Answer:
NaOH + HCl = NaCl + H2O
(3.612 moles of HCl) x (1/1) x (39.9971 g/mol) = 144.5 grams
So answer B.
Explanation:
NaOH + HCl = NaCl + H2O
(3.612 moles of HCl) x (1/1) x (39.9971 g/mol) = 144.5 grams
To solve such this we must know the concept of double displacement reaction. Therefore, 144.48g sodium hydroxide will neutralize completely 3.612 moles of HCl.
What is chemical reaction?Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.
The balanced reaction is
NaOH + HCl = NaCl + H2O
To neutralize completely 3.612 moles of HCl, 3.612 moles of NaOH is required.
mass of NaOH =Mole× Molar mass of NaOH
mass of NaOH=3.612× 40 g/mol
mass of NaOH=144.48g
Therefore, 144.48g sodium hydroxide will neutralize completely 3.612 moles of HCl.
Learn more about the chemical reactions, here:
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Calculate the amount of heat, in Joules, needed to raise 34.0g of water from 55.0°C to 76.0*C. The specific heat of water is 4.18 J/gºC.
Answer:
2984.52J
Explanation:
Using the formula: Q = m × c × ∆T
Where;
Q = amount of heat (in Joules)
m = mass (in grams)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
Based on the information provided in the question;
m = 34.0g
c = 4.18 J/gºC.
Initial temperature = 55.0°C
Final temperature = 76.0°C
Hence, Q = m × c × ∆T
Q = 34 × 4.18 × (76 - 55)
Q = 142.12 × 21
Q = 2984.52J
Therefore, 2984.52J is the amount of heat, in Joules, needed to raise 34.0g of the water.