE = CB - BE = 10 - 5.4 = 4.6 ft

The pair of angles that share a ray as a common side in the given diagram is: ∠FAB and ∠FAD.

Adjacent angles are angles that lie adjacent or next to each other sharing a common vertex and have the same ray as a common side.

In the diagram attached below, ∠FAB and ∠FAD share a common vertex, A, and a ray FA as a common side.

Therefore, the pair of angles is: ∠FAB and ∠FAD.

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Answer:

Tabled Function

Step-by-step explanation:

To determine which function is increasing the fastest over the interval [-5, 3], we need to calculate and compare each function's average rate of change over the given interval.

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:

[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]

Given interval:  -5 ≤ x ≤ 3

Therefore, a = -5  and  b = 3

[tex]f(3)=7[/tex]

[tex]f(-5)=-17[/tex]

[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)}=\dfrac{7-(-17)}{3+5}=3[/tex]

[tex]f(3)=(3)^2-2=7[/tex]

[tex]f(-5)=(-5)^2-2=23[/tex]

[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)}=\dfrac{7-23}{3-(-5)}=-2[/tex]

From inspection of the graph:

[tex]f(3)\approx8[/tex]

[tex]f(-5) \approx 0[/tex]

[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)} \approx \dfrac{8-0}{3-(-5)}=1[/tex]

Therefore, the Tabled Function has the greatest average rate of change in the interval [-5, 3] and so it is increasing the fastest.

Using the information in the diagram, the measure of [tex]\overset{\LARGE\frown}{CD}[/tex] is 89.0°

From the question, we are to determine the measure of [tex]\overset{\LARGE\frown}{CD}[/tex]

Consider the right triangle

The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] is twice the measure of the unknown angle

Let the unknown angle in the right triangle be x

∴ The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] = 2x

Then,

x + 90° + 45.5° = 180° (Sum of angles in a triangle)

x = 180° - 90° - 45.5°

x = 44.5°

Thus,

The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] = 2×44.5°

The measure of [tex]\overset{\LARGE\frown}{CD}[/tex] = 89°

Hence, the measure of [tex]\overset{\LARGE\frown}{CD}[/tex] is 89.0°

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The amount of milk needed for a 17-pound goat and a 55-pound goat are 55 and 87.5 cubic units, respectively

The equation is given as:

y =1.5x + 5

For a 17-pound goat, we have:

x = 17

This gives

y =1.5 * 17 + 5

y = 30.5

For a 55-pound goat, we have:

x = 55

This gives

y = 1.5 * 55 + 5

y = 87.5

Hence, the amount of milk needed for a 17-pound goat and a 55-pound goat are 55 and 87.5 cubic units, respectively

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Answer: Hope this helps you!

6th floor

Step-by-step explanation:

If it starts on the 9th floor and goes down 7 floors that is:

9 (9 floors) + -7 (down 7 floors)

which is also equal to 9-7

9-7 = 2

Next, we need to go up by 4 floors starting with 2, 2+4

2+4 = 6

Brainliest?

The quadrants is tan⁻¹x restricted is A. Quadrants I and IV

To answer the question, we need to know what tan⁻¹x is.

tan⁻¹x is the inverse trigonometric function of tanx, which is the value of the angle for tanx.

To find the quadrants in which tan⁻¹x is restricted, we know that tanx lies in the range

-∞ ≤ tanx ≤ +∞ for -90° ≤ x ≤ 90°.

tan⁻¹x lies between quadrant I and IV

So, the quadrants is tan⁻¹x restricted is A. Quadrants I and IV

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Answer:

25 degrees

Step-by-step explanation:

arc divided by 2 = angle

50/2=25

Answer:

Step-by-step explanation:

The profit = 150 000 - 120 000 = 30 000

………………………………………………………

The profit percentage is :

[tex]=\frac{30000}{120000} \times 100=0.25 \times 100 = 25 \%[/tex]

The correct value of this equation is m = 24

This equation contains a fractional term. We note that the denominator of this equation is the term 4. Therefore, we will multiply the sides by 4:

13 = m/4 + 7

13 . 4 = 4(m/4) + 7 . 4

52 = m + 28

Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

52 = m + 28

-m = 28 - 58

-m = -24

m = 24

Therefore, the correct value of this equation will be m = 24

Answer: I think

Step-by-step explanation:Let the coordinate of the point be (x,y,z). Since the point is located 3 units behind the YZ− plane, 4 units to the right of XZ− plane and 5 units above the XY−plane ,x=−3,y=4 and z=5 Hence, coordinates of the required points are (−3,4,5)

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to simplify the expression 2(7x+3)+9x.

[tex]\triangle~\fbox{\bf{KEY:}}[/tex]

So, let's compute...

\\\////\\\///\\\///\\\///\\\///\\\///\\\///\\\///\\\\///\\\////\\\///\\\///\\\///\\\///\\\///\\\//\\//\\\/

After performing multiplication we obtain

[tex]\star~\mathrm{14x+6+9x}[/tex]

Now add 9x:

[tex]\star~\mathrm{23x+6}[/tex]

Hope it helps you out! :D

Ask in comments if any queries arise.

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~Just a smiley person helping fellow students :)

Answer:

30

Step-by-step explanation:

[tex]\frac{5\cdot\frac{6}{6} }{2\cdot\frac{6}{6} } = \frac{25}{30}, \frac{12}{30}[/tex]

Answer:

the value is 14

Step-by-step explanation:

because im just trying to get points