What is the total area of the desk in square feet?

Answer:

(-2, 5), 6, 12

Step-by-step explanation:

Center: (-2, 5)

Radius: 6

Diameter: 12

Answer: $906.51

Step-by-step explanation:

Answer:

either a. or c. I hope it helps

Step-by-step explanation:

because half of 64 is 32

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Answer: Most likely he will exercise 6/7 hours on Wednesday!

Explanation:

I hope this helped!

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- Zack Slocum

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Answer:

1 ,x=18,y=13.3

2,x=8,y=30

3,x=15

Answer:

b

Step-by-step explanation:

Answer:

50.27 cm

Step-by-step explanation:

4 to the second power=16

16×3.14=50.27

Answer:

0.75

Step-by-step explanation:

what you do is divde 3 by 4 which equals to 0.75

Answer:

75%

Step-by-step explanation:

If your rounding 2 decimals. Hope this helps!

Answer:

:P

Step-by-step explanation:

Answer:

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

The value of a gold coin picturing the head of the Roman Emperor Domitian is increasing at the rate of 6% per year. If the coin is worth $155 now, what will it be worth in 14 years?

Question 6 options:

$239.00

$285.20

$294.72

$350.44

Step-by-step explanation:

Answer:

1/10 or 10%

...........

Answer:

hello there how are you today

Answer:

0

Step-by-step explanation:

discriminant,b2-4ac

=4^2-4×1×4

=16-16=0

Answer:

Find the area by multiplying the base by the height. From the problem, the length (base) of the rectangle is 5 units. The height of the rectangle is

[tex]3\frac{1}{2} [/tex]

inches. Multiply to find the area.

[tex]5 \times 3 \frac{1}{2} = 17 \frac{1}{2} [/tex]

The area of the rectangle is 17 1/2 units squared. The answer you provided is correct!

Given:

The phrase is "six times a number is less than negative thirty-nine and three-quarters".

To find:

The inequality represented by the given phrase.

Solution:

Let x be the unknown number.

Six times a number is "6x".

Less than is "<".

Negative thirty-nine and three-quarters is "[tex]-39\dfrac{3}{4}[/tex]".

So, six times a number is less than negative thirty-nine and three-quarters is:

[tex]6x<-39\dfrac{3}{4}[/tex]

Therefore, the correct option is C.

Answer:

"six times a number is less than negative thirty-nine and three-quarters".

Step-by-step explanation:

or C

Answer:

Triangle A

Step-by-step explanation:

Because in the picture it shows the grid and if you look closely you can see the points on the x and y axis, (3,2) (4,7) and (5,6) are the three points formed to make triangle A.

Answer:

10

Step-by-step explanation:

Answer:

down below

Step-by-step explanation:

y = -5/4 - 3r/8

r = -10/3 - 8y/3

I hoped this help plsssss mark me as brainlist if it does that would mean alot and i took lots of . time in this thank you!

Answer:

y = -7

Step-by-step explanation:

5x+8y=29

5(17)+8y=29 (simplify by multiplying)

85+8y=29 (subtract 85 from both sides)

8y= -56 (divide both sides by 8y)

y = -7

Answer:

A2 = 120

A3 = 60

A5 = 60

A6 = 120

Step-by-step explanation:

Angle 1 and 2 are supplementary, so A2 = 180 - 60, which is 120.

Angle 1 and 3 are vertical angles, which are always the same measure.

Angle 5 is alternate interior angles with 3, which means it is also 60.

Angle 6 is alternate interior angles with 4, which means it is 120.

Answer:

[tex]\frac{(8+2)^2}{2} = 50[/tex]

[tex]10+5^2-3 * 2^2 = 23[/tex]

Step-by-step explanation:

[tex]\frac{(8+2)^2}{2}[/tex]

[tex]\frac{10^2}{2}[/tex]

[tex]\frac{100}{2}[/tex]

50

------------------------------

[tex]10+5^2-3 * 2^2[/tex]

[tex]10+25-3 * 4[/tex]

[tex]10+25-12[/tex]

[tex]35-12[/tex]

23

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph represent the value of goods at which profit of of the company is zero → Break even of the company

Maximum value of the graph represents the maximum profit of the company at certain price of the goods.

Part B

Interval in which the function is increasing → x = 0 to x = $3

Profit of the company increases when price of the goods increase from 0 to 3.

Interval in which the function is decreasing → x = $3 to x = $6

Profit of the company decreases when the price of the goods increases from 3 to 6.

Part C

Average rate of change of the function from x = a and x = b,

= [tex]\frac{f(b)-f(a)}{b-a}[/tex]

By applying the same rule,

Average rate of change of the function between x = 1 and x = 3

= [tex]\frac{120-60}{3-1}[/tex]

= [tex]\frac{60}{2}[/tex]

= 30

Answer:

4/15

Step-by-step explanation:

Answer:

570 of 2% 4years

570×2÷100 4years

11.5 × 4÷12

3.8..

Answer: He has 8 dimes

Step-by-step explanation:

Answer:

17 dimes

7 nickels

Step-by-step explanation:

n = number of nickels

d = number of dimes

0.10d + 0.05n = 2.05

n + d = 24, n = 24 - d

substitute for n:

0.10d + 0.05(24 - d) = 2.05

simplify:

0.10d + 1.20 - 0.05d = 2.05

0.05d = 0.85

d = 17

n = 24-17 = 7

Answer:

m=1/5

Step-by-step explanation:

Answer:

[tex]x = 9[/tex]

Step-by-step explanation:

Assume EFGH and JKLM are rectangles

JKLM appears to be the smaller of both.

So:

[tex]EF = n * JK[/tex] and [tex]GH = n * LM[/tex]

Where n is the scale of dilation

The area of EFGH is:

[tex]Area = EF * GH[/tex] ----- (1)

Substitute [tex]EF = n * JK[/tex] and [tex]GH = n * LM[/tex]

[tex]Area = n*JK * n*LM[/tex]

[tex]Area = n^2*JK * LM[/tex]

So, we have:

[tex]Area = EF * GH[/tex] and [tex]Area = n^2*JK * LM[/tex]

[tex]EF * GH = 2x + 9[/tex] --- Given

[tex]JK * LM = 2x - 6[/tex] --- Given

So:

[tex]Area = EF * GH[/tex] and [tex]Area = n^2*JK * LM[/tex]

[tex]Area = 2x + 9[/tex] and [tex]Area = n^2 * (2x - 6)[/tex]

Equate bot areas

[tex]2x + 9 = n^2*(2x - 6)[/tex]

Make n^2 the subject

[tex]n^2 = \frac{2x + 9}{2x - 6}[/tex]

The perimeter (P) of EFGH is:

[tex]P = 2*(EF + GH)[/tex] ----- (1)

Substitute [tex]EF = n * JK[/tex] and [tex]GH = n * LM[/tex]

[tex]P = 2*(n*JK + n*LM)[/tex]

[tex]P = 2n*(JK + LM)[/tex]

So, we have:

[tex]P = 2*(EF + GH)[/tex] and [tex]P = 2n*(JK + LM)[/tex]

[tex]2*(EF + GH) = x + 3[/tex] --- Given

[tex]2*(JK + LM) = x - 1[/tex] --- Given

So:

[tex]P = 2*(EF + GH)[/tex] and [tex]P = 2n*(JK + LM)[/tex]

[tex]P =x + 3[/tex] and [tex]P = n *(x - 1)[/tex]

Equate bot perimeters

[tex]x + 3 = n(x - 1)[/tex]

Make n the subject

[tex]n =\frac{x + 3}{x - 1}[/tex]

Square both sides

[tex]n^2 =\frac{(x + 3)^2}{(x - 1)^2}[/tex]

Recall that: [tex]n^2 = \frac{2x + 9}{2x - 6}[/tex]

So, we have:

[tex]\frac{(x + 3)^2}{(x - 1)^2} = \frac{2x + 9}{2x - 6}[/tex]

Evaluate all squares

[tex]\frac{x^2 + 6x +9}{x^2 - 2x + 1} = \frac{2x + 9}{2x - 6}[/tex]

Cross multiply

[tex](x^2 + 6x +9)(2x - 6) = (x^2 - 2x + 1)(2x + 9)[/tex]

Open brackets

[tex]2x^3 +12x^2 + 18x - 6x^2 -36x -54 = 2x^3 - 4x^2 + 2x + 9x^2 - 18x +9[/tex]

Subtract 2x^3 from both sides

[tex]12x^2 + 18x - 6x^2 -36x -54 = - 4x^2 + 2x + 9x^2 - 18x +9[/tex]

Collect like terms

[tex]12x^2 - 6x^2 + 18x -36x -54 = - 4x^2 + 9x^2+ 2x - 18x +9[/tex]

[tex]6x^2 - 18x -54 = 5x^2- 16x +9[/tex]

Collect like terms

[tex]6x^2 -5x^2 - 18x +16x -54 -9= 0[/tex]

[tex]x^2 -2x -63= 0[/tex]

Expand

[tex]x^2 +7x - 9x - 63 = 0[/tex]

Factorize

[tex]x(x +7) - 9(x + 7) = 0[/tex]

[tex](x -9) (x + 7) = 0[/tex]

[tex]x = 9\ or\ -7[/tex]

x can not be negative.

So: [tex]x = 9[/tex]

Step-by-step explanation:

the lebgth to form the right angle is e9